Sequelize Many-to-many table with identical foreign key is selecting just one value - mysql

Question

I have the following structure:
var User = sequelize.define('user', {
name: DataTypes.STRING
});
var Post = sequelize.define('post', {
text: DataTypes.STRING
});
var PostComment = sequelize.define('postComment ', {
id: {
type: DataTypes.BIGINT,
primaryKey: true,
autoIncrement: true
},
comment: DataTypes.TEXT
});
Post.belongsToMany(User, {as: 'postUserComment', through: {model: models.PostComment, unique: false}, foreignKey: 'idPost'});
User.belongsToMany(Post, {through: {model: models.PostComment, unique: false}, foreignKey: 'idUserComment'});
I am able to create multiples comments to the same post with an user.
But if i have more then one comment to the same post with the same user and try to select them by doing:
Post.findAll({
include: [{model: models.User, as: 'postUserComment', attributes:['name'], through: {attributes: ['comment']}},
limit: 10,
offset: 0,
order: "id DESC"
...
it just return 1 comment for each user in a post. What do i have to do to select them all?
Dialect: mysql,
Sequelize version: ~3.27.0

Answer 1

Having association with BelongsToMany and the same ids is somehow tricky in Sequelize.
As you have already noticed in GitHub #6906 and other related issues there, the best way to do this is to mitigate it with different relations.
For example you can add :
Post.hasMany( models.PostComment, { foreignKey: 'idPost' } );
And then to your query
Post.findAll({
include: [
{model: models.User, as: 'postUserComment', attributes:['name'], through: {attributes: ['comment']}},
{model : models.PostComment}
],
limit: 10,
offset: 0,
order: "id DESC"
..
This will not change your database structure and will have the effect that you want.