MyPHP and SQL creating a new table based on others - mysql

Question

I have three tables; Table 1 (appointments) that contains the appointment start and end time in YYYY-MM-DD HH:MM:SS format, provider ID, Customer ID and Service ID.
Table 2 (users) contains both Provider and Customer IDs and First/Last names.
Table 3 (services) contains the service ID, service name, and service description.
I need to create a fourth table, called display, that will display the Provider name, Client name, Service name, and start and end times in HH:MM format.
I've tried googling joins, but I'm not seeming to get anywhere.
I'm using a simple script from w3schools, below:
<?php
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM ea_appointments INNER JOIN ea_services";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Start: " . $row["start_datetime"]. "End: " . $row["end_datetime"]. " - Provider: " . $row["id_users_provider"]. " - Customer: " . $row["id_users_customer"]. " - Service: " . $row["id_services"]."<br>";
}
} else {
echo "0 appointments";
}
$conn->close();
?>

Answer 1

In this case do not create a table because you just want to combine data from various tables. Just have a query or create a view.
In the query you need to tell mysql how to join your tables using the on clause. I'll show you how to join 2 tables, the rest is up to you:
SELECT *
FROM ea_appointments a
INNER JOIN ea_services s on a.serviceid=s.serviceid