Copy and Delete a column with transpose style - google-apps-script

Question

I have in a column the invoice info of a client (name, address, email, phone number) each one in one row of the column A, and I need to Copy it to another range in transpose style.
I used the following script trying to edit it as I need but I do not find how
function copyAndDeleteSalidas () {
var ss = SpreadsheetApp.getActiveSpreadsheet ();
var source = ss.getRange ("Sheet1!A1:A6");
var destSheet = ss.getSheetByName("Sheet2!");
var destRange = destSheet.getRange(destSheet.getLastRow()+1,1);
source.copyTo (destRange, {contentsOnly: true});
source.clear ();
}

Answer 1

You'll need a function for transposing 2D arrays, since it appears there isn't a built-in option for this purpose in Apps Script. There are several versions of such a function on Stack Overflow, I used one of them below.
The main difference from your script is that instead of copyTo, I use setValues and getValues. Also, the destination range now must have the size that matches the size of values inserted in it.
function copyTransposeAndDelete () {
var ss = SpreadsheetApp.getActiveSpreadsheet ();
var source = ss.getRange("Sheet1!A1:A6");
var destSheet = ss.getSheetByName("Sheet2");
var destRange = destSheet.getRange(destSheet.getLastRow()+1, 1, source.getWidth(), source.getHeight());
destRange.setValues(transpose(source.getValues()));
source.clear ();
}
function transpose(array) {
return array[0].map(function(col, i) {
return array.map(function(row) {
return row[i];
});
});
}