I am trying to execute a MySQL command in phpMyAdmin so that I can replace all the value in a column AFTER selecting certain values from another column specific values.
The query I am using to select them is this:
SELECT * FROM `homes` WHERE `world` LIKE '%plot%'
However, I am trying to replace all the values in column after selecting them all:
SELECT world,server, REPLACE(server,'drug','plots') FROM homes WHERE world='%plot%'
I am not entirely sure that's what i need to do but here is an image explaining it a bit more.
I have also tried these queries but without any luck:
update homes set server = "plots" where world = '%plot%';
SELECT world,server, REPLACE(server,'drug','plots') FROM homes WHERE world='%plot%'
I am not sure if I understand your question correctly, but do you mean something like this?
SELECT world
, server
, case server
when 'drug' then 'differentValue'
when 'med' then 'anotherdifferentValue'
end server2
FROM homes
WHERE world like 'plot%'
Related
I'd like to use an SQL query to find and replace multiple values. I've had a look at this question that shows the following answer:
UPDATE
YourTable
SET
Column1 = REPLACE(Column1,'a','b')
WHERE
Column1 LIKE '%a%'
How can I find and replace multiple values instead of just the one?
My data is like the following, there's hundreds of rows, I'm specifically wanting to target each product_id:123:
subscription_id,products
"128","product_id:268|quantity:1|total:3.15|meta:|tax:0;product_id:267|quantity:1|total:2.97|meta:|tax:0"
I need to replace the product id's with new products id's. So it'll be "everything matching 268 will become 195" and "everything matching 267 will become 194".
Is there an efficient way to do it other than taking the code block above and using that for each product. Can I be done with one sweep through?
Simplest possible way would be to chain REPLACEs together, but considering the concatenated nature of the field you need to be sure you don't inadvertently target something that's not actually a product_id value. You can mitigate this by including some contextual content from the string value itself:
UPDATE YourTable
SET products = REPLACE(REPLACE(products, "product_id:267|", "product_id:194|"), "product_id:268|", "product_id:195|");
DBFiddle | MySQL 5.6 Reference Manual :: 13.2.8 REPLACE Statement
If there's some variability in how these strings might appear in a given field and you're running MySQL >=8.0, you can leverage something like REGEXP_REPLACE() to perform this same replacement using a defined RegExp pattern.
Yes, there are ways. For example, you can create a table like
replacements(id, oldval, newval)
and do the following:
UPDATE
Yourtable
JOIN
replacements
ON
Yourtable.Column1 LIKE CONCAT('%', replacements.oldval, '%')
SET
Yourtable.Column1 = REPLACE(Yourtable.Column1, replacements.oldval, replacements.newval);
The problem is that you would need to fill replacements with the pairs of oldval-newval, but MySQL cannot guess that. Insertion is as simple (assuming that id is auto_increment) as
INSERT INTO replacements(oldval, newval) VALUES
('a', 'b'),
('c', 'd'),
...
;
I'm new to SQL and I'm stuck on a multiple find in SQL.
Here I'm trying to search table1 in the three columns. But I'm stuch in trying to find two phrases. I'm trying with an OR statement.
If I remove OR LIKE '%paris%' it works but how do I find multiple words/phrases. And would this statement be case sensitive?
I'm also using MySQL to run the above.
SELECT * FROM `table1`
WHERE
CONCAT_WS('|',`target_1`,`target_2`,`target_3`)
LIKE '%london%' OR LIKE '%paris%'
In your code your second condition is sintactically wrong because is missing the a part for the match
so you should repeat the condition as
SELECT *
FROM `table1`
WHERE CONCAT_WS('|',`target_1`,`target_2`,`target_3`) LIKE '%london%'
OR CONCAT_WS('|',`target_1`,`target_2`,`target_3`) LIKE '%paris%'
One option is to use regular expression, then you can also have case insensitive matching (3rd parameter to REGEXP_LIKE)
SELECT *
FROM table1
WHERE REGEXP_LIKE(CONCAT_WS('|',`target_1`,`target_2`,`target_3`), 'london|paris', 'i');
You should repeat the left operand and use (maybe?) multiple conditions i/o concatenating:
SELECT * FROM `table1`
WHERE (`target_1` like '%london%' OR `target_1` like '%paris%')
AND (`target_2` like '%london%' OR `target_2` like '%paris%')
AND (`target_3` like '%london%' OR `target_3` like '%paris%')
I have a field called 'areasCovered' in a MySQL database, which contains a string list of postcodes.
There are 2 rows that have similar data e.g:
Row 1: 'B*,PO*,WA*'
Row 2: 'BB*, SO*, DE*'
Note - The strings are not in any particular order and could change depending on the user
Now, if I was to use a query like:
SELECT * FROM technicians WHERE areasCovered LIKE '%B*%'
I'd like it to return JUST Row 1. However, it's returning Row 2 aswell, because of the BB* in the string.
How could I prevent it from doing this?
The key to using like in this case is to include delimiters, so you can look for delimited values:
SELECT *
FROM technicians
WHERE concat(', ', areasCovered, ', ') LIKE '%, B*, %'
In MySQL, you can also use find_in_set(), but the space can cause you problems so you need to get rid of it:
SELECT *
FROM technicians
WHERE find_in_set('B', replace(areasCovered, ', ', ',') > 0
Finally, though, you should not be storing these types of lists as strings. You should be storing them in a separate table, a junction table, with one row per technician and per area covered. That makes these types of queries easier to express and they have better performance.
You are searching wild cards at the start as well as end.
You need only at end.
SELECT * FROM technicians WHERE areasCovered LIKE 'B*%'
Reference:
Normally I hate REGEXP. But ho hum:
SELECT * FROM technicians
WHERE concat(",",replace(areasCovered,", ",",")) regexp ',B{1}\\*';
To explain a bit:
Get rid of the pesky space:
select replace("B*,PO*,WA*",", ",",");
Bolt a comma on the front
select concat(",",replace("B*,PO*,WA*",", ",","));
Use a REGEX to match "comma B once followed by an asterix":
select concat(",",replace("B*,PO*,WA*",", ",",")) regexp ',B{1}\\*';
I could not check it on my machine, but it's should work:
SELECT * FROM technicians WHERE areasCovered <> replace(areaCovered,',B*','whatever')
In case the 'B*' does not exist, the areasCovered will be equal to replace(areaCovered,',B*','whatever'), and it will reject that row.
In case the 'B*' exists, the areCovered will NOT be eqaul to replace(areaCovered,',B*','whatever'), and it will accept that row.
You can Do it the way Programming Student suggested
SELECT * FROM technicians WHERE areasCovered LIKE 'B*%'
Or you can also use limit on query
SELECT * FROM technicians WHERE areasCovered LIKE '%B*%' LIMIT 1
%B*% contains % on each side which makes it to return all the rows where value contains B* at any position of the text however your requirement is to find all the rows which contains values starting with B* so following query should do the work.
SELECT * FROM technicians WHERE areasCovered LIKE 'B*%'
PROVINCE -- varchar(25)
SELECT * FROM listings WHERE PROVINCE='Bakersfield'
Returns empty resultset when entries with Bakersfield as province exist
I am pretty unsure as to why. When I remove the WHERE it works.
BTW I am running this in phpmyadmin, where it lets one execute SQL statements
In phpmyadmin it shows ... beneath the equals sign. I am not sure why. That may be a hint.
If
SELECT * FROM listings WHERE PROVINCE like '%Bakersfield%'
works for you then you have spaces in your data. You can remove them with
update listings
set PROVINCE = trim(PROVINCE)
See TRIM()
After that you should check your code where you insert the data. Check why there are spaces inserted and fix it.
Change you equal = to LIKE operator
SELECT * FROM listings WHERE PROVINCE LIKE 'Bakersfield'
This should solve your issue. If you want to find places that includes your string simply surround it with wildcards %..%
SELECT * FROM listings WHERE PROVINCE LIKE '%Bakersfield%'
SELECT * FROM listings WHERE PROVINCE='Bakersfield'
There is no point the abpve query doesnt work if the follwing case is not the problem.
1) If case is the prob then use upper or lower
SELECT * FROM listings WHERE upper(PROVINCE)=upper('Bakersfield');
2) If extra space is the problem use replace or Trim
SELECT * FROM listings WHERE replace(PROVINCE,' ','') ='Bakersfield'
There might be sum other seniario if not then use "Like " key word as suggested by others. :)
select concat(mem_fname, mem_lname) as 'Membership Name'
from membership;
select concat (mem_street, mem_city, mem_state, mem_zip) as 'Membership Address'
from membership;
I am trying to make these 2 concat statements make 1 single table. The table should be like this:
Membership name and membership address are the fields with the correct data below them (tried to make a table in this but it is not letting me).
Now each of these work if I just use 1 concat statement, so I know that they are working and giving me the output that I am looking for but I do not know how to put them into 1 single table. If you want to see the full data for the tables I am looking to make I can post it.
I am using MySQL.
I think you are looking for this:
select concat(mem_fname, mem_lname) as Name,
concat (mem_street, mem_city, mem_state, mem_zip) as Address
from membership;