I am trying to create a trigger where if the no tickets are less than the no of adults then value 1 will be inserted in trig table.But, I am getting an error.The code is:
CREATE TRIGGER ch
BEFORE INSERT
ON packagebooking
IF(tick.tickets<packagebooking.Adult
AND tick.Package_id=packagebooking.Package_id)
Begin atomic
insert into trig values(1)
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'IF(tick.tickets<packagebooking.Adult
AND tick.Package_id=packagebooking.Pa' at line 4.
What changes should I do?
Your syntax for trigger creation has an error, place the IF statement inside the FOR EACH ROW as shown below:
CREATE TRIGGER ch BEFORE INSERT
ON `database`.`table`
FOR EACH ROW BEGIN
IF(tick.tickets<packagebooking.Adult
AND tick.Package_id=packagebooking.Package_id)
THEN Begin atomic
insert into trig values(1)
END IF;
END;
Related
I'm trying to create a trigger in MySQL using phpMyAdmin, but I'm getting and error and I can't detect the mistake. The main idea its to create a row in the tables stuff and config when a new user is insered.
The code:
CREATE TRIGGER create_stuff_and_config
AFTER INSERT ON user
FOR EACH ROW
BEGIN
insert into stuff(user_id) values (NEW.user_id);
insert into config(user_id) values(NEW.user_id);
END;
The error:
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5
I've checked the MySQL doc but I see like I'm doing it well...
I've tried too: INSERT INTO stuff SET user_id = NEW.user_id;
Thank you!
Okay, the solution is to add delimiters...
DELIMITER //
CREATE TRIGGER create_stuff_and_config
AFTER INSERT ON user
FOR EACH ROW
BEGIN
insert into stuff(user_id) values (NEW.user_id);
insert into config(user_id) values(NEW.user_id);
END; //
DELIMITER ;
m writing following lines for creating a trigger:
create trigger notify after insert on applications
for each row
begin
insert into notifications SET sno=1;
end;
but everytime i get following error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 4
line 4 is - insert into notifications SET sno=1
MySQL is confused about the delimiters. It thinks the first ; is the end of the TRIGGER declaration (which it is not). Use delimiter to change it temporarily, and later to change it back:
delimiter |
create trigger notify after insert on applications
for each row
begin
insert into notifications (sno) values (1);
end;
|
delimiter ;
More in the documentation.
I try to create trigger in MySql but get the following error:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'DELIMITER' at line 1
DELIMITER $$
CREATE TRIGGER library_update
AFTER UPDATE ON wq6vt_vehiclemanager_vehicles
FOR EACH ROW
BEGIN
INSERT IGNORE INTO wq6vt_vehiclemanager_library (maker, model) VALUES(NEW.maker, NEW.vmodel);
INSERT INTO wq6vt_vehiclemanager_library_data (co2_class)
SELECT co2_class FROM wq6vt_vehiclemanager_vehicles
WHERE maker = NEW.maker AND vmodel = NEW.vmodel;
END $$
DELIMITER;
The first query in the trigger do not lead to errors, but second one does. There is some problem with SELECT inside of INSERT ...I think so
there should be a space between the keyword and the symbol,
DELIMITER ;
-- ^ space in between here
I tried writing this small trigger in MySQL,
CREATE TRIGGER `leg` BEFORE INSERT ON `bckoff`
FOR EACH ROW BEGIN
INSERT INTO `bckoff` SET `step`=1;
END;
after which I get this error.. I'm a newbie to MySQL.. so please help me out here..
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 3
Even after you fix this error - you'll get another one: you cannot modify the table that your trigger was created at.
Btw, this is how you should create this trigger:
delimiter |
CREATE TRIGGER `leg` BEFORE INSERT ON `bckoff`
FOR EACH ROW BEGIN
INSERT INTO `bckoff` SET `step`=1;
END;
|
delimiter ;
I have this code (mySql 5.1.36)
CREATE TRIGGER problem_description AFTER INSERT ON problem_description
FOR EACH ROW BEGIN
INSERT INTO log SET Id=NEW.Id,user_name=NEW.user_name;
END;
and have this error:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 3
For some older phpMyadmin and MySQL you cannot use the standard trigger creation. My question:
http://stackoverflow.com/questions/4289502/trigger-to-track-changes-in-mysql-databse
i had the same issue. you need to remove the delimiter and begin/end statements. your trigger would look somehting like:
DROP TRIGGER IF EXISTS problem_descripter;
CREATE TRIGGER problem_descriptor AFTER insert ON problem_description
FOR EACH ROW
insert into log (Id, user_name)
values(NEW.Id, NEW.user_name);
When do you get this error message? When you create the trigger? You may need to use another delimiter than ; when you create your trigger.
delimiter //
create trigger problem_descriptor after insert on problem_description
for each row begin
insert into
log
set
`Id`=NEW.`Id`,
`user_name`=NEW.`user_name`;
end;
//
delimiter ;