My data value like below
date_time
----------------
24:Sep:2016 22:19:35
22:Oct:2016 22:19:35
26:Sep:2016 22:19:35
28:Sep:2016 22:19:35
Here I am using a query to check data where matched by month like below.
SELECT * FROM `audit_log` WHERE MONTH(STR_TO_DATE(date_time, '%d:%M:%Y %H:%i:%s')) ='Oct'
But this not working for me. But for year if I use that working
SELECT * FROM `audit_log` WHERE YEAR(STR_TO_DATE(date_time, '%d:%M:%Y %H:%i:%s')) ='2016'
I got my answer.
I used long form month to search and in query used MONTHNAME
SELECT * FROM `audit_log` WHERE MONTHNAME(STR_TO_DATE(date_time, '%d:%M:%Y %H:%i:%s')) ='October'
in different process I can use MONTH though it's return number. I have to use month number to search in query. like bwlow
SELECT * FROM `audit_log` WHERE MONTH(STR_TO_DATE(date_time, '%d:%M:%Y %H:%i:%s')) ='10'
Related
Since few days, I am trying to count records per hour from the MySQL database.
I have a table with a lot of records and I have column DATE and column TIME where in DATE I have the date of the record in the format 2022-05-19, and in the column TIME, I have the time of the record in the format 14:59:38.
What I am trying is to count every single day how many records per hour I have. Something like this:
DATE HOUR PCS
22-05-18 06-07 11
22-05-18 08-09 20
......... ..... ..
....... 21-22 33
I have tried many different ways but no success.
For example:
SELECT 'Date', count(*) FROM `root4`
where
DATE between '2022-05-01' and '2022-05-1' AND
TIME BETWEEN '06:11:05' AND '07:11:05'
Any help is highly evaluated.
I would recommend not using reserved words for columns, as you will have to escape them a lot. https://dev.mysql.com/doc/refman/8.0/en/keywords.html
If you stored TIME as a timestamp, you can extract the hour using the HOUR() function and group by that:
SELECT
`DATE`,
HOUR(`TIME`) AS `HOUR`,
COUNT(1)
FROM your_table
GROUP BY
`DATE`,
HOUR(`TIME`)
If you happened to store it as text you can use REGEXP_SUBSTR to get the hour value from your time string.
SELECT
`DATE`,
CAST(REGEXP_SUBSTR(`TIME`, '[0-9]+') AS UNSIGNED) AS `HOUR`,
COUNT(1)
FROM your_table
GROUP BY
`DATE`,
CAST(REGEXP_SUBSTR(`TIME`, '[0-9]+') AS UNSIGNED)
You can format your HOUR column how you want, like displaying 01-02 instead of 1 by using CONCAT, but this is your basic setup.
I want to filter records based on the month of the available due date.
I am trying with the following query but It's not working.
SELECT * FROM m_bills WHERE due_date LIKE substr('201704',4,2)
in this example, I just want to filter all records with the month of April "04".
Use Query Like this select * from m_bills where monthname(due_date) = 'April'
monthname function
i want to search on date field with year. i used Extract like this but it generates error.
SELECT * FROM (blog) WHERE EXTRACT(YEAR FROM blog_dt) = '2014'
you should do it like this:
SELECT * FROM (blog) WHERE EXTRACT(YEAR FROM blog_dt)= '2014' ;
or
SELECT * FROM (blog) WHERE YEAR(blog_dt)='2014';
It's much simpler:
SELECT * FROM (blog) WHERE YEAR(blog_dt) = 2014
See the manual:
YEAR
Returns the year for date, in the range 1000 to 9999, or 0 for the
“zero” date.
mysql> SELECT YEAR('1987-01-01');
-> 1987
You have an extra apostrophe after the EXTRACT() function, remove it and it should work (although #VMai's solution is much easier and more readable
You can use the Function DateFormat available in MYSQL.
select * FROM blog WHERE DATE_FORMAT(blog_dt,'%Y')='2014';
For more Date Related Functions visit URL
my table and fields are like these:
i must find $sy<year<$ey then it must filter only values by $sm<month<$em at last it must find $sd<day<$ed
i need to find records between dates for example like 2010/10/25 , 2010/10/10
at first i tried :
SELECT SUM(barname) allin,SUM(rooz) allhoghogh,user_id FROM work_result
WHERE (`year`>='$sy' and `month`>='$sm' and `day`>='$sd') and (`year`<='$ey' and `month`<='$em' and `day`<='$ed') group by user_id ;
but it cant find records for dates like e like 2010/10/25 , 2010/10/28
than i tried
SELECT * FROM work_result as t1 join work_result as t2 on t1.year<='$sy' and t2.year>='$ey' and t1.month<='$em' and t2.month>='$sm' and t1.day<='$ed' and t2.day>='$sd' WHERE 1 group by t1.wrid
this isnt usful in my case!
i need some thing like priority select first select all between years than month and than day!!
other way is convert mysql records to timestamp by year and month and day and compare it by input date but UNIX_TIMESTAMP('year-month-day 00:00:00') dont worked correct for me.
i used it like :
SELECT * FROM `work_result` WHERE UNIX_TIMESTAMP('year-month-day 00:00:00')>1238921453
If convert to timestamp didn't work for you what about use date_format to convert:
SELECT *
FROM `work_result`
WHERE date_format(concat(year,'-',month,'-',day), '%Y-%m-%d') >
DATE_FORMAT(FROM_UNIXTIME(`yourDateGoesHere`), '%Y-%m-%d')
my dates in my table are strings in the format:
"10/12/2009"
Now how would one get all the records from a month, lets say June (number "6" being provided)?
Check the MySQL function STR_TO_DATE.
You should not store dates as string, however. Use the type DATE.
The short answer to your question is that you can use the STR_TO_DATE and MONTH functions to 1) convert the string representation into a DATE, and 2) extract the month component from the date:
SELECT t.*
FROM mytable t
WHERE MONTH(STR_TO_DATE(t.dateasstringcol,'%M/%d/%Y')) = 6
(This is assuming here that by '10/12/2009', you are specifying Oct 12, and not Dec 10. You'd need to adjust the format string if that's not the case.)
Alternatively, if month is indeed the leading part of the date, you could do a simple string comparison, if the month is the leading component:
SELECT t.*
FROM mytable t
WHERE t.dateasstringcol LIKE '6/%'
OR t.dateasstringcol LIKE '06/%'
(You could eliminate one of those predicates, if you have an exact format specified for the striing value representing the date: either if month is always stored as two digits -OR- the month is never stored with a leading zero.)
If you are passing in an argument for the month, e.g. '6', then you could construct your statement something like this:
WHERE t.dateasstringcol LIKE '6' + '/%'
If month is the second component of the date, then you could use:
SELECT t.*
FROM mytable t
WHERE t.dateasstringcol LIKE '%/' + '6' + '/%'
OR t.dateasstringcol LIKE '%/' + '06' + /%'
NOTE:
All of the previous example queries will return rows for June of any year (2009, 2010, 2011)
You can extend those examples, and do something similar with the year, using the YEAR function in place of the MONTH function, or for string comparison
AND t.dateasstringcol LIKE '%/%/2011'
Normally, we'd extract rows for a particular month for a particular year, using a date range, for example:
SELECT t.*
FROM mytable t
WHERE MONTH(STR_TO_DATE(t.dateasstring,'%M/%d/%Y')) >= '2011-06-01'
AND MONTH(STR_TO_DATE(t.dateasstring,'%M/%d/%Y')) < '2011-07-01'
Of course, when the date value is stored as a DATE datatype rather than as a VARCHAR, this means we don't need the STR_TO_DATE and MONTH functions, we can specify a comparison to the native DATE column. This approach allows us to make use of an index on the date column, which can improve query performance on large tables.
SELECT t.*
FROM mytable t
WHERE t.realdatecol >= '2011-06-01'
AND t.realdatecol < '2011-07-01'
The STR_TO_DATE function is your friend here:
SELECT * FROM my_table
WHERE STR_TO_DATE('10/12/2009','%M/%d/%Y') >= '2012-06-01';
MONTH should help here if we want current month or particular month data. e.g:
$month = date('m'); OR particular month.
SELECT * FROM users WHERE MONTH(str_to_date("10/12/2009",'%e/%m/%Y')) = $month;