I have 2 tables, survey_product and survey_result table
survey_product looks like this:
id product
1 abc
2 asd
3 xyz
survey_result looks like this:
id user_id product_id answer
1 2 1 1
2 2 2 0
3 2 3 1
4 3 1 1
5 3 2 0
6 3 3 1
I need the result to be:
id user abc asd xyz .......
1 2 1 0 1
2 3 1 0 1
There is no easy way to do this in MySQL. You have to put case statement and convert them in to columns for all the users available.
select s.id,
case when s.user = 1 then answer else 0 end as 'abc',
...
...
from survey_result s
join user u on s.user = u.id
group by s.id
However you can simply export the result set as csv and do the necessary pivoting in an spreadsheet software like excel.
Related
Assume I have table count and the column is (nilai, id_courses, id_lecturer)
nilai id_courses id_lecturer
----- ---------- -----------
2 1 1
2 1 1
2 1 1
3 1 1
3 1 1
1 2 1
1 2 1
5 2 1
5 2 1
then I want to create view like this :
nilai id_courses id_lecturer count
----- ---------- ----------- -----
2 1 1 3
3 1 1 2
1 2 1 2
5 2 1 2
how to do that in SQL syntax?
I just know how to count 1 value with this code
SELECT COUNT( nilai ) , id_courses, id_lecturer FROM count where nilai=1
I've read this post but its to complex, so I don't know how it's work
You need to count all distinct entries by grouping them. The query
SELECT nilai, id_courses, id_lecturer, COUNT(*) AS count
FROM count GROUP BY nilai, id_courses, id_lecturer
should exactly return the table you posted.
I am stuck in query I have a table like this
budget_details
id budget_id expenditure_head_id budget
1 1 1 1233
2 1 2 333
3 1 3 567
4 2 1 343
5 2 2 343
6 2 3 6767
7 2 4 557
expenditure_heads
id name
1 abc
2 xyz
3 qwe
4 uvw
I want to get all the expenditure_heads from budget_details that even
if not in budget_details like here budget_id=1 does not contain expenditure_head_id 4
but I want to select that to with 0 or null displaying
I tried this but it not displaying expenditure_head_id 4
select `expenditure_heads`.`name`, `budget_details`.`budget`, `budget_details`.`id` from
`budget_details`
right join `expenditure_heads` on `budget_details`.`expenditure_head_id` = `expenditure_heads`.`id`
where `budget_details`.`budget_id` = 1"
The where avoid you to get the missing row you need. The left join is done on the ON statement, so this query should work for you:
SELECT EH.name, BD.budget, BD.id FROM expenditure_heads EH
LEFT JOIN budget_details BD
ON (BD.expenditure_head_id = EH.id AND BD.budget_id = 1)
I'm stuck with the following problem.
I have a website with for example supermarket shopping items. People can search the website for items.
Now I want on the search result page at the top 2 items to be displayed that I have selected to be on offer. There can be lots more items on offer.
So for example, someone would search for shampoo, the query would display all the shampoo items in the database table but I want just 2 shampoo offer items at the top of the query. There could be 2 or more shampoo offers in the database table, then the other would just not be shown.
Example with names :
Table:
id name C D
----------------------------------
1 Jack 1 1
2 Joe 1 1
3 Dave 3 0
4 Sue 1 0
5 Mike 1 1
6 Steve 4 0
7 David 1 0
8 Susan 4 1
9 Marc 1 1
10 Ronald 4 1
11 Michael 4 1
EXAMPLE 1
Query :
WHERE C = 1 AND D = 1 (But only maximum of 2 'D' records, these 2 'D' records show at the top of the result)
Desired Query Result :
id name C D
----------------------------------
1 Jack 1 1
2 Joe 1 1
4 Sue 1 0
7 David 1 0
EXAMPLE 2
Query :
WHERE C = 4 AND D = 1 (But only maximum of 2 'D' records, these 2 'D' records show at the top of the result)
Desired Query Result :
id name C D
----------------------------------
8 Susan 4 1
10 Ronald 4 1
6 Steve 4 0
I hope this explains my goal what I'm trying to achieve.
Many thanks for any help or suggestions!
That's two queries that you can combine with UNION ALL:
select * from mytable where c = 1 and d = 1 limit 2
union all
select * from mytable where c = 1 and d = 0
order by d desc;
UPDATE: If you want to have the two rows chosen randomly, then order by RAND(). (Without an ORDER BY the rows are chosen arbitrarily, which means it's not guaranteed to get the same two rows picked again when re-running the query ‐ but it's quite likely.) As we need an ORDER BY for a partial query (the first query in the complete union-alled query), we must use parentheses, because otherwise only one ORDER BY would be allowed, namely for the complete query at the query's end.
(select * from mytable where c = 1 and d = 1 order by rand() limit 2)
union all
(select * from mytable where c = 1 and d = 0)
order by d desc;
SQL fiddle: http://sqlfiddle.com/#!9/ed53f6/3.
I have this table:
ID STUDENT CLASS QUESTION ANSWER TIME
1 1 1 1 c 12:30
2 1 1 1 d 12:36
3 1 1 2 a 12:38
4 2 1 1 b 11:24
5 2 1 1 c 11:26
6 2 1 3 d 11:35
7 2 3 3 b 11:24
I'm trying to write a query that does this:
For each STUDENT in a specific CLASS select the most recent ANSWER for each QUESTION.
So, choosing class "1" would return:
ID STUDENT CLASS QUESTION ANSWER TIME
2 1 1 1 d 12:36
3 1 1 2 a 12:38
5 2 1 1 c 11:26
6 2 1 3 d 11:35
I've tried various combinations of subqueries, joins, and grouping, but nothing is working. Any ideas?
You can use a sub-query to get most recent ANSWER per QUESTION, Then use this as a derived table and join back to the original table:
SELECT m.*
FROM mytable AS m
INNER JOIN (
SELECT STUDENT, QUESTION, MAX(`TIME`) AS mTime
FROM mytable
WHERE CLASS = 1
GROUP BY STUDENT, QUESTION
) AS d ON m.STUDENT = d.STUDENT AND m.QUESTION = d.QUESTION AND m.`TIME` = d.mTime
WHERE m.CLASS = 1
Demo here
I have two tables:
id category status
1 test 1
2 test1 1
3 test2 1
This is the group_master table.
groupid groupname groupmaster
1 yy 1
2 xx 1
3 yyyy 1
4 xrx 1
5 yy 2
6 xx 2
7 yyyy 2
8 xfgdrx 3
This is the membergroup table.
The group_master.id is same as in membergroup.groupmaster.That menas i want to get each row from first table and also want to get the count from second table
That means:
id category status Count
1 test 1 4
2 test1 1 3
3 test2 1 1
This is the result i want to get.
How can i do this in Cakephp with pagination ?
try this:
You need to JOIN both tables and do a GROUP BY
SELECT g.id,g.category,g.status,count(*) as Count
FROM group_master g
JOIN membergroup m
ON g.id=m.groupmaster
GROUP BY g.id,g.category,g.status
SQL Fiddle Demo