I need to write a query for finding the length of the word between value1 and value2. I tried the query below:
select * from table_name where LENGTH (column_name (BETWEEN 1 and 2) );
You can do it like this:
SELECT *
FROM table_name
WHERE LENGTH (column_name) BETWEEN 1 and 2;
The following will select all rows where col_name has a length between 1 and 5:
SELECT table_name.*,
LENGTH(col_name) AS len
FROM table_name
HAVING len
BETWEEN( 1 AND 5 );
You could also use CHAR_LENGTH() or CHARACTER_LENGTH() if needed. Please note that LENGTH() will give you the number of bytes the string occupies (when using multi-byte charsets at least).
Be sure you absolutely need EVERYTHING (i.e. *) from the table, though -- that's very rarely the case.
Related
I have a table with a few mudiumtext datatype columns. Now I need to find the longest word in each row, in terms of word LENGTH. Like below.
The text column is for storing product description (like a paragraph in general understanding). So the column has multiple words. And I need to find what is the longest word in the column.
I tried with union all, but word count in rows is dynamic.
select sum(len) from (
SELECT LENGTH(description) - LENGTH(REPLACE(description, ' ', '')) + 1 as len
FROM test.city
union all
SELECT LENGTH(name) - LENGTH(REPLACE(name, ' ', '')) + 1 as len
FROM test.city
) as tablen;
I would do it by sorting the list according to the length of the words and then pick up the first element:
SELECT * FROM TEST ORDER BY CHAR_LENGTH(name) DESC LIMIT 1;
And for calculating the length of the row you can use something like
SELECT *, CHAR_LENGTH(name) + CHAR_LENGTH(description) as len FROM TEST ORDER BY len DESC LIMIT 1;
Hope that will solve your problem if I correctly understood it
Using MySQL how can I query for all records that start with a certain letter ranging from one letter to another? For example I want to find all entries that have the first letter between a-f.
Matches:
Albert
Donald
Frank
Non Matches:
Sarah
Reba
Thomas
With numbers I can use
SELECT * FROM table WHERE id >= int AND id <= int
Or use the between statement. How can I do that using letters using the first letter of each word in the database?
You should be able to use a range here. To cover a through and including f, regardless of case, we can try:
SELECT *
FROM yourTable
WHERE (name >= 'a' AND name < 'g') OR (name >= 'A' AND name < 'G');
Demo
Note that this approach leaves open the possibility of MySQL being able to use an index which might exist on the name column.
As #John commented below, if you are not using a collation which is case sensitive, then we can simplify the above query to this:
SELECT *
FROM yourTable
WHERE name >= 'a' AND name < 'g';
You can use regular expression for this. Read more here: REGEX_LIKE(). The query you need will be like this:
MySQL 8.0
SELECT
*
FROM
<table_name>
WHERE
REGEXP_LIKE(<column_name>, '^[a-f]');
MySQL < 8.0
SELECT
*
FROM
<table_name>
WHERE
<column_name> REGEXP '^[a-f]';
This will match all register with starting with [a to f] range letters.
SELECT * FROM table ORDER BY string_length(column);
Is there a MySQL function to do this (of course instead of string_length)?
You are looking for CHAR_LENGTH() to get the number of characters in a string.
For multi-byte charsets LENGTH() will give you the number of bytes the string occupies, while CHAR_LENGTH() will return the number of characters.
SELECT * FROM table
ORDER BY LENGTH(column);
Documentation on the LENGTH() function, as well as all the other string functions, is available here.
Having a look at MySQL documentation for the string functions, we can also use CHAR_LENGTH() and CHARACTER_LENGTH() as well.
In my case I get data using mobile number length greater than 10 digits using the below query
SELECT * FROM table_name WHERE CHAR_LENGTH(mobile) > 10;
The function that I use to find the length of the string is length, used as follows:
SELECT * FROM table ORDER BY length(column);
I used this sentences to filter
SELECT table.field1, table.field2 FROM table WHERE length(field) > 10;
you can change 10 for other number that you want to filter.
select * from *tablename* where 1 having length(*fieldname*)=*fieldlength*
Example if you want to select from customer the entry's with a name shorter then 2 chars.
select * from customer where 1 **having length(name)<2**
How can I make a MySQL query asking for all the string fields in a column that have a particular length?
Thanks!
Use LENGTH() for checking length in bytes:
SELECT str FROM sometable WHERE LENGTH(str) = 5;
Or CHAR_LENGTH() for checking length in number of characters (useful for multi-byte strings):
SELECT str FROM sometable WHERE CHAR_LENGTH(str) = 5;
select *
from myTable
where length(myColumn) = 5
Is there any function like "strlen" in mysql?
Mysql does have a length function to return the length of a string.
so you could do something like.
select * from some_table where length(some_string) > 0;
You can do it with using LENGTH keyword
SELECT * FROM table WHERE LENGTH (name) > 150;
How to select one text column, which string length >0 ?
You could compare to the empty string:
SELECT yourcolumn
FROM yourtable
WHERE yourcolumn <> ''
The following query would do the job for you.
select length(your_text_column) from sample_table where length(some_column) > 0
For anyone who comes across this answer in Google, keep this in mind:
Actually, CHAR_LENGTH() should be a better choice. For multi-byte charsets LENGTH() will give you the number of bytes the string occupies, while CHAR_LENGTH() will return the number of characters
MySQL - How to select data by string length