lets says i have these variable:
$post_id = 222;
$IsLoggIn =2;
I have same column "post_id" name in five different tables.
I want to write an sql statement to check and see if there is a row with column name "post_id" whose value is equal to variable "$post_id" and delete that row
Note: Apart from the "public_feed_table", it is possible there could be no row with post_id equal to variable "$post_id" so the sql statement should check if there is a row before deleting.
I want a single sql statement that can do this job.
What I tried is below. Please help:
global $dbc_conn,
$public_feed_table,
$images_table,
$comments_table,
$rating_table,
$notification_table,
$IsLoggIn;
$sql = "DELETE
p,i,c,r,n
FROM
$public_feed_table p
LEFT JOIN
$images_table i,
$comments_table c,
$rating_table r,
$notification_table n
ON
i.post_id,
c.post_id,
r.post_id,
n.post_id=p.post_id
WHERE p.post_id='$post_id'
AND p.user_id='$IsLoggIn'
";
//query database
$query = mysqli_query($dbc_conn,$sql);
You join Syntax is worng. It must be:
$sql = "DELETE p,i,c,r,n
FROM
$public_feed_table p
LEFT JOIN
$images_table i ON
p.post_id = i.post_id
LEFT JOIN
$comments_table c ON
p.post_id = c.post_id
LEFT JOIN
$rating_table r ON
p.post_id = r.post_id
LEFT JOIN
$notification_table n ON
p.post_id=n.post_id
WHERE p.post_id='$post_id'
AND p.user_id='$IsLoggIn'
";
For more Information see: http://www.w3schools.com/sql/sql_join_left.asp
Your JOIN syntax is total weird. It rather should be
FROM
$public_feed_table p
LEFT JOIN
$images_table i ON i.col = p.col,
LEFT JOIN $comments_table c ON p.col = c.col,
** col is for example, substitute it with actual column name per your table schema
Related
I'm trying to join four tables together. The code works fine when I'm only comparing the EVENT_DATA and joining the PERSONA tables as I'm able to get the "Name" column from PERSONA (which doesn't exist in the EVENT_DATA table). However, one of the problems is that this "Name" column also exists in the CUSTOMCAR table, so I can only get one or the other. Additionally, when I tried adding the last join statement, the code wouldn't run at all.
If someone could please help me, that would be great!
$sql = "SELECT * FROM EVENT_DATA
LEFT JOIN PERSONA ON EVENT_DATA.personaId = PERSONA.ID
LEFT JOIN CUSTOMCAR ON CUSTOMCAR.ownedCarId = EVENT_DATA.carId
LEFT JOIN CARCLASSES ON CARCLASSES.store_name = CUSTOMCAR.name
WHERE (EVENT_DATA.EVENTID = '299')";
You should avoid * and use explicit columns list instead:
SELECT EVENT_DATA.personaId, ...
FROM EVENT_DATA
LEFT JOIN PERSONA ON EVENT_DATA.personaId = PERSONA.ID
LEFT JOIN CUSTOMCAR ON CUSTOMCAR.ownedCarId = EVENT_DATA.carId
LEFT JOIN CARCLASSES ON CARCLASSES.store_name = CUSTOMCAR.name
WHERE (EVENT_DATA.EVENTID = '299');
If you have same column name you need to to use aliasing:
SELECT ...
CUSTOMCAR.NAME AS c_name,
PERSONA.NAME AS p_name
...
You could also use Aliasing:
$sql = "SELECT ed.*,
pa.*,
cc.*,
ccs.*
FROM EVENT_DATA AS ed
LEFT JOIN PERSONA AS pa ON ed.personaId = pa.ID
LEFT JOIN CUSTOMCAR AS cc ON cc.ownedCarId = e.carId
LEFT JOIN CARCLASSES AS ccs ON ccs.store_name = cc.name
WHERE (ed.EVENTID = '299')";
Note: Although as suggested by #Lukasz, you should really avoid using wildcard (*), and provide an explicit list of columns in the SELECT clause.
I am trying to run the following query:
SELECT `aalv_test`.`aircraft`.*, `aalv_test`.`airports`.*, `aalv_test`.`bids`.*
FROM `bids`
LEFT JOIN `aalv_test`.`pilots` ON `bids`.`pid` = `pilots`.`id`
LEFT JOIN `aalv_test`.`schedules` ON `bids`.`fid` = `schedules`.`id`
LEFT JOIN `aalv_test`.`aircraft` ON `schedules`.`aircraft` = `aircraft`.`id`
LEFT JOIN `aalv_test`.`airports` AS `arr` ON `schedules`.`arricao` = `arr`.`icao`
LEFT JOIN `aalv_test`.`airports` AS `dep` ON `schedules`.`depicao` = `dep`.`icao`
WHERE `pilots`.`id` = 419
However,
MYSQL returns error #1051 - Table airports does not exist.
I don't know what the issue is and Google hasn't helped. Any ideas? Also, if I only use one alias, I only get one airport but I need both. And the data is only in the table airports which according to this query, does not exist. Also, if I try throwing an AS section in the SELECT clause, I get error 1064: syntax error near AS.
EDIT: Database name is aalv_test, the .* at the end specifies to use all fields in the table, and the middle part is the table name, yes I am chaining fields.
Try this:
SELECT a.*, arr.*, dep.*, b.*
FROM bids AS b
LEFT JOIN aalv_test.pilots AS p ON b.pid = p.id
LEFT JOIN aalv_test.schedules AS s ON b.fid = s.id
LEFT JOIN aalv_test.aircraft AS a ON s.aircraft = a.id
LEFT JOIN aalv_test.airports AS arr ON s.arricao = arr.icao
LEFT JOIN aalv_test.airports AS dep ON s.depicao = dep.icao
WHERE p.id = 419;
I hope you can help me again, thanks already for pointing me to the right direction with creating the check digit for the new IBAN in Germany. I am now trying to update our membership database with the newly calculated BIC and IBAN but seem to have a problem with the UPDATE statement on the MariaDB MySQL database, despite the fact that I think I got the syntax right.
All I am trying to do is set the two fields "konto_bic" and "konto_iban" in the table "mitglieder" from the SELECT statement which creates a temporary table called b with the columns "id", "bic" and "iban". The "id" is the same in the two tables.
Here is my first try:
update a
set a.`konto_bic` = b.`BIC`, a.`konto_iban` = b.`IBAN`
from `mitglieder` a
INNER JOIN (SELECT m.`id`, m.`nachname`, m.`vorname`, m.`konto_bank`, m.`konto_blz`, m.`konto_nummer`, k.`bic` AS 'BIC', CONCAT('DE',LPAD(98-MOD(CONVERT(CONCAT(m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0'),'1314','00'), decimal(24)),97),2,'0'),m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0')) AS 'IBAN'
FROM `mitglieder` m
LEFT JOIN `konvert_bic_blz` k
ON m.`konto_blz` = k.`blz`
ORDER BY m.`nachname`, m.`vorname`) b
ON a.`id` = b.`id`
However, this produced an error and I tried this instead:
update `mitglieder` a
set a.`konto_bic` = b.`bic`, a.`konto_iban` = b.`iban`
FROM (SELECT m.`id` as 'id', k.`bic` as 'bic', CONCAT('DE',LPAD(98-MOD(CONVERT(CONCAT(m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0'),'1314','00'), decimal(24)),97),2,'0'),m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0')) AS 'iban'
FROM `mitglieder` m
LEFT JOIN `konvert_bic_blz` k
ON m.`konto_blz` = k.`blz`) b
WHERE a.`id` = b.`id`
That also did not get me any further (error from DB).
Can anyone see what my syntax error might be?
Thank you in advance for your help
Stephan
Try below SQL
UPDATE `mitglieder` a,
(SELECT m.`id` AS 'id',
k.`bic` AS 'bic',
CONCAT('DE',LPAD(98-MOD(CONVERT(CONCAT(m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0'),'1314','00'), decimal(24)),97),2,'0'),m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0')) AS 'iban'
FROM `mitglieder` m
LEFT JOIN `konvert_bic_blz` k ON m.`konto_blz` = k.`blz`) b
SET a.`konto_bic` = b.`bic`, a.`konto_iban` = b.`iban`
WHERE a.`id` = b.`id`
UPDATE Syntax
http://dev.mysql.com/doc/refman/5.0/en/update.html
I tried this on MariaDB 10.2.6 :
SET sql_mode = 'ANSI_QUOTES'
UPDATE "test"."user" AS "a"
INNER JOIN "test"."user_profile" AS "c" ON "c".user_id = "a".id
INNER JOIN "test"."profile" AS "d" ON "d".id = "c".profile_id
SET "a".firstname = 'laurent'
WHERE "a".id = 3;
And it works :)
So I have the following table, do_stock_movement, that looks like this:
stock_movement_id sm_number sm_source_id sm_destination_id
15164b86a7533d 145 1516478840ee29 151644d8bd63f2
15166b89d1a9fc 194 15165c481bd9d0 151659e632cd48
The columns sm_source_id and sm_destination_id both reference product points stored in do_product_points.
I'm using the following SQL query:
SELECT * FROM do_stock_movement
INNER JOIN do_product_points ON product_points_id = sm_source_id
WHERE sm_number = '145'
In do_product_points, there's a field called pp_name. I need the corresponding pp_name for both sm_source_id and sm_destination_id.
However, the query above will only return the pp_name for sm_source_id, or for sm_destination_id if you change the joined field to that.
What SQL query will return the corresponding pp_name for both sm_source_id and sm_destination_id?
I hope this is clear. Please ask questions if it isn't!
JOIN this table do_product_points one more times for the sm_destination_id:
SELECT
s.pp_name AS SourcePoint,
d.pp_name AS DestinationPoint,
...
FROM do_stock_movement AS m
INNER JOIN do_product_points s ON s.product_points_id = m.sm_source_id
INNER JOIN do_product_points d ON d.product_points_id = m.sm_destination_id
WHERE m.sm_number = '145'
You need join twice and use alias:
SELECT *, Src.pp_name, Dst.pp_name FROM do_stock_movement
INNER JOIN do_product_points as Src
ON Src.product_points_id = sm_source_id
INNER JOIN do_product_points as Dst
ON Dst.product_points_id = sm_destination_id
You need to join to the product_points table twice, once with source_id and once with destination_id:
SELECT * FROM do_stock_movement move
INNER JOIN do_product_points source ON source.product_points_id = move.sm_source_id
INNER JOIN do_product_points dest ON dest.product_points_id = move.sm_destination_id
WHERE sm_number = '145'
I have the below SQL statement. What I would like to do is include an IF statement to cover the possibility of one of the columns returning a 0 or blank result, there are no 0 ID's. In this case, I'm trying to cover the possibility of the magez_cfv_nations result possibly returning a zero or blank result.
SELECT c.clan_name, n.nation_name,
CONCAT(r.rarity_shorthand, " - ", r.rarity_name) AS rarity_text,
t.trigger_name, s.skill_name
FROM `magez_cfv_cards` AS cards
JOIN `magez_cfv_clans` c ON cards.clan_id = c.clan_id
JOIN `magez_cfv_nations` n ON cards.nation_id = n.nation_id
JOIN `magez_cfv_rarity` r ON cards.rarity_id = r.rarity_id
JOIN `magez_cfv_trigger` t ON cards.trigger_id = t.trigger_id
JOIN `magez_cfv_skills` s ON cards.skill_id = s.skill_id
You need a LEFT JOIN
The LEFT JOIN keyword returns all rows from the left table
(table_name1), even if there are no matches in the right table
Try this
SELECT c.clan_name, n.nation_name,
CONCAT(r.rarity_shorthand, " - ", r.rarity_name) AS rarity_text,
t.trigger_name, s.skill_name
FROM `magez_cfv_cards` AS cards
JOIN `magez_cfv_clans` c ON cards.clan_id = c.clan_id
LEFT JOIN `magez_cfv_nations` n ON cards.nation_id = n.nation_id
JOIN `magez_cfv_rarity` r ON cards.rarity_id = r.rarity_id
JOIN `magez_cfv_trigger` t ON cards.trigger_id = t.trigger_id
JOIN `magez_cfv_skills` s ON cards.skill_id = s.skill_id
the function you should use is IIF() and its syntax is
IIF([condition],[if true],[if false])