MultiColumn where IN in mysql - mysql

I am running a query like this -
UPDATE table
SET eligible=1
where (name, age) in [["john",29],["mark",28],["jim",20]]
table structure is like this
name age eligible
mark 28 null
john 29 null
Max 20 null
But mysql throws the wrong syntax error, can anyone confirm that this is allowed in mysql?

SELECT * FROM my_table ORDER BY id LIMIT 10;
+----+-------+--------+
| id | type | count |
+----+-------+--------+
| 1 | green | 4 |
| 2 | blue | 3 |
| 3 | blue | 443792 |
| 4 | green | 455353 |
| 5 | blue | 445389 |
| 6 | blue | 360885 |
| 7 | green | 468258 |
| 8 | red | 258636 |
| 9 | blue | 388405 |
| 10 | green | 166117 |
+----+-------+--------+
SELECT *
FROM my_table
WHERE (type,count) IN (('red',1000),('green',2000),('blue',3000)) ORDER BY id LIMIT 100
-> ;
+--------+-------+-------+
| id | type | count |
+--------+-------+-------+
| 137339 | blue | 3000 |
| 339554 | red | 1000 |
| 947445 | green | 2000 |
+--------+-------+-------+
Note that MySQL can have problems utilising indexes when using this method. For that reason, it can prove more efficient to write the query out 'long-hand'.

If you're on an older version of MySQL, or an alternative way is to separate out the where statements:
UPDATE table
SET eligible=1
WHERE
(name = "john" AND age = 29) OR
(name = "mark" AND age = 28) OR
(name = "jim" AND age = 20)

Related

How to make a pivot table by multiple unique ID numbers?

I'm trying to break up a SQL table that needs to take a users name and find the unique user ID's from up to 4 systems.
The data is currently like this:
| Name | User_ID |
-----------------
| A | 10 |
| A | 110 |
| A | 1500 |
| A | 4 |
| B | 20 |
| B | 100 |
| B | 2 |
| C | 10 |
I need to pivot it around the user's name to look like this (the id's don't need to be in numerical order as the SYS#_ID for each doesn't matter):
| Name | SYS1_ID | SYS2_ID | SYS3_ID | SYS4_ID |
------------------------------------------------
| A | 4 | 10 | 110 | 1500 |
| B | 2 | 20 | 100 | NULL |
| C | 10 | NULL | NULL | NULL |
This is the code I have tried on MySQL:
PIVOT(
COUNT(User_ID)
FOR Name
IN (SYS1_ID, SYS2_ID, SYS3_ID, SYS4_ID)
)
AS PivotedUsers
ORDER BY PivotedUsers.User_Name;
I'm unsure if PIVOT works on MySQL as I keep getting an error "PIVOT unknown". Is there a way to find the values that each user has and if they do not appear in the table already add them to the next column with a max of 4 values?

ORDER BY - Identical values

Here is a table structure example:
// tablename
+----+------+---------+
| id | numb | color |
+----+------+---------+
| 1 | 4 | green |
| 2 | 4 | yellow |
| 3 | 3 | red |
+----+------+---------+
Here is a query example:
SELECT id, numb, color FROM tablename ORDER BY numb asc
The result will be:
+----+------+---------+
| id | numb | color |
+----+------+---------+
| 3 | 3 | red |
| 1 | 4 | green |
| 2 | 4 | yellow |
+----+------+---------+
Now, my focus is on the order of these rows:
| 3 | 4 | green |
| 2 | 4 | yellow |
Because their numb values are equal, Now I want to know, for several executing that query, they will be constant? (Is order guaranteed for the identical values?) Or there isn't any guarantee and I should use another column name in the query like this ORDER BY numb, id asc ?
Short answer: No, there is no guarantee. (as #Strawberry wrote under the question)
Full answer: You can add a new column named sort_identical, And fill it whatever you like. And then use this:
... ORDER BY numb, sort_identical asc
(Also you can use id instead of creating a new column - But if you need to sort it differently than id, then create a new column)
+----+------+---------+----------------+
| id | numb | color | sort_identical |
+----+------+---------+----------------+
| 3 | 3 | red | 1 |
| 1 | 4 | green | 2 |
| 2 | 4 | yellow | 3 |
+----+------+---------+----------------+

Big Mysql Query (Join counts in the result and modify a string)

I am brand new to mysql so please excuse my level of knowledge here, and feel free to direct me in a better direction if what I am doing is out of date.
I am pulling information from a database to fill in a php page.
My tables:
Server:
|ServerID (int) | ArticleID (int) | locationID (int) |
| 1 | 46 | 55 |
| 2 | 11 | 81 |
| 3 | 81 | 46 |
| 4 | 55 | 11 |
| 5 | 81 | 99 |
| 5 | 11 | 52 |
Article:
|ArticleID (int) | Name (varchar) | Typ (int) |
| 46 | domain | 0 |
| 81 | root-server | 1 |
| 55 | vserver | 2 |
| 11 | root-server2 | 1 |
Location:
|LocationID (int) | location (varchar) |
| 46 | 1-5-15-2 |
| 81 | 1-5-14-2 |
| 55 | 2-25-1-9 |
| 11 | 21-2-5-8 |
| 99 | 17-2-5-8 |
| 52 | 1-8-5-8 |
Result:
|location (int) | name (varchar) | count (int) |
| 1 | root-server | 1 |
| 1 | root-server2 | 2 |
| 17 | root-server | 1 |
The location in the result is the first number block of the location in the location table (1-5-15-2 -> 1, 1-8-5-8 -> 1, 21-2-5-8 -> 21, 17-2-5-8 -> 17).
The count is the sum of all servers with the same name and the same first location block.
Do anyone think its possible to get this result in only one query?
Thanks for any answer!
Check this
SELECT SUBSTRING_INDEX(location, '-', 1) as LID,Article.Name,Count(*) as Count
from Location join Server
on Server.locationID=Location.locationID
join Article on Article.ArticleID=Server.ArticleID
group by LID,Article.ArticleID ;
DEMO
Please give this a shot:
SELECT
s.locationID as id, a.name, count(*) as count
FROM
`Server` s
LEFT JOIN
`Article` a ON s.ArticleID = a.ArticleID
GROUP BY s.locationID, a.name
something like this should work
select
s.location_id as location, a.name, count(location) as count
from
server as s, article as a
where
s.articleID = a.articleID
group by location, a.name

Subtract values from line above the current line in MySQL

I've the following table:
| id | Name | Date of Birth | Date of Death | Result |
| 1 | John | 3546565 | 3548987 | |
| 2 | Mary | 5233654 | 5265458 | |
| 3 | Lewis| 6546876 | 6548752 | |
| 4 | Mark | 6546546 | 6767767 | |
| 5 | Steve| 6546877 | 6548798 | |
And I need to do this for the whole table:
Result = 1, if( current_row(Date of Birth) - row_above_current_row(Date of Death))>X else 0
To make things easier, I guess, I created the same table above but with 2 extra id fields: id_minus_one and id_plus_one
Like this:
| id | id_minus_one | id_plus_one |Name | Date_of_Birth | Date_of_Death | Result |
| 1 | 0 | 2 |John | 3546565 | 3548987 | |
| 2 | 1 | 3 |Mary | 5233654 | 5265458 | |
| 3 | 2 | 4 |Lewis| 6546876 | 6548752 | |
| 4 | 3 | 5 |Mark | 6546546 | 6767767 | |
| 5 | 4 | 6 |Steve| 6546877 | 6548798 | |
So my approach would be something like (in pseudo code):
for id=1, ignore result. (Because there is no row above)
for id=2, Result = 1 if( (Where id=2).Date_of_Birth - (where id_minus_one=id-1).Date_of_Death )>X else 0
for id=3, Result = 1 if( (Where id=3).Date_of_Birth - (where id_minus_one=id-1).Date_of_Death)>X else 0
and so on for the whole table...
Just ignore id_plus_one if there is no need for it, I'll use it later for the same thing. So, if I manage to do this for id_minus_one I'll manage for id_plus_one as they are the same algorithm.
My question is how to pass that pseudo code into SQL code, I can't find a way to relate both ids in just one select.
Thank you!
As you describe this, it is just a self join with some logic on the select:
select t.*,
((t.date_of_birth - tprev.date_of_death) > x) as flag
from t left outer join
t tprev
on t.id_minus_one = tprev.id

MYSQL - how to string comparisons and query?

+--------------------+---------------+------+-----+---------+-------+
| ID | GKEY |GOODS | PRI | COUNTRY | Extra |
+--------------------+---------------+------+-----+---------+-------+
| 1 | BOOK-1 | 1 | 10 | | |
| 2 | PHONE-1 | 2 | 12 | | |
| 3 | BOOK-2 | 1 | 13 | | |
| 4 | BOOK-3 | 1 | 10 | | |
| 5 | PHONE-2 | 2 | 10 | | |
| 6 | PHONE-3 | 2 | 20 | | |
| 7 | BOOK-10 | 2 | 20 | | |
| 8 | BOOK-11 | 2 | 20 | | |
| 9 | BOOK-20 | 2 | 20 | | |
| 10 | BOOK-21 | 2 | 20 | | |
| 11 | PHONE-30 | 2 | 20 | | |
+--------------------+---------------+------+-----+---------+-------+
Above is my table. I want to get all records which GKEY > BOOK-2, Who can tell me the expression with mysql?
Using " WHERE GKEY>'BOOK-2' " Cannot get the correct results.
How about (something like):
(this is MSSQL - I guess it will be similar in MySQL)
select
*
from
(
select
*,
index = convert(int,replace(GKEY,'BOOK-',''))
from table
where
GKEY like 'BOOK%'
) sub
where
sub.index > 2
By way of explanation: The inner query basically recreates your table, but only for BOOK rows, and with an extra column containing the index in the right data type to make a greater than comparison work numerically.
Alternatively something like this:
select
*
from table
where
(
case
when GKEY like 'BOOK%' then
case when convert(int,replace(GKEY,'BOOK-','')) > 2 then 1
else 0
end
else 0
end
) = 1
Essentially the problem is that you need to check for BOOK before you turn the index into a numberic, as the other values of GKEY would create an error (without doing some clunky string handling).
SELECT * FROM `table` AS `t1` WHERE `t1`.`id` > (SELECT `id` FROM `table` AS `t2` WHERE `t2`.`GKEY`='BOOK-2' LIMIT 1)