SQL: Linking Two Tables - mysql

Let me start my saying I have the following two tables:
Fixtures Table:
| straightred_fixture | CREATE TABLE `straightred_fixture` (
`fixtureid` int(11) NOT NULL,
`hometeamscore` int(11) DEFAULT NULL,
`awayteamscore` int(11) DEFAULT NULL,
`homegoaldetails` longtext,
`awaygoaldetails` longtext,
`awayteamid` int(11) NOT NULL,
`hometeamid` int(11) NOT NULL,
PRIMARY KEY (`fixtureid`),
KEY `straightred_fixture_2e879a39` (`awayteamid`),
KEY `straightred_fixture_bcb6decb` (`hometeamid`),
KEY `straightred_fixture_d6d641f1` (`soccerseasonid`),
KEY `straightred_fixture_fixturematchday2_f98c3a75_uniq` (`fixturematchday`),
CONSTRAINT `D9b896edf0aff4d9b5c00682a8e21ea3` FOREIGN KEY (`fixturematchday`) REFERENCES `straightred_fixturematchday` (`fixturematchdayid`),
CONSTRAINT `straightr_soccerseasonid_92496b92_fk_straightred_season_seasonid` FOREIGN KEY (`soccerseasonid`) REFERENCES `straightred_season` (`seasonid`),
CONSTRAINT `straightred_fixtu_awayteamid_3d1961ba_fk_straightred_team_teamid` FOREIGN KEY (`awayteamid`) REFERENCES `straightred_team` (`teamid`),
CONSTRAINT `straightred_fixtu_hometeamid_6e37e94b_fk_straightred_team_teamid` FOREIGN KEY (`hometeamid`) REFERENCES `straightred_team` (`teamid`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 |
Team Table:
| straightred_team | CREATE TABLE `straightred_team` (
`teamid` int(11) NOT NULL,
`teamname` varchar(36) NOT NULL,
`country` varchar(36) DEFAULT NULL,
`stadium` varchar(36) DEFAULT NULL,
`homepageurl` longtext,
`wikilink` longtext,
`teamcode` varchar(5) DEFAULT NULL,
`teamshortname` varchar(24) DEFAULT NULL,
`currentteam` smallint(5) unsigned DEFAULT NULL,
PRIMARY KEY (`teamid`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 |
The Query::
select hometeamid as team, awayteamid as opponent, hometeamscore as team_score, awayteamscore as opponent_score,
(case when (hometeamscore-awayteamscore)>0 then 'W' when (hometeamscore-awayteamscore)<0 then 'L' ELSE 'D' END) as result, 'home' as mstatus
from straightred_fixture sf, straightred_team st;
What I want to do is return the team name rather than the id of the teams in the query above. I realize some sort of join is required but I am getting myself in a right muddle.

You need to join on the teams table twice, once for the home team and once for the away team:
SELECT home.teamname AS team,
away.teamname AS opponent,
hometeamscore AS team_score,
awayteamscore AS opponent_score,
CASE WHEN (hometeamscore - awayteamscore) > 0 then 'W'
WHEN (hometeamscore - awayteamscore) < 0 then 'L'
ELSE 'D'
END AS result,
'home' AS mstatus
FROM straightred_fixture sf
JOIN straightred_team home ON hometeamid = home.teamid
JOIN straightred_team away ON awayteamid = away.teamid

My suggestion based on my experience is probably one you won't like (I'm including it as an answer because a comment was too long.
In my opinion/experience here is what you need to do. You need to break up the fixtures table.
The fixtures table should have the information that is specific to the fixture itself (date, time, perhaps other specific information)
A related table can be called fixture_participants and includes the team information - each fixture has two rows in fixture participants.
In my solution, I created a column for 'home/away' represented by H/A and wins/losses represented by W/L (integers might be a better solution now that I think about it). I'm thinking this is european football so you should include a column for goals scored.
So you can now easily identify home and away teams you just have to write slightly more involved queries but you can also say 'what is the average goals scored by team A on the road' much more easily.
PS - if you need a sample of what i'm talking about this repository builds a similar table relationship for USA Basketball

Related

Mysql query to get hotel room availability

I'm implementing a booking platform I have 3 tables:
"hotel" - to hold the hotel information
"hotel_room" - to hold room info per hotel
"hotel_room_price" - have the availability by date, number of rooms available and price
I want to search by start date and end date, local and number of rooms (each room have the number of adults and number of child)
Here is some example of my tables:
CREATE TABLE `hotel` (
`id` int(11) NOT NULL,
`name` varchar(255) NOT NULL,
`rating` smallint(6) NOT NULL DEFAULT '3' COMMENT '0 - Not Rated | 1 - One Star | 2 - Two Stars | 3 - Three Stars | 4 - Four Stars | 5 - Five Stars',
`local` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE `hotel_room` (
`id` int(11) NOT NULL,
`hotel_id` int(11) NOT NULL,
`name` varchar(255) NOT NULL,
`max_capacity_adult` smallint(6) NOT NULL,
`max_capacity_child` smallint(6) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
ALTER TABLE `hotel_room` ADD CONSTRAINT `fk_hotel_room_hotel_id` FOREIGN KEY (`hotel_id`) REFERENCES `hotel` (`id`) ON DELETE CASCADE;
CREATE TABLE `hotel_room_price` (
`id` int(11) NOT NULL,
`hotel_room_id` int(11) NOT NULL,
`price_adult` decimal(20,2) DEFAULT NULL,
`price_child` decimal(20,2) DEFAULT NULL,
`quantity` int(11) NOT NULL DEFAULT '1' COMMENT 'available rooms, 0 if there is no more available',
`date` date NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
ALTER TABLE `hotel_room_price` ADD CONSTRAINT `fk_hotel_room_price_hotel_room_id` FOREIGN KEY (`hotel_room_id`) REFERENCES `hotel_room` (`id`) ON DELETE CASCADE;
What is the better approach get the available rooms when a user search, one note it is possible to search for multiple rooms for example:
start_date = 2019-06-25
end_date = 2019-06-29
local = "Tomar"
Room=[
[
nr_adults = 2,
nr_children=1
],
[
nr_adults = 4,
nr_children=0
]
]
I think first thing to do it check only hotels from the right local then check if the room can hold the number of adults and children if yes check for availability.
I'm with lot of problems to create a query or multiple queries to handle this in the right way.
You can check and example of my database here http://sqlfiddle.com/#!9/458be2c
Here is query that selects all room ID's available in a given time frame. In this instance I picked June 26- June 28. This should be a good starting point for the rest of the query.
SELECT hotel_room_id
FROM hotel_room_price
WHERE date between '2019-06-26' AND '2019-06-28'
AND quantity > 0
GROUP BY hotel_room_id
HAVING COUNT(*) > DATEDIFF('2019-06-28', '2019-06-26')
Here is a somewhat hacky query to get some of the information about the rooms. Note there is not functionality for searching for multiple rooms in this sample:
SELECT h.name AS Name, h.rating AS Rating, sq.name AS Type
FROM hotel h
INNER JOIN
(SELECT *
FROM hotel_room
WHERE hotel_room.id IN
(SELECT hotel_room_id
FROM hotel_room_price
WHERE date between '[START DATE]' AND '[END DATE]'
AND quantity > 0
GROUP BY hotel_room_id
HAVING COUNT(*) > DATEDIFF('[END DATE]', '[START DATE]'))
AND max_capacity_child >= [CHILD COUNT]
AND max_capacity_adult >= [ADULT COUNT]) sq
ON h.id = sq.hotel_id
WHERE h.local = "[LOCATION]"

MySQL UNIQUE key not working

I am building as type on inventory table that keeps track of stock by 6 different factors. I am using an I query much like this one:
INSERT INTO inventory ( productid, factor1, factor2, factor3, factor4, factor5, factor6, quantity, serial_number)
VALUES (242332,1,1,1,'V67',3.30,'NEW',10,NULL)
ON DUPLICATE KEY UPDATE `quantity` = VALUES(`quantity`) + quantity;
The inventory table has a UNIQUE KEY for ( productid, factor1, factor2, factor3, factor4, factor5, factor6, serial_number ). For some reason, it is not picking up on the key and just INSERTing instead of UPDATEing. Can anyone offer an explanation why? What am I missing?
Here is the table create statement:
CREATE TABLE `inventory` (
`stockid` int(11) unsigned NOT NULL AUTO_INCREMENT,
`productid` int(11) unsigned NOT NULL,
`factor1` int(11) unsigned NOT NULL,
`factor2` int(11) unsigned NOT NULL,
`factor3` int(11) unsigned NOT NULL,
`factor4` varchar(8) NOT NULL,
`factor5` decimal(10,2) NOT NULL,
`factor6` enum('A','B','C','D','NEW') NOT NULL,
`quantity` int(11) NOT NULL,
`stamp` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`serial_number` varchar(11) DEFAULT NULL,
PRIMARY KEY (`stockid`),
UNIQUE KEY `serial_number` (`serial_number`),
UNIQUE KEY `productid_2` (`productid`,`factor1`,`factor2`,`factor3`,`factor4`,`factor5`,`factor6`,`serial_number`),
KEY `productid` (`productid`),
KEY `factor1` (`factor1`),
KEY `factor2` (`factor2`),
KEY `factor3` (`factor3`),
CONSTRAINT `books_stock_ibfk_2` FOREIGN KEY (`productid`) REFERENCES `produx_products` (`productid`),
CONSTRAINT `books_stock_ibfk_5` FOREIGN KEY (`factor1`) REFERENCES `table_factor1` (`factorid`),
CONSTRAINT `books_stock_ibfk_6` FOREIGN KEY (`factor2`) REFERENCES `table_factor2` (`factorid`),
CONSTRAINT `books_stock_ibfk_7` FOREIGN KEY (`factor3`) REFERENCES `table_factor3` (`factorid`)
)
ENGINE=InnoDB AUTO_INCREMENT=38 DEFAULT CHARSET=latin1
More in-depth:
The purpose of this table is to hold stock quantities. I think this is pretty straight forward. The factors that separate these quantities are as follows:
factor1 = storeid (the unique indentifier for the store that ownes this quantity).
factor2 = supplierid (the unique indentfier for the supplier that we got the quantity from)
factor3 = warehouseid (unique identifier for the warehouse where it resides)
factor4 = locationid (unique string for the location. Its physically painted on the shelf)
factor5 = cost (what we paid for each of the quantity)
factor6 = condition (enum ['NEW','USED','RENTAL','PREORDER']. The first three are easy, the fourth is for quantites we ordered, want to sell, but have not received it yet.)
I know this is a hefty key but I am forced to keep it this way. I have had many suggestion to move cost or condition to the product table. I cannot do this. The cost isn't always the same since we buy a lot from auctions or other places with very variable costs and conditions.
I hope this helps more to explain what I am trying to do.
Mysql allows multiple NULLs in an unique constraint.In your serial_number column replace NULL with a value and the constraint is triggered,see:
http://sqlfiddle.com/#!2/9dbd19/1
a UNIQUE index permits multiple NULL values for columns that can
contain NULL
Docs
Make the column NOT NULL and use '' which is empty.

SQL select entries in other table linked by foreign keys

I have redesigned my database structure to use PRIMARY and FOREIGN KEYs to link the entries in my 3 tables together, and I am having problems trying to write queries to select data in one table given data in a another table. Here is an example of my 3 CREATE TABLE statements:
CREATE TABLE IF NOT EXISTS players (
id INT(10) NOT NULL AUTO_INCREMENT,
username VARCHAR(16) NOT NULL,
uuid VARCHAR(200) NOT NULL DEFAULT 0,
joined TIMESTAMP DEFAULT 0,
last_seen TIMESTAMP DEFAULT 0,
PRIMARY KEY (id)
);
/* ^
One |
To
| One
v
*/
CREATE TABLE IF NOT EXISTS accounts (
id INT(10) NOT NULL AUTO_INCREMENT,
account_id INT(10) NOT NULL,
pass_hash VARCHAR(200) NOT NULL,
pass_salt VARCHAR(200) NOT NULL,
created BIGINT DEFAULT 0,
last_log_on BIGINT DEFAULT 0,
PRIMARY KEY (id),
FOREIGN KEY (account_id) REFERENCES players(id) ON DELETE CASCADE
) ENGINE=InnoDB;
/* ^
One |
To
| Many
v
*/
CREATE TABLE IF NOT EXISTS purchases (
id INT(10) NOT NULL AUTO_INCREMENT,
account_id INT(10) NOT NULL,
status VARCHAR(20) NOT NULL,
item INT NOT NULL,
price DOUBLE DEFAULT 0,
description VARCHAR(200) NOT NULL,
buyer_name VARCHAR(200) NOT NULL,
buyer_email VARCHAR(200) NOT NULL,
transaction_id VARCHAR(200) NOT NULL,
payment_type VARCHAR(20) NOT NULL,
PRIMARY KEY (id),
FOREIGN KEY (account_id) REFERENCES accounts(account_id) ON DELETE CASCADE
) ENGINE=InnoDB;
Say for example, I want to select all the usernames of users who purchased anything greater than $30. All the usernames are stored in the players table, which is linked to the accounts table and that is linked to the purchases table. Is this this the best way to design this relational database? If so, how would I run queries similar to the above example?
I was able to get get all of a users purchase history given their username, but I did it with 2 sub-queries... Getting that data should be easier than that!
Here is the SELECT query I ran to get all of a players purchase data:
SELECT *
FROM purchases
WHERE account_id = (SELECT id FROM accounts WHERE account_id = (SELECT id FROM players WHERE username = 'username'));
Also, when I try to make references to the other tables using something like 'players.username', I get an error saying that the column doesn't exist...
I appreciate any help! Thanks!
Your design is ok in my opinion. The relation between players and account is one-to-many and not one-to-one since this way, you can have two tuples referencing a single player.
I would write the query you need as:
SELECT DISTINCT p.id, p.username
FROM players p INNER JOIN accounts a ON (p.id = a.account_id)
INNER JOIN purchases pc ON (a.id = pc.account_id)
WHERE (pc.price > 30);
As Sam suggested, I added DISTINCT to avoid repeating id and username in case a user have multiple purchases.
Note the id is here to avoid confusion among repeated usernames.

mySql subtract row of different table

I want to subtract between two rows of different table:
I have created a view called leave_taken and table called leave_balance.
I want this result from both table:
leave_taken.COUNT(*) - leave_balance.balance
and group by leave_type_id_leave_type
Code of both table
-----------------View Leave_Taken-----------
CREATE ALGORITHM = UNDEFINED DEFINER=`1`#`localhost` SQL SECURITY DEFINER
VIEW `leave_taken`
AS
select
`leave`.`staff_leave_application_staff_id_staff` AS `staff_leave_application_staff_id_staff`,
`leave`.`leave_type_id_leave_type` AS `leave_type_id_leave_type`,
count(0) AS `COUNT(*)`
from
(
`leave`
join `staff` on((`staff`.`id_staff` = `leave`.`staff_leave_application_staff_id_staff`))
)
where (`leave`.`active` = 1)
group by `leave`.`leave_type_id_leave_type`;
----------------Table leave_balance----------
CREATE TABLE IF NOT EXISTS `leave_balance` (
`id_leave_balance` int(11) NOT NULL AUTO_INCREMENT,
`staff_id_staff` int(11) NOT NULL,
`leave_type_id_leave_type` int(11) NOT NULL,
`balance` int(3) NOT NULL,
`date_added` date NOT NULL,
PRIMARY KEY (`id_leave_balance`),
UNIQUE KEY `id_leave_balance_UNIQUE` (`id_leave_balance`),
KEY `fk_leave_balance_staff1` (`staff_id_staff`),
KEY `fk_leave_balance_leave_type1` (`leave_type_id_leave_type`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;
------- Table leave ----------
CREATE TABLE IF NOT EXISTS `leave` (
`id_leave` int(11) NOT NULL AUTO_INCREMENT,
`staff_leave_application_id_staff_leave_application` int(11) NOT NULL,
`staff_leave_application_staff_id_staff` int(11) NOT NULL,
`leave_type_id_leave_type` int(11) NOT NULL,
`date` date NOT NULL,
`active` int(11) NOT NULL DEFAULT '1',
`date_updated` date NOT NULL,
PRIMARY KEY (`id_leave`,`staff_leave_application_id_staff_leave_application`,`staff_leave_application_staff_id_staff`),
KEY `fk_table1_leave_type1` (`leave_type_id_leave_type`),
KEY `fk_table1_staff_leave_application1` (`staff_leave_application_id_staff_leave_application`,`staff_leave_application_staff_id_staff`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=32 ;
Well, I still don't think you've provided enough information. It would be very helpful to have some sample data and your expected output (in tabular format). That said, I may have something you can start working with. This query finds all staff members, calculates their current leave (grouped by type), and determines the difference between that and their balance by leave type. Take a look at it, and more importantly (perhaps) the sqlfiddle here that I used which has the sample data in it (very important to determining if this is the correct path for your data).
SELECT
staff.id_staff,
staff.name,
COUNT(`leave`.id_leave) AS leave_count,
leave_balance.balance,
(COUNT(`leave`.id_leave) - leave_balance.balance) AS leave_difference,
`leave`.leave_type_id_leave_type AS leave_type
FROM
staff
JOIN `leave` ON staff.id_staff = `leave`.staff_leave_application_staff_id_staff
JOIN leave_balance ON
(
staff.id_staff = leave_balance.staff_id_staff
AND `leave`.leave_type_id_leave_type = leave_balance.leave_type_id_leave_type
)
WHERE
`leave`.active = 1
GROUP BY
staff.id_staff, leave_type;
Good luck!

How to create relationships in MySQL

In class, we are all 'studying' databases, and everyone is using Access. Bored with this, I am trying to do what the rest of the class is doing, but with raw SQL commands with MySQL instead of using Access.
I have managed to create databases and tables, but now how do I make a relationship between two tables?
If I have my two tables like this:
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY ( account_id )
)
and
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
PRIMARY KEY ( customer_id )
)
How do I create a 'relationship' between the two tables? I want each account to be 'assigned' one customer_id (to indicate who owns it).
If the tables are innodb you can create it like this:
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY ( account_id ),
FOREIGN KEY (customer_id) REFERENCES customers(customer_id)
) ENGINE=INNODB;
You have to specify that the tables are innodb because myisam engine doesn't support foreign key. Look here for more info.
as ehogue said, put this in your CREATE TABLE
FOREIGN KEY (customer_id) REFERENCES customers(customer_id)
alternatively, if you already have the table created, use an ALTER TABLE command:
ALTER TABLE `accounts`
ADD CONSTRAINT `FK_myKey` FOREIGN KEY (`customer_id`) REFERENCES `customers` (`customer_id`) ON DELETE CASCADE ON UPDATE CASCADE;
One good way to start learning these commands is using the MySQL GUI Tools, which give you a more "visual" interface for working with your database. The real benefit to that (over Access's method), is that after designing your table via the GUI, it shows you the SQL it's going to run, and hence you can learn from that.
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY ( account_id )
)
and
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
)
How do I create a 'relationship' between the two tables? I want each account to be 'assigned' one customer_id (to indicate who owns it).
You have to ask yourself is this a 1 to 1 relationship or a 1 out of many relationship. That is, does every account have a customer and every customer have an account. Or will there be customers without accounts. Your question implies the latter.
If you want to have a strict 1 to 1 relationship, just merge the two tables.
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
)
In the other case, the correct way to create a relationship between two tables is to create a relationship table.
CREATE TABLE customersaccounts(
customer_id INT NOT NULL,
account_id INT NOT NULL,
PRIMARY KEY (customer_id, account_id),
FOREIGN KEY customer_id references customers (customer_id) on delete cascade,
FOREIGN KEY account_id references accounts (account_id) on delete cascade
}
Then if you have a customer_id and want the account info, you join on customersaccounts and accounts:
SELECT a.*
FROM customersaccounts ca
INNER JOIN accounts a ca.account_id=a.account_id
AND ca.customer_id=mycustomerid;
Because of indexing this will be blindingly quick.
You could also create a VIEW which gives you the effect of the combined customersaccounts table while keeping them separate
CREATE VIEW customeraccounts AS
SELECT a.*, c.* FROM customersaccounts ca
INNER JOIN accounts a ON ca.account_id=a.account_id
INNER JOIN customers c ON ca.customer_id=c.customer_id;
Adding onto the comment by ehogue, you should make the size of the keys on both tables match. Rather than
customer_id INT( 4 ) NOT NULL ,
make it
customer_id INT( 10 ) NOT NULL ,
and make sure your int column in the customers table is int(10) also.
Certain MySQL engines support foreign keys. For example, InnoDB can establish constraints based on foreign keys. If you try to delete an entry in one table that has dependents in another, the delete will fail.
If you are using a table type in MySQL, such as MyISAM, that doesn't support foreign keys, you don't link the tables anywhere except your diagrams and queries.
For example, in a query you link two tables in a select statement with a join:
SELECT a, b from table1 LEFT JOIN table2 USING (common_field);
Here are a couple of resources that will help get started: http://www.anchor.com.au/hosting/support/CreatingAQuickMySQLRelationalDatabase and http://code.tutsplus.com/articles/sql-for-beginners-part-3-database-relationships--net-8561
Also as others said, use a GUI - try downloading and installing Xampp (or Wamp) which run server-software (Apache and mySQL) on your computer.
Then when you navigate to //localhost in a browser, select PHPMyAdmin to start working with a mySQL database visually. As mentioned above, used innoDB to allow you to make relationships as you requested. Makes it heaps easier to see what you're doing with the database tables. Just remember to STOP Apache and mySQL services when finished - these can open up ports which can expose you to hacking/malicious threats.
One of the rules you have to know is that the table column you want to reference to has to be with the same data type as
The referencing table . 2 if you decide to use mysql you have to use InnoDB Engine because according to your question that’s the engine which supports what you want to achieve in mysql .
Bellow is the code try it though the first people to answer this question
they 100% provided great answers and please consider them all .
CREATE TABLE accounts(
account_id INT NOT NULL AUTO_INCREMENT,
customer_id INT( 4 ) NOT NULL ,
account_type ENUM( 'savings', 'credit' ) NOT NULL,
balance FLOAT( 9 ) NOT NULL,
PRIMARY KEY (account_id)
)ENGINE=InnoDB;
CREATE TABLE customers(
customer_id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(20) NOT NULL,
address VARCHAR(20) NOT NULL,
city VARCHAR(20) NOT NULL,
state VARCHAR(20) NOT NULL,
PRIMARY KEY ( account_id ),
FOREIGN KEY (customer_id) REFERENCES customers(customer_id)
)ENGINE=InnoDB;
create table departement(
dep_id int primary key auto_increment,
dep_name varchar(100) not null,
dep_descriptin text,
dep_photo varchar(100) not null,
dep_video varchar(300) not null
);
create table newsfeeds(
news_id int primary key auto_increment,
news_title varchar(200) not null,
news_description text,
news_photo varchar(300) ,
news_date varchar(30) not null,
news_video varchar(300),
news_comment varchar(200),
news_departement int foreign key(dep_id) references departement(dep_id)
);