I'm new for mysql, Already value in time field, I want to update extra 5 minutes in time field using query. I tried so many things but not working.
Here my query:
UPDATE STUDENT SET START_TIME = ADDTIME(START_TIME, 500) WHERE ID = 1;
Above query working but one issue is there that is, If my field having 23:55:00.
I want result after executing query 00:00:00 but it updates 24:00:00.
Anyone help me!
Thanks in advance!!
This is bit tricky, because you only have the time, and you want it to wrap around to 0 after hitting 24 hours. My approach is to extract the number of seconds from START_DATE, add 5 minutes, then take the mod of this by 24 hours to wrap around to zero if it exceeds one day's worth of seconds.
UPDATE STUDENT
SET START_TIME = CAST(STR_TO_DATE(CAST(MOD((TIME_TO_SEC(START_TIME) + 300), 86400) AS CHAR(5)), '%s') AS TIME)
WHERE ID = 1
In the demo below, you can see the logic in action which correctly converts 23:55:00 with five minutes added to become 00:00:00.
SQLFiddle
However, the easiest solution in your case might be to just use a DATETIME and ignore the date component. Then the time should wrap automatically to a new day.
select addtime('23:55:00', '00:06:00');
output - 24:01:00 (Ideally it is right, because time datatype represents only time, if it converts to 00:01:00 then time component looses 24hr, which is wrong)
select addtime('2016-09-01 23:55:00', '00:06:00');
output - 2016-09-02 00:01:00 (In this case, 24hr gets added in date so time component is represented as 00:01:00)
If the requirement is to get it as 00:01:00 then here is the workaround -
SELECT TIME((ADDTIME(TIME('23:59:59'), TIME('02:00:00')))%(TIME('24:00:00')));
reference -
ADDTIME() return 24 hour time
Related
I have a system where tablets perform tasks and report back with what tasks have been completed and when. One of the tablets has come out of sync and the time is 2 days, 3 hours, 31 mins and 31 secs behind, which is messing up my reporting.
Is there an easy way to add the missing time to the fields with a query?
I can identify which fields need to be altered as they are all tied to a single job, so can add WHERE job_id = 998 to the end.
I have had a look around, and can't really make sense of answers provided, and can't afford to mess up and insert the incorrect times.
Just for clarification, I basically have an event that the tablet believes happened at '2015-12-01 07:57:30' but actually happened at '2015-12-03 11:29:01'. I worked that one out manually, but I have over 100 rows that need updating. Something like: UPDATE job_logs SET entry_time = <CURRENT FIELD DATE> ADD <OUT OF SYNC TIME> WHERE job_id = 998;
Any answers are appreciated, additional detail would be preferred as I'm still learning & would like to understand how the solution works...
Thanks in advance!
You can use MySQL DATE_ADD() function, check this below given SELECT query with your <CURRENT FIELD DATE> field
SELECT <CURRENT FIELD DATE>,DATE_ADD(<CURRENT FIELD DATE>, INTERVAL '2 3:31:31' DAY_SECOND)
FROM job_logs
WHERE job_id = 998;
then you can use same in your UPDATE query as
UPDATE job_logs
SET entry_time = DATE_ADD(<CURRENT FIELD DATE>, INTERVAL '2 3:31:31' DAY_SECOND)
WHERE job_id = 998;
I hope this works...
there is no issue with adding date or time in a datetime filed in mysql
UPDATE job_logs SET entry_time = ADDTIME(entry_time , '1:2:3') WHERE job_id = 998
this will update your entry_time to 1 hour 2 min and 3 sec to existing entry_time.
I am looking for a way to be able to grab rows from a database from a time.
Two columns exist:
Time - scheduled Time
Delay - +seconds that time is delayed.
Let's say:
ID,time,delay
1,18:23,360
2,18:25,0
3,17:15,-60
Now, let's say I am searching for buses after actually arriving at/after 18:25, how would i do it to include these two results:
2,18:25,0
1,18:23,360 (note: 18:23 + 360 seconds = 18:29)
in a query like
where `time` >= '18:23'
Thanks
SELECT * FROM [TABLE] WHERE DATE_ADD(Time,INTERVAL TimeDelay SECOND) >= '18:25:00'
MySql Date_Add Function
SELECT *
FROM tablename
WHERE
MAKETIME(3,0,0) BETWEEN MAKETIME(23,0,0) AND MAKETIME(5,0,0)
is returning nothing And 3:00 is between 23:00 AND 5:00 time. Why is that can anyone explain me how to solve this problem?
It's unclear what you're actually trying to do here, because even if 3 were between 5 and 23 your query would simply return every record in the table.
SELECT MAKETIME(3,0,0) BETWEEN MAKETIME(5,0,0) AND MAKETIME(23,0,0)
Returns 0, because 3 is not between 5 and 23.
SELECT MAKETIME(5,0,0) BETWEEN MAKETIME(3,0,0) AND MAKETIME(23,0,0)
Returns 1, because 5 is between 3 and 23.
Demo: SQL Fiddle
Presumably you're trying to wrap into the previous day, in which case you can directly compare datetime values, but it's unclear given your question what fields/datatypes you're actually working with.
Update:
Based on your comment, I think you want 2 comparisons. 3 is not between 5 and 23, because time doesn't wrap across days. But if you only care about the time portion you can handle it like this:
SELECT *
FROM tablename
WHERE YourTime BETWEEN MAKETIME(23,0,0) AND MAKETIME(23,59,59)
OR YourTime BETWEEN MAKETIME(0,0,0) AND MAKETIME(5,0,0)
Remember that BETWEEN is inclusive, so if 5am is your cutoff time you may want it to be MAKETIME(4,59,59) so it includes 4:59 but not 5:00
Function MAKETIME returns a time value calculated from the hour, minute, and second arguments:
mysql> SELECT MAKETIME(3,0,0),MAKETIME(23,0,0),MAKETIME(5,0,0)
-> '03:00:00', '23:00:00', '05:00:00'
and, of course, 3 is not BETWEEN 23 AND 5 and it will return false. But yes, 3AM actually is between 11PM and 5AM, so how could you solve this?
Let's consider 23 as your START_TIME, and 5 as your END_TIME.
Since START_TIME has to happen before END_TIME, if this is not the case (23>5) that means that the interval rolls over the next day.
I would try with a query like this:
SELECT *
FROM yourtable
WHERE
(MAKETIME(START_TIME,0,0)<=MAKETIME(END_TIME,0,0) AND MAKETIME(3,0,0) BETWEEN MAKETIME(START_TIME,0,0) AND MAKETIME(END_TIME,0,0))
OR
(MAKETIME(START_TIME,0,0)>MAKETIME(END_TIME,0,0) AND NOT (MAKETIME(3,0,0) BETWEEN MAKETIME(START_TIME,0,0) AND MAKETIME(END_TIME,0,0)))
I'm in need of a method to store a time duration in a db field. I'm building a website where customers should be able to choose how long they would like an advert to display from a particular start date.
I had thought about using TIME but that has a max of '838:59:59' which works out at about 34 days. Its possible that a client would want an advert to exist for longer than that.
So what would be the best way to deal with this? Just a really large INT?
If you intend to have a column for start time and one for duration, I think you can store it in seconds. So, I assume you will have something like this;
+-----------+--------------------------+------------------+
| advert_id | start_time | duration_seconds |
+-----------+--------------------------+------------------+
| 2342342 |'2012-11-12 10:23:03' | 86400 |
+-----------+--------------------------+------------------+
(For the sake of the example, we will call this table adverts)
advert_id - a key pointing to your advert
start_time - the time the advert should start (data type - TIMESTAMP)
duration_seconds - Time in seconds that the advert is supposed to "live" (INTEGER(11)
SELECT TIME_TO_SEC(timediff(now(),start_time)) as 'time_difference_in_seconds_since_advert_started' FROM adverts;
If you want to get only adverts that have not expired, you will run a query like this;
SELECT * FROM `adverts` WHERE TIME_TO_SEC(timediff(now(),start_time))<=`duration_seconds`;
That's one way I would do it if I were to go with the "duration" field.
Yes, you can store time as INT data type (or another big integer: MEDIUMINT, LONGINT). Then use you can easily get days and time part from this, e.g. -
SELECT time DIV 86400 AS days, SEC_TO_TIME(column1 MOD 86400) AS time FROM table
Where 86400 is a number of seconds in 24h (60 * 60 * 24 = 86400).
not the best solution but you can add one column in your db, and check when time is more than 24 hours, calculate it as 1 day and write in that column, and all the rest time write in time column. But selecting from db you should calculate also that column of days
In MySQL I can create a table with a time field, and the value can be as high as 838:59:59 (839 hours - 1 second). I just read that in PostgreSQL, the hour field cannot exceed 23:00:00 (24 hours). Is there a way around this? I'm trying to make a simple DB that keeps track of how many hours & minutes were spent doing something, so it'll need to go higher than 23 hours & some minutes. I can do this in MySQL, but I need to use PostgreSQL for this. I Googled, but didn't find what I'm looking for, so I'm hoping I just didn't use the right keywords.
Postgres has no "hour field" - it has a few date/time types which serve different needs. The type I believe best fits your needs is INTERVAL.
Although they use the same notation, there's a difference between time of day and elapsed time. Some of their values overlap, but they're different domains. 838 isn't a valid value for an hour if you're talking about a time of day. 838 is a valid value for an hour if you're talking about elapsed time.
This distinction leads to two different data types: timestamp and interval.
create table intervals (
ts timestamp primary key,
ti interval not null
);
insert into intervals values (current_timestamp, '145:23:12');
select *
from intervals;
2011-08-03 21:51:16.837 145:23:12
select extract(hour from ti)
from intervals
145
I believe you are right, but It should not be an issue to work around. Would suggest storing the UNIX time integers for when you "punch in" and out again, and then adding the delta to an int field.
This will yield the number of seconds spent, which can be translated trivially into an hours:minutes:seconds format.
The delta (difference) can be calculated by subtracting the start timestamp from the end timestamp.
you could use a datetime field... 839 hours being something on the order 34.9 days...