using first sql statement result into another sql statement - mysql

Question

What basically i want to do is pick all the coordinates from roadData
one by one and then find all the point in tweetMelbourne within 20
miles of it and insert those point into another table.
So for every (x,y) in roadData table find neighbouring data point from
tweetMelbourne and insert those points into another new table.
So I have to do this:
SELECT geo_coordinates_latitude, geo_coordinates_longitude
FROM tweetmelbourne
HAVING ( 3959 * acos( cos( radians(latitude) ) * cos( radians( geo_coordinates_latitude ) ) *
cos( radians( geo_coordinates_longitude ) - radians(longitude) ) + sin( radians(latitude) ) *
sin( radians( geo_coordinates_latitude ) ) ) ) < .1 ORDER BY distance LIMIT 0 , 20;
in which the value of latitude and longitude i have to get from another table :
select longitude,latitude from roadData;
describe tweetmelbourne;
describe roadData;
SELECT geo_coordinates_latitude, geo_coordinates_longitude
FROM tweetmelbourne;
select longitude,latitude from roadData;

Answer 1

The correct syntax of IN() with multiple arguments is : (Val1,Val2) IN(SELECT VAL1,val2..
SELECT t.address,(t.x+t.y) as z
FROM student t
WHERE (t.x,t.y) IN(SELECT x,y FROM tweet)
Also can be done with a join :
SELECT t.address,(t.x+t.y) as z
FROM student t
JOIN tweet s
ON(t.x = s.x and t.y = s.y)
EDIT: I think what you want is:
SELECT s.address,t.x+t.y as z
FROM student s
CROSS JOIN tweet t

Answer 2

Try this:
SELECT s.address, (t.x + t.y) as z
from (SELECT id,x,y FROM `tweet`) as t, student s
WHERE t.id = s.id;

Answer 3

You need to join the two tables, calculating the distance in the ON clause to select the nearby rows.
SELECT *
FROM tweetmelbourne
JOIN roadData
ON ( 3959 * acos( cos( radians(latitude) ) * cos( radians( geo_coordinates_latitude ) ) *
cos( radians( geo_coordinates_longitude ) - radians(longitude) ) + sin( radians(latitude) ) *
sin( radians( geo_coordinates_latitude ) ) ) ) < .1
This will be very slow if the tables are large. It's not possible to use indexes to implement the join, so it will have to perform that complex formula on every pair of rows. You might want to look at MySQL's Spatial Data extensions.