Datediff in MsAccess - ms-access

Question

I am stuck in one place.
I am using DateDiff in Ms Access it is giving me proper output, like
StartDate is 10-Sep-2016
EndDate is 15-Oct-2016
Total Days which I will get is 35
& months will i get is 1 Month
DateDiff('d',StartDate,EndDate)
**But I want output as 2 months if it is exeeded the 30 days.
if it is 61 days then 3 months & so on.
**IIFFF days diffrence is
29 Days then output should be 1 months
30 Days then output should be 1 months
32 Days then output should be 2 months
60 Days then output should be 2 months
62 Days then output should be 3 months**
Will that be possible in the DateDiff in MsAccess
or is there any other function available so that i can achieve the same output.**

Answer 1

You can do this using conditional logic. Perhaps something like this:
select iif(DateDiff('d', StartDate, EndDate) > 30,
DateDiff('d',StartDate,EndDate) & " days",
"2 months"
)
Your logic that anything exceeding 30 days is "2 months" seems strange. Normally, I think the logic would look like this:
select iif(DateDiff('d', StartDate, EndDate) > 30,
DateDiff('d', StartDate, EndDate) & " days",
DateDiff('m', StartDate, EndDate) & " months"
)

Answer 2

will this logic suffice to modify your SQL function?
Public Function FN_GET_MONTH(iDays As Long, Optional iDaysInMonth As Long = 30)
If (iDays / iDaysInMonth) > iDays \ iDaysInMonth Then
FN_GET_MONTH = (iDays \ iDaysInMonth) + 1
Else
FN_GET_MONTH = (iDays \ iDaysInMonth)
End If
End Function
?FN_GET_MONTH(29) = 1
?FN_GET_MONTH(31) = 2
?FN_GET_MONTH(60) = 2
?FN_GET_MONTH(80) = 3
?FN_GET_MONTH(91) = 4
you can have this public function and use it in your SQL code like
FN_GET_MONTH(DateDiff("d", StartDate, EndDate))

Answer 3

This query seems to give the results you seek:
SELECT
StartDate,
EndDate
numDays,
((numDays - 1) \ 30) + 1 AS numMonths
FROM
(
SELECT
StartDate,
EndDate,
DateDiff("d", StartDate, EndDate) AS numDays
FROM YourTable
)
It gives me
numDays numMonths
------- ---------
...
29 1
30 1
31 2
32 2
...
59 2
60 2
61 3
62 3
...

Answer 4

It seems like your minimum count of months for a positive count of days is 1, thus:
MonthCount = Sgn(DateDiff("d",StartDate,EndDate)) + DateDiff("m",StartDate,EndDate)
Edit
For a 30-day cut that will produce your example output, use this simple formula in your query:
MonthCount: (DateDiff("d",[StartDate],[EndDate])-1)\30+1