How to get the child count for parent child relationship - mysql

Question

Using this query will get the result as in shown in below image link
select c.property_title,b.property_title as building,d.property_title as floor,e.house_name as house,
f.room_no as room,g.bed_no as bed
from g_property_group c
left join g_property_group b on b.parent_id = c.id and b.is_deleted = '0'
left join g_property_group d on d.parent_id = b.id and d.is_deleted = '0'
left join g_house e on e.property_group_id = d.id and e.is_deleted = '0'
left join g_room f on f.house_id = e.id and f.is_deleted = '0'
left join g_bed g on g.room_id = f.id and g.is_deleted = '0'
where c.id = 'a976df373f75d3f8cc49938ae9fead8e4fc8ad19'
and c.is_deleted = '0'
I have written the query for fetching the count of parent and child .will get the building count as 7 floor count as 7 house count as 5 room count as 4, instead the count of building should be 2, floor = 2, house = 4, Rooms = 5 and Bed 1.
select c.property_title,count(b.property_title)as building,count(d.property_title)as floor,count(e.house_name)as house,
count(f.room_no)as room,count(g.bed_no) as bed
from g_property_group c
left join g_property_group b on b.parent_id = c.id and b.is_deleted = '0'
left join g_property_group d on d.parent_id = b.id and d.is_deleted = '0'
left join g_house e on e.property_group_id = d.id and e.is_deleted = '0'
left join g_room f on f.house_id = e.id and f.is_deleted = '0'
left join g_bed g on g.house_id = g.id and g.room_id = f.id and g.is_deleted = '0'
where c.id = 'a976df373f75d3f8cc49938ae9fead8e4fc8ad19'
and c.is_deleted = '0'
Thank you in advance

Answer 1

Try this:
SQL SERVER
select count([building]) over (order by building) as [bulding count],
count([floor]) over (order by [floor],[building]) as [floor count],
count([house]) over (order by building,[floor],[house]) as [house count],
count([room]) over (order by building,[floor],[house],[room]) as [room count],
count([bed]) over (order by building,[floor],[house],[room],[bed]) as [room count]