Find average amount paid to each doctor - mysql

Create Table Doctor(
doctorID varchar(50) Primary key,
doctorFName varchar(50),
);
Create Table Appointment(
appID varchar(50) Primary Key,
doctorID varchar(50) Foreign Key References Doctor(doctorID),
);
Create Table Payment(
paymentID varchar(50) Primary Key,
paymentAmount int,
appID varchar(50) Foreign Key References Appointment(appID),
);
paymentAmount is also known as payment for each appointment
How can I get the average payment amount of each doctor?
I tried:
SELECT d.doctorID, d.doctorFName, SUM(p.paymentAmount) as AverageDailySalary
FROM Payment p JOIN Appointment a ON p.appID = a.appID JOIN Doctor d ON a.doctorID = d.doctorID
ORDER BY d.doctorID


That's a simple JOIN..GROUP BY query :
SELECT d.doctorID,d.doctorFName,AVG(p.paymentAmount) as avg_pay
FROM Doctor d
JOIN Appoitment a
ON(d.doctorID = a.doctorID)
JOIN payment p
ON(a.appID = p.appID)
GROUP BY d.doctorID,d.doctorFName

Related

Altering a Table to Add a Column thats Value is set using a UPDATE JOIN Query

Im trying to create a Column thats Value is defined through anUPDATE JOIN SET statement. The exact question that im trying to answer actually is
"Add to a relational table EMPLOYEE information about the total number of orders handled by each employee. Note, that if an employee handled no orders then for such employee the total number of orders must be set to zero. Enforce the appropriate consistency constraints on a relational table EMPLOYEE. "
ALTER TABLE EMPLOYEE
ADD TOTALNUMBER VARCHAR(40) NOT NULL;
UPDATE EMPLOYEE E JOIN ORDERS O ON(E.EMPLOYEE_ID = O.EMPLOYEE_ID)
SET E.TOTALNUMBER = E.EMPLOYEE_ID + O.ORDER_ID;
UPDATE EMPLOYEE
SET TOTALNUMBER = 0
WHERE TOTALNUMBER IS NULL;
tables being used
CREATE TABLE EMPLOYEE
(
EMPLOYEE_ID DECIMAL(9) NOT NULL,
LASTNAME VARCHAR(20) NOT NULL,
FIRSTNAME VARCHAR(10) NOT NULL,
TITLE VARCHAR(30),
TITLE_OF_COURTESY VARCHAR(25),
BIRTHDATE DATE,
HIREDATE DATE,
ADDRESS VARCHAR(60),
CITY VARCHAR(15),
REGION VARCHAR(15),
POSTAL_CODE VARCHAR(10),
COUNTRY VARCHAR(15),
HOME_PHONE VARCHAR(24),
EXTENSION VARCHAR(4),
PHOTO VARCHAR(255),
NOTES VARCHAR(2000),
REPORTS_TO DECIMAL(9),
CONSTRAINT PK_EMPLOYEE PRIMARY KEY (EMPLOYEE_ID)
);
CREATE TABLE ORDERS
(
ORDER_ID DECIMAL(9) NOT NULL,
CUSTOMER_CODE VARCHAR(5) NOT NULL,
EMPLOYEE_ID DECIMAL(9) NOT NULL,
ORDER_DATE DATE NOT NULL,
REQUIRED_DATE DATE,
SHIPPED_DATE DATE,
SHIP_VIA VARCHAR(40),
FREIGHT DECIMAL(10,2) DEFAULT 0,
SHIP_NAME VARCHAR(40),
SHIP_ADDRESS VARCHAR(60),
SHIP_CITY VARCHAR(15),
SHIP_REGION VARCHAR(15),
SHIP_POSTAL_CODE VARCHAR(10),
SHIP_COUNTRY VARCHAR(15),
CONSTRAINT PK_ORDERS PRIMARY KEY (ORDER_ID),
CONSTRAINT FK_CUSTOMER_CODE FOREIGN KEY (CUSTOMER_CODE) REFERENCES CUSTOMER(CUSTOMER_CODE),
CONSTRAINT FK_EMPLOYEE_ID FOREIGN KEY (EMPLOYEE_ID) REFERENCES EMPLOYEE(EMPLOYEE_ID),
CONSTRAINT FK_SHIP_VIA FOREIGN KEY (SHIP_VIA) REFERENCES SHIPPER(COMPANY_NAME)
);
Im unsure of what the exact result should be but i recieve a total of 9 rows with values ranging between 252 to 296. It doesnt seem to odd that an employee would deal with this many Orders but it seems to be too small of a list.

I don't recommend your current approach, and the best way to determine the number of orders per employees is to just aggregate and join, without storing this number in the actual employee table. That being said, if you want to proceed this way, then consider using this update query:
UPDATE EMPLOYEE e
LEFT JOIN
(
SELECT EMPLOYEE_ID, COUNT(*) AS num_orders
FROM ORDERS
GROUP BY EMPLOYEE_ID
) o
ON e.EMPLOYEE_ID = o.EMPLOYEE_ID
SET TOTALNUMBER = COALESCE(o.num_orders, 0);
Or, you could use:
SET TOTALNUMBER = o.num_orders;
and then use your second update to zero-out the employee totals which had no orders at all:
UPDATE EMPLOYEE
SET TOTALNUMBER = 0
WHERE TOTALNUMBER IS NULL;
But note that this would require that the TOTALNUMBER columns is not nullable. So you would need to remove the NOT NULL constraint.

Trouble with JOINS in mysql

I was working in mySQL and made a fake database for reviews, reviewers and tv series. So I made 3 different tables, one for reviewers, one for reviews and one for the series.
CREATE TABLE reviewers
(
id INT AUTO_INCREMENT PRIMARY KEY,
first_name VARCHAR(100) NOT NULL,
last_name VARCHAR(150) NOT NULL
);
CREATE TABLE series
(
id INT AUTO_INCREMENT PRIMARY KEY,
title VARCHAR(100) NOT NULL,
released_year YEAR(4),
genre VARCHAR(50)
);
CREATE TABLE reviews(
id INT AUTO_INCREMENT PRIMARY KEY,
rating DECIMAL(2,1),
series_id INT,
reviewer_id INT,
FOREIGN KEY(series_id) REFERENCES series(id),
FOREIGN KEY(reviewer_id) REFERENCES reviewers(id)
);
The thing that I wanted to ask is, how can I get the highest rating from each reviewer and in which show they gave it?
UPDATE
I came up with this code
SELECT first_name,last_name,title, a.series_id,a.rating FROM
( SELECT series_id,MAX(rating) AS max FROM reviews
GROUP BY series_id ) AS b
INNER JOIN reviews AS a
ON a.series_id=b.series_id AND a.rating=b.max
INNER JOIN reviewers
ON reviewers.id=a.reviewer_id
INNER JOIN series
ON series.id=a.series_id
GROUP BY series_id;
which gives me the max rating in each series and who gave that rating

Unexpected error MySQL Query

I have three tables:
STUDENT table:
create table student
(
sid int auto_increment primary key,
fname varchar(30),
lname varchar(30)
);
COURSE table:
create table course
(
cid int auto_increment primary key,
ctype text,
cclass text,
cduration int,
certification int,
cteacher text,
standard_course_fee int,
);
STUDENT_PAYMENT table:
create table student_payment
(
transaction_id int auto_increment primary key,
sid int,
cid int,
paidamount int,
paiddate date,
paymentdue int,
FOREIGN KEY (sid) REFERENCES student(sid),
FOREIGN KEY (cid) REFERENCES course(cid)
);
I wrote this query:
select
sid, fname, lname, cid, ctype, cclass, paidamount, paiddate, paymentdue
from
student, student_payment, course
where
course.cid = student_payment.cid and
student.sid = student_payment.sid and
sid = 1;
To get expect output table like this:
|sid| fname | lname | ctype | cclass | paidamount | paiddate | paymentdue |
---------------------------------------------------------------------------
but I get an error:
Column sid in field list is ambiguous
Please someone correct my query.

You need to add alise as below. Also, use the join instead of adding all the tables in FROM
select student.sid,fname,lname,course.cid,ctype,cclass,paidamount,paiddate,paymentdue
from student
inner join student_payment on student.sid=student_payment.sid
inner join course on course.cid=student_payment.cid
where student.sid=1;

MySQL: Implicit Join with conditions: What kind of statement would I need for duplicate removal?

I'm working on JOIN statements (implicit) and I've set up the code to join without much of a hitch, and when the code runs I get quite a few duplicates per person. I was wondering what kind of statement I should use to only show one of each person?
Select Statement
SELECT CONCAT(customers.customer_first_name, ' ', customers.customer_last_name) as 'Customer',
orders.order_date as 'Order Date', customers.customer_zip as 'Zipcode'
FROM customers, orders, order_details
WHERE order_details.item_id = 10
ORDER BY CONCAT(customers.customer_first_name, ' ', customers.customer_last_name) ASC;
If you need other parts of the code, they are readily available.
Create Table/Insert Statements:
/*Create Tables*/
CREATE TABLE customers
(
customer_id INT,
customer_first_name VARCHAR(20),
customer_last_name VARCHAR(20) NOT NULL,
customer_address VARCHAR(50) NOT NULL,
customer_city VARCHAR(20) NOT NULL,
customer_state CHAR(2) NOT NULL,
customer_zip CHAR(5) NOT NULL,
customer_phone CHAR(10) NOT NULL,
customer_fax CHAR(10),
CONSTRAINT customers_pk
PRIMARY KEY (customer_id)
);
CREATE TABLE artists
(
artist_id INT NOT NULL,
artist_name VARCHAR(30),
CONSTRAINT artist_pk
PRIMARY KEY (artist_id)
);
CREATE TABLE items
(
item_id INT NOT NULL,
title VARCHAR(50) NOT NULL,
artist_id INT NOT NULL,
unit_price DECIMAL(9,2) NOT NULL,
CONSTRAINT items_pk
PRIMARY KEY (item_id),
CONSTRAINT items_fk_artists
FOREIGN KEY (artist_id) REFERENCES artists (artist_id)
);
CREATE TABLE employees
(
employee_id INT NOT NULL,
last_name VARCHAR(20) NOT NULL,
first_name VARCHAR(20) NOT NULL,
manager_id INT,
CONSTRAINT employees_pk
PRIMARY KEY (employee_id),
CONSTRAINT emp_fk_mgr FOREIGN KEY (manager_id) REFERENCES employees(employee_id)
);
CREATE TABLE orders
(
order_id INT NOT NULL,
customer_id INT NOT NULL,
order_date DATE NOT NULL,
shipped_date DATE,
employee_id INT,
CONSTRAINT orders_pk
PRIMARY KEY (order_id),
CONSTRAINT orders_fk_customers
FOREIGN KEY (customer_id) REFERENCES customers (customer_id),
CONSTRAINT orders_fk_employees
FOREIGN KEY (employee_id) REFERENCES employees (employee_id)
);
CREATE TABLE order_details
(
order_id INT NOT NULL,
item_id INT NOT NULL,
order_qty INT NOT NULL,
CONSTRAINT order_details_pk
PRIMARY KEY (order_id, item_id),
CONSTRAINT order_details_fk_orders
FOREIGN KEY (order_id)
REFERENCES orders (order_id),
CONSTRAINT order_details_fk_items
FOREIGN KEY (item_id)
REFERENCES items (item_id)
);
/*Insert Statements*/
INSERT INTO customers VALUES
(1,'Korah','Blanca','1555 W Lane Ave','Columbus','OH','43221','6145554435','6145553928'),
(2,'Yash','Randall','11 E Rancho Madera Rd','Madison','WI','53707','2095551205','2095552262'),
(3,'Johnathon','Millerton','60 Madison Ave','New York','NY','10010','2125554800',NULL),
(4,'Mikayla','Davis','2021 K Street Nw','Washington','DC','20006','2025555561',NULL),
(5,'Kendall','Mayte','4775 E Miami River Rd','Cleves','OH','45002','5135553043',NULL),
(6,'Kaitlin','Hostlery','3250 Spring Grove Ave','Cincinnati','OH','45225','8005551957','8005552826'),
(7,'Derek','Chaddick','9022 E Merchant Wy','Fairfield','IA','52556','5155556130',NULL),
(8,'Deborah','Davis','415 E Olive Ave','Fresno','CA','93728','5595558060',NULL),
(9,'Karina','Lacy','882 W Easton Wy','Los Angeles','CA','90084','8005557000',NULL),
(10,'Kurt','Nickalus','28210N Avenue Stanford','Valencia','CA','91355','8055550584','055556689'),
(11,'Kelsey','Eulalia','7833 N Ridge Rd','Sacramento','CA','95887','2095557500','2095551302'),
(12,'Anders','Rohansen','12345 E 67th Ave NW','Takoma Park','MD','24512','3385556772',NULL),
(13,'Thalia','Neftaly','2508 W Shaw Ave','Fresno','CA','93711','5595556245',NULL),
(14,'Gonzalo','Keeton','12 Daniel Road','Fairfield','NJ','07004','2015559742',NULL),
(15,'Ania','Irvin','1099 N Farcourt St','Orange','CA','92807','7145559000',NULL),
(16,'Dakota','Baylee','1033 NSycamore Ave.','Los Angeles','CA','90038','2135554322',NULL),
(17,'Samuel','Jacobsen','3433 E Widget Ave','Palo Alto','CA','92711','4155553434',NULL),
(18,'Justin','Javen','828 S Broadway','Tarrytown','NY','10591','8005550037',NULL),
(19,'Kyle','Marissa','789 E Mercy Ave','Phoenix','AZ','85038','9475553900',NULL),
(20,'Erick','Kaleigh','Five Lakepointe Plaza, Ste 500','Charlotte','NC','28217','7045553500',NULL),
(21,'Marvin','Quintin','2677 Industrial Circle Dr','Columbus','OH','43260','6145558600','6145557580'),
(22,'Rashad','Holbrooke','3467 W Shaw Ave #103','Fresno','CA','93711','5595558625','5595558495'),
(23,'Trisha','Anum','627 Aviation Way','Manhatttan Beach','CA','90266','3105552732',NULL),
(24,'Julian','Carson','372 San Quentin','San Francisco','CA','94161','6175550700',NULL),
(25,'Kirsten','Story','2401 Wisconsin Ave NW','Washington','DC','20559','2065559115',NULL);
INSERT INTO artists(artist_id,artist_name) VALUES
(10,'Umani'),
(11,'The Ubernerds'),
(12,'No Rest For The Weary'),
(13,'Burt Ruggles'),
(14,'Sewed the Vest Pocket'),
(15,'Jess & Odie'),
(16,'Onn & Onn');
INSERT INTO items (item_id,title,artist_id,unit_price) VALUES
(1,'Umami In Concert',10,17.95),
(2,'Race Car Sounds',11,13),
(3,'No Rest For The Weary',12,16.95),
(4,'More Songs About Structures and Comestibles',12,17.95),
(5,'On The Road With Burt Ruggles',13,17.5),
(6,'No Fixed Address',14,16.95),
(7,'Rude Noises',15,13),
(8,'Burt Ruggles: An Intimate Portrait',13,17.95),
(9,'Zone Out With Umami',10,16.95),
(10,'Etcetera',16,17);
INSERT INTO employees VALUES
(1,'Smith','Cindy',null),
(2,'Jones','Elmer',1),
(3,'Simonian','Ralph',2),
(9,'Locario','Paulo',1),
(8,'Leary','Rhea',9),
(4,'Hernandez','Olivia',9),
(5,'Aaronsen','Robert',4),
(6,'Watson','Denise',8),
(7,'Hardy','Thomas',2);
INSERT INTO orders VALUES
(19,1,'2012-10-23','2012-10-28',6),
(29,8,'2012-11-05','2012-11-11',6),
(32,11,'2012-11-10','2012-11-13',NULL),
(45,2,'2012-11-25','2012-11-30',NULL),
(70,10,'2012-12-28','2013-01-07',5),
(89,22,'2013-01-20','2013-01-22',7),
(97,20,'2013-01-29','2013-02-02',5),
(118,3,'2013-02-24','2013-02-28',7),
(144,17,'2013-03-21','2013-03-29',NULL),
(158,9,'2013-04-04','2013-04-20',NULL),
(165,14,'2013-04-11','2013-04-13',NULL),
(180,24,'2013-04-25','2013-05-30',NULL),
(231,15,'2013-06-14','2013-06-22',NULL),
(242,23,'2013-06-24','2013-07-06',3),
(264,9,'2013-07-15','2013-07-18',6),
(298,18,'2013-08-18','2013-09-22',3),
(321,2,'2013-09-09','2013-10-05',6),
(381,7,'2013-11-08','2013-11-16',7),
(413,17,'2013-12-05','2014-01-11',7),
(442,5,'2013-12-28','2014-01-03',5),
(479,1,'2014-01-30','2014-03-03',3),
(491,16,'2014-02-08','2014-02-14',5),
(523,3,'2014-03-07','2014-03-15',3),
(548,2,'2014-03-22','2014-04-18',NULL),
(550,17,'2014-03-23','2014-04-03',NULL),
(601,16,'2014-04-21','2014-04-27',NULL),
(607,20,'2014-04-25','2014-05-04',NULL),
(624,2,'2014-05-04','2014-05-09',NULL),
(627,17,'2014-05-05','2014-05-10',NULL),
(630,20,'2014-05-08','2014-05-18',7),
(651,12,'2014-05-19','2014-06-02',7),
(658,12,'2014-05-23','2014-06-02',7),
(687,17,'2014-06-05','2014-06-08',NULL),
(693,9,'2014-06-07','2014-06-19',NULL),
(703,19,'2014-06-12','2014-06-19',7),
(778,13,'2014-07-12','2014-07-21',7),
(796,17,'2014-07-19','2014-07-26',5),
(800,19,'2014-07-21','2014-07-28',NULL),
(802,2,'2014-07-21','2014-07-31',NULL),
(824,1,'2014-08-01',NULL,NULL),
(827,18,'2014-08-02',NULL,NULL),
(829,9,'2014-08-02',NULL,NULL);
INSERT INTO order_details VALUES
(381,1,1),
(601,9,1),
(442,1,1),
(523,9,1),
(630,5,1),
(778,1,1),
(693,10,1),
(118,1,1),
(264,7,1),
(607,10,1),
(624,7,1),
(658,1,1),
(800,5,1),
(158,3,1),
(321,10,1),
(687,6,1),
(827,6,1),
(144,3,1),
(479,1,2),
(630,6,2),
(796,5,1),
(97,4,1),
(601,5,1),
(800,1,1),
(29,10,1),
(70,1,1),
(165,4,1),
(180,4,1),
(231,10,1),
(413,10,1),
(491,6,1),
(607,3,1),
(651,3,1),
(703,4,1),
(802,3,1),
(824,7,2),
(829,1,1),
(550,4,1),
(796,7,1),
(693,6,1),
(29,3,1),
(32,7,1),
(242,1,1),
(298,1,1),
(479,4,1),
(548,9,1),
(627,9,1),
(778,3,1),
(19,5,1),
(89,4,1),
(242,6,1),
(264,4,1),
(550,1,1),
(693,7,3),
(824,3,1),
(829,5,1),
(829,9,1);

You have a Descartes product, not a join. You could use the distinct keyword or you could do a group by, but it seems you really need a join instead. I am writing something like that for you, but since I do not know your table structure, I will be guessing the columns:
SELECT CONCAT(customers.customer_first_name, ' ', customers.customer_last_name) as 'Customer',
orders.order_date as 'Order Date', customers.customer_zip as 'Zipcode'
FROM order_details
join orders
on order_details.order_id = orders.order_id and order_details.item_id = 10
join customers
on orders.customer_id = customers.customer_id
ORDER BY CONCAT(customers.customer_first_name, ' ', customers.customer_last_name) ASC;
Naturally, there is no guarantee there will be a single record per customer, since we, at least lacking information cannot assume that there are no customers who have multiple orders, each having an order detail with item_id = 10

See Explicit vs implicit SQL joins ... right now you are likely getting a Cartesian product. Sorry this isn't in comments ... new user, score isn't high enough to comment yet.

If you don't want to use the JOIN keyword you can add the key columns on whick the tables are related to the WHERE clause like this:
SELECT CONCAT(customers.customer_first_name, ' ', customers.customer_last_name) as 'Customer',
orders.order_date as 'Order Date', customers.customer_zip as 'Zipcode'
FROM customers, orders, order_details
WHERE order_details.item_id = 10
AND orders.customer_id = customers.customer_id
AND order_details.order_id = orders.order_id
ORDER BY CONCAT(customers.customer_first_name, ' ', customers.customer_last_name) ASC;

How do I extract results after joining multiple tables in the following schema?

I've used the following commands for creating the tables.
CREATE TABLE Customer(
custid int NOT NULL AUTO_INCREMENT,
fname varchar(30) NOT NULL,
lname varchar(30) NOT NULL,
mno varchar(10),
password varchar(30),
PRIMARY KEY (custid)
);
CREATE TABLE Employee(
empid int NOT NULL,
fname varchar(30) NOT NULL,
lname varchar(30) NOT NULL,
mno varchar(10),
password varchar(30),
PRIMARY KEY (empid)
);
CREATE TABLE Address(
id int NOT NULL,
street varchar(30),
doorno varchar(30),
city varchar(30),
statee varchar(30),
zip varchar(5),
county varchar(30) NOT NULL,
PRIMARY KEY (id),
FOREIGN KEY (id) REFERENCES Customer (custid)
);
CREATE TABLE EmpAddress(
id int NOT NULL,
street varchar(30),
doorno varchar(30),
city varchar(30),
statee varchar(30),
zip varchar(5),
county varchar(30) NOT NULL,
PRIMARY KEY (id),
FOREIGN KEY (id) REFERENCES Employee (empid)
);
CREATE TABLE Service(
serviceid int NOT NULL,
serviceType varchar(30),
amount int,
PRIMARY KEY (serviceid)
);
CREATE TABLE Booking(
bookingid int NOT NULL AUTO_INCREMENT,
empid int NOT NULL,
custid int NOT NULL,
serviceid int NOT NULL,
PRIMARY KEY (bookingid),
FOREIGN KEY (empid) REFERENCES Employee (empid),
FOREIGN KEY (custid) REFERENCES Customer (custid),
FOREIGN KEY (serviceid) REFERENCES Service (serviceid)
);
CREATE TABLE Availability(
empid int NOT NULL,
datee date NOT NULL,
startTime int NOT NULL,
PRIMARY KEY (empid, datee, startTime),
FOREIGN KEY (empid) REFERENCES Employee (empid)
);
CREATE TABLE Transactions(
bookingid int NOT NULL,
paymentMethod varchar(20),
serviceid int,
amount int,
PRIMARY KEY (bookingid),
FOREIGN KEY (bookingid) REFERENCES Booking (bookingid),
FOREIGN KEY (serviceid) REFERENCES Service (serviceid)
);
I am trying to write a query that returns the bookingid, firstName, lastName, street, door no, zip code, serviceType, date and startTime GIVEN empid.
It is essentially a join of 5 tables and I'd implemented the query as:
SELECT B.bookingid, C.fname, C.lname, AD.street,
AD.doorno, AD.zip,S.serviceType, A.datee, A.startTime
FROM booking as B, availability as A, customer as C,
address as AD, Service as S
WHERE
B.empid=501 AND B.custid=C.custid
AND C.custid=AD.id
AND B.serviceid=S.serviceid AND B.empid=A.empid;
The REQUIRED results should have been:
BookingID fname lname street doorno zipcode serviceType date starttime
1 X Y ABC 33 5335 Clean 2015-05-20 9
2 P Q NMO 55 8294 Shift 2015-06-11 11
But the results give me the cross product of tables:
BookingID fname lname street doorno zipcode serviceType date starttime
1 X Y ABC 33 5335 Clean 2015-05-20 9
1 X Y ABC 33 5335 Shift 2015-06-11 11
2 P Q NMO 55 8294 Clean 2015-05-20 9
2 P Q NMO 55 8294 Shift 2015-06-11 11
Please let me know what is wrong with my query.

The primary key for Availability is currently (empid, datee, startTime), yet the JOIN is done on just on Booking.empid - it is possible there is more than one availability row per Employee.
I believe you will need to add a timestamp to Booking and interpolate on date during the join to Availability:
CREATE TABLE Booking(
-- ...
bookingDate datetime NOT NULL,
-- ...
);
I would also suggest that you add and end datetime bounds to the Availability, and store Date and Time as one (otherwise you will need to continually add the time back in):
CREATE TABLE Availability(
-- ...
startDateTime datetime NOT NULL,
endDateTime datetime NOT NULL,
PRIMARY KEY (empid, startDateTime), -- Put some rules to prevent overlap
);
The query then interpolates Booking to Availability on Date and Time:
SELECT B.bookingid, C.fname, C.lname, AD.street, AD.doorno, AD.zip,
S.serviceType, A.startDateTime
FROM
booking as B
INNER JOIN customer as C
ON B.custid=C.custid
INNER JOIN availability as A
ON B.empid=A.empid AND b.bookingDate BETWEEN A.startDateTime AND A.endDateTime
INNER JOIN address as AD
ON C.custid=AD.id
INNER JOIN Service as S
ON B.serviceid=S.serviceid
WHERE
B.empid=501;
I've also adjusted the join to use JOIN ON rather than doing the join in the WHERE.
This would address the duplicated availability data. However, I can't see how ServiceType would be different for the same booking.

You can use DISTINCT to eliminate duplicate records. Also always try to use explicit joins.
SELECT DISTINCT B.bookingid, C.fname, C.lname, AD.street,
AD.doorno, AD.zip,S.serviceType, A.datee, A.startTime
FROM booking as B
INNER JOIN availability as A ON B.empid = A.empid
INNER JOIN customer as C ON B.custid = C.custid
INNER JOIN address as AD ON C.custid = AD.id
INNER JOIN Service as S ON B.serviceid = S.serviceid
WHERE B.empid = 501