Hello i need a regular expression per my sql query to match to text
"SIP/(10 NUMBERS)"
equals
"SIP/1234567890"
"SIP" are text
and 10 number randoms 0-9
UPDATE
Final text are SIP/0123456789-000001cc
where
"SIP/" is text
"0123456789" Always 10 digits
"-" is character
"000001cc" is random alphanumeric
You can use this regex:
^SIP/[[:digit:]]{10}-
Examples:
mysql> select 'SIP/0123456789-000001cc' regexp '^SIP/[[:digit:]]{10}-';
+----------------------------------------------------------+
| 'SIP/0123456789-000001cc' regexp '^SIP/[[:digit:]]{10}-' |
+----------------------------------------------------------+
| 1 |
+----------------------------------------------------------+
1 row in set (0.00 sec)
mysql> select 'SIP/123456789-000001cc' regexp '^SIP/[[:digit:]]{10}-';
+----------------------------------------------------------+
| 'SIP/123456789-000001cc' regexp '^SIP/[[:digit:]]{10}-' |
+----------------------------------------------------------+
| 0 |
+----------------------------------------------------------+
1 row in set (0.00 sec)
Use \ to escape /
The following RegEx targets SIP followed by /and then 10 digit characters:
SIP\/\d{10}
Related
I have a MySQL DB table where a text column has some values which seem to be only CR and LF control characters (the value is just the line break).
I need a query which will identify all such rows. I tried something like this
SELECT * FROM mytable WHERE mycolumn REGEXP "\r\n";
from here. But that didn't work. I guess I just need the correct regex in my case. Any suggestions would be greatly appreciated.
I inserted a col with line breaks, i could retrieve it with foll SQL
mysql> select lat from TEST_INSERT where lat regexp '.*[\n]';
+--------------+
| lat |
+--------------+
| xx
yy
zz
|
+--------------+
1 row in set (0.00 sec)
WHERE col = "\r\n"
will check for that column having only a Windows-type line break.
WHERE col = "\n"
for unix-style.
Is it what you are looking for???
mysql> select lat from TEST_INSERT where lat regexp '^\n+$';
+-------+
| lat |
+-------+
|
|
+-------+
1 row in set (0.00 sec)
I am trying to build a query that checks whether the string contains at least more than 5 consecutive digits or not.
Query;
SELECT count(id) as gV FROM someTable WHERE ... title REGEXP '(\d{5,})' order by id limit 0,10
Sample data
Some text here 123456 (MATCH)
S0m3 t3xt h3r3
Some text 123 here 345
98765 Some text here (MATCH)
Some12345Text Around (MATCH)
Desired output
3 (Some text here 123456, 98765 Some text here, Some12345Text Around)
Is there any specific rules for regex in MySQL queries?
MySQL's regular expression engine does not implement the \d "digit" expression, but instead you can represent it either as a character class range like [0-9] or as the special character class [[:digit:]]. The curly brace repeat syntax {5,} is supported in the form you've attempted.
The available regular expression syntax is described in the manual
So you can use either of the following forms:
title REGEXP '[0-9]{5,}'
title REGEXP '[[:digit:]]{5,}'
Examples:
Non matching:
> SELECT '123' REGEXP '[[:digit:]]{5,}';
+--------------------------------+
| '123' REGEXP '[[:digit:]]{5,}' |
+--------------------------------+
| 0 |
+--------------------------------+
> SELECT '1X345' REGEXP '[0-9]{5,}';
+--------------------------------+
| '123' REGEXP '[0-9]{5,}' |
+--------------------------------+
| 0 |
+--------------------------------+
Matching examples:
> SELECT '98765 Some text here' REGEXP '[[:digit:]]{5,}';
+-------------------------------------------------+
| '98765 Some text here' REGEXP '[[:digit:]]{5,}' |
+-------------------------------------------------+
| 1 |
+-------------------------------------------------+
> SELECT 'Some text here 123456' REGEXP '[0-9]{5,}';
+--------------------------------------------+
| 'Some text here 123456' REGEXP '[0-9]{5,}' |
+--------------------------------------------+
| 1 |
+--------------------------------------------+
1 row in set (0.00 sec)
I am trying to fetch rows from my database by checking if the json in one of their fields contains a specific id.
Example: col(kats): [2,4,7,9]
I am trying to do so by using the following query
SELECT column FROM table WHERE column REGEXP '(\[|\,)1(\]|\,)'
The Problem: MySQL returns 1 for every row in the table.
MySQL requires that any literal backslash \ characters (which are literal in the REGEXP string as escape characters to the following []) be escaped themselves. Thus, you must double-escape [] as \\[ and \\].
From the docs:
Because MySQL uses the C escape syntax in strings (for example, “\n” to represent the newline character), you must double any “\” that you use in your REGEXP strings.
The rest of your pattern is basically correct, except that the comma , does not require escaping.
1 does not match:
> SELECT '[2,4,7,9]' REGEXP '(\\[|,)1(\\]|,)';
+--------------------------------------+
| '[2,4,7,9]' REGEXP '(\\[|,)1(\\]|,)' |
+--------------------------------------+
| 0 |
+--------------------------------------+
1 row in set (0.00 sec)
But 2 does match
> SELECT '[2,4,7,9]' REGEXP '(\\[|,)2(\\]|,)';
+--------------------------------------+
| '[2,4,7,9]' REGEXP '(\\[|,)2(\\]|,)' |
+--------------------------------------+
| 1 |
+--------------------------------------+
1 row in set (0.00 sec)
Why does this match (it should match (44[0-9]) zero or more times)
mysql> SELECT "tampampam" REGEXP "(44[0-9])*$";
+----------------------------------+
| "tampampam" REGEXP "(44[0-9])*$" |
+----------------------------------+
| 1 |
+----------------------------------+
1 row in set (0.00 sec)
And this does not (it should match 44 followed by ([0-9]) zero or more times
mysql> SELECT "44tampampam" REGEXP "44([0-9])*$";
+------------------------------------+
| "44tampampam" REGEXP "44([0-9])*$" |
+------------------------------------+
| 0 |
+------------------------------------+
1 row in set (0.00 sec)
Well, it is a very strange regex expression.
As for the first case, (44[0-9])*$ means "match a string starting with 44 and then a number from 0 to 9, any number of times up to the end of string". Since "any number" is possible, the string "tampampam" is matched.
As for the second case, 44([0-9])*$ means "match 44, then any number from 0 to 9 (with heavy backtracking), zero or more times, up to the end of string". But after 44 there is "tampampam". No match is due. Remove $, and you'll have a match.
You must use start anchor also to make sure it doesn't match unwanted text:
SELECT "tampampam" REGEXP "^(44[0-9])*$";
+-----------------------------------+
| "tampampam" REGEXP "^(44[0-9])*$" |
+-----------------------------------+
| 0 |
+-----------------------------------+
The first query matches because matching something zero or more times, means that not matching it (ie. matching zero times), is also a match.
The second query does not match, because you have anchored the regular expression to the end of the string, because of the dollar-sign ($). As the end of the string is not the string 44 optionally followed by digits, it does not match.
I see no reason to use *$ in your case. Keep it simple:
SELECT "tampampam" REGEXP "44[0-9]";
=> 0
SELECT "t441ampampam" REGEXP "44[0-9]";
=> 1
SELECT "t441ampampam" REGEXP "^44[0-9]";
=> 0
SELECT "441tampampam" REGEXP "^44[0-9]";
=> 1
So if you need 44 to be the first characters in the string use '^44[0-9]'.
If you don't care that is as simple as '44[0-9]'.
I have to get last 5 numbers using mysql.
My values are like YOT-A78514,LOP-C4521 ...
I have to get only last five char . How can I do this in query?
You can do this with RIGHT(str,len) function. Returns the rightmost len characters from the string str,
Like below:
SELECT RIGHT(columnname,5) as yourvalue FROM tablename
"Right"-function is the way to, using the substring may lead to an problem that is not so easy to notice:
mysql> select right('hello', 6);
+-------------------+
| right('hello', 6) |
+-------------------+
| hello |
+-------------------+
1 row in set (0.00 sec)
mysql> select substring('hello', -6);
+------------------------+
| substring('hello', -6) |
+------------------------+
| |
+------------------------+
1 row in set (0.00 sec)
But if you don't try to go past the start of the string, then substring of course works fine:
mysql> select substring('hello', -5);
+------------------------+
| substring('hello', -5) |
+------------------------+
| hello |
+------------------------+
1 row in set (0.00 sec)
Right is a good choice but you can also use substring like this-
SELECT Substring(columnname,-5) as value FROM table_name
SELECT row_id
FROM column_name
WHERE column_value LIKE '%12345';
This will return the "row_id" when "12345" is found to be the tailing suffix of the "column_value" within the "column_name".
And if you want to get a dinamic number of right characters after a character:
SELECT TRIM(
RIGHT(
database.table.field,
(LENGTH(database.table.field) - LOCATE('-',database.table.field))
)
)
FROM database.table;
SELECT SUBSTR('Stringname', -5) AS Extractstring;