I can't find why DATE(created) LIKE '2016-1%' does not return from database anything, while DATE(created) LIKE '2016%' will return the row with date 2016-1-22, this column is timestamp format with CURRENT_TIMESTAMP.
SELECT * FROM logs WHERE DATE(created) LIKE '2016-1%'
I can't find the row either with 2016-1-22 ...
The DATE part of a TIMESTAMP column is retrieved by MySQL in the format 'YYYY-MM-DD' (see documentation). So a date like 2016-1-22 is actually represented as 2016-01-22, which does not match '2016-1%'.
Try prefixing month filed with 0, till 9(i.e. 01,02,03,..).
So your query should become like
SELECT * FROM logs WHERE DATE(created) LIKE '2016-01%'
Related
I have the following mysql table:
tasks:
=====================
tid
status
desc
duedate
And i have the following records in that table:
records
===========================
1
active
Test description
08/15/2014
2
active
Another description
08/31/204
I am trying to get the days that there is a task for, in that particular month. I have the following query but when i run it it gets both records but "day" is null on both of them for some reason. Can someone please help me with this.
MYSQL QUERY
====================
SELECT DATE_FORMAT(due_date,'%d') AS day FROM tasks WHERE due_date BETWEEN '08/01/2014' AND '08/31/2014'
Try:
SELECT DAY(due_date) AS day
FROM tasks
WHERE due_date >= '2014-08'
AND due_date < '2014-09';
DAY() is a better function for what you want and I prefer using >= and < than BETWEEN for date comparisons, as it allows you to specify precise ranges more easily. Here, for example, you don't need to know the number of days in the month.
I have also used the default date format, which is preferable. If you need the, in my opinion, cray American date format, use DATE_FORMAT() in your SELECT.
This will only work with DATE, DATETIME and TIMESTAMP columns, which is how your due_date should be stored, preferably DATE.
UPDATE
To convert the VARCHAR column to DATE run:
UPDATE tasks SET due_date=STR_TO_DATE(due_date,'%m/%d/%Y')
Then change the type. Also remember to change your INSERT statements to use the default format.
You've got to convert those "date" strings to proper date values with STR_TO_DATE:
SELECT
DAY(STR_TO_DATE(due_date,'%m/%d/%Y')) AS day
FROM tasks
WHERE
STR_TO_DATE(due_date, '%m/%d/%Y')
BETWEEN STR_TO_DATE('08/01/2014' '%m/%d/%Y')
AND STR_TO_DATE('08/31/2014', '%m/%d/%Y')
else you're comparing strings instead.
Note:
It would be better to use a proper DATE or DATETIME column instead.
With the current VARCHAR format MySQL is unable to use indexes. That's very bad for performance.
You can convert your data by adding another column to your table:
ALTER TABLE tasks
ADD COLUMN new_due_date DATE;
Then you use an UPDATE statement to fill this new column
UPDATE tasks
SET new_due_date = STR_TO_DATE(due_date, '%m/%d/%Y');
If you don't need your old column anymore then you can delete this column and modify the new column to have the name of the old one. Then you will have your table with all your data in a DATE column.
I have list of date in MySQL in the format of "MM-DD-YYYY" and When I was trying to fetch the latest date from table it just return the last date of a Year like 12-01-2014 instead of return latest date 03-16-2016.
Payment history table:
to_date
03-16-2016
12-01-2014
11-07-2014
10-03-2014
01-09-2014
I used following query:
SELECT MAX(to_date) FROM paymenthistory WHERE empid=59;
Result : 12-01-2014
Related post: Get the latest date from grouped MySQL data
Thanks in advance
You're working with strings, not native dates, so you're getting the maximum date.
Either convert those strings to ACTUAL mysql date/datetime values, or you'll have to go with ugly hacks, like
SELECT MAX(STR_TO_DATE(to_date, '%m-%d-%Y'))
and performance will be massively bad. MySQL's native date format is yyyy-mm-dd hh:mm:ss, which is a natural "most significant first" format. If your date strings were formatted like that, then even a max(string) would work.
It sounds like your date column is actually a VARCHAR format since it is seeing 12-01-2014 as the last date which is only true if stored as a VARCHAR.
Be sure your to_date column is a DATE type.
have you tried this?
SELECT TOP 1 * FROM paymenthistory WHERE empid = 29 ORDER BY to_date DESC;
For mysql try this
SELECT * FROM paymenthistory WHERE empid=59 ORDER BY to_date DESC LIMIT 1;
im having a problem where i cant think of a solution, maybe im having a bad table-structure or i just dont know enough about mysql select commands to think of a good solution. Maybe you can help me out:
So i got a table that has a Column with the Date-format (yyyy-mm-dd) i wanted to select all upcoming dates so i did:
SELECT * WHERE date >= now.
This worked kinda well but i also got "dates" where only the year is entered (2014-00-00) i also wanted to select these but "now" is already bigger so i made another column with the year only and if the month, date or both arent known i will use 0000-00-00 and the Column "year" now i could select like this:
SELECT * WHERE date >= now AND year >=now(year)
Now all entrys with 0000-00-00 wont be selected. If i use OR the entrys from last year will be shown.
So thats my problem, is there any way i can change my table so i can have entries with only the year or only year and month and of course all together? I already considered get rid of the date-format and use simple INT with seperated columns for year, month and date. But i think i will have the same problem.
Sometimes i just want to do a capsuled select like
SELECT *
WHERE (date >= now AND year >= now(year))
OR date == "0000-00-00" (i know that this doesnt work)
If I understood your problem correctly, you could use this request:
WHERE (date >= now OR year > now(year))
There is probably a simpler way though, that would preserve your design, like initializing at January 1st (01-01) instead of 00-00
I think you can use this code:
$_SESSION['month'] = //set here your selected month
$_SESSION['year'] = //set here your selected year
SELECT * FROM table WHERE DATEPART(m,date) >= '".$_SESSION['month']."' AND DATEPART(yyyy,year) >= '".$_SESSION['year']."' AND date <> '0000-00-00'
Change your table structure format. Actually just allow for that field to have null value when not entered. By default it will be null then. You shouldn't be storing 0000-00-00 as a value for Date type field. I would rather leave it as null , or as suggested in some of previous answers, initialize it with some other date. It would be much easier to manipulate with database then.
the problem is that half of you write is not MySQL and your database schema is terrible...
You have the following problems:
column data date does not have the date data type.
To fix it, you need to add a cast to the select statement eg. cast(datecolumn as date)
select * from table where cast(datecolumn as date) >= '2014-01-10';
the way to use now date is using the now function.
select now(), date(now());
result> 2014-01-10 11:11:36, 2014-01-10
select * from table where cast(datecolumn as date) >= date(now());
Because your datecolumn is not a date (2014-00-00 is not a valid date), you need to use string manipulation to extract the year.
select substring('2014-01-01', 1,4)
result> 2014
select * from table where substring(datecolumn, 1,4) = year(now());
The comparassion operator is = and not ==
the select statement syntax looks like this (pay attention because you are missing the table in your statement)
select * from [Table] where [column] = condition ...
You probably need or instead of ands, therefore your query should look like this:
select * from FooTable where
cast(datecolumn as date) >= date(now())
or substring(datecolumn, 1,4) >= year(now())
or datecolumn = '0000-00-00'
You should use something like phpmyAdmin or mySQL workbench to test your sql queries before try to use them on php, java or whatever is your programing language.
I just want to ask how can i filter a timestamp value in Mysql?
Let's say we have the following datetime as
1351128031
1351128045
1351128097
How can I create a date range using this format?
How can I perform this in a query?
Like this:
SELECT * FROM user
WHERE acct_created BETWEEN (datefrom) AND (dateto) -- my problem is I can't filter the timestamp
You want to use a mysql function called UNIX_TIMESTAMP http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_unix-timestamp
SELECT * FROM user
WHERE acct_created BETWEEN UNIX_TIMESTAMP('datefrom') AND UNIX_TIMESTAMP('dateto')
where datefrom and dateto are dates formated as string similar to '2012-01-01 00:00:00' in UTC
Here is the SQLFiddel Demo
Below is the MySQL Select Query :
select *,
UNIX_TIMESTAMP(`Timestamps`)
from Table1
where UNIX_TIMESTAMP(`Timestamps`) between 1351128040 and 1351128099
All Columns have a timestamp from that I can get that information. I tried already this
but I don't get it to work!!
if for example you want to group the number of occurences of a row by the hour part of the time stamp, try something like this (MySQL syntax):
select hour(TimeStamp) as interval, count(*) from data group by interval;
Did you try
... WHERE timestamp > 1305211123 AND timestamp < 1305215094
This is for unix timestamp of course, if you have datefield instead it's pretty similar though.