I am quite new to Groovy and I am parsing a JSON file with following code:
void getItemData()
{
def jsonSlurper = new JsonSlurper()
def reader = new BufferedReader(new InputStreamReader(new FileInputStream("data.json"),"UTF-8"));
data = jsonSlurper.parse(reader);
data.TESTS.each{println it.MEMBER_ID}
}
And I am getting printed properly the value of MEMBER_ID.
I want to Parameterize the above function like:
void getItemData(String item)
{
...
}
so that I can call this function with the desired item I want. For example: I want the MEMBER_ADDRESS. I want to call the function like:
getItemData("MEMBER_ADDRESS")
Now How I should change the statement:
data.TESTS.each{println it.MEMBER_ID}
I tried with
it.${item}
and some other ways not working.
Please teach me how to do it.
My JSON file is like below:
{
"TESTS":
[
{
"MEMBER_ID": "my name",
"MEMBER_ADDRESS": "foobarbaz",
}
]
}
Those here from google, looking for an answer to parse JSON File.
void getItemData(String item) {
def jsonSlurper = new JsonSlurper()
def data = jsonSlurper.parseText(new File("data.json").text)
println data.TESTS.each{ println it["$item"] }
}
getItemData("MEMBER_ADDRESS")
You need to add quotes around ${item} like:
import groovy.json.*
void getItemData(String item) {
def jsonSlurper = new JsonSlurper()
def reader = new BufferedReader(new InputStreamReader(new FileInputStream("/tmp/json"),"UTF-8"))
data = jsonSlurper.parse(reader)
data.TESTS.each { println it."$item" }
}
getItemData("MEMBER_ADDRESS")
Related
In a controller, how can I redirect json view output to a file instead of to the http response?
Grails 3.2.5.
You can do something like this...
#Autowired
JsonViewTemplateEngine templateEngine
void myMethod() {
Template t = templateEngine.resolveTemplate('/book/show')
def writable = t.make(book: new Book(title:"The Stand"))
def fw = new FileWriter(...)
writable.writeTo( fw )
...
}
Another simple option would be:
def action() {
def json = [ key1:'value1', key2:[ key21:'value21' ]
new File( '/the/path' ).withOutputStream{ it << ( json as JSON ) }
[ some:result ]
}
I'm new to groovy. I'm trying to split the values in json object in groovy but i cant seem to find a solution. Please find the sample code below
def inputFile = new File("C:\\graph.json")
def InputJSON = new JsonSlurper().parseFile(inputFile,'UTF-8')
InputJSON.each{println it}
def names = InputJSON.graph;
def name
for (int kk=0;kk<4;kk++)
{
name=names.JArray1[kk]
run.put(name.runid, name.rundetails);
println "test::"+name.runid+"--------------"+name.rundetails
}
graph.json
{
"graph": {
"JArray1": [
{
"runid": 1,
"rundetails":{
"01_Home":0.231,
"02_Login":0.561}
}
]
}
}
name.rundetails contains the below values
[01_Home:0.231, 02_Login:0.561]
I would like to split and add it as key and value in Hashmap like below format
Key:01_Home Value:0.231
Key:02_Login Value:0.561
How would i do that any advise on this would be helpful. Thanks in advance.
import groovy.json.*
def inputFile = new StringReader('''
{
"graph": {
"JArray1": [{
"runid": 1,
"rundetails": {
"01_Home": 0.231,
"02_Login": 0.561
}
}
]
}
}
''')
def json = new JsonSlurper().parse(inputFile)
json.graph.JArray1.each{run->
println "runid = ${run.runid}"
// at this point `run.rundetails` is a map like you want
println "details = ${run.rundetails}"
}
As I understand you need collection like:
[[Key:01_Home, Value:0.231], [Key:02_Login, Value:0.561]]
Then you may do:
println InputJSON.graph
.JArray1
.rundetails
.collectEntries{it}
.collect{[Key: it.key, Value: it.value]}
I am just two days old to groovy, I need to parse a json file with below structure. My actual idea is I need to run a set of jobs in different environments based on different sequences, so I came up with this format of json as a input file to my groovy
{
"services": [{
"UI-Service": [{
"file-location": "/in/my/server/location",
"script-names": "daily-batch,weekly-batch,bi-weekly-batch",
"seq1": "daily-batch,weekly-batch",
"seq2": "daily-batch,weekly-batch,bi-weekly-batch",
"DEST-ENVT_seq1": ["DEV1", "DEV2", "QA1", "QA2"],
"DEST-ENVT_seq2": ["DEV3", "DEV4", "QA3", "QA4"]
}]
}, {
"Mobile-Service": [{
"file-location": "/in/my/server/location",
"script-names": "daily-batch,weekly-batch,bi-weekly-batch",
"seq1": "daily-batch,weekly-batch",
"seq2": "daily-batch,weekly-batch,bi-weekly-batch",
"DEST-ENVT_seq1": ["DEV1", "DEV2", "QA1", "QA2"],
"DEST-ENVT_seq2": ["DEV3", "DEV4", "QA3", "QA4"]
}]
}]
}
I tried below script for parsing the json
def jsonSlurper = new JsonSlurper()
//def reader = new BufferedReader(new InputStreamReader(new FileInputStream("in/my/location/config.json"),"UTF-8"))
//def data = jsonSlurper.parse(reader)
File file = new File("in/my/location/config.json")
def data = jsonSlurper.parse(file)
try{
Map jsonResult = (Map) data;
Map compService = (Map) jsonResult.get("services");
String name = (String) compService.get("UI-Service");
assert name.equals("file-location");
}catch (E){
println Exception
}
I need to first read all the services (UI-service, Mobile-Service, etc..) then their elements and their value
Or you could do something like:
new JsonSlurper().parseText(jsonTxt).services*.each { serviceName, elements ->
println serviceName
elements*.each { name, value ->
println " $name = $value"
}
}
But it depends what you want (and you don't really explain in the question)
Example for reading from JsonParser object:
def data = jsonSlurper.parse(file)
data.services.each{
def serviceName = it.keySet()
println "**** key:${serviceName} ******"
it.each{ k, v ->
println "element name: ${k}, element value: ${v}"
}
}
other options:
println data.services[0].get("UI-Service")["file-location"]
println data.services[1].get("Mobile-Service").seq1
I am trying to build a REST service which accepts XML and convert it into JSON and call external Service which accepts JSON and put my JSON into it. I am able to put the json without pretty but I want to PUT the json in pretty format. Please suggest how to do, below is my code ...
package com.mypackge
import grails.converters.JSON
import grails.rest.RestfulController
import grails.plugins.rest.client.RestBuilder
class RestCustomerController extends RestfulController {
/*
static responseFormats = ['json', 'xml']
RestCustomerController() {
super(Customer)
}
*/
def index() {
convertXmlToJson()
}
def myJson = ''
def convertXmlToJson() {
def xml = ''' <Customer>
<customerid>9999999999999</customerid>
<ssn>8888</ssn>
<taxid>8888</taxid>
<address>
<addressline1>Yamber Ln</addressline1>
<addressline1>8664 SE</addressline1>
<city>CCCCC</city>
<state>CC</state>
<zipcode>97679</zipcode>
</address>
<firstname>Scott</firstname>
<middlename></middlename>
<lastname>David</lastname>
<account>
<accountno>576-294738943</accountno>
<accounttype>Lease</accounttype>
<accountsubtype></accountsubtype>
<accountstatus>complete</accountstatus>
<firstname>Scott</firstname>
<middlename></middlename>
<lastname>David</lastname>
<businessname></businessname>
<billingsystem>yoiuhn</billingsystem>
<brand></brand>
<plantype></plantype>
<billingaddress>
<addressline1>Yamber Ln</addressline1>
<addressline1>8664 SE </addressline1>
<city>CCCCC</city>
<state>CC</state>
<zipcode>97679</zipcode>
</billingaddress>
<job>
<jobid>8276437463728</jobid>
<jobstatus>SUCCESS</jobstatus>
</job>
</account>
</Customer>
'''.stripMargin()
// Parse it
def parsed = new XmlParser().parseText( xml )
def myId = parsed.customerid.text()
// Deal with each node:
def handle
handle = { node ->
if( node instanceof String ) {
node
}
else {
[ (node.name()): node.collect( handle ) ]
}
}
// Convert it to a Map containing a List of Maps
def jsonObject = [ (parsed.name()): parsed.collect { node ->
[ (node.name()): node.collect( handle ) ]
} ]
def json = new groovy.json.JsonBuilder(jsonObject) //.toPrettyString()
// Check it's what we expected
def mmyresp
try{
mmyresp = putRequest(myId,json)
}catch(Exception e) {
mmyresp = 'Please Validate JSON ....'
}
}
def putRequest(String id, JSON myJson) {
String url = "http://foo.com/customer/external/"+id
def rest = new RestBuilder()
def resp = rest.put(url){
contentType "application/json"
json{
myJson
}
}
return resp
}
}
The record is added in below format ...
{"Customer":[{"customerid":["9999999999999"]},{"ssn":["8888"]},
{"taxid":["8888"]},{"address":[{"addressline1":["Yamber Ln"]},
{"addressline1":["8664 SE"]},{"city":["CCCCC"]},{"state":["CC"]},{"zipcode":["97679"]}]},
{"firstname":["Scott"]},{"middlename":[]},{"lastname":["David"]},{"businessname":[]},
{"account":[{"accountno":["576-294738943"]},{"accounttype":["Lease"]},{"accountsubtype":[]},
{"accountstatus":["complete"]},{"firstname":["Scott"]},{"middlename":[]},{"lastname":["David"]},
{"businessname":[]},{"billingsystem":["yoiuhn"]},{"brand":[]},{"plantype":[]},
{"billingaddress":[{"addressline1":["Yamber Ln"]},{"addressline1":["8664 SE"]},
{"city":["CCCCC"]},{"state":["CC"]},{"zipcode":["97679"]}]},{"job":[{"jobid":["8276437463728"]},
,{"jobstatus":["SUCCESS"]}]}]}]}
But I want this to be inserted in pretty format. I tried .toPrettyString() but got casting exception when try to put as json. I am trying the REST services for the first time, not sure where I am doing wrong. Please suggest me on this.
You should set following field in you Config.groovy.
grails.converters.default.pretty.print = true
This will pretty print for both the xml and json.
you could optionally set it up for xml or json only like below:
For json:
grails.converters.json.pretty.print = true
For xml
grails.converters.xml.pretty.print = true
A sample of Config.groovy entry is:
environments {
development {
grails.converters.json.pretty.print = true
}
}
Hope it helps!!!
For Grails 4, try this:
def json = x as JSON
json.prettyPrint = true;
log.info(json.toString())
I have been experimenting with the groovy Jsonbuilder as you can see below trying to look at different ways to build JSON objects and arrays. After things started to make sense, I tried expanding to what is shown below. The question I have is, why does "content" show up in the json pretty string output? I actually have another json object displaying this.class information in json string outputs.
Any ideas? I'm new to this, so it could definitely be an obvious one.
def tt = ["test", "test1"]
def jjj = "jason"
def js3 = new groovy.json.JsonBuilder()
def js2 = new groovy.json.JsonBuilder(tt);
js3 hello: "$jjj", "$jjj": tt
def js4 = new groovy.json.JsonBuilder()
def result = js4([sdn: js3, openflow: js2, type: 3])
println js4.toPrettyString();
outputs:
{
"sdn": {
"content": {
"hello": "jason",
"jason": [
"test",
"test1"
]
}
},
"openflow": {
"content": [
"test",
"test1"
]
},
"type": 3
}
The problem can be restated as...
why does this:
import groovy.json.*
def js3 = new JsonBuilder(["test", "test1"])
def js4 = new JsonBuilder(js3)
println js4.toString()
print:
{"content":["test","test1"]}
and this:
import groovy.json.*
def js3 = new JsonBuilder(["test", "test1"])
def js4 = new JsonBuilder(js3.content)
println js4.toString()
prints this (?) :
["test","test1"]
The short answer is that JsonBuilder has a member named content, which represents the payload. When one JsonBuilder absorbs another, we want to replace the payload, and not nest it. This line is the way to replace the payload:
def js4 = new JsonBuilder(js3.content)
Ultimately, this stems from the fact that JsonBuilder.toString() (code here) calls JsonOutput.toJson(object) (code here).
An exercise for the reader is to experiment with:
class MyBuilder {
def content
}
def myB = new MyBuilder(content: ["test", "test1"])
println JsonOutput.toJson(myB)
println JsonOutput.toJson(myB.content)