Please consider two tables with names. They are joined by Table A id, so that two names get associated.
Is there a MySQL query that returns distinct pair of names regardless the order?
First table:
table_a
+-----------+--------------+
| id | name |
+-----------+--------------+
| 1 | John |
+-----------+--------------+
| 2 | Jane |
+-----------+--------------+
| 3 | Jane |
+-----------+--------------+
| 4 | Sammy |
+-----------+--------------+
Second Table:
table_b
+-----------+-------------------+-------------+
| id | id_table_a | name |
+-----------+-------------------+-------------+
| 1 | 1 | Jane |
+-----------+-------------------+-------------+
| 2 | 2 | John |
+-----------+-------------------+-------------+
| 3 | 3 | Sammy |
+-----------+-------------------+-------------+
| 4 | 4 | Tara |
+-----------+-------------------+-------------+
Desired result
(John, Jane)
(Jane, Sammy)
(Sammy, Tara)
Thanks in advance!
Here's one option using least and greatest:
select distinct least(a.name, b.name), greatest(a.name, b.name)
from table_a a
join table_b b on a.id = b.id_table_a
SQL Fiddle Demo
Related
I have two MySQL tables (table_a and table_b) and a join table (table_c).
Table Structures:
table_a:
__________________
| table_a: |
|----------------|
| id |
| result_column |
------------------
table_b:
__________________
| table_b: |
|----------------|
| id |
| name |
------------------
table_c:
__________________
| table_c: |
|----------------|
| id |
| table_a_id |
| table_b_id |
------------------
My Goal:
I want to find a query that will:
Iterate over every table_a record and get the table_a.id value
Find any records in table_c which have a matching table_c.table_a_id value
For each matching record in table_c get the table_c.table_b_id value
Find the record in table_b which has a matching table_b.id value
For that matching record in table_b get the table_b.name value
In table_a, concatenate each matched name value into the corresponding table_a.result_column
Example:
Before the Query:
_______________________ _________________________________ ________________
| table_a: | | table_c: | | table_b: |
|---------------------| |-------------------------------| |--------------|
| id | result_column | | id | table_a_id | table_b_id | | id | name |
|-----|---------------| |-----|------------|------------| |-----|--------|
| 1 | | | 1 | 1 | 3 | | 1 | Kevin |
| 2 | | | 2 | 1 | 4 | | 2 | Jesse |
| 3 | | | 3 | 2 | 2 | | 3 | Karen |
----------------------- | 4 | 3 | 1 | | 4 | Tim |
| 5 | 3 | 5 | | 5 | Lauren |
--------------------------------- ----------------
After the Query:
_______________________ _________________________________ ________________
| table_a: | | table_c: | | table_b: |
|---------------------| |-------------------------------| |--------------|
| id | result_column | | id | table_a_id | table_b_id | | id | name |
|-----|---------------| |-----|------------|------------| |-----|--------|
| 1 | Karen, Tim | | 1 | 1 | 3 | | 1 | Kevin |
| 2 | Jesse | | 2 | 1 | 4 | | 2 | Jesse |
| 3 | Kevin, Lauren | | 3 | 2 | 2 | | 3 | Karen |
----------------------- | 4 | 3 | 1 | | 4 | Tim |
| 5 | 3 | 5 | | 5 | Lauren |
--------------------------------- ----------------
For absolute clarity, I understand that this is incredibly bad practice within a relational data-table. This is as far from normalization as one can get. I would never design a database like this. I was tasked with creating a custom column with a list of values purely for a business case.
The query you seem to want is:
select c.table_a_id, group_concat(b.name separator ', ')
from c join
b
on c.table_b_id = b.id
group by c.table_a_id;
If you actually want to update a, you can put this into an update statement:
update a join
(select c.table_a_id, group_concat(b.name separator ', ') as names
from c join
b
on c.table_b_id = b.id
group by c.table_a_id
) cb
on cb.table_a_id = a.id
set result_column = cb.names
Previous answer is close; but you also required that you only want the records matched in table C that are in A.
The first query does not meet this requirement; but the update statement does, as it will only update records in table A, if the id matches the table_a_id value pulled from table C.
Given what you said you wished for the end result, the update statement above would work.
If you wish to be explicit in your logic, just add a join from table A to table C.
select a.id, group_concat(b.name separator ', ')
from a
join c ON (a.id = c.table_a_id)
join b ON (c.table_b_id = b.id)
group by a.id;
I need a help with mySQL SELECT query from multiple tables. I have got four tables: school, discipline, pupils and teams.
School table looks like:
+------+---------+---------------+----------+
| id | name | discipline_id | pupil_id |
+------+---------+---------------+----------+
| 1 | one | 2 | 5 |
+------+---------+---------------+----------+
| 2 | two | 3 | 8 |
+------+---------+---------------+----------+
| 3 | three | 4 | 12 |
+------+---------+---------------+----------+
Discipline table looks like:
+------+---------+
| id | name |
+------+---------+
| 1 | math |
+------+---------+
| 2 | bio |
+------+---------+
| 3 | liter |
+------+---------+
| 4 | geo |
+------+---------+
Teams table looks like:
+------+---------+---------------+-----------+
| id | name | school_id | member_id |
+------+---------+---------------+-----------+
| 1 | T1 | 1 | 3 |
+------+---------+---------------+-----------+
| 2 | T2 | 3 | 3 |
+------+---------+---------------+-----------+
| 3 | T3 | 2 | 9 |
+------+---------+---------------+-----------+
The result of disciplines I need to get with a "SELECT from discipline..." query by "member_id = 3" is:
+-----------------+---------------+
| discipline_name | discipline_id |
+-----------------+---------------+
| bio | 2 |
+-----------------+---------------+
| geo | 4 |
+-----------------+---------------+
By matching member's school and then getting its discipline, if it makes sense...Is it possible to do with just one mySQL query?
Type of: member_id 3 => school_id 1,3 => discipline_id = show related disciplines names and ids which are 2, 4
Thank you very much...
Your goal is not clear or makes no sense to me.
But here is what you are literally asking for:
SELECT
s.discipline_id
d.name
FROM teams t
LEFT JOIN school s
ON s.id = t.school_id
LEFT JOIN discipline d
ON d.id = s.discipline_id
WHERE t.member_id = 3
I have two tables (as seen bellow) and i want to join them and select the person who has multiple values form the second table. The first table is a list of all people and their unique IDs, the second table is a list of peoples favorite colors.
Table A.: Unique ID | Name
+-----+-------------+
| uid | name |
+-----+-------------+
| 321 | Ana |
| 662 | Nick |
| 003 | Fred |
+-----+-------------+
Table B.: Table ID | Unique ID | Color ID
+----------+--------+-----------+
| id | uid | color_id |
+----------+--------+-----------+
| 1 | 121 | 1 |
| 2 | 127 | 2 |
| 3 | 003 | 11 |
| 4 | 002 | 11 |
| 5 | 111 | 3 |
| 6 | 044 | 5 |
| 7 | 003 | 5 |
| 8 | 003 | 8 |
+----------+--------+-----------+
So i want to select only the users (uid) who matches all the colors given, for example 11 and 8 (red and fusia). In this case that would be user 003 | Fred, and only have 1 row per match, and not multiple (for each value).
I have tried using where color_id IN (x,y,z...) but this will return any person who has at least 1 color in the list
You can try below -
select uniqueid, name from tableA a
inner join tableB b on a.uniqueid=b.uid
where color_id in (11,8)
group by uniqueid, name
having count(distinct color_id)=2
you can do your wish by
select distinct tableA.uid, tableA.name tableB.color_id from tableA
inner join tableB on tableA.uniqueid=tableB.uid
group by tableA.uid , tableA.name ,tableB.color_id
having count(distinct color_id)=2
So in order to know how many people in a table are called Johnny I would need to excecute the following query.
Query:
Select count(*) from mytable where first = 'Johnny';
It would give me 2 as the result.
What I wish to do however is record this number in the count column so that the end result comes out like this.
+--------+----------+
| First | COUNT |
+--------+----------+
| Johnny | 2 |
| Diane | 1 |
| Johnny | 2 |
| Harold | 1 |
| Amy | 3 |
| Roy | 2 |
| Amy | 3 |
| Amy | 3 |
| Roy | 2 |
+--------+----------+
Is there any query or procedure capable of resulting in this type of output?
To get your exact output, you need to use a subquery:
select
mytable.First,
counts.`COUNT`
from
mytable
join (
select
First,
count(*) `COUNT`
from
mytable
group by
First
) counts on mytable.First = counts.First;
Try this:
SELECT T1.First, T2.COUNT
FROM mytable T1 JOIN
(SELECT First, COUNT(*) as COUNT
FROM mytable
GROUP BY First) as T2 ON T1.First=T2.First
The result will be:
+--------+----------+
| First | COUNT |
+--------+----------+
| Johnny | 2 |
| Diane | 1 |
| Johnny | 2 |
| Harold | 1 |
| Amy | 3 |
| Roy | 2 |
| Amy | 3 |
| Amy | 3 |
| Roy | 2 |
+--------+----------+
Lets say that I have something table like this:
<b>Name</b>
+---------+--------+
| name_id | name |
+---------+--------+
| 5 | Betti |
| 6 | Derry |
| 7 | Alfred |
| 8 | Elsie |
| 9 | Cinta |
+---------+--------+
<b>Goods</b>
+----------+-----------+
| goods_id | goods |
+----------+-----------+
| 1 | Computer |
| 2 | AC |
| 3 | Microwave |
| 4 | TV |
+----------+-----------+
<b>Transaction</b>
+-------+---------+----------+
| ai_id | name_id | goods_id |
+-------+---------+----------+
| 1 | 7 | 2 |
| 2 | 5 | 4 |
| 3 | 9 | 3 |
+-------+---------+----------+
I want to replace name_id column on Transaction table with name column on Name table with corresponding name_id column and so for goods_id to produce something similar to this table:
<b>Transaction</b>
+-------+--------+-----------+
| ai_id | name | goods |
+-------+--------+-----------+
| 1 | Alfred | AC |
| 2 | Betti | TV |
| 3 | Cinta | Microwave |
+-------+--------+-----------+
If you're looking to just display the information rather than actually "replacing" your tables with new ones, then you could use a SELECT query with a simple INNER JOIN. This way you can display columns from multiple tables.
SELECT T.ai_id, N.Name, G.goods
FROM Transaction T
INNER JOIN Name N ON N.name_id = T.name_id
INNER JOIN Goods G ON G.goods_id = T.goods_id;
Try with inner join
SELECT T.ai_id,N.name,G.goods
FROM Transaction as T
INNER JOIN Goods as G ON T.goods_id = G.goods_id
INNER JOIN Name as N ON N.name_id = T.name_id;
Try this one
select tb3.ai_id,tb2.name,tb1.goods from Goods tb1,Name tb2,Transaction tb3 where tb3.name_id=tb2.name_id and tb3.goods_id=tb1.goods_id order by tb3.ai_id
try this:
SELECT C.ai_id,A.name,B.goods
FROM Transaction C
INNER JOIN Name A
ON A.name_id=C.name_id
INNER JOIN Goods B
ON B.goods_id=C.goods_id;
http://sqlfiddle.com/#!2/3c5f3/8