Rails DateTime helper logic - mysql

Quick question. I am using the distance_of_time_in_words helper to check how many days an object was created. This works fine but I dont want it to have to go 24 hrs before it counts a day but want it to count "1" day once it is "00:00"
eg distance_of_time_in_words("2016-08-11 11:00", "2016-08-12 00:00") should be 1 day but it is 13 hrs
I want that once it passes "00:00" it should count as a 1 day?

You may be able to use
time_ago_in_words(date_item_was_created.at_midnight)
time_ago_in_words allows you to forgo adding the 'now' time* and by moving the created-at date back to midnight, you'll cross the one-day mark
at the next midnight. According to the API doc, it should give you 'round' days for anything over a day, which sounds like what you're after.
*You can continue to use distance_of_time_in_words if you're not comparing to the current time.

This is what you meant I guess.
def distance_of_time_in_words(time1,time2)
d1 = Time.parse(time1.to_s).to_date.strftime("%d").to_i
d2 = Time.parse(time2.to_s).to_date.strftime("%d").to_i
seconds = Time.parse(time2.to_s)- Time.parse(time1.to_s)
hours = seconds/3600
if d2-d1 >= 1
return "#{(d2-d1).to_s} days"
else
return "#{hours.to_s} hours"
end
end

Related

Calculate Overtime Based On StartTime And StopTime

I have a table where I register the duration of events that take place in an Auditorium of the company I work in. The table has all the event data includind the TimeStart field and TimeEnd field.
Our technician shift ends at 6pm.
So if an event duration ends beyond 6pm, I need to track the overtime the technician worked.
Can anyone help me with this matter?
Thanks to everyone in advance,
Hope your all safe.
That will be:
ShiftEnd = #06:00:00 PM#
Overtime = CDate(DurationEnd - ShiftEnd)
If over-Midnight may be expected, as one day:
Overtime = TimeValue(CDate(1 + DurationEnd - ShiftEnd))
The "magic" here is due to the nature of data type Date around numeric zero:
MS Access Can Handle Millisecond Time Values--Really : Page 2
Notice the graph: Firgure 1.
Overtime will be counted in days. To obtain an hour value, multiply by 24.

How can I tell how many minutes have passed between Now() and 7am that day?

Basically I just need to know how much time has passed from a certain time that day till Now() this will be run on a timer throughout the day and used to determine when something should be run (this might seem odd but there is logic behind it).
The issue with the code below is that it gives me a very high negative number. I can only assume that this is caused from the TimeSerial not actually containing a date and only the time so it throws everything off.
Can anyone point me in the direction of a way to do what I want? I am certain that the answer is something super simple that I am missing but I haven't been able to find it.
DateDiff("n",Now(),TimeSerial(07,0,0))
You want the number of minutes from 7 AM until now. Your DateDiff had those two swapped around and that's why you got a negative value.
The reason the magnitude of that number was so large is you were asking for the difference between 07:00 on Dec 30 1899 and today. This is what that TimeSerial expression gives you ...
? Format(TimeSerial(07,0,0), "mmm d yyyy, hh:nn:ss")
Dec 30 1899, 07:00:00
I think this is what you want instead ...
DateDiff("n", Date + #07:00#, Now)

Past 5 week calculation in WEBI (BO 4.0)?

I am facing issue in calculating past 5 week data based on current date (excluding currrent week)
For e.g:
Suppose we are in 40th week of this year, I need to get the sum of all the transactions for the previous 5 weeks (39, 38, 37, 36 & 35).
Currently calculating based on the calendar day but as Calendar day is giving the granular level of data, inorder to increase the performance I need to use the calendar week (sample data like (2012/40).
Is there a way to do this?
I'd construct a flag field (either in the back-end or in the universe) using datediff (in SQL Server terms).
Failing that, you could construct a variable in Web Intelligence using the Week function.
Pseudo-code but something like:
=IF(Transaction_Date < Week(CurrentDate()) AND Transaction_Date >= (Week(CurrentDate())-5); "TRUE"; "FALSE")

Get the next xx:30 time (the next half-past hour) after a specified time

I'm trying to find a MySQL query which will obtain the time that is the next half-past-the-hour from a specified datetime. I explicitly mean the next half-past-the-hour, not the next half-hourly point.
So for instance:
If the datetime was "2009-10-27
08:15:24", the answer would be
"2009-10-27 08:30:00"
If the
datetime was "2009-10-27 08:49:02",
the answer would be "2009-10-27
09:30:00".
I came across this page which refers to SQL Server, and towards the end of that thread there is a similar sort of problem. But it's not quite the same, and it relies on a function that MySQL doesn't have.
Here is a fuller list of examples and expected return values:
2009-10-27 08:15:24 should return 2009-10-27 08:30:00
2009-10-27 08:49:02 should return 2009-10-27 09:30:00
2009-10-27 23:49:10 should return 2009-10-28 00:30:00
2009-10-27 10:30:00(.000001) should return 2009-10-27 11:30:00
(Note how, in the fourth example, because the exact half-past (10:30:00.0000000) has already gone, the next half-past-the-hour point is found.)
I tried using this kind of thing:
SELECT IF( (MINUTE(NOW()) < 30), HOUR(NOW()), (HOUR(NOW()) + 1) )
(after which addition of a CONCATed string would take place), but it would fail because of the changeover to another day, and it feels inherently 'hacky'.
Can anyone suggest a suitable sort of algorithm? I wouldn't expect a full answer (though that would be nice!), but suggestions as to the kind of algorithm would be helpful. I've been drawing over bits of paper for two hours now! I have a hunch that using modulo might be useful but I'm not sufficiently familiar with using it.
The answer will be fed to a PHP class later, but I'd rather implement this at SQL level if possible, as the rest of query also performs other date comparison functions efficiently.
This is a little messy, but works:
select from_unixtime( floor((unix_timestamp(MY_DATE)+(30*60))/(60*60))*(60*60) + (30*60) )
It pushes the time forward 30 minutes, then truncates to the top of the hour, then adds 30 minutes to it. Because it's working unix timestamps (seconds since 1970), you don't have to worry about the boundaries of days, months, years, etc.
I can't help but notice that this would be much easier at the PHP level :-) That said, here's what you can do:
Add 30 minutes to your datetime using DATE_ADD(); this will move to the next hour if it's already past half-hour
Create a new datetime value by extracting date / hour and hard coding minutes / seconds. CONVERT(), ADDTIME() and MAKETIME() all help.
The end result is:
select ADDTIME(
CONVERT(DATE(DATE_ADD(yourDateTime, INTERVAL 30 MINUTE)), DATETIME), # date part
MAKETIME(HOUR(DATE_ADD(yourDateTime, INTERVAL 30 MINUTE)), 30, 0) # hour + :30:00
) from ...
Use the MAKETIME(hour,minute,second) function to construct the desired value.

Get the week number from a given date

Examples:
'DD/MM/YYYY
"1/1/2009" should give `1`
"31/1/2009" should give `5`
"1/2/2009" should also give `5`
Format("1/2/2009", "ww") returns 6.
So, how can I get the correct result?
It's doing two things here which don't match your expectations, I think:
Assuming you want the week with Jan 1 in as week 1, and using Sunday as first day of the week
So it has week 1 running from Sunday 28th December 2008 to Saturday 3rd Jan 2009.
Week 6 would begin on Sunday 1st Feb by this method.
The ISO standard is for week 1 to be the one containing 4 days of January, or the first Thursday of the year (different ways of expressing the same thing).
You can specify this method of calculation and the first day of the week:
Format(SomeDate,"ww",vbMonday,vbFirstFourDays)
see here for syntax:
https://support.office.com/en-US/article/Format-Function-6F29D87B-8761-408D-81D3-63B9CD842530
Regardless of the day of the week your week starts on, you need to pass unambiguous date values. "31/1/2009" can only be one date (Jan 31st), but "1/2/2009" could be Jan. 2 (US style) or Feb. 1st (everybody else who has more sense that we USAns).
In this case, I'd use DateSerial() to make sure the date is not misinterpreted:
Format(DateSerial(2009,2,1), "ww", vbMonday)
While this is not causing your problem, because Access helpfully utilizes your system's localized date settings, I think it's something you should do anyway. You certainly are forced to do so in SQL in Access, so I don't think it's a bad habit in code and expressions.
This might work: Format(YourDate, "ww",vbMonday)
"Correct result" depends on the locale. Maybe VBA will let you pick a calendar-system, otherwise you're pretty much out of luck.
Note that First-Day-On-xxDay isn't your only problem. There is also variation on what a complete week is so Week 1 in one system could be Week 53 of the previous year in another system.
So test thoroughly and don't be seduced to "correct by 1".
There is a whole standard for week numbers: ISO-8601
http://en.wikipedia.org/wiki/ISO_8601#Week_dates
I had the same problem.
It showed week 53 and week 1, yet days in week 53 and week 1 are all in week 1
I first tried changing the date format in the Access Query to this:
OrderWeek: Format([OrderDate],"yyyy-ww",1,3) <-- But it did not do the trick.
You get dates like 2014-52 for week 52 and 2015-52 where it was week 1 before.
Also the sorting was not how I liked. It sorted the data as 2014-1, 2014-11, 2014-2 etc. I want it to show as 2014-01, 2014-02 .. 2014-11 etc.
So here is the new code to display both the year and the week correctly in an Access Query:
ActualWeek: IIf(DatePart("ww",[SomeDate])=53,DatePart("yyyy",[SomeDate])+1,DatePart("yyyy",[SomeDate])) & "-" & IIf(DatePart("ww",[SomeDate])=53,"01",IIf(DatePart("ww",[SomeDate])<10,"0" & DatePart("ww",[SomeDate]),DatePart("ww",[SomeDate])))
This now shows any days from week 53 as being part of week 1
If sunday is the first day of the week (as it is in some locales) then 6 is the correct weeknumber for "1/2/2009" (february 1. 2009)
In terms of the sorting, I had the same issue and used this code to resolve it:
IIf(Format([SomeDate],"ww")<10,Format([SomeDate],"yyyy-") & "0" & Format([SomeDate],"ww"),Format([SomeDate],"yyyy-ww"))
If the week number is less than 10, add a zero, else leave it as is.
Now the sorting is fine. Hope this helps somebody.