Error in if...end-if stored procedure in mysql - mysql

Question

drop procedure if exists test;
delimiter $$
create procedure `test`()
begin
DECLARE done INT DEFAULT FALSE;
DECLARE i1 VARCHAR(20);
DECLARE i2 DATE;
DECLARE i3 VARCHAR(20);
DECLARE i4 INT;
DECLARE curs1 CURSOR FOR SELECT * FROM test11;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
OPEN curs1;
FETCH curs1 INTO i1,i2,i3,i4;
if i4=22 then
insert into test1(abc) values(i1);
end if ;
CLOSE curs1;
end ;
;;
delimiter ;
above throws an error : SQL Error [1064] [42000]: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 14
create table test11(abc varchar(20), cde varchar(20), eg varchar(20), asda varchar(20));
insert into test11 values("Hello",'1989-08-09','sdads','22');
create table test1(abc varchar(20), cde int(20), eg date, asda varchar(20));
I don't what i am doing wrong. Syntax seems to be fine.
drop procedure if exists sp;
CREATE PROCEDURE sp()
BEGIN
DECLARE intoffer INT;
SELECT max(asda) INTO intoffer FROM test11;
IF (intoffer IS NULL) THEN
SET intoffer = 1;
ELSE
SET intoffer = intoffer + 1;
END IF;
INSERT INTO test1 (asda) VALUES (intoffer);
end;
This is another procedure throwing same error. After removing the if..end-if both the code seems to work fine.

Answer 1

You are Missing fetch from
drop procedure if exists test;
delimiter $$
create procedure `test`()
begin
DECLARE done INT DEFAULT FALSE;
DECLARE i1 VARCHAR(20);
DECLARE i2 DATE;
DECLARE i3 VARCHAR(20);
DECLARE i4 INT;
DECLARE curs1 CURSOR FOR SELECT * FROM test11;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
OPEN curs1;
insertLoop: LOOP
FETCH FROM curs1 INTO i1,i2,i3,i4;
if i4=22 then
insert into test1(abc) values(i1);
end if ;
END LOOP insertLoop;
CLOSE curs1;
end ;
;;
delimiter ;