45 Degree Angle cut on divs - html

I'm trying to cut out the top right corner of most of my div elements on my site. These divs are all different sizes. I'm trying to find a responsive way of doing this. I ran into this site here: http://bennettfeely.com/clippy/ which allows you to cut out a custom polygon shape.
Here is what I have so far:
div {
width: 280px;
height: 280px;
background: #1e90ff;
-webkit-clip-path: polygon(0% 100%, 100% 100%, 100% 9%, 89% 0%, 0% 0%);
clip-path: polygon(0% 100%, 100% 100%, 100% 9%, 89% 0%, 0% 0%);
}
/* Center the demo */
html, body { height: 100%; }
body {
background-image: url('http://www.planwallpaper.com/static/images/recycled_texture_background_by_sandeep_m-d6aeau9_PZ9chud.jpg');
display: flex;
justify-content: center;
align-items: center;
}
<div></div>
My question is I'm trying to read these clippings and find out how to make the perfect 45 degree angle cut off the top right corner. As of right now this polygon was created by me freehand. And I'm trying to see what percentages I would need to use to make the perfect 45 degree angle cut from the top right.
With the solution I will be adding the cutoff to most of my divs, buttons, and images.
I found other ways of doing this on Stack Overflow using border-left and right with absolute position, but the problem is I need the div cutoff to be transparent because some of them have background images behind it.
Here is a JS Fiddle that's set up: https://jsfiddle.net/xyvz5z8m/1/

You should be able to do an exact 45 degree clip by using CSS calc, to work out the positions to clip from, instead of the percentages. e.g.
-webkit-clip-path: polygon(0% 100%, 100% 100%, 100% 30px, calc(100% - 30px) 0%, 0% 0%);
clip-path: polygon(0% 100%, 100% 100%, 100% 30px, calc(100% - 30px) 0%, 0% 0%);
div {
width: 100px;
height: 100px;
background: #1e90ff;
-webkit-clip-path: polygon(0% 100%, 100% 100%, 100% 30px, calc(100% - 30px) 0%, 0% 0%);
clip-path: polygon(0% 100%, 100% 100%, 100% 30px, calc(100% - 30px) 0%, 0% 0%);
/* Resizing this div just to show that this will remain at 45 degrees */
animation: resize 5s infinite;
}
html, body {
height: 100%;
}
body {
background: #ededed;
display: flex;
justify-content: center;
align-items: center;
}
#keyframes resize {
0% { width: 100px; height: 100px; }
25% { width: 50px; height: 100px; }
50% { width: 50px; height: 50px; }
75% { width: 150px; height: 50px; }
100% { width: 100px; height: 100px; }
}
<div></div>
The key part being that we use pixel sizes for the positioning of the clipped area, and calc(100% - 30px) to get an exact position from the far side of the element, though bare in mind this may have very limited browser support.

Related

Clip path seems to be broken

I am working on a project where I need to use a Polygon shaped container. I managed to make it work on chrome with -webkit-clip-path. I know that i have to use a other class name to make it work on Firefox. I tried moz-clip-pathbut that didn't seem to work. I will leave a code sample so that you can try it out yourself.
I am thankful for any suggestions
display: block;
margin: 0 auto;
position: relative;
width: 352px;
height: 304px; /* width * 0.866 */
background: #333333;
box-sizing: border-box;
-webkit-clip-path: polygon(
0% 50%,
25% 0%,
75% 0%,
100% 50%,
75% 100%,
25% 100%
);
-moz-clip-path: polygon(0% 50%, 25% 0%, 75% 0%, 100% 50%, 75% 100%, 25% 100%);
}

How to add a gradient on top of a sliced div? [duplicate]

This question already has answers here:
Cut Corners using CSS
(16 answers)
Closed 1 year ago.
Basically, I have this CSS code that uses a linear gradient to cut a 45-degree chunk out of the corner of my div. However, I want to apply a gradient to the top of the div with the transparent part still there.
What I want
What I have
This is the code I have in CSS
.sectionlabel {
position: absolute;
width: 100%;
color: white;
height: 35px;
top: -35px;
border-top-left-radius: 6px;
background: linear-gradient(225deg, transparent 10px, #676767 0);
}
I'm not completely sure what to add to this to overlay a gradient onto the div.
All help is appreciated!
Thanks,
GraysonDaMighty
Consider using clip-path to cut the edge of an angle.
div {
height: 35px;
width: 200px;
-webkit-clip-path: polygon(0% 100%, 100% 100%, 100% 10px, calc(100% - 10px) 0%, 0% 0%);
clip-path: polygon(0% 100%, 100% 100%, 100% 10px, calc(100% - 10px) 0%, 0% 0%);
background-image: linear-gradient(0deg, black, gray 80%);
}
<div></div>

How to calculate the proportion between vw and vh in CSS

I've been working on a website and as I'm trying to use the clip-path property in a div in order to create an arrow shape which I intend for it to be a right triangle, I'm getting this result by now:
.aboutus {
width: 100%;
height: 50vh;
position: relative;
background: #589AB8;
clip-path: polygon(0% 100%, 40% 100%, 50% 50%, 60% 100%, 100% 100%, 100% 0%, 0% 0%);
}
<div id="aboutus" class="aboutus">
</div>
I want to know if there is a way in which I can obtain the proportion between vh and vw (vh/vw) to get to mantain the proportion of the triangle sides for any viewport, without it deformating when I change the viewport size.
Or if you have any suggestions for it to mantain the shape, I will welcome it.
Thanks
The calc() function mgiht help
The calc() CSS function lets you perform calculations when specifying CSS property values. It can be used anywhere a <length>, <frequency>, <angle>, <time>, <percentage>, <number>, or <integer> is allowed.
a triangle always of 20px/30px
.aboutus {
width: 100%;
height: 50vh;
position: relative;
background: #589AB8;
clip-path: polygon(0% 100%, calc(50% - 20px) 100%, 50% calc(100% - 20px ), calc(50% + 20px) 100%, 100% 100%, 100% 0%, 0% 0%);
}
<div id="aboutus" class="aboutus">
</div>
a triangle set from vmin
.aboutus {
width: 100%;
height: 50vh;
position: relative;
background: #589AB8;
clip-path: polygon(0% 100%, calc(50% - 10vmin) 100%, 50% calc(100% - 10vmin ), calc(50% + 10vmin) 100%, 100% 100%, 100% 0%, 0% 0%);
}
<div id="aboutus" class="aboutus">
</div>
a triangle set from vmax
.aboutus {
width: 100%;
height: 50vh;
position: relative;
background: #589AB8;
clip-path: polygon(0% 100%, calc(50% - 5vmax) 100%, 50% calc(100% - 5vmax), calc(50% + 5vmax) 100%, 100% 100%, 100% 0%, 0% 0%);
}
<div id="aboutus" class="aboutus">
</div>
a mix of vh/vw ?, maybe what you try to do ?
.aboutus {
width: 100%;
height: 50vh;
position: relative;
background: #589AB8;
clip-path: polygon(0% 100%, calc(50% - (5vh + 2.5vw)) 100%, 50% calc(100% - (5vh + 2.5vw)), calc(50% + (5vh + 2.5vw)) 100%, 100% 100%, 100% 0%, 0% 0%);
}
<div id="aboutus" class="aboutus">
</div>
In addition to the answer of #G-Cyrillus that I recommend you can consider the use of mask and some CSS variables to easily control the shape and maintain the proportion.
.aboutus {
--angle:45deg;
--d:10vh;
height: 50vh;
background: #589AB8;
margin:5px;
--g:transparent var(--d),#fff calc(var(--d) + 1px);
-webkit-mask:
linear-gradient( var(--angle) ,var(--g)) right,
linear-gradient(calc(-1*var(--angle)),var(--g)) left ;
-webkit-mask-size:50% 100%;
-webkit-mask-repeat:no-repeat;
mask:
linear-gradient( var(--angle) ,var(--g)) right,
linear-gradient(calc(-1*var(--angle)),var(--g)) left ;
mask-size:50% 100%;
mask-repeat:no-repeat;
}
<div class="aboutus"></div>
<div class="aboutus" style="--angle:60deg;"></div>
<div class="aboutus" style="--angle:30deg;--d:30px;"></div>

Keep image not rotation when skew?

I want to cut small element in an image. So, I am using skew to do this.
But when to skew, the image seems broken, I want to keep image is not rotation.
My code like this:
.image-skew{
/* transform: skewX(-25deg); */
position: absolute;
width: 100%;
height: auto;
}
.img-skew-invest {
transform: skewX(-25deg);
display: flex;
}
<div class="image-skew">
<img class="img-skew-invest" src="http://thebusiness.vn/uploads/business360/chuyenkinhdoanh/lazada-co-noi-got-foodpanda-roi-khoi-viet-nam/lazada-co-noi-got-foodpanda-roi-khoi-viet-nam.png" alt="" style="width: 100%; height: auto"/>
</div>
Same image.
I cut an element of the picture with skew, but it should be a not rotation.
clip-path will match your requirement:
.image-skew {
-webkit-clip-path: polygon(25% 0, 100% 0, 100% 75%, 75% 100%, 0 100%, 0% 25%);
clip-path: polygon(25% 0, 100% 0, 100% 75%, 75% 100%, 0 100%, 0% 25%);
}
Try it yourself: https://jsfiddle.net/hgzsr5f5/1/ or try clip-path generator: http://bennettfeely.com/clippy/

Triple 'Rhomboid' Image Split CSS

I'm trying to re-design a website homepage.
How can I split the full screen background image currently being used into 3 sections, with a gap between each with the image only being shown within the Rhomboid shape?
I've looked around and have found the CSS + HTML to create the Rhomboid with the image inside however it's the whole image and only one of these Rhomboid shapes.
.polygon-each {
padding: 10px;
text-align: center;
}
.polygon-each-img-wrap img {
margin-bottom: 10px;
}
.polygon-each img {
display: block;
margin-left: auto;
margin-right: auto;
}
}
img {
max-width: 100%;
height: auto;
}
.polygon-clip-rhomboid {
-webkit-clip-path: polygon(0% 100%, 30% 0%, 100% 0%, 70% 100%);
clip-path: polygon(0% 100%, 30% 0%, 100% 0%, 70% 100%);
-webkit-clip-path: url("#polygon-clip-rhomboid");
clip-path: url("#polygon-clip-rhomboid");
}
<div class="polygon-each">
<div class="polygon-each-img-wrap">
<img src="/img/rules-bgrnd.png" alt="demo-clip-rhomboid" class="polygon-clip-rhomboid">
</div>
<svg class="clip-svg">
<defs>
<clipPath id="polygon-clip-rhomboid" clipPathUnits="objectBoundingBox">
<polygon points="0 1, 0.3 0, 1 0, 0.7 1" />
</clipPath>
</defs>
</svg>
</div>
A view of what is currently shown can be seen here
One way you could do this is just by utilizing a more complex clipping path that has three rhomboids in it. There are some tools that help you "draw" the path you want and generate the CSS for you, http://bennettfeely.com/clippy/ is one I was able to find, but there seem to be more as well.
Essentially, you want your path to have points positioned in a way where it looks like you're creating three different shapes, even though it's all one clip.
.polygon-each {
padding: 10px;
text-align: center;
}
.polygon-each-img-wrap img {
margin-bottom: 10px;
width:100%;
-webkit-clip-path: polygon(0% 100%, 15% 0, 33% 0%, 18% 100%, 32% 100%, 46% 0, 66% 0, 52% 100%, 68% 100%, 80% 0%, 100% 0%, 91% 100%);
clip-path: polygon(0% 100%, 15% 0, 33% 0%, 18% 100%, 32% 100%, 46% 0, 66% 0, 52% 100%, 68% 100%, 80% 0%, 100% 0%, 91% 100%);
}
.polygon-each img {
display: block;
margin-left: auto;
margin-right: auto;
}
}
img {
max-width: 100%;
height: auto;
}
https://jsfiddle.net/bjc89nkv/
There's a quick and messy demo of what I was able to "draw" to create such an effect.