select x,
count(case when i='abc' then 1 else null end) as ele1,
count(case when i='def' then 1 else null end) as ele2,
sum(ele1+ele2) as sum1 from (INNER QUERY)
When i am using sum(ele1+ele2), it is throwing error that ele1 not found. How to fetch sum1 in the same query without using any other outer query?
You can't use alias as column name in select
select x,
count(case when i='abc' then 1 else null end) as ele1,
count(case when i='def' then 1 else null end) as ele2,
sum( ( case when i='abc' then 1 else null end ) +
( case when i='def' then 1 else null end ) ) as sum1
from (INNER QUERY)
You cannot use alias as a column name, but if your concern is in verboseness - in your particular case you can write something like below, which is easy readable and skinny enough (for BigQuery Legacy SQL)
SELECT
SUM( i ='abc' ) AS ele1,
SUM( i = 'def' ) AS ele2,
SUM( i IN ('abc', 'def') ) AS sum1
FROM (INNER QUERY)
Related
new to MySQL..so pls help me out with this basic code..
i have a query something like this...
select weekofyear(id_time),
(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
and it gives correct results as--here
however i want to use sum after case when statement so that I can get total values where BO=1 and group by week of year , so i made following changes-
select weekofyear(id_time),
count(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
sum(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
group by weekofyear(id_time)
but it always returns 0 as output.
Output --here 2
Please help , I don't know what am I doing wrong here.
Thanx !
As others have already said, session variables can be unpredictable (especially when aggregation gets mixed in). That said, it doesn't look like you're using the session variables to carry over values from one row to the next (as is often done), but to just make aliases of sorts for calculations you don't want to repeat.
A better way to handle that is just through subqueries.
SELECT woy, id, Tat1, Tat2, check1, check2
, CASE
WHEN check2=0 THEN (
CASE
WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+10))) THEN 1
ELSE 0
END
)
ELSE (
CASE WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+20))) THEN 1
ELSE 0
END
)
END AS BO
FROM (
SELECT WEEKOFYEAR(id_time) AS woy
, id
, exp1 AS Tat1
, exp2 AS Tat2
, exp3 AS check1
, exp4 AS check2
FROM datb
WHERE cid=18
AND id_time BETWEEN '2019-11-01 06:00:00' AND '2019-11-25 06:00:00'
) AS subQ
;
You can then tweak the above query for aggregation, or use it as a subquery for an aggregating outer query.
I have seperate queries but i need to reduce the no so put all in one
select count(applicant_id) as registered from student_application where filter_status=0 AND
select count(applicant_id) as filer_select from student_application where filter_status=1 AND
select count(applicant_id) as filter_reject from student_application where filter_status=2
but this shows some errors
Use CASE expression.
Query
select
count(case when filter_status = 0 then applicant_id else null end) as registered,
count(case when filter_status = 1 then applicant_id else null end) as filer_select,
count(case when filter_status = 2 then applicant_id else null end) as filer_reject
from student_application;
SQL Fiddle
You could also use group_by, with the where clause if you're looking for a subset rather than all possible values of filter_status:
SELECT filter_status, COUNT(*)
FROM student_application
WHERE filter_status in (0, 1, 2)
GROUP BY filter_status;
I'm having trouble writing a SQL query to show the status of a row as it's own column as shown in the picture.
I was thinking of using an alias for Status as:
SELECT 'Table A.Date', 'Table A.Status' as ... FROM Table A;
But this doesn't resolve the issue on how to display each status type as their own column and number value.
Can someone point out how to do this?
Try this one. I used CASE statement to conditionally count the status as one depending on the status type given.
SELECT
Date,
SUM(CASE WHEN Status='Pending' THEN 1 ELSE 0 END)Pending,
SUM(CASE WHEN Status='Completed' THEN 1 ELSE 0 END)Completed,
SUM(CASE WHEN Status='Cancelled' THEN 1 ELSE 0 END)Cancelled
FROM Table A
WHERE Date='2014-01-01'
GROUP BY Date
Try this:
select A.date,
count(
case
when A.Status='Pending'
Then 1
Else NULL
End
) as Pending,
count(
case
when A.Status='Completed'
Then 1
Else NULL
End
) as Completed,
count(
case
when A.Status='Cancelled'
Then 1
Else NULL
End
) as Cancelled
From A
group by A.date
While I was preparing an answer to one of our fellows here on SO I've encounter an odd situation, at least to me. The original question is here: Pivot Table Omitting Rows that Have Null values
I've modified the query to use max instead of group_concat in order to show the "problem" in all databases.
SELECT
id,
max(case when colID = 1 then value else '' end) AS fn,
max(case when colID = 2 then value else '' end) AS ln,
max(case when colID = 3 then value else '' end) AS jt
FROM tbl
GROUP BY id
The result of this query is this:
ID FN LN JT
1 Sampo Kallinen Office Manager
2 Jakko Salovaara Vice President
3 (null) Foo No First Name
The user asks to filter the row with id 3 because the field value is null.
When it seems pretty obvious that only it needs to do was to add a WHERE value IS NOT NULL constraint on that query to achieve what the user expect. It won't work.
So I start to test it on the other databases to see what happens (Queries with the WHERE CLAUSE)
SELECT
id,
max(case when colID = 1 then value else '' end) AS fn,
max(case when colID = 2 then value else '' end) AS ln,
max(case when colID = 3 then value else '' end) AS jt
FROM tbl
WHERE value is not null
GROUP BY id
Mysql: http://sqlfiddle.com/#!2/78395/1
Postgres: http://sqlfiddle.com/#!15/78395/1
SQLServer: http://sqlfiddle.com/#!6/78395/1
Oracle: http://sqlfiddle.com/#!4/78395/1
For my surprise the result was the same, none worked.
Then I tried a different version of the same query:
SELECT * FROM (
SELECT
id,
max(case when colID = 1 then value else '' end) AS fn,
max(case when colID = 2 then value else '' end) AS ln,
max(case when colID = 3 then value else '' end) AS jt
FROM tbl
GROUP BY id
) T
WHERE fn IS NOT NULL
AND ln IS NOT NULL
AND jt IS NOT NULL
Oracle: http://sqlfiddle.com/#!4/78395/2 WORKED
MySql: http://sqlfiddle.com/#!2/78395/2
Postgres: http://sqlfiddle.com/#!15/78395/2
SQLServer: http://sqlfiddle.com/#!6/78395/2
The only way I could make it work on all databases was with this query:
SELECT
id,
max(case when colID = 1 then value else '' end) AS fn,
max(case when colID = 2 then value else '' end) AS ln,
max(case when colID = 3 then value else '' end) AS jt
FROM tbl
WHERE NOT EXISTS (SELECT * FROM tbl b WHERE tbl.id=b.id AND value IS NULL)
GROUP BY id
So I ask:
What is happening here that except for that specific case on Oracle all other DBs seem to ignore the IS NOT NULL filter?
To omit the row from the result if any of the source rows for the same id has value IS NULL, a solution in Postgres would be to use the aggregate function every() or (synonym for historical reasons) bool_and() in the HAVING clause:
SELECT id
, max(case when colID = 1 then value else '' end) AS fn
, max(case when colID = 2 then value else '' end) AS ln
, max(case when colID = 3 then value else '' end) AS jt
FROM tbl
GROUP BY id
HAVING every(value IS NOT NULL);
SQL Fiddle.
Explain
Your attempt with a WHERE clause would just eliminate one source row for id = 3 in your example (the one with colID = 1), leaving two more for the same id. So we still get a row for id = 3 in the result after aggregating.
But since we have no row with colID = 1, we get an empty string (note: not a NULL value!) for fn in the result for id = 3.
A faster solution in Postgres would be to use crosstab(). Details:
PostgreSQL Crosstab Query
Other RDBMS
While EVERY is defined in the SQL:2008 standard, many RDBMS do not support it, presumably because some of them have shady implementations of the boolean type. (Not dropping any names like "MySQL" or "Oracle" ...). You can probably substitute everywhere (including Postgres) with:
SELECT id
, max(case when colID = 1 then value else '' end) AS fn
, max(case when colID = 2 then value else '' end) AS ln
, max(case when colID = 3 then value else '' end) AS jt
FROM tbl
GROUP BY id
HAVING count(*) = count(value);
Because count() doesn't count NULL values. In MySQL there is also bit_and().
More under this related question:
Is there any equivalent to Postgresql EVERY aggregate function on other RDBMS?
It works in Oracle because Oracle handles NULL incorrectly in that NULL and '' are the same. The other databases don't do this because it is wrong. NULL is unknown, versus '' which is just a blank, empty string.
So if your where clause said something like WHERE (fn IS NOT NULL or fn <> '') you would probably get further.
I think this is a case where a HAVING clause will do what you need.
SELECT id, max ... (same stuff as before)
FROM tbl
GROUP by id
HAVING fn IS NOT NULL
AND ln IS NOT NULL
AND jt IS NOT NULL
I am trying to get the count of females and males in the gender field of a table.
Is there a way to get the count of each in one query?
Something like:
select * from table count(where gender = 'm') as total_males, count(where gender = 'f') as total_females;
or will it require two queries?
select count(*) from table where gender = 'm';
select count(*) from table where gender = 'f';
This is basically a PIVOT. MySQL does not have a pivot so you can use an aggregate function with a CASE statement to perform this:
select
sum(case when gender = 'm' then 1 else 0 end) Total_Male,
sum(case when gender = 'f' then 1 else 0 end) Total_Female
from yourtable
See SQL Fiddle with Demo
Or using COUNT:
select
count(case when gender = 'm' then 1 else null end) Total_Male,
count(case when gender = 'f' then 1 else null end) Total_Female
from yourtable;
See SQL Fiddle with Demo
Something like this will work:
SELECT SUM(IF(t.gender='m',1,0)) AS total_males
, SUM(IF(t.gender='f',1,0)) AS total_females
FROM mytable t
The "trick" here is that we are using a conditional test to return either a 0 or a 1 for each row, and then adding up the 0's and 1's. To make this a little more clear, I am using the SUM aggregate function rather than COUNT, although COUNT could be used just as easily, though we'd need to return a NULL in place of the zero.
SELECT COUNT(IF(t.gender='m',1,NULL)) AS total_males
, COUNT(IF(t.gender='f',1,NULL)) AS total_females
FROM mytable t
Consider that the two expressions in the SELECT list of this query:
SELECT COUNT(1)
, SUM(1)
FROM mytable t
Will return the same value.
If you want to avoid the MySQL IF function, this can also be done using the ANSI SQL CASE expression:
SELECT SUM( CASE WHEN t.gender = 'm' THEN 1 ELSE 0 END )) AS total_males
, SUM( CASE WHEN t.gender = 'f' THEN 1 ELSE 0 END )) AS total_females
FROM mytable t
select sum(case when gender='m' then 1 else null end) as total_males, sum(case when gender='f' then 1 else null end) as total_females from ...
Should work just fine!
If your only issue is to avoid two queries, you can always write two queries as subselects of one query.
Select (select 1 from dual) as one, (select 2 from dual) as two from dual
This would work for your scenario, too.