My code looks like this:
<div class="hovereffect">
<img class="img-responsive" src="/some-image" alt="">
<input type="checkbox" class="img-checkbox">
</div>
.hovereffect {
width: 100%;
height: 100%;
margin-bottom: 20px;
float: left;
overflow: hidden;
position: relative;
text-align: center;
cursor: default;
}
.hovereffect .img-checkbox{
position: absolute;
width: 18px;
height: 18px;
top: 3px;
right: 5px;
cursor: pointer;
}
So there is the checkbox in the right upper corner over the image and would like to extend the clickable are to the whole image for a better user experience.
As you can see the checkbox has no label and I would like to achieve the goal without a label.
I tried tricks with the ::after element which kinda worked with chrome but not really with firefox and I couldn't make the clickable area responsive that is to say, extend to the whole area of the image.
Can you use Javascript/jQuery?
You can start by assigning unique id to every image you have (Ex: img1,img2,img3) and every checkbox associated to the image (Ex: img1-checkbox).Then you can use the code below:
$('#img1').click(
$('#img1-checkbox').attr('checked', true);
);
Or something like that.
This has been a problem since a very long time and you simply cannot achieve your goal with pure css. The only available ways of getting it done are ou using label or jquery/javascript or :after pseudo class.
If you want to expand the checkbox size, then try this:
.hovereffect input[type=checkbox]
{
width:100px !important; //adjust as per need
height:100px !important; //adjust as per need
}
This will increase the clickable area of the checkbox field. Working Link
But, if you want the checkbox to be transparent and show the image behind, then you will have to use label and set it's background color to transparent.
I'm waiting to see someone prove me wrong with working code.
Related
I am trying to create a custom input field with a text input and a button with an eye icon to show/hide the password text.
Now, I know that simply create an input field and absolutely position the eye button but the problem with that is that on certain browsers, the Lastpass extension or Safari keychain will insert their respective icons thus overlapping the eye icon which I always want to be visible and clickable. As an example, this is bad:
Therefore, this is what I want to achieve:
I am trying something like this:
<div className="input-wrapper">
<input className="password-input" type="password" />
<button className="password-eye">
</div>
CSS
.input-wrapper {
position: relative;
border: 1px solid #ccc;
}
.password-input {
border: none;
width: calc(100% - 32px);
height: 40px;
}
.password-eye:extend(.icon-password-eye all) {
background: white;
border: none;
height: 40px;
font-size: 24px;
position: absolute;
right: 0px;
top: 0px;
padding-right: 8px;
}
.icon-password-eye::before {
content: '\e618';
}
The problem that I'm facing is that because I want the whole wrapper to behave as if it were an input component, when the user selects the input field, only the actual input part is selected. In addition, if the password validation errors out, only input field is shown to be red while I want the entire portion to be red.
This is what is happening:
Any help would be greatly appreciated.
what you want to do is changing the border CSS of the input-wrapper class.
and not the input
you need to change the code that changing the input css to change the input-wrapper css.
if you need help in that , please give the full code.
Just like the Title says, "How to use text as a background instead of an image?"
I'm making a little application, that I personally think is cool but will probably be a waste of peoples time, and am altering the button in the drop down button to an upside down triangle using this html code ▼ . I'm not talking about setting the z-index or anything just simply placing a character for the little arrow. I thought about leaving it blank but I don't think users would understand that they are supposed to use the menu if I did so. Therefore I'm going to use the upside down triangle.
My CSS for the drop-down list is set up like this
select {
border: none;
overflow: hidden;
background: no-repeat right #ffffff;
-moz-appearance: none;
-webkit-appearance: none;
text-indent: 0.01px;
text-overflow: '';
}
Put the text inside an HTML tag with class .text-background, set CSS styles to
.text-background {
position: absolute;
z-index: 1;
}
and set z-index to the elements you want to be on top of the text with z-index higher than 1.
edit:
If you know what the size of the select element is, you probably want to position that text over the dropdown. This however will block the button.
JSFiddle
If you want better looks and functionality you can use a 3rd party libraries such as this or this.
edit 2:
I just found this CSS only solution given by Danield that's probably going to suite your needs better.
https://stackoverflow.com/a/13968900/1419575
Try This, as suggested by Paulo Bergantino:
JS Fiddle
Click Here
HTML
<div id="container">
<div id="background">
Text to have as background
</div>
Normal contents
</div>
CSS
#container{
position: relative;
}
#background{
position: absolute;
top: 0;
left: 0;
bottom: 0;
right: 0;
z-index: -1;
overflow: hidden;
}
I have a html page which is using the same icon many times, and so I have embedded that icon as a background-image in css.
In css, the class for the icon is like this:
.user {
background-image: url(data:image/png;base64,...encoded png file...);
background-position: 0 0;
background-repeat: no-repeat;
width: 16px;
height: 16px;
}
I display the icon using a<span class='user'></span> tag, so far, so good.
I want the icon to be a link to another page, but I can't make the icon look correct when I do this.
I have tried:
<img class="user" src=""></img>
but this draws a broken link icon over it in Explorer, it looks ok, but has a border in Chrome. It is obviously wrong.
I also tried:
<span class="user"></span>
and this works, but the mouse cursor does not change to a pointer when over the icon.
What should I be doing?
You should make the element block level (at least inline-block) to set the width/height and explicitly set the cursor. These two things are the key components.
.user {
background-image: url(data:image/png;base64,...encoded png file...);
background-position: 0 0;
background-repeat: no-repeat;
display: inline-block; /* set display so you can set width/height */
cursor: pointer; /* ensure it shows the link cursor */
width: 16px;
height: 16px;
}
And the HTML:
<span class="user"></span>
So, you end up with an inline-block element which shows the image, and then you wrap that with an anchor. This is basically the same as wrapping an anchor around an <img />.
Alternatively, you could do this with just the <a>. You would use the exact same CSS, with this HTML:
Both should achieve what you're after. The difference between these two choices is mostly semantics.
You can set the class attribute on the anchor tag.
Are you looking for something like THIS
The HTML:
The CSS:
.user {
text-indent: -99999px;
background: url("http://www.google.co.in/images/srpr/logo4w.png") no-repeat top left;
float: left;
overflow: hidden;
width: 600px;
height: 200px;
margin: 10px;
}
Hope this is what you need.
try to add this one on your css
cursor:pointer;/*Link with poniter*/
<span class="user" /></span>
Chrome and Safari are displaying a border around the image, but I don't want one. There is no border in Mozilla. I've looked through the CSS and HTML, and I can't find anything that is fixing it.
Here is the code:
<tr>
<td class="near">
<a href="../index.html"class="near_place">
<img class="related_photo" />
<h4 class="nearby"> adfadfad </h4>
<span class="related_info">asdfadfadfaf</span>
</a>
...
CSS:
a.near_place {
border: none;
background: #fff;
display: block;
}
a.near_place:hover{
background-color: #F5F5F5;
}
h4.nearby {
height: auto;
width: inherit;
margin-top: -2px;
margin-bottom: 3px;
font-size: 12px;
font-weight: normal;
color: #000;
display: inline;
}
img.related_photo {
width: 80px;
height: 60px;
border: none;
margin-right: 3px;
float: left;
overflow: hidden;
}
span.related_info {
width: inherit;
height: 48px;
font-size: 11px;
color: #666;
display: block;
}
td.near {
width: 25%;
height: 70px;
background: #FFF;
}
Sorry, I copied some old code before. Here is the code that is giving me trouble
Thanks in advance
Now I don't know if this is a bug with Chrome or not but the grey border appears when it can't find the image, the image url is broken or as in your case the src isn't there. If you give the image a proper URL and the browser finds it then the border goes away. If the image is to not have a src then you will need to remove the height and width.
sarcastyx is right, but if you want a workarround you can set the width and height to 0 and a padding to make space for your image.
If you want a icon of 36x36, you can set width and height to 0 and pading:18px
I know it is an old question. But another solution is to set the src to a 1x1 transparent pixel
<img class="related_photo"
src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" />
This works for me.
.related_photo {
content: '';
}
This may happen when the image is planted dynamically by css (e.g. by http://webcodertools.com/imagetobase64converter) in order to avoid extra HTTP requests. In this case we don't want to have a default image because of performance issues. I've solved it by switching from an img tag to a div tag.
img[src=""]{
content: "";
}
Lazy image solution (img loading="lazy")
If you are using lazy image loading you may notice this thin thin border before the image has loaded more than if you didn't.
You're more likely to see this for a horizontal scrolling gallery than a normal vertical scrolling webpage.
Why?
Lazy loading unfortunately only works on the vertical axis. I'm assuming this is because there's a high likelihood that you're going to scroll down, but not left to right. The whole point of lazy loading is to reduce images 'below the fold' from consuming unnecessary bandwidth.
Soution 1:
Detect when the user has scrolled (eg. using intersection observer) and then set loading="eager" on each image you want to immediately load.
I haven't actually tested this, and it's possible some browser's won't immediately load images - but it should be fine.
Solution 2:
Detect when the image has finished loading loaded and then fade it in.
img.setAttribute('imageLoaded', 'false');
img.onload = () =>
{
img.setAttribute('imageLoaded', 'true');
};
Then with css hide the image until it's loaded, after which it fades in nicely:
img
{
opacity: 1;
transition: opacity .5s;
}
img[imageLoaded='false']
{
opacity: 0; // hide image including gray outline
}
Also this behavior is subject to change, the browser may be clever enough to detect a horizontal scrolling element in future - but right now Chrome and Safari both seem to have a zero pixel window for looking for horizontal lazy images.
img.related_photo {
width: 80px;
height: 60px;
**border: solid thin #DFDFDF;** //just remove this line
margin-right: 3px;
float: left;
overflow: hidden;
}
Inside img.related_photo, you need to change border: solid thin #DFDFDF; to border: 0.
I have fixed this issue with:
<img src="img/1.jpg" style="height:150px; position: absolute; right: 15px;">
The right: 15px is where you want the image to be shown, but you can place it where you want.
I just added src="trans.png", trans.png is just a 100x100 transparent background png from photoshop.
Worked like a charm no borders
To summarise the answers given already: your options to remove the grey border from an img:not([src]), but still display an image using background-image in Chrome/Safari are:
Use a different tag that doesn't have this behaviour. (Thanks #Druvision) Eg: div or span. Sad face: it's not quite as semantic.
Use padding to define the dimensions. (Thanks #Gonzalo)Eg padding: 16px 10px 1px; replaces width:20px; height:17px; Sad face: dimensions and intentions aren't as obvious in the CSS, especially if it's not an even square like #Gonalo's example.
How do I create a similar “search” element to the one in this site?
If we view source, he has one textbox followed by a <span> tag.
<input type="text" name="q" id="site-search-input" autocomplete="off" value="Search" class="gray" />
<span id="g-search-button"></span>
Where do I get a similar "magnifying glass" image?
Put the image into the span, for example using background-image, then give it a relative position and move it to the left so it overlaps the right end of the search box, for example:
#g-search-button {
display: inline-block;
width: 16px;
height: 16px;
position: relative;
left: -22px;
top: 3px;
background-color: black; /* Replace with your own image */
}
Working example on JSBin
Your eyes are deceiving you. The button is not within the text box. Using a background image is NOT the way to go, as it wont provide the clickable submit button.
What you need to do is add a wrapper div around the input:text and input:submit.
The wrapper will look like it's a text box, but will actually contain a transparent text box and a submit button. You'll need to specifically remove the styles for the input:text and input:submit elements.
It's very important that you keep the submit button, otherwise hitting enter while searching will not have a default reaction. Additionally placing the submit button after the text field allows people to actually click on the button.
You can make your own magnifying image, they're pretty easy to make in a 20x20px transparent png.
.search {
border: 1px solid #000000;
width: 200px;
}
.search input[type="text"] {
background: none;
border: 0 none;
float: left;
height: 1.5em;
line-height: 1.5em;
margin: 0;
padding: 3px 0;
width: 180px;
}
.search input[type="submit"] {
background: #CCCCCC url(path/to/image.jpg);
border: 0 none;
height: 1.5em;
line-height: 1.5em;
margin: 0;
padding: 3px 0;
text-indent: 100px;
width: 20px;
}
<form ...>
<div class="search">
<input type="text" />
<input type="submit" />
</div>
</form>
If you view the page in Google Chrome, right-click on the search button and select “Inspect element”, you’ll be able to see the CSS used to achieve this effect.
If you’re not familiar with CSS, I thoroughly recommend ‘CSS: The Definitive Guide’.
A site like Iconspedia has a number of free icons that are similar.
Wherever you get the icon be careful to ensure that you have the rights to use it in your application. Many graphics are protected and some have restrictive licenses.
If you use a background image on the field then there's no way to bind to it to get the click action. So the solution is to have a separate search field and image, so you can bind click event in jQuery to the image. Fiddle here:
http://jsfiddle.net/Lzm1k4r8/23/
You can adjust left: position to be left or right side of the search box.
To help with user feedback why not add the pointer icon to your mouse when you're hovering over the magnifying glass? Just att this to your CSS:
.search:hover {
cursor:pointer;
}
I'd like to plug a new jQuery plugin I wrote because I feel it answers to the OP's request.
It's called jQuery.iconfield: https://github.com/yotamofek/jquery.iconfield.
It lets you easily add an icon to the left side of your text field. For using the icon as a button, you can easily bind to the 'iconfield.click' event, which is triggered when the user clicks the icon. It also takes care of changing the cursor when the mouse is hovering over the icon.
For instance:
$('#search-field').iconfield( {
'image-url': 'imgs/search.png', // url of icon
'icon-cursor': 'pointer' // cursor to show when hovering over icon
} );
$('#search-field').on( 'iconfield.click', function( ) {
$('#search-form').submit()
}
I would love to get some feedback on my work.