check a specific submit button value in controller (Yii2) - yii2

Question

how to check a submit button value in controller (Yii2). I am working with multiple submit button.
I tried simple php code. but it is not working.
if(isset($_POST['next']) && $_POST['next']=='gotocartfive')
code in view is :
<?php $form = ActiveForm::begin(); ?>
<?= $form->field($model, 'status')->checkbox(); ?>
</div>
<div class="form-group">
<?php echo Html::submitButton('NEXT',array('value'=>'gotocartfive','name' => 'next','id'=>'next_summary','class'=>'btn btn-primary pull-right')); ?>
<?php echo Html::submitButton('PREVIOUS',array('value'=>'previous_four','name' => 'cartfour','class'=>'btn btn-primary pull-left')); ?>
</div>
<?php ActiveForm::end(); ?>

Answer 1

<?= Html::submitButton('Submit 1', ['name' => 'action', 'value' => 'submit_1']) ?>
<?= Html::submitButton('Submit 2', ['name' => 'action', 'value' => 'submit_2']) ?>
PHP
If (\Yii::$app->request->isPost) {
switch (\Yii::$app->request->post('action')) {
case 'submit_1':
case 'submit_2':
}
}
When you submit form by pressing enter (without click any submit button), submit_1 will be default value.

Answer 2

You can try following code.
Code in view file.
<?= Html::submitButton(Yii::t('app', '<i class="fa fa-times"></i> Remove'), ['class' => 'btn red', 'name' => 'submit', 'value' => '0']) ?>
<?= Html::submitButton(Yii::t('app', '<i class="fa fa-check"></i> Save'), ['class' => 'btn blue', 'name' => 'submit', 'value' => '1']) ?>
Code in controller action
if (Yii::$app->request->post()) {
if (Yii::$app->request->post('submit') == 0) {
//Code for value 0
}
if (Yii::$app->request->post('submit') == 1) {
//Code for value 1
}
}
Please let me know if you've any questions.

Answer 3

Try This :
View File
<?php $form = ActiveForm::begin(); ?>
<?= $form->field($model, 'status')->checkbox(); ?>
<div class="form-group">
<?= Html::submitButton('NEXT',[ 'name'=>'submit', 'value' => 'next', 'class' => 'btn btn-primary pull-right']) ?>
<?= Html::submitButton('PREVIOUS',[ 'name'=>'submit', 'value' => 'previous', 'class' => 'btn btn-primary pull-right') ?>
</div>
<?php ActiveForm::end(); ?>
Controller File
public function actionYourControllerName()
{
if(isset($_POST['submit') && $_POST['submit']=='next')
{
// your code
}
else if(isset($_POST['submit']) && $_POST['submit']=='previous')
{
// your code
}
}

Answer 4

Also you can add this little js snippet to your project and bind it to beforeSubmit event in yii.activeForm.js like this:
(function ($) {
var formId = !!yiiconfig.viewPolicyParams && yiiconfig.viewPolicyParams.formId && yiiconfig.viewPolicyParams.formId,
$form = formId && $("#" + formId);
/**
* Updates hidden field that represents clicked submit button.
* #param event event object triggered
*/
function updateHiddenButton (event) {
var $buttons = $form.find(':submit');
$buttons.length && $buttons.each(function (i,b) {
var $hiddenButton = $('input[type="hidden"][name="' + $(b).attr('name') + '"]', $form);
$hiddenButton.length && $hiddenButton.remove();
});
};
$form && $form.bind('beforeSubmit.' + formId, updateHiddenButton);
} (jQuery));
This code removes all hidden inputs which are being created by yii.activeForm before submitting.
Then after this inputs will be recreated by yii.activeForm.
hope this helps