Can you tell me what I need to manipulate in this query to get it working?
select C.ID from
(select A.ID from CUSTOMERS A inner join PROFILES B on A.ID=B.ID where CTR='67564' and CST_CD in
('G','H')) as C
inner join
(select ID from RELATION_CODES where R_CD='KC') as R
on C.ID=R.ID
The individual inner queries are working just fine and giving correct results, not sure what is the problem with inner join in from clause..
Not completely sure I'm understanding your question, but this should be able to be rewritten without the subqueries:
select c.id
from customers c
join profiles p on c.id = p.id
join relation_codes rc on rc.id = c.id
where ctr = '67564'
and cst_cd in ('G','H')
and rc.r_cd = 'KC'
If this isn't working, please provide your table structure and sample data and expected results. This should get you pretty close though.
I have to ask, is the id field in the relation_codes table and the profiles table the same as the id in the customers table. Perhaps you need to identify how your tables are related.
A Visual Explanation of SQL Joins
Related
I'm trying to update one table from another that isn´t directly connected, through another table and the statement executes correctly, but it doesn't work because it's updating without data.
The query is:
UPDATE cities
INNER JOIN footprints ON cities.ID=footprints.ID
INNER JOIN (SELECT code,id_code,sum(price) AS price FROM buildings GROUP BY code,id_code) AS SUM_Price ON footprints.code=SUM_Price.code AND footprints.id_code=SUM_Price.id_code
SET cities.Total_Price=SUM_Price.price
Add some sample data as example.
Example of Data tables
Does anyone know what is happening?
Thanks for your support!
First you must join footprints to buildings and aggregate and then join to cities:
UPDATE cities c
INNER JOIN (
SELECT f.id, sum(b.price) price
FROM footprints f INNER JOIN buildings b
ON f.code = b.code AND f.id_code = b.id_code
GROUP BY f.id
) s ON s.id = c.id
SET c.total_price = s.price
Is there a best way to write this query? It is working just fine on workbench but when I run it on JS, it's not returning the right value.
What I want to do is I want to show users the list of all the items based on their filtered settings (basing on selected category's material and design).
Query:
SELECT COUNT(A.id)
FROM tbl_product A
JOIN tbl_product_details B ON A.id = B.prod_id
JOIN tbl_category C ON A.id = C.prod_id
JOIN tbl_material D ON A.id = D.prod_id
JOIN tbl_design E ON A.id = E.prod_id
WHERE C.category_id IN (6) AND (D.material_id IN (15) OR E.design_id IN (39));
I expect the output to be (workbench result):
COUNT(A.id): 42
instead, it's giving me:
COUNT(A.id): 1582
I am guessing that you want:
SELECT COUNT(DISTINCT A.id)
There are probably other ways to phrase the query (notably, using EXISTS), but this is the simplest modification.
I have come up with two queries, both use an inner join on two different tables.
Query 1
SELECT PRODUCTS.CODE, PRODUCTS.REFERENCE, PRODUCTS.TAXCAT, PRODUCTS.DISPLAY,PRODUCTS.NAME, PRODUCTS.PRICEBUY, PRODUCTS.PRICESELL, CATEGORIES.NAME AS CATEGORY
FROM PRODUCTS INNER JOIN CATEGORIES ON PRODUCTS.CATEGORY = CATEGORIES.ID;
Query 2
SELECT PRODUCTS.CODE, PRODUCTS.REFERENCE, PRODUCTS.TAXCAT, PRODUCTS.DISPLAY,PRODUCTS.NAME, PRODUCTS.PRICEBUY, PRODUCTS.PRICESELL,STOCKCURRENT.UNITS AS UNIT FROM PRODUCTS INNER JOIN STOCKCURRENT ON STOCKCURRENT.PRODUCT = PRODUCTS.ID;
Both queries run fine on their own, when I try to use both inner joins together I get errors. This is what I came up with on my own. I'm having trouble understanding the syntax to achieve this.
SELECT PRODUCTS.CODE, PRODUCTS.REFERENCE, PRODUCTS.TAXCAT,
PRODUCTS.DISPLAY,PRODUCTS.NAME, PRODUCTS.PRICEBUY,
PRODUCTS.PRICESELL,STOCKCURRENT.UNITS AS UNIT FROM PRODUCTS INNER JOIN
STOCKCURRENT ON STOCKCURRENT.PRODUCT = PRODUCTS.ID, CATEGORIES.NAME AS
CATEGORY FROM PRODUCTS INNER JOIN CATEGORIES ON PRODUCTS.CATEGORY =
CATEGORIES.ID;
Thank you.
Your attempted query has several syntax problems. Assuming you just want to join together the three tables, you may try the following query:
SELECT
p.CODE,
p.REFERENCE,
p.TAXCAT,
p.DISPLAY,
p.NAME,
p.PRICEBUY,
p.PRICESELL,
s.UNITS AS UNIT,
c.NAME AS CATEGORY
FROM PRODUCTS p
INNER JOIN STOCKCURRENT s
ON s.PRODUCT = p.ID
INNER JOIN CATEGORIES c
ON p.CATEGORY = c.ID;
Note that I introduced table aliases here. These aliases can be used elsewhere in the query to avoid having to repeat the entire table name.
By the way, I can also see taking a union of your two original queries. But without expected output, it was not entirely clear what you want.
I have 3 tables each have almost 70,000 data
when i execute select query in which i add one inner join than it works faster.
Following works faster
select A.id from product as A
inner join product_cat as B on A.id=B.mapped_id
OR
select A.id from product as A
inner join product_sup as C on A.id = C.mapped_id
(It works faster for one inner join)
but when i add both inner join in same select query than it works too slower(Does not display data it just show loading label in phpmyadmin)
select A.id
from product as A
inner join product_cat as B
on A.id = B.mapped_id
inner join product_sup as C
on A.id = C.mapped_id
my purpose it only to find out how much record is there in database.
also tried with count function though takes too much time.
Any help will be appreciated,
Thanks,
Use EXPLAIN to analyze performance of the query and identify any missing indexes.
http://dev.mysql.com/doc/refman/5.5/en/using-explain.html
http://dev.mysql.com/doc/refman/5.5/en/explain-output.html
Add your actual query, execution plan printed by EXPLAIN and CREATE TABLE statements of all involved tables to your question if you want to get a specific advice.
Maybe your query is trying to return more than 1 million of result and that is the reason fo the slowness. Maybe you are doing a Cartesian product between tables B and C.
Let's put an example.
Table (A) = (id=1)
Table (B) = (id=1,mapped_id=1),(id=2,mapped_id=1),
(id=3,mapped_id=1),(id=4,mapped_id=1)
Table (C) = (id=1,mapped_id=1),(id=2,mapped_id=1), (id=3,mapped_id=1)
If we do that query with those data it would return 12 rows, all of them with A.id=1
To solve the problem you could try to use a DISTINCT on the SELECT clause or to do a group with the GROUP BYclase, but I think the better solution is to redesing the query depending on your goals.
If you want to use the group by your query will be something like this
select A.id from product as A
inner join product_cat as B on A.id = B.mapped_id
inner join product_sup as C on A.id = C.mapped_id
group by A.id
I have a query that needs the most recent record from a secondary table called tbl_emails_sent.
That table holds all the emails sent to clients. And most clients have several to hundreds of emails recorded. I want to pull a query that displays the most recent.
Example:
SELECT c.name, c.email, e.datesent
FROM `tbl_customers` c
LEFT JOIN `tbl_emails_sent` e ON c.customerid = e.customerid
I'm guessing a LEFT JOIN with a subquery would be used, but I don't delve into subqueries much. Am I going the right direction?
Currently the query above isn't optimized for specifying the most recent record in the table, so I need a little assistance.
It should be like this, you need to have a separate query to get the maximum date (or the latest date) that the email was sent.
SELECT a.*, b.*
FROM tbl_customers a
INNER JOIN tbl_emails_sent b
ON a.customerid = b.customerid
INNER JOIN
(
SELECT customerid, MAX(datesent) maxSent
FROM tbl_emails_sent
GROUP BY customerid
) c ON c.customerid = b.customerid AND
c.maxSent = b.datesent
Would this not work?
SELECT t1.datesent,t1.customerid,t2.email,t2.name
FROM
(SELECT max(datesent) AS datesent,customerid
FROM `tbl_emails_sent`
) as t1
INNER JOIN `tbl_customers` as t2
ON t1.customerid=t2.customerid
Only issue you have then is what if two datesents are the same, what is the deciding factor in which one gets picked?