Given 2 tables, I want to generate top 3 highest amount from [Purchase] table.
Additional criteria is [Crocs] must be included in top 3 of the records.
I have following SQL, but it cannot generates the result as I wanted (Result A), please guide me on how to pull out the result in Result B. Thank you.
Table (Purchase):
Purchase_ID | StoreID | Amount
------------|---------|--------
1 | 21 | 22
2 | 23 | 13
3 | 25 | 6
4 | 26 | 23
5 | 28 | 18
Table (Store):
Store_ID | StoreName
---------|----------
21 | Adidas
22 | Nike
23 | Puma
24 | New Balance
25 | Crocs
26 | Converse
SQL:
SELECT IF(SUM(amount) IS NULL, 0, SUM(amount)) as totalAmount
FROM (
SELECT a.amount
FROM purchase a
INNER JOIN store b
ON a.store_id = b.storeid
GROUP BY a.amount
HAVING b.StoreName = 'Crocs'
ORDER BY a.amount DESC
LIMIT 3
) t
Result A: $6
Explanation A: Amount of Crocs is $6
Result B: $51
Explanation B: Total Amount of top 3 = $22 (Adidas) + 23 (Puma) + $6 (Crocs)
The answer from scaisEdge is almost right, but the first query could also return a row with crocs and the sorting is wrong (order by max(a.amount) limit 2 means that the lowest 2 results will be shown). Additionally you could wrap the query in another select query to sort the results
SELECT * FROM (
SELECT b.storename, max(a.amount) as maxAmount
FROM purchase a
INNER JOIN store b ON a.store_id = b.storeid
WHERE b.storename != 'crocks'
GROUP BY a.storename
ORDER BY max(a.amount) DESC
LIMIT 2
UNION
SELECT b.storename, a.amount as maxAmount
FROM purchase a
INNER JOIN store b
ON a.store_id = b.storeid
WHERE b.storename='crocks'
ORDER BY a.amount DESC
LIMIT 1
) ORDER BY maxAmount DESC
You could use an union
SELECT b.storename, max(a.amount)
FROM purchase a
INNER JOIN store b
ON a.store_id = b.storeid
GROUP BY a.storename
order by max(a.amount) limit 2
union
SELECT b.storename, a.amount
FROM purchase a
INNER JOIN store b
ON a.store_id = b.storeid
where b.storename='crocks'
try this one:
SELECT sum(amount)as sum_amount,a.store_id,storename,category from
(select amount,store_id from tbl_purchase) as a
inner JOIN
(select store_id,storename,category from tbl_store)as b on a.store_id = b.store_id where b.category = 'supermarket' GROUP BY category
Related
I have this query:
SELECT
achievements.id,
achievements.name,
achievements.category,
userAchievements.createdAt
FROM
achievements
INNER JOIN
userAchievements ON userAchievements.achievementId = achievements.id
AND userAchievements.userId = 12
WHERE
achievements.type = 2
Result of this query is:
id
name
category
createdAt
8
First
1
2021-02-11
13
Second
2
2021-02-12
14
Third
4
2021-03-01
15
Fourth
4
2021-03-02
I have to leave only unique category with max createdAt field.
I need a query that will give the following result:
id
name
category
createdAt
8
First
1
2021-02-11
13
Second
2
2021-02-12
15
Fourth
4
2021-03-02
If I use group by then it returns row with id 14.
MySQL version - 5.7.33.
Achievements table:
id
name
category
8
First
1
13
Second
2
14
Third
4
15
Fourth
4
UserAchievements table:
id
achievementId
userId
createdAt
3
8
12
2021-02-11
7
13
12
2021-02-12
36
15
12
2021-03-02
40
14
12
2021-03-01
P.S.
I managed to write a query that solves the problem
SELECT
*
FROM
(SELECT
*,
IF(#prev <> category, #rn:=0, #rn),
#prev:=category,
#rn:=#rn + 1 AS rn
FROM
(SELECT
achievements.id,
achievements.name,
achievements.category,
userAchievements.createdAt
FROM
achievements
INNER JOIN userAchievements ON userAchievements.achievementId = achievements.id
AND userAchievements.userId = 12
WHERE
achievements.type = 2) as ach, (SELECT #rn:=0) rn, (SELECT #prev:='') prev
ORDER BY ach.createdAt DESC) t
WHERE
rn = 1
You can use window functions:
SELECT a.*
FROM (SELECT a.*,
ROW_NUMBER() OVER (PARTITION BY a.category ORDER BY a.created_at DESC) as seqnum
FROM achievements JOIN
userAchievements ua
ON ua.achievementId = a.id AND
ua.userId = 12
WHERE a.type = 2
) a
WHERE seqnum = 1;
This subquery basically search for all maximum dates, grouped by category.
SELECT MAX(_ua.createdAt) FROM `achievements` _a INNER JOIN user_achievements _ua ON _a.id = _ua.achievementId group by _a.category
So you maybe you can do :
SELECT a.* FROM achievements a
INNER JOIN user_achievements ua ON a.id = ua.achievementId
AND ua.createdAt IN (SELECT MAX(_ua.createdAt) FROM `achievements` _a INNER JOIN
user_achievements _ua ON _a.id = _ua.achievementId group by _a.category)
So i get 10 results from my first select and 1 from the other one after union like this:
(SELECT a.*,
b.*
FROM all a,
names b
WHERE b.name_id = a.name_id
ORDER BY name_id DESC
LIMIT 10)
UNION
(SELECT a.*,
b.*
FROM all a,
names b
WHERE b.name_id = a.name_id
ORDER BY request_id ASC
LIMIT 1)
i would like to get the result of the second select as the second last result like this
********
name_id 100
name_id 99
name_id 98
name_id 97
name_id 96
name_id 95
name_id 94
name_id 93
name_id 92
name_id 1 <- second select result as second last result
name_id 91
********
Can someone help pls?
Synthesize a row number column for the query as it stands and shuffle positions as needed.
SELECT x.name
, x.name_id
FROM (
SELECT #rownum:=#rownum + 1 as row_number,
t.name,
t.name_id
FROM (
-- original query from the question starts here
(SELECT b.name,
a.name_id
FROM allx a,
names b
WHERE b.name_id = a.name_id
ORDER BY name_id DESC
LIMIT 10)
UNION
(SELECT b.name,
a.name_id
FROM allx a,
names b
WHERE b.name_id = a.name_id
ORDER BY request_id ASC
LIMIT 1)
) t,
(SELECT #rownum := 0) r
) x
ORDER BY CASE row_number
WHEN 10 THEN 11
WHEN 11 THEN 10
ELSE row_number
END
;
(Note that the query has been sightly modified to avoid syntax errors / support the demo: table all has been named allx, explicit projections of the union's subqueries).
That gets complicated quickly thus next to ad hoc reporting it is preferable to synthesize an attribute in the subqueries of the union that reflects a global order.
Demo here (SQL fiddle)
Credits
Row number synthesizing taken from this SO answer
Interesting question given
+----+--------+
| id | sname |
+----+--------+
| 1 | sname1 |
| 2 | sname2 |
| 3 | sname3 |
| 4 | sname4 |
| 5 | sname5 |
| 6 | sname6 |
+----+--------+
6 rows in set (0.001 sec)
(select id,sname,#r:=#r+1 rn
from users
cross join(select #r:=0) r
order by sname desc limit 3
)
union
(
select u.id,u.sname,
#r:=#r - .9
from users u
left join (select id from users order by sname desc limit 3) u1 on u1.id = u.id
where u1.id is null
order by u.id asc limit 0,1
)
order by rn;
Where a variable is used to calculate a row number in the first sub query, since this variable is not reset in the second query a simple piece of arithmetic works out where to position the second sub query result. Note the second sub query uses a left join to check that the result has not already appeared in the first sub query,
I would suggest union all and three selects:
SELECT an.*
FROM ((SELECT a.*, n.*, 1 as ord
FROM all a JOIN
names n
ON n.name_id = a.name_id
ORDER BY n.name_id DESC
LIMIT 9
) UNION ALL
(SELECT a.*, n.*, 3 as ord
FROM all a JOIN
names n
ON n.name_id = a.name_id
ORDER BY n.name_id DESC
LIMIT 9 OFFSET 9
) UNION ALL
(SELECT a.*, b.*
FROM all a JOIN
names n
WHERE n.name_id = a.name_id
ORDER BY request_id ASC
LIMIT 1
)
) an
ORDER BY ord, name_id;
i need a query that should first look the oldest order which has status 0 (zero). and retrieves all the similar orders of that kind(matches exact total qty, itemSku and number of distinct items ordered).
***OrdersTable***
ID OrderNumber CustomerId Status created_at
1 123456 1 0 2018-01-01
2 234567 1 0 2018-01-02
3 345678 1 0 2018-01-03
4 456789 1 0 2018-01-04
***PurchasedProductsTable***
OrderId itemSku Qty
1 1000001 1
1 1000002 2
2 1000001 3
3 1000001 1
3 1000002 2
4 1000001 3
In the above table the query should first look at the oldest (created_at ASC) order (i.e with Id 1) having status 0 (in order table). and along with that order it should retrieves all the other orders that matches the same itemSku, qty and total distinct items count (in purchasedProducts table).
here order 1 and 3 matches the same itemSKu (1000001 and 1000002) and qty ( 1 and 2) and both have (2) distinct items count respectively so order 1 and 3 should be retrived at first.and when i marked order 1 and 3 as shipped (i.e chang status to 2).
and if i run query again it should retrive similar oders. now order 2 and 4 as order 2 and 4 are similar orders. (have same itemSkus (1000001, Qty (3) and distinct items count (1)).
please help thanks
You have to go trough your tables two times :)
Something like this :
SELECT DISTINCT O2.ID
FROM OrdersTable O1
INNER JOIN PurchasedProductsTable P1 ON O1.ID = P1.OrderId
INNER JOIN PurchasedProductsTable P2 ON P1.itemSku = P2.itemSku
AND P1.Qty = P2.Qty
INNER JOIN OrdersTable O2 ON O2.ID = P2.OrderId
WHERE O1.ID =
(SELECT ID FROM OrdersTable WHERE Status = 0
ORDER BY created_at ASC LIMIT 1)
AND (SELECT COUNT(*) FROM PurchasedProductsTable WHERE OrderId = O1.ID)
= (SELECT COUNT(*) FROM PurchasedProductsTable WHERE OrderId = O2.ID)
ORDER BY O2.ID ASC;
https://www.db-fiddle.com/f/65t9GgSfqMpzNVgnrJp2TR/2
You can get the earliest order via a limit and ordered by the date.
Then you can left join to get that order and any other order that at least has the same items.
Then once you have those order id's from the sub-query result, you can get the order details.
SELECT o.*
FROM
(
SELECT DISTINCT ord2.ID as OrderId
FROM
(
SELECT ID, CustomerId, Status
FROM OrdersTable
WHERE Status = 0
ORDER BY created_at
LIMIT 1
) AS ord1
JOIN PurchasedProductsTable AS pprod1
ON pprod1.OrderId = ord1.ID
LEFT JOIN OrdersTable ord2
ON ord2.CustomerId = ord1.CustomerId
AND ord2.Status = ord1.Status
LEFT JOIN PurchasedProductsTable pprod2
ON pprod2.OrderId = ord2.ID
AND pprod2.itemSku = pprod1.itemSku
AND pprod2.Qty = pprod1.Qty
GROUP BY ord1.CustomerId, ord1.ID, ord2.ID
HAVING COUNT(pprod1.itemSku) = COUNT(pprod2.itemSku)
) q
JOIN OrdersTable AS o ON o.ID = q.OrderId;
Test on RexTester here
$stmt = $conn->prepare('SELECT a.*, c.*, SUM(a.money+b.RESULT) AS ARESULT
FROM users a
INNER JOIN bankaccounts c
ON a.id = c.owner
INNER JOIN
(
SELECT owner, SUM(amount) AS RESULT
FROM bankaccounts
GROUP BY owner
) b ON a.id = b.owner
ORDER BY ARESULT DESC LIMIT 10');
What's problem, it show wrong only one record? I want list max 10 records - like TOP 10 richest who has [money+(all his bankaccounts amount)]
Lets say.. I have 2 tables.
Table: users
ID | username | money
1 | richman | 500
2 | richman2 | 600
Table: bankaccounts
ID | owner | amount
65 | 1 | 50
68 | 1 | 50
29 | 2 | 400
So it would list:
richman2 1000$
richman 600$
Try using a subqueries...
$stmt = $conn->prepare('SELECT a.*,
IFNULL((SELECT SUM(amount) FROM bankaccounts b WHERE b.owner=a.id),0) AS BANK_MONEY,
(IFNULL(a.money,0) + IFNULL((SELECT SUM(amount) FROM bankaccounts c WHERE c.owner=a.id),0)) AS ARESULT
FROM users a
ORDER BY ARESULT DESC LIMIT 0, 10');
EDIT: Added a field for bank account totals
EDIT2: Added IFNULL to SQL statement in case user is not in BankAccounts table
Try this:
SELECT a.*, (a.money + b.RESULT) AS ARESULT
FROM users a
INNER JOIN (SELECT owner, SUM(amount) AS RESULT
FROM bankaccounts
GROUP BY owner
) b ON a.id = b.owner
ORDER BY ARESULT DESC
LIMIT 10
I've got a budget table:
user_id product_id budget created
-----------------------------------------------------------------
1 1 300 2011-12-01
2 1 400 2011-12-01
1 1 500 2011-12-03
2 2 400 2011-12-04
I've also got a manager_user table, joining a manager with the user
user_id manager_id product_id
------------------------------------
1 5 1
1 9 2
2 5 1
2 5 2
3 5 1
What I'd like to do is grab each of the user that's assigned to Manager #5, and also get their 'budgets'... but only the most recent one.
Right now my statement looks like this:
SELECT * FROM manager_user mu
LEFT JOIN budget b
ON b.user_id = mu.user_id AND b.product_id = mu.product_id
WHERE mu.manager_id = 5
GROUP BY mu.user_id, mu.product_id
ORDER BY b.created DESC;
The problem is it doesn't pull the most recent budget. Any suggestions? Thanks!
To accomplish your task you can do as follows:
select b1.user_id,
b1.budget
from budget b1 inner join (
select b.user_id,
b.product_id,
max(created) lastdate
from budget b
group by b.user_id, b.product_id ) q
on b1.user_id=q.user_id and
b1.product_id=q.product_id and
b1.created=q.lastdate
where b1.user_id in
(select user_id from manager_user where manager_id = 5);
I'm assuming here that your (user_id, product_id, created) combination is unique.
For what it's worth, here's the code that returned what I was looking for:
SELECT DISTINCT(b1.id),mu.user_id,mu.product_id,b1.budget,b1.created
FROM budget b1
INNER JOIN (
SELECT b.user_id, b.product_id, MAX(created) lastdate
FROM budget b
GROUP BY b.user_id, b.product_id) q
ON b1.user_id=q.user_id AND
b1.product_id=q.product_id AND
b1.created=q.lastdate
RIGHT JOIN manager_user mu
ON mu.user_id = b1.user_id AND
mu.product_id = b1.product_id
WHERE mu.manager_id = 5;
Thanks for the help Andrea!