mysql: two table join with sum - mysql

Question

I'm attempting to join two tables and also get a SUM and flailing badly. I need to get the total commission amounts for each affiliate where affiliate.approved=1 AND order.status=3.
//affiliate table
affiliate_id | firstname | lastname | approved |
1 joe shmoe 1
2 frank dimag 0
3 bob roosky 1
here's the order table
//order
affiliate_id | order_status_id | commission
1 3 0.20
1 0 0.30
2 3 0.10
3 3 0.25
1 3 0.25
2 3 0.15
2 0 0.20
and here's what I'd like the query to return:
affiliate_id | commission
1 0.45
3 0.25
Here is my attempt that doesn't work. It outputs just one line.
SELECT order.affiliate_id, SUM(order.commission) AS total, affiliate.firstname, affiliate.lastname FROM `order`, `affiliate` WHERE order.order_status_id=3 AND affiliate.approved=1 AND order.affiliate_id = affiliate.affiliate_id ORDER BY total;
thanks for any help.

Answer 1

You've missed GROUP BY, try this:
SELECT
`order`.affiliate_id,
SUM(`order`.commission) AS total,
affiliate.firstname,
affiliate.lastname
FROM `order`
JOIN `affiliate`
ON `order`.order_status_id = 3 AND affiliate.approved = 1 AND `order`.affiliate_id = affiliate.affiliate_id
GROUP BY `order`.affiliate_id
ORDER BY total;
Demo Here

Answer 2

You can try this Query for your solution :-
SELECT order.affiliate_id, SUM(order.commission) AS total,affiliate.firstname,
affiliate.lastname
FROM `order`, `affiliate`
WHERE order.order_status_id=3
AND affiliate.approved=1
AND order.affiliate_id = affiliate.affiliate_id
GROUP BY order.affiliate_id
ORDER BY total;

Answer 3

Here is the solution:
select affiliate.affiliate_id,sum(`order`.commission) as total from affiliate left join `order` on affiliate.affiliate_id=`order`.affiliate_id
where affiliate.approved=1 and `order`.order_status_id=3 group by affiliate.affiliate_id
In addition,"order" is a key word of SQL , I recommend you not to use it as a table/column name.

Answer 4

First: Remove the implicit join syntax. It's confusing.
Second: You needed to group by affiliate_id. Using aggregate function without group by collapses your result set into a single row.
Here's the query using INNER JOIN:
SELECT
`order`.affiliate_id,
SUM(`order`.commission) AS total,
affiliate.firstname,
affiliate.lastname
FROM `order`
INNER JOIN`affiliate` ON `order`.affiliate_id = affiliate.affiliate_id
WHERE `order`.order_status_id = 3
AND affiliate.approved = 1
GROUP BY affiliate.affiliate_id
ORDER BY total;
WORKING DEMO
Caution: You have picked one of the reserved words of MySQL as table name (order). Be aware to enclose it with (`)backtick always .
Just a gentle reminder