I have a table (chapter) that contains 5 columns for officers in an organization: ID (key), president, vice_president, secretary, treasurer. For each office there is the value of a reference number to an individual.
For some IDs, the same value is listed for more than one of the 4 offices. You can see a basic example of my data structure below:
ID president vice_president secretary treasurer
105 1051456 1051456 1051466 1051460
106 1060923 1060937 1060944 1060944
108 1081030 1081027 1081032 1081017
110 1100498 1100491 1100485 1100485
I have also posted the same at http://sqlfiddle.com/#!9/57df1
My goal is to identify when a value is in more than one field and to SELECT that value as well as a concatenated list of all of the column titles in which it is found. For example from the supplied sample dataset, I would ideally like to return the following:
member offices
1051456 president, vice_president
1060944 secretary, treasurer
1100485 secretary, treasurer
I have found a few other examples that are similar, but nothing seems work towards what I am looking to do. I'm a novice but can piece things together from examples fairly well. I was also thinking that there might be an easier way by joining with the information_schema database as that is how I have pulled column titles in the past. It doesn't seem that this should as difficult as it is, and hopefully I am missing an easy and obvious solution. My full dataset is rather large and I would prefer to avoid any intensive sub-queries for the sake of performance. My SQL format is MySQL 5.5.
Any help or guidance would be greatly appreciated!
One method uses union all to unpivot the data and then re-aggregates:
select member, group_concat(office)
from ((select id, president as member, 'president' as office from t) union all
(select id, vice_president, 'vice_president' as office from t) union all
(select id, secretary, 'secretary' as office from t) union all
(select id, treasurer, 'treasurer' as office from t)
) t
group by member
having count(distinct office) > 1;
If you want to control the order of the values, then add a priority:
select member, group_concat(office order by priority) as offices
from ((select id, president as member, 'president' as office, 1 as priority from t) union all
(select id, vice_president, 'vice_president' as office, 2 from t) union all
(select id, secretary, 'secretary' as office, 3 from t) union all
(select id, treasurer, 'treasurer' as office, 4 from t)
) t
group by member
having count(distinct office) > 1;
Related
I have three separate tables that represent student attendance for three weeks, respectively. I want to be able to generate four columns that break down the attendance by week for each of the students. If a student was present multiple times a week, the number of times present should be added. Also, if a student was present in one week and not the next, it would get 1 for the month present (assuming it was only present once) and and 0 for the one absent. I have tried to multiple variations of count() and joins but to no avail. Any help would be greatly appreciated. The following is a truncated fiddle:
http://www.sqlfiddle.com/#!9/b847a
Here is a sample of what I am trying to achive:
Name | CurrWeek | LastWeek | TwoWkAgo
Paula | 0 | 2 | 3
Rather than three tables you should have only one with a column for the week. So naturally one solution for your request is to build it on-the-fly with UNION ALL:
select
name,
sum(week = 'currentWeek') as currentWeek,
sum(week = 'lastWeek') as lastWeek,
sum(week = 'thirdWeek') as thirdWeek
from
(
select 'currentWeek' as week, name from currentWeek
union all
select 'lastWeek' as week, name from lastWeek
union all
select 'thirdWeek' as week, name from thirdWeek
) all_weeks
group by name
order by name;
(If you want to join the three tables instead, you'd need full outer joins, which MySQL does not support, if I remember correctly. Anyway, my advice is to change the data model.)
You can try this query:
select currweek.name, currweek.att, lastweek.att, twoWkAgo.att from
(select name, count(attendance) as att from currentWeekTable group by name) currweek,
(select name, count(attendance) as att from lastWeekTable group by name) lastweek,
(select name, count(attendance) as att from twoWeekTable group by name) twoWkAgo
where twoWkAgo.name=currWeek.name and twoWkAgo.name=lastweek.name;
Assuming your 3 attendance tables contain name as common field.
I have a table that tracks employee quality assessment data. It includes the employee name, 5 yes/no fields tracking important items and the date the user did each task as column headings. Each employee gets 10 records a month so it includes a lot of data about how well our employees are doing at those 5 tasks.
I would like a report that shows me the monthly averages of these 5 yes/no fields: Appeal, NRP, Churn, Protocol, and Resub. I want those to be the Row Headers. I want the column headers to be sequential Months and the Averages to be the values. I can do this with a crosstab query for a single item such as avg:Appeal as the value and the user as the row header. How can I construct my query to use all 5 yes/no fields? They hoped for result would look like:
Table image showing how I want it to look
Comments on the Correct Answer:
June7 came up with a great answer! I changed the True to False in the DataUNION query because I wanted the Accuracy percentage and the true indicates an error on the employee evaluation. I also added in a few fields I didn't mention before. Thank you very much for helping a scrub out June7! Reading through what you wrote inspired me to start taking an SQL course on Lynda. I know its basic but you have to start somewhere and I'm getting to the point where access's builtin functions aren't doing it for me. Hopefully with the next question I'll be able to address the concerns of the commentators below that were upset that I didn't have code for myself that I had tried first.
June7's revised Code
Consider:
Query1: DataUNION
SELECT ID AS SourceID, Emp, Year([TaskDate]) AS Yr, Format([TaskDate], "mmm") AS Mo, "Appeal" AS Trend
FROM Data
WHERE Appeal=True
UNION SELECT ID, Emp, Year([TaskDate]), Format([TaskDate], "mmm"), "NRP"
FROM Data WHERE NRP = True
UNION SELECT ID, Emp, Year([TaskDate]), Format([TaskDate], "mmm"), "Churn"
FROM Data WHERE Churn = True
UNION SELECT ID, Emp, Year([TaskDate]), Format([TaskDate], "mmm"), "Protocol"
FROM Data WHERE Protocol = True
UNION SELECT ID, Emp, Year([TaskDate]), Format([TaskDate], "mmm"), "Resub"
FROM Data WHERE Resub = True;
Query2: DataCOUNT
SELECT DataUNION.Yr, DataUNION.Mo, DataUNION.Trend,
Count(DataUNION.Emp) AS CountOfEmp, Q.CntYrMo, Count([Emp])/[CntYrMo]*100 AS Pct
FROM (SELECT Year([TaskDate]) AS Yr, Format([TaskDate],"mmm") AS Mo, Count(Data.ID) AS CntYrMo
FROM Data
GROUP BY Year([TaskDate]), Format([TaskDate],"mmm")) AS Q
INNER JOIN DataUNION ON (Q.Yr = DataUNION.Yr) AND (Q.Mo = DataUNION.Mo)
GROUP BY DataUNION.Yr, DataUNION.Mo, DataUNION.Trend, Q.CntYrMo;
Query3:
TRANSFORM First(DataCount.Pct) AS FirstOfPct
SELECT DataCount.Yr, DataCount.Trend
FROM DataCount
GROUP BY DataCount.Yr, DataCount.Trend
PIVOT DataCount.Mo In ("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec");
First the schema - i have 4 tables:
office - officeid, officename
member - memberid, officeid, membername (multiple members per office)
transaction - transactionid, memberid, transactiontype (multiple transactions per member)
activity - activityid, officeid (multiple activities per office)
How can i get the list of member names, along with offices and the count of each transaction type and total count of activities for that office with a single query?
I have tried myself and i can get the office names, member names and activity count but not able to get the transaction count (per transaction type) with a single query. Wondering if this is possible at all.
Any suggestions/help is appreciated. Please let me know if i can provide any details which i missed
Edit - I added a sqlfiddle with some sample data at http://sqlfiddle.com/#!9/9cf7b/1
Also realized i had missed the officeid foreign key in the member table.
Edit - Adding expected output
officename, membername, transaction_count_1, trasaction_count_2, activitycount
abc , aa , 1 , 1, , 3
abc , bb , 1 , 0, , 1
abc , cc , 0 , 1, , 0
I think this can solve your purpose.
select b.membername,a.officename,count(transactiontype)
from office a,
member b,
transaction c
where a.officeid = b.officeid
and b.memberid = c.memberid
group by b.membername,a.officename
If you need any further data manipulation just give me an idea (perferably a screenshot or an image) of how your output shall look and i shall change the query accordingly.
Thanks.
I'm having a bit of trouble figuring out a good statement to write. I am able to achieve what I want when I query a specific 'Company' but I wanting to get the values for all of the companies in the database.
Basically I have 3 tables: Users, Companies, Plans_ExchangeMailbox. What I need to do is query how many plans are in use for each company. The plans are assigned at the user level in the users table.
Here is my table layouts:
USERS
DisplayName
CompanyCode (This is the ID from the CompanyCode in the Companies table)
MailboxPlan (This is the ID from the Plans_ExchangeMailbox Table)
Companies
CompanyName
CompanyCode
Plans_ExchangeMailbox
MailboxPlanName
MailboxPlanID
Here is the format I am looking to generate:
CompanyName, MailboxPlanName, Count (this is the number of MailboxPlanID for a company)
I was able to get this working but the problem is it can only do one company at a time and it doesn't get the CompanyName:
SELECT
Plans_ExchangeMailbox.MailboxPlanName,
SUM(CASE WHEN Users.MailboxPlan = Plans_ExchangeMailbox.MailboxPlanId THEN 1 ELSE 0 END) AS PlanCount
FROM
Plans_ExchangeMailbox, Users
WHERE
Users.CompanyCode='CC0'
GROUP BY
Plans_ExchangeMailbox.MailboxPlanName
The Final Format How it Should Be:
Headers: CompanyName, PlanName, Count
Values:
Microsoft, Bronze Plan, 5
Microsoft, Gold Plan, 20
Dell, Bronze Plan, 3
Dell, Silver Plan, 80
etc.....
Try this:
SELECT
C.CompanyName,
E.MailboxPlanName,
COUNT(1) Cnt
FROM Companies C
JOIN Users U
ON C.CompanyCode = U.CompanyCode
JOIN Plans_ExchangeMailbox E
ON U.MailboxPlan = E.MailboxPlanID
GROUP BY
C.CompanyCode,
C.CompanyName,
E.MailboxPlanID,
E.MailboxPlanName
Grouped by C.CompanyCode and E.MailboxPlanID in case if there are different companies or MailboxPlan with same name. If no,you can remove them from GROUP BY clause.
I've got a table where the columns that matter look like this:
username
source
description
My goal is to get the 10 most recent records where a user/source combination is unique. From the following data:
1 katie facebook loved it!
2 katie facebook it could have been better.
3 tom twitter less then 140
4 katie twitter Wowzers!
The query should return records 2,3 and 4 (assume higher IDs are more recent - the actual table uses a timestamp column).
My current solution 'works' but requires 1 select to generate the 10 records, then 1 select to get the proper description per row (so 11 selects to generate 10 records) ... I have to imagine there's a better way to go. That solution is:
SELECT max(id) as MAX_ID, username, source, topic
FROM events
GROUP BY source, username
ORDER BY MAX_ID desc;
It returns the proper ids, but the wrong descriptions so I can then select the proper descriptions by the record ID.
Untested, but you should be able to handle this with a join:
SELECT
fullEvent.id,
fullEvent.username,
fullEvent.source,
fullEvent.topic
FROM
events fullEvent JOIN
(
SELECT max(id) as MAX_ID, username, source
FROM events
GROUP BY source, username
) maxEvent ON maxEvent.MAX_ID = fullEvent.id
ORDER BY fullEvent.id desc;