I need to create a select statement where the statement need to retrieve data from other table column data
eg.
Table1 Table2
id id2
age age2
Select id, age from table 1 where id= id2
Is that possible.
You can use INNER JOIN
SELECT
T1.id,
T1.age
FROM Table1 AS T1
INNER JOIN Table2 AS T2
ON T1.id = T2.id2
DEMO using INNER JOIN
You can use EXISTS
SELECT
T1.id,
T1.age
FROM Table1 AS T1
WHERE EXISTS(
SELECT 1
FROM Table2 AS T2
WHERE T2.id2 = T1.id
);
You can use IN
SELECT
T1.id,
T1.age
FROM Table1 AS T1
WHERE T1.id IN (SELECT T2.id2 FROM Table2 AS T2)
Note:
In the working demo the output consists of two rows. There are two entries in tabel1 and three entries in table2. But there are only two matching entries found between these two tables. That's why output consists of only two rows.
Yes you can. It is called a JOIN and there are several types of JOINs. I suggest you read up on them on SQL JOINs.
SELECT id ,age
FROM TABLE 1
WHERE id IN (SELECT id2 FROM TABLE2);
OR
SELECT id ,age
FROM TABLE1 , TABLE2
WHERE id = id2 ;
OR
SELECT id ,age
FROM TABLE 1 , (SELECT id2 FROM TABLE2) TBL2
WHERE id = TBL2.id2 ;
Related
Here are 2 tables.
Table 1
id value
1 3
2 2
3 3
4 1
5 4
6 3
Table 2
id
1
3
4
How do I get the ids that are in Table 2 which have the max value in Table 1?
Output:
id
1
3
I already tried the following to get the max value, but I cannot figure out how to use it in a single query to get the matching rows. Because I think I need to select from the same table I just inner joined.
select max(table1.value)
from table2
inner join table1 on table1.id = table2.id;
Here is one method:
select t2.id
from (select t2.*, rank() over (order by value desc) as seqnum
from table2 t2 join
table1 t1
on t2.id = t1.id
) t
where seqnum = 1;
Or, an alternative that puts all the ids on one row:
select group_concat(t2.id) as ids
from table2 t2 join
table1 t1
on t2.id = t1.id
group by t1.value
order by t1.value desc
limit 1;
You have a couple of options available without using window functions:
You can use a WHERE clause to select only id values that have a value equal to the MAX(value) from your query and an id that is in Table2:
SELECT t1.id
FROM Table1 t1
WHERE value = (
SELECT MAX(t1.value)
FROM Table2 t2
JOIN Table1 t1 ON t1.id = t2.id
)
AND id IN (SELECT id FROM Table2)
You can JOIN your query to Table1 and Table2 again, matching the value in Table1 and the id in Table2:
SELECT t1.id
FROM (
SELECT MAX(t1.value) AS max_value
FROM Table2 t2
JOIN Table1 t1 ON t1.id = t2.id
) t
JOIN Table1 t1 ON t1.value = t.max_value
JOIN Table2 t2 ON t2.id = t1.id
In both cases the output is
id
1
3
Demo on SQLFiddle
Too low to comment but from the SQL statement you gave, you just need to add the tableid in your select parameters.
select table2.id, max(table1.value)
from table2
inner join table1 on table1.id = table2.id;
I have two table, t1 and t2.
-- t1
id name address
1 Tim A
2 Marta B
-- t2
id name address
1 Tim A
3 Katarina C
If I do t1 full outer join with t2
SELECT * FROM t1
LEFT JOIN t2 ON t1.id = t2.id
UNION ALL
SELECT * FROM t1
RIGHT JOIN t2 ON t1.id = t2.id
However, the result has ambitious id, name, address.
How do I rename this so that I don't have duplicate column name?
Attempt:
SELECT name, address FROM
(SELECT * FROM t1
LEFT JOIN t2 ON t1.id = t2.id
UNION ALL
SELECT * FROM t1
RIGHT JOIN t2 ON t1.id = t2.id) as derived_table;
return: ERROR- duplicate column name "name".
Ditch the * in the SELECT list.
Specify the list of expressions to be returned. And qualify all column references with either the table name, or preferably, a shorter table alias.
And assign an alias to the expression and that will be the name of the column in the resultset.
Also, the query shown is not equivalent to a FULL OUTER JOIN.
If the goal is return all rows from t1, and to also return rows from t2 where a matching row doesn't exist in t1, I'd do something like this...
SELECT t.id AS t_id
, t.name AS t_name
, t.addr AS t_addr
FROM t1 t
UNION ALL
SELECT s.id
, s.name
, s.addr
FROM t2 s
LEFT
JOIN t1 r
ON r.id = s.id
WHERE r.id IS NULL
Try fully qualifying it like
SELECT t1.id, t1.name, t1.address FROM t1
I have two tables. The first table contains ID, First_Name and Last_Name.
The 2nd table contains two foreign key fields containing different ID's of the first table.
I want to be able to run a SQL query that gets reults of the 2nd table which then grabs the First_Name of each member based on the two different foreign keys.
How would I go about doing this?
select t2.*, t1a.firstname, t1b.firstname
from table2 t2
left join table1 t1a on t2.fk1 = t1a.id
left join table1 t1b on t2.fk2 = t1b.id
Suppose the second table has fields as such
userid, supervisorid ( both referring to the Id column of the first table )
you may write join to get the value like this
SELECT t2.*, ID, firstname, lastname FROM table 2 t2
LEFT OUTER JOIN table 1 t1 ON
t2.userid = t1.id
OR t2.supervisorid = t1.id
I think correct sql would be below one using OR condition in outer join or using union
SELECT t1.id,t1.name from table1 t1, table2 t2 WHERE t1.id1 = t2.id1
UNION
SELECT t1.id,t1.name from table1 t1, table2 t2 WHERE t1.id1 = t2.id0
SELECT t1.id, t1.name from table2 t2 LEFT OUTER JOIN table1 t2 ON t1.id = t2.id or t1.id1 = t2.id0
I have two tables, which I will call table1 and table2. Table1 has 2 fields, id and auth, table2 also has two fields, id and keywords. Note that id of table1 and table2 match.
This is my query:
SELECT id, MATCH(keywords) AGAINST('example') FROM table2 WHERE MATCH(keywords) AGAINST('example')
How am I going to exclude results where the auth (table1) of that same id is not 1?
SELECT id, MATCH(keywords) AGAINST('example')
FROM table2 t2
WHERE MATCH(keywords) AGAINST('example')
AND NOT EXISTS (select 1 from table1 t1 where t1.id = t2.id and t1.auth != 1)
SELECT *
FROM table1 t1
INNER JOIN table2 t2
ON t1.id != t2.id
I want to do a sql query and have some problems:
I want to select from table_1 the ID's Where parent_id is the value I have:
SELECT ID
FROM table_1
WHERE parent_ID = 'x'
I want to use the ID'S I got in 1. and
SELECT
FROM table_2
WHERE ID = 'The ID's from Query 1.'
Like this?
select ...
from table_1 a
join table_2 b on(a.id = b.id)
where a.parent_id = 'x';
Edit
Note: the query will potentially produce duplicate rows depending on the keys and relation between the tables. For example, you will get duplicates if, for a given table_1.parent_id = X, there can be multiple occurrences of the same table_1.ID.
Another example is when table_2.ID isn't unique.
In those cases you would want to remove the duplicates (using distinct, group by, partitioned #row_number, etc) or, not produce the duplicates in the first place using a semi-join instead (exists, in). Have a look #OMG Ponies answer for reference.
Using IN
SELECT t2.*
FROM TABLE_2 t2
WHERE t2.id IN (SELECT t1.id
FROM TABLE_1 t1
WHERE t1.parent_id = 'x')
Using EXISTS
SELECT t2.*
FROM TABLE_2 t2
WHERE EXISTS (SELECT NULL
FROM TABLE_1 t1
WHERE t1.id = t2.id
AND t1.parent_id = 'x')
Using an INNER JOIN
The DISTINCT (or GROUP BY) is necessary to eliminate duplicates if there are more than one records in TABLE_1 that relate to a record in TABLE_2:
SELECT DISTINCT t2.*
FROM TABLE_2 t2
JOIN TABLE_1 t1 ON t1.id = t2.id
AND t1.parent_id = 'x'
It can be solved with the use of IN as follows:
SELECT * FROM table_2 WHERE ID IN (SELECT ID FROM table_1 WHERE parent_ID = 'x')
select * from table_2 where id in (select id from table_1 where parent_id = 'x')
Yes, it's better to you use this:
SELECT [value]
FROM [table2]
WHERE [value] IN (SELECT [value]
FROM [table1]
WHERE [value] = "[value]"
)