I am trying to get a list of company_id's that have no company-level notes. The company may, however, have location-level notes.
company
-------------------------
company_id name deleted
1 Foo 0
2 Bar 0
3 Baz 0
location
-----------------------
location_id company_id
6 1
7 2
8 3
note
-----------------------------------------
note_id company_id location_id deleted
10 2 6 0 // location-level note
11 1 7 0 // location-level note
12 null 8 0 // location-level note
13 2 null 0 // company-level note
I would want my result table to be this:
company_id name
1 Foo
3 Baz
Update
Foo/company_id = 1 does not have a company-level note because the note also has a location_id, which makes it a location-level note. Company-level notes are notes that only link to a company (and not a location).
End of Update
I've tried doing something like this, but it returns an empty set, so I'm not sure if it's working and there aren't any companies without company-level notes or if I'm doing something wrong.
SELECT DISTINCT
c.company_id,
c.name
FROM company AS c
LEFT JOIN note AS n
ON c.company_id = n.company_id
WHERE
c.deleted = 0 AND
n.deleted = 0 AND
n.location_id IS NOT NULL AND
n.location_id != 0 AND
c.company_id = (SELECT MAX(company_id) FROM company)
Revised Accepted Answer by Mike
SELECT
company_id,
name
FROM company
WHERE
deleted = 0 AND
company_id NOT IN (
SELECT DISTINCT
c.company_id
FROM company AS c
INNER JOIN note AS n
ON c.company_id = n.company_id
WHERE (
n.deleted = 0 AND
(n.location_id IS NULL OR
n.location_id = 0)
)
);
The easiest way to think about this is to first find the all the companies that have company level notes, which you can do with
select distinct c.company_id
from company c
inner join notes n
on c.company_id = n.company_id
where n.location_id is null;
Then simply remove these companies from the company select:
select company_id,
name
from company
where company_id not in (select distinct c.company_id
from company c
inner join notes n
on c.company_id = n.company_id
where n.location_id is null);
*Updated to use inner join instead of comma-separated join.
SELECT DISTINCT c.*
FROM company c
LEFT
JOIN note n
ON n.company_id = c.company_id
AND n.location_id IS NULL
WHERE n.note_id IS NULL;
Related
I have 3 tables.
Owners:
ownerID name
1 josh
Pets:
petID name
1 M
2 x
3 f
4 h
PetsOwners:
petID ownerID
1 1
3 1
4 1
I have a query that returns the ownerID from a person. "SELECT ownerID FROM Owners WHERE name = 'josh';" This will return ownerID = 1. I need a query that returns all pets that josh owns. In this case will be "m", "f" and "h" according to the petsOwners table.
If you have ownerId use
SELECT p.name
FROM Pets p
JOIN PetsOwners po
ON p.petID = po.petID
WHERE po.ownerID = 1
If you only have the owner name, need join all 3 tables
SELECT p.name
FROM Pets p
JOIN PetsOwners po
ON p.petID = po.petID
JOIN Owners o
ON po.ownerID = o.ownerID
WHERE o.name = 'josh'
If you just want their names:
SELECT Pets.name
FROM Pets, PetsOwners, Owners
WHERE Pets.petID = PetsOwners.petID
AND Owners.ownerID = PetsOwners.ownerID;
try this:
select a.ownerID,a.`name`as OwnerName, b.petID,b.`name` as PetName from
(select ownerID `name` from Owners) as a
right join
(select a.petID,a.`name`,OwnerID from
(select petID,`name` from Pets) as a
left JOIN
(select petID,OwnerID from PetsOwners) as b
on a.petID = b.petID) as b
on a.ownerID = b.OwnerID
I see your question and this is easy you see the query I wrote blow:
SELECT links.`link`,
links.`link_id`
FROM links
WHERE links.`link_id` NOT IN
(SELECT Y.`link_id`
FROM users X
INNER JOIN user_visited Y ON X.`user_id` = Y.`user_id`
WHERE X.`user_id` = 22 );
I have a table like this, in which I need to set the male and female counts for the primary key id:
summaryTable:
id femaleCount maleCount
-----------------------------
s1 ? ?
s2 ? ?
... and so on
There is a detail table as below, that has the users corresponding to each id of summaryTable:
id parentId userId
--------------------------
1 s1 u1
2 s1 u2
3 s2 u2
4 s2 u2
...and so on
The third is the user table like this:
userTable:
userId gender
-------------
u1 M
u2 F
u3 F
..and so on
I have to update the summary table with the counts of male and female. So as per the above, for id=s1, femaleCount should be set to 1 , maleCOunt=1
For id=s2, femaleCOunt should get set to 2 and maleCount=0
Is this possible to do using an UPDATE query in MySQL?
I tried the following, but this returns the sum of occurences of a user i.e. if u1 occurs 2 times for p1(say), then it will return count as 2 and not 1:
SELECT
d.parentId,
SUM(gender = 'F') AS 'F#',
sum(gender = 'M') as 'M#'
FROM detailsTable as d
JOIN userTable as c on c.userId = d.userId
GROUP BY d.parentId;
Also tried as below, but it gave an error:
select d.parentId,
count(case when c.gender='M' then 1 end) as male_cnt,
count(case when c.gender='F' then 1 end) as female_cnt,
from detailsTable d, userTable c where d.userId=c.userId group by d.parentId, d.userId ;
Further, my problem doesnt just end at the select, I need to get the values and then update these in the summary table too.
I might be rusty on the syntax for MySql but I believe this does what you need. The CASE/SUM is effectively a pivot to get the counts, then you can update the table as normal.
UPDATE summaryTable AS st
INNER JOIN ( SELECT parentId
,SUM(CASE WHEN gender = 'f' THEN 1
ELSE 0
END) femaleCount
,SUM(CASE WHEN gender = 'm' THEN 1
ELSE 0
END) maleCount
FROM userTable d
INNER JOIN (SELECT DISTINCT parentId, userId FROM detail) ut ON d.userId = ut.userId
GROUP BY parentId
) AS c ON c.parentId = st.parentId
SET femaleCount = c.femaleCount
,maleCount = c.maleCount
I have been trying to solve this issue for a while, hope anyone help me. I am having two table, the first table is
Table Name : OnlineTest
OnlineTestId category subcategory
1 English Spelling
2 English Grammar
3 English Antonyms
4 English Synonyms
The second table is
Table Name : UserStatus
Id userId status onlineTestId
1 1 Finished 1
2 1 Not Finished 2
3 2 Not Finished 1
4 2 Finished 3
5 3 Not Finished 4
Result
OnlineTestId userId status
1 1 Finished
2 1 Not Finished
3 null null
4 null null
I have tried this query,
select c.onlinetestid, d.userid, d.status from onlinetest c left join userstatus d on d.onlinetestid = c.onlinetestid
where c.category = 'English' and d.userid = 1;
But this query is bring the first two row of the result and not the last two, in which the userId and status are null.
How to bring the above result?
Place the d.userid = 1 predicate in the ON clause:
select c.onlinetestid, d.userid, d.status
from onlinetest c
left join userstatus d on d.onlinetestid = c.onlinetestid and d.userid = 1
where c.category = 'English'
This will return all rows from onlinetest, having columns of userstatus filled with nulls where predicate d.userid = 1 fails.
You can also use left outer Join as below :
SELECT c.OnlineTestId, d.userId, d.status
FROM OnlineTest AS c LEFT OUTER JOIN
UserStatus AS d ON d.onlineTestId = c.OnlineTestId AND d.userId = 1
WHERE (c.category = 'English')
I have 3 table, log, member, also guest, but my log i stored as customer(user)'s id only, which is either their guest_id or member_id. So here's the problem, because they're from different table, I'm not sure how to join & group together their data.
checkout_log table
id user_id checkout_as
--------------------------------------
1 1 member
2 2 guest
members table
id fullname
--------------------------------------
1 member01
2 member02
guests table
id fullname
--------------------------------------
1 guest01
2 guest02
What I wanted to Achieve - Result
id user_id fullname checkout_as
----------------------------------------------
1 1 member01 member
2 2 guest02 guest
Had tried following sql statement with UNION ALL, or GROUP BY , but had no luck.
SELECT * FROM
(
SELECT checkout_log.id,checkout_log.user_id,guests.fullname,guests.email,checkout_log.checkout_as
FROM checkout_log
LEFT JOIN checkout_product ON checkout_product.checkout_log_id = checkout_log.id
LEFT JOIN guests ON checkout_log.user_id = guests.id
UNION ALL
SELECT checkout_log.id,checkout_log.user_id,members.fullname,members.email,checkout_log.checkout_as
FROM checkout_log
LEFT JOIN checkout_product ON checkout_product.checkout_log_id = checkout_log.id
LEFT JOIN members ON checkout_log.user_id = members.id
) derivedTable
GROUP BY id
Try doing this with joins instead of union
select cl.id, cl.user_id,
coalesce(m.fullname, g.fullname) as fullname,
cl.checkout_as
from checkout_log cl left join
members m
on cl.user_id = m.id and cl.checkout_as = 'member' left join
guests g
on cl.user_id = g.id and cl.checkout_as = 'guest';
Below is the query I am using to get the team information. However, I want also display both usernames assorted with the team. The database is setup using two tables. One contains all of the user information and the other (userLeagues) contains a set of ids, such as userID and teamID.
Example - userLeagues
leagueID | userID | teamID
1 1 1
1 5 1
1 10 2
2 1 1
2 8 1
This is result I am trying to achieve.
leagueID | TeamID | userID1| userID1
1 1 1 5
This would then be outputed as :
leagueID | TeamID | userID1 | userID1
1 Mad Racing driver 1 dirver 5
This is the code I have so far which gets the team but how do I get both driers and their username associated with the same team?
SELECT
u.username
, t.teamName
, t.teamImage
/* File Table */
, f.fileType
FROM
userleague ul
INNER JOIN users u ON u.userID = ul.userID
LEFT JOIN teams t ON t.teamID = ul.teamID
LEFT JOIN fileType f ON f.fileID = t.fileID
WHERE leagueID = 1
GROUP BY ul.teamID
You can do this with min() and max(), if there are only two values:
SELECT t.teamName, t.teamImage, f.fileType,
min(u.username) as user1,
(case when max(u.username) > min(u.username) then max(u.username) end) as user2
FROM userleague ul INNER JOIN
users u
ON u.userID = ul.userID LEFT JOIN
teams t
ON t.teamID = ul.teamID LEFT JOIN
fileType f
ON f.fileID = t.fileID
WHERE leagueID = 1
GROUP BY t.teamName, t.teamImage, f.fileType;