MySql multiple times Where in Condition if possible - mysql

Question

i am Performing the MySQL query with Where In conditions.
Here is my Query.
The query should be:
SELECT * FROM users WHERE id IN (44,44,33,44,33,0);
Query showing my correct result, no problem at all,
but what i want to do is Can we Divide all the id with the individual conditions ?
Or can a query has multiple Where In for a single column?
like
SELECT * FROM users WHERE id IN (44)
AND id IN (45)
AND id IN (46);
like this.
Is that possible ? ?
My query code for performing the query, its in Laravel.
$films = Film::with('genre')->with('languages')->with('likes')->with('comments')->with('likedBy');
if(Input::get('sort')){
$sort = Input::get('sort');
switch ($sort){
case 'old_new':
$films = $films->orderBy('created_at', 'asc');
break;
case 'new_old':
$films = $films->orderBy('created_at', 'desc');
break;
case 'views':
// $films = DB::table('films')
// ->leftJoin('film_views', 'films.id', '=', 'film_views.film_id')
// ->select(DB::raw('films.*, count(film_views.film_id) as views'))
// ->groupBy('films.id')
// ->orderBy('views' , 'desc')
// ;
$films = $films
->leftJoin('film_views', 'films.id', '=', 'film_views.film_id')
->select(DB::raw('films.*, count(film_views.film_id) as views'))
//->whereBetween('created_at', [$this->first_day_of_search, $this->final_day_of_search])
->groupBy('films.id')
->orderBy('views' , 'desc')
;
break;
case 'likes':
$films = $films
->leftJoin('film_likes', 'films.id', '=', 'film_likes.film_id')
->select(DB::raw('films.*, count(film_likes.film_id) as likes'))
->groupBy('films.id')
->orderBy('likes' , 'desc')
;
break;
}
}
if(Input::get('filter')) {
$jsonFilter = Input::get('filter');
$filters = json_decode($jsonFilter);
foreach ($filters as $filter => $value){
switch ($filter){
case "genre":
if($value){
$films = $films->whereHas('genre', function ($query) use($value) {
$query->whereIn('genre_id', $value);
});
}
break;
case "cert":
if($value){
$films = $films->whereIn('cert', $value);
}
break;
case "country":
if($value){
$films = $films->whereIn('country', $value);
}
break;
case "lang":
if($value){
$films = $films->whereHas('languages', function ($query) use($value) {
$query->whereIn('language_id', $value);
});
}
break;
}
}
}
$films = $films->paginate(5);
return parent::api_response($films->toArray(), true, ['return' => 'all films'], 200);

Answer 1

I will post an answer if for no other reason than amusement. I believe that a WHERE IN clause is internally converted into a series of equality onditions separated by OR. So your original query
SELECT * FROM users WHERE id IN (44,44,33,44,33,0)
would be internally converted to this
SELECT * FROM users WHERE id = 44 OR id = 44 OR id = 33 OR id = 44 OR
id = 33 OR id = 0
So having a single number for your IN clause would be equivalent to a single equality condition.
By the way, you have the same numbers appearing multiple times, which doesn't make any sense.

Answer 2

Yes, it is possible to have multiple WHERE IN.
SELECT * FROM users WHERE id IN (44) OR id IN (45) OR id IN (46);
This is correct.
However I don't understand why you want to do this because this is low in performance compared to having one IN