select data mysql - mysql

i have in my table places named field. there are space separated values(there are problem to store csv value in one field). now i want to fire query like below. how i can do ??
select * from tablename where variablename in places
i did try this way but it shows syntax error.
select * from tablename where variablename in replace(places,' ',',')
### places ###
bank finance point_of_interest establishment


Use FIND_IN_SET
For comma separated
SELECT *
FROM tablename
WHERE ( FIND_IN_SET( 'bank', variablename ) )
Refer : SQL Fiddle
For space separated
SELECT *
FROM tablename
WHERE ( FIND_IN_SET( 'bank', replace(variablename,' ',',') ) )
Refer : SQL Fiddle


The best solution would be to normalise your data structure and do not have a single field storing multiple values.
You can make a query work without normalisation, but any solutions would be lot less optimal from a performance point of view.
Use patter matching with like operator:
... where fieldname like '% searched_value %'
Use the replace() function and combine it with find_in_set():
... where find_in_set('searched_value',replace(fieldname,' ',','))>0


Hi I think your problem comes from the usage of IN
IN for MySql is used like this
SELECT *
FROM table_name
WHERE column_name IN (bank,finance,point_of_interest, establishment);
In case of you want to select places you need to specify each place into value like

Related

how to pass multiple variables in WHERE ... IN in stored procedure? [duplicate]

I have a column in one of my table where I store multiple ids seperated by comma's.
Is there a way in which I can use this column's value in the "IN" clause of a query.
The column(city) has values like 6,7,8,16,21,2
I need to use as
select * from table where e_ID in (Select city from locations where e_Id=?)
I am satisfied with Crozin's answer, but I am open to suggestions, views and options.
Feel free to share your views.

Building on the FIND_IN_SET() example from #Jeremy Smith, you can do it with a join so you don't have to run a subquery.
SELECT * FROM table t
JOIN locations l ON FIND_IN_SET(t.e_ID, l.city) > 0
WHERE l.e_ID = ?
This is known to perform very poorly, since it has to do table-scans, evaluating the FIND_IN_SET() function for every combination of rows in table and locations. It cannot make use of an index, and there's no way to improve it.
I know you said you are trying to make the best of a bad database design, but you must understand just how drastically bad this is.
Explanation: Suppose I were to ask you to look up everyone in a telephone book whose first, middle, or last initial is "J." There's no way the sorted order of the book helps in this case, since you have to scan every single page anyway.
The LIKE solution given by #fthiella has a similar problem with regards to performance. It cannot be indexed.
Also see my answer to Is storing a delimited list in a database column really that bad? for other pitfalls of this way of storing denormalized data.
If you can create a supplementary table to store an index, you can map the locations to each entry in the city list:
CREATE TABLE location2city (
location INT,
city INT,
PRIMARY KEY (location, city)
);
Assuming you have a lookup table for all possible cities (not just those mentioned in the table) you can bear the inefficiency one time to produce the mapping:
INSERT INTO location2city (location, city)
SELECT l.e_ID, c.e_ID FROM cities c JOIN locations l
ON FIND_IN_SET(c.e_ID, l.city) > 0;
Now you can run a much more efficient query to find entries in your table:
SELECT * FROM location2city l
JOIN table t ON t.e_ID = l.city
WHERE l.e_ID = ?;
This can make use of an index. Now you just need to take care that any INSERT/UPDATE/DELETE of rows in locations also inserts the corresponding mapping rows in location2city.

From MySQL's point of view you're not storing multiple ids separated by comma - you're storing a text value, which has the exact same meaing as "Hello World" or "I like cakes!" - i.e. it doesn't have any meaing.
What you have to do is to create a separated table that will link two objects from the database together. Read more about many-to-many or one-to-many (depending on your requirements) relationships in SQL-based databases.

Rather than use IN on your query, use FIND_IN_SET (docs):
SELECT * FROM table
WHERE 0 < FIND_IN_SET(e_ID, (
SELECT city FROM locations WHERE e_ID=?))
The usual caveats about first form normalization apply (the database shouldn't store multiple values in a single column), but if you're stuck with it, then the above statement should help.

This does not use IN clause, but it should do what you need:
Select *
from table
where
CONCAT(',', (Select city from locations where e_Id=?), ',')
LIKE
CONCAT('%,', e_ID, ',%')
but you have to make sure that e_ID does not contain any commas or any jolly character.
e.g.
CONCAT(',', '6,7,8,16,21,2', ',') returns ',6,7,8,16,21,2,'
e_ID=1 --> ',6,7,8,16,21,2,' LIKE '%,1,%' ? FALSE
e_ID=6 --> ',6,7,8,16,21,2,' LIKE '%,6,%' ? TRUE
e_ID=21 --> ',6,7,8,16,21,2,' LIKE '%,21,%' ? TRUE
e_ID=2 --> ',6,7,8,16,21,2,' LIKE '%,2,%' ? TRUE
e_ID=3 --> ',6,7,8,16,21,2,' LIKE '%,3,%' ? FALSE
etc.

Don't know if this is what you want to accomplish. With MySQL there is feature to concatenate values from a group GROUP_CONCAT
You can try something like this:
select * from table where e_ID in (Select GROUP_CONCAT(city SEPARATOR ',') from locations where e_Id=?)

this one in for oracle ..here string concatenation is done by wm_concat
select * from table where e_ID in (Select wm_concat(city) from locations where e_Id=?)
yes i agree with raheel shan .. in order put this "in" clause we need to make that column into row below code one do that job.
select * from table where to_char(e_ID)
in (
select substr(city,instr(city,',',1,rownum)+1,instr(city,',',1,rownum+1)-instr(city,',',1,rownum)-1) from
(
select ','||WM_CONCAT(city)||',' city,length(WM_CONCAT(city))-length(replace(WM_CONCAT(city),','))+1 CNT from locations where e_Id=? ) TST
,ALL_OBJECTS OBJ where TST.CNT>=rownum
) ;

you should use
FIND_IN_SET Returns position of value in string of comma-separated values
mysql> SELECT FIND_IN_SET('b','a,b,c,d');
-> 2

You need to "SPLIT" the city column values. It will be like:
SELECT *
FROM table
WHERE e_ID IN (SELECT TO_NUMBER(
SPLIT_STR(city /*string*/
, ',' /*delimiter*/
, 1 /*start_position*/
)
)
FROM locations);
You can read more about the MySQL split_str function here: http://blog.fedecarg.com/2009/02/22/mysql-split-string-function/
Also, I have used the TO_NUMBER function of Oracle here. Please replace it with a proper MySQL function.

IN takes rows so taking comma seperated column for search will not do what you want but if you provide data like this ('1','2','3') this will work but you can not save data like this in your field whatever you insert in the column it will take the whole thing as a string.

You can create a prepared statement dynamically like this
set #sql = concat('select * from city where city_id in (',
(select cities from location where location_id = 3),
')');
prepare in_stmt from #sql;
execute in_stmt;
deallocate prepare in_stmt;

Ref: Use a comma-separated string in an IN () in MySQL
Recently I faced the same problem and this is how I resolved it.
It worked for me, hope this is what you were looking for.
select * from table_name t where (select (CONCAT(',',(Select city from locations l where l.e_Id=?),',')) as city_string) LIKE CONCAT('%,',t.e_ID,',%');
Example: It will look like this
select * from table_name t where ',6,7,8,16,21,2,' LIKE '%,2,%';

SQL SELECT WHERE NOT LIKE

I have an array:
$codes = array (97121, 97122, 97123, 97180);
The real array is much longer, it contains nearly 130 codes so I think it doesn't have to be a loop.
And I have a mySQL table that has a column VilleAnn (city with postal code) ex:
Sainte-Anne 97180
Sanary-sur-Mer 83110
Using mysqli I have to select where VilleAnn doesn't contain any postal code from the array $codes.
If the VilleAnn is a simple postal code I would say:
SELECT * FROM table WHERE VilleAnn NOT IN(97121, 97122, 97123, 97180)
But in this case it must be something using NOT LIKE "%..."
Any suggestions?

You could you REGEXP:
SELECT * FROM table WHERE VilleAnn NOT REGEXP '97121|97122|97123|97180|....'

In condition doesn't work with the wildcard characters. Your best bet is to try and extract the postcode from the original field, in this example
SELECT * FROM table WHERE right(VilleAnn,5) NOT IN ('97121', '97122', '97123', '97180')
I presume real life is more complicated, so this might need to be adjusted to reflect the actual format of the field.

Something like this:
SELECT *
FROM `table`
WHERE (
`VilleAnn` NOT LIKE '%97121%' AND
`VilleAnn` NOT LIKE '%97122%' AND
`VilleAnn` NOT LIKE '%97123%' AND
`VilleAnn` NOT LIKE '%97180%'
)

SELECT * FROM table WHERE VilleAnn NOT REGEXP '[0-9]';
This will help you.
For to check four times occurrences you can use:
SELECT * FROM table WHERE VilleAnn NOT REGEXP '[0-9]{4}';

Match comma seperated list with input in SQL statement

Im optimizing my SQL statement to make it faster.
I have a comma seperated list with zipcodes like
1111, 1112,1115,1112 etc etc
Now in my query I want to match if the iput matches 1 of those zipcodes. If so.. then it will return a ID of the object that has all those zipcodes.
But what is the best way to do this now im doing
AND ( loc.loc_zip LIKE '%".$_REQUEST['zip']."%'
Validation of the input will be added ofcourse.. but this is just for testing. But I have tested this and it seems a bit slow.
Is this the best way to do this ?

you should use 'in'
select * from Users where userid in (1,2,3,4,45,6,656)
Edit:
if the ZipCodes are Chars, you can only use in if you separate them by ''
select * from loc where loc.loc_zip in ('1111','1112','1115','1112')
if .$_REQUEST['zip']. has ' ' then->
select * from loc where loc.loc_zip in (.$_REQUEST['zip'].)
if the ZipCodes are int you can use the first statement
Bare in mid you must intersect your list with '' or it wont work

MySQL get all characters before specific character

I have a table where I extract some values, one column values can contain "value1|value2|value3", but I only want to get the characters before the | - "value1".
This is what I tried, but it doesn't work.. What am I doing wrong?
Thanks!
$sql = "SELECT * LEFT('Like', LOCATE('|', 'Like')-1) FROM $tablename
WHERE Parent = '0' AND Type LIKE 'top' ORDER BY Order ASC";
I want to use this for ALL values, not just one field..

you need the following statement to get that portion of [ColName]:
LEFT([ColName],INSTR([ColName],"|")-1)
If you want to select multiple columns into the same recordset column you can union all with something like the following:
SELECT LEFT(ColName,INSTR(ColName,"|")-1) AS FirstValue From $TableName;
UNION ALL
SELECT LEFT(ColName2,INSTR(ColName2,"|")-1) AS FirstValue From $TableName;
If you want to use this on multiple columns, script the creation of the sql.

Two things: (1) you don't have a comma between your * and the expression you're trying to do with LEFT and (2) you're putting like in quotes, so the functions are working on the constant value like instead of your column named like. Try putting like in backticks.
SELECT *, LEFT(`Like`, LOCATE('|', `Like`)-1)
...
You can also use the MySQL SUBSTRING_INDEX function for this:
SELECT *, SUBSTRING_INDEX(`Like`, '|', 1)
...

"Merge" IN and LIKE operator in Mysql

I've a problem and I'm guessing if there's a better way to achieve my goal. I've this query in Mysql to retrieve some rows:
SELECT *
FROM table
WHERE field IN ('V','S','G','B')
What I would like to do is to run a query that retrieve the rows where the field has value LIKE those in the IN list. I know that the trivial way is to use this query:
SELECT *
FROM table
WHERE field LIKE '%V%' OR field LIKE '%S%' OR
field LIKE '%G%' OR field LIKE '%B%'
What I want to know is there's an operator that do this or at least, if that operator does not exist, a better way to write the query.
Thanks to everyone that will help me.

Put the values in a table (Params) then use
SELECT *
FROM table
WHERE EXISTS (
SELECT *
FROM Params
WHERE table.field LIKE '%' + Params.col + '%'
);
Consider also putting the wildcard characters into the values in the Params table.