I want a MySQL query to fetch previous year records.
I already wrote a query to fetch current year records but I want previous year record also. There is a column called "date_created" based upon this date I have to fetch the status of the meterial.
SELECT material_status, COUNT(*) c
FROM purchase_order
WHERE YEAR(date_created) = YEAR(CURDATE()) AND material_status='open';
to get last year data
SELECT material_status, COUNT(*) c
FROM purchase_order
WHERE YEAR(date_created) = YEAR(DATE_SUB(CURDATE(), INTERVAL 1 YEAR)) AND material_status='open';
Query to see how the date time functions for MySQL works
Try This:
select
CURRENT_USER() user,
CURRENT_TIME() current_time,
CURRENT_DATE() current_date,
year(CURRENT_DATE()) current_year,
YEAR(DATE_SUB(CURDATE(), INTERVAL 1 YEAR)) previous_year;
Related
I have the query where i am getting the data but one year back till now,
select * from tblorders
where CreatedDateTime >= DATE_SUB(NOW(),INTERVAL 1 YEAR);
how can i get the data from the start of the current year till date data
start of the current year like 01/01/2021
select * from tblorders
where ( CreatedDateTime between DATE_FORMAT(NOW() ,'%Y-01-01') AND NOW() )
This would return from the beginning of the current year till current date
How about
select * from tblorders
where YEAR(CreatedDateTime) = YEAR(NOW());
DBFiddle: https://www.db-fiddle.com/f/d7h2raMmvxngn1uigPjoB5/0
I want to count the distinct number of fd_id over the time between today and yesterday, between today and 3 days ago, between today and 5 days ago, between today and 7 days ago, between today and 15 days ago, between today and 30 days ago.
My data table looks like the following:
user_id. fd_id. date
1. 123a. 20201010
1. 123a. 20201011
1. 124a. 20201011
...
and the desired result is of the following format:
user_id count_fd_id_1d count_fd_id_3d ... count_fd_id_30d
Specifically, I know I can do the following 6 times and join them together (some column bind method):
select user_id, count(distinct fd_id) as count_fd_id_1d
from table
where date <= today and date >= today-1 (#change this part for different dates)
select user_id, count(distinct fd_id) as count_fd_id_3d
from table
where date <= today and date >= today-3 (#change this part for different dates)
...
I am wondering how I may do this in one shot without running almost identical code for 6 times.
You can use conditional aggregation:
select user_id,
count(distinct case when date >= current_date - 1 day and date < current_date then fd_id end) as cnt_1d,
count(distinct case when date >= current_date - 3 day and date < current_date then fd_id end) as cnt_3d,
...
from mytable
goup by user_id
You can play around with the date expressions to set the ranges you want. The above works on entire days, and does not include the current day.
If the date column in the the table really does look like that (not in date/datetime format), I think you need to use STR_TO_DATE() to convert it to date format then uses DATEDIFF to check the date differences. Consider this example query:
SELECT user_id,
MAX(CASE WHEN ddiff=1 THEN cn END) AS count_fd_id_1d,
MAX(CASE WHEN ddiff=2 THEN cn END) AS count_fd_id_2d,
MAX(CASE WHEN ddiff=3 THEN cn END) AS count_fd_id_3d,
MAX(CASE WHEN ddiff=4 THEN cn END) AS count_fd_id_4d,
MAX(CASE WHEN ddiff=5 THEN cn END) AS count_fd_id_5d
FROM (SELECT user_id,
DATEDIFF(CURDATE(), STR_TO_DATE(DATE,'%Y%m%d')) ddiff,
COUNT(DISTINCT fd_id) cn
FROM mytable
GROUP BY user_id, ddiff) A
GROUP BY user_id;
At the moment, if you check date value simply by using direct subtraction, you'll get incorrect result. For example:
*your current date value - how many days:
'20201220' - 30 = '20201190' <-- this is not correct.
*if you convert the date value and using the same subtraction:
STR_TO_DATE('20201220','%Y%m%d') - 30 = '20201190' <-- still get incorrect.
*convert date value then uses INTERVAL for the date subtraction:
STR_TO_DATE('20201220','%Y%m%d') - INTERVAL 30 DAY = '2020-11-20'
OR
DATE_SUB(STR_TO_DATE('20201220','%Y%m%d'),INTERVAL 30 DAY) = '2020-11-20'
*IF your date column is storing standard date format value, then omit STR_TO_DATE
'2020-12-20' - INTERVAL 30 DAY = '2020-11-20'
OR
DATE_SUB('2020-12-20',INTERVAL 30 DAY) = '2020-11-20'
Check out more date manipulation in MySQL.
For the question, I made a fiddle with a bunch of testing.
From this database, I want to select those data which payment_date is current month but the service_date is any month except this month.
Database sample
One way to check if 2 dates are in the same month is with the use of the function last_day(), because if for 2 dates the last day of their month is the same then they are in the same month:
select *
from tablename
where last_day(payment_date) = last_day(curdate())
and last_day(service_date) <> last_day(curdate())
If you want the results for any month and not for the current month only:
select *
from tablename
where last_day(payment_date) <> last_day(service_date)
I have a table
id user Visitor timestamp
13 username abc 2014-01-16 15:01:44
I have to 'Count' total visitors for a 'User' for last seven days group by date(not timestamp)
SELECT count(*) from tableA WHERE user=username GROUPBY __How to do it__ LIMIT for last seven day from today.
If any day no visitor came so, no row would be there so it should show 0.
What would be correct QUERY?
There is no need to GROUP BY resultset, you need to count visits for a week (with unspecified user). Try this:
SELECT
COUNT(*)
FROM
`table`
WHERE
`timestamp` >= (NOW() - INTERVAL 7 DAY);
If you need to track visits for a specified user, then try this:
SELECT
DATE(`timestamp`) as `date`,
COUNT(*) as `count`
FROM
`table`
WHERE
(`timestamp` >= (NOW() - INTERVAL 7 DAY))
AND
(`user` = 'username')
GROUP BY
`date`;
MySQL DATE() function reference.
Try this:
SELECT DATE(a.timestamp), COUNT(*)
FROM tableA a
WHERE a.user='username' AND DATEDIFF(NOW(), DATE(a.timestamp)) <= 7
GROUP BY DATE(a.timestamp);
i think it's work :)
SELECT Count(*)
from table A
WHERE user = username AND DATEDIFF(NOW(),timestamp)<=7
I have a table with columns: NAME, CHANGE_ID, and CHANGE_DATE, where each row constitutes a single change, the columns indicated who made the change(name), when it was made(timestamp), and an id for the change(integer).
I can retrieve a list of names sorted by those that have made the most changes(in the last month) with the following query:
SELECT
NAME AS name,
COUNT(DISTINCT CHANGE_ID) AS changes
FROM
CHANGE_TABLE
WHERE
DATE(CHANGE_DATE) > DATE(now() - INTERVAL 1 MONTH)
GROUP BY
name
ORDER BY
changes DESC
And I can retrieve a list of changes made per month in the last 10 months with the following query:
SELECT
DATE_FORMAT(CHANGE_DATE, '%Y-%m') AS date,
COUNT(DISTINCT CHANGE_ID) AS change_count
FROM
CHANGE_TABLE
WHERE
CHANGE_DATE > curdate() - INTERVAL 10 MONTH
GROUP BY
date
What I want is a query that will return the combined information of these queries: I want the names of the top change-makers and how many changes they have made each month for the last 10 months. I don't particularly care how the resulting table looks as long as the data is there. I have wracked my brain, but my SQL understanding is not great enough to solve the problem. Any help would be appreciated.
Have you tried grouping on date and name, something like:
SELECT
DATE_FORMAT(CHANGE_DATE, '%Y-%m') AS date,
COUNT(DISTINCT CHANGE_ID) AS change_count,
NAME
FROM
CHANGE_TABLE, (SELECT
NAME AS name,
COUNT(DISTINCT CHANGE_ID) AS changes
FROM CHANGE_TABLE
WHERE DATE(CHANGE_DATE) > DATE(now() - INTERVAL 1 MONTH)
GROUP BY name
ORDER BY changes DESC
) subq
WHERE CHANGE_DATE > curdate() - INTERVAL 10 MONTH AND change_table.name = subq.name
GROUP BY date, name