Single function to bubble sort 2 lists - function

Question

Good evening. I have managed to bubble sort listOne. ListTwo will also need sorting. Is there a way to add listTwo into the bubble sort that I already have so that it gets sorted as well.
Or do I need to write another loop?
listOne = [3, 9, 2, 6, 1]
listTwo = [4, 8, 5, 7, 0]
def bubbleSort (inList):
moreSwaps = True
while (moreSwaps):
moreSwaps = False
for element in range(len(listOne)-1):
if listOne[element]> listOne[element+1]:
moreSwaps = True
temp = listOne[element]
listOne[element]=listOne[element+1]
listOne[element+1]= temp
return (inList)
print ("List One = ", listOne)
print ("List One Sorted = ", bubbleSort (listOne))
print ("List Two = ", listTwo)
print ("List Two Sorted = ", bubbleSort (listTwo))

Answer 1

I think you just need one method and then call the call it on the two list you can try this:
That is one method to do two jobs for you.
listOne = [3, 9, 2, 6, 1]
listTwo = [4, 8, 5, 7, 0]
def bubblesort(array):
for i in range(len(array)):
for j in range(len(array) - 1):
if array[j] > array[j + 1]:
swap = array[j]
array[j] = array[j + 1]
array[j + 1] = swap
print(array)
bubblesort(listOne)
bubblesort(listTwo)
[1, 2, 3, 6, 9]
[0, 4, 5, 7, 8]