I have next data:
mysql> select no,crt_date,tobilling_date,sent_to_client,dop_prov from assistfin limit 20;
+--------+---------------------+---------------------+----------------+------------+
| no | crt_date | tobilling_date | sent_to_client | dop_prov |
+--------+---------------------+---------------------+----------------+------------+
| 50.01 | 2014-02-05 10:28:10 | 2014-02-05 14:42:35 | 2014-04-16 | 2014-09-23 |
| 123.01 | 2014-02-05 19:17:36 | 2014-03-17 18:58:05 | 2014-04-10 | 2014-06-30 |
| 51.01 | 2014-02-06 00:09:32 | 2014-03-20 16:53:46 | 2014-04-10 | 2014-06-30 |
| 124.01 | 2014-02-06 15:29:08 | 2014-03-20 17:04:42 | 2014-04-10 | 2014-06-30 |
| 230.01 | 2014-02-07 22:01:11 | 2014-03-20 16:41:03 | 2014-04-10 | 2014-06-30 |
| 252.01 | 2014-02-08 02:52:33 | 2014-03-20 16:43:03 | 2014-04-10 | 2014-06-30 |
| 123.02 | 2014-02-08 03:00:52 | 2014-03-17 18:58:10 | 2014-04-10 | 2014-06-30 |
| 213.01 | 2014-02-08 04:01:35 | 2014-03-26 19:03:01 | 2014-04-10 | 2014-09-19 |
| 55.01 | 2014-02-08 21:04:45 | 2014-03-07 18:40:46 | NULL | 2014-06-26 |
| 126.01 | 2014-02-08 21:46:58 | 2014-09-02 18:39:36 | 2014-09-09 | 2014-09-26 |
| 284.01 | 2014-02-09 01:52:54 | 2014-06-11 19:11:06 | 2014-07-02 | 2014-07-21 |
| 261.01 | 2014-02-09 02:20:34 | 2014-03-17 20:57:39 | 2014-04-10 | 2014-06-30 |
| 318.01 | 2014-02-09 03:09:28 | 2014-03-17 20:44:25 | 2014-04-10 | 2014-06-30 |
| 225.01 | 2015-02-10 03:21:08 | 2014-03-20 16:57:56 | 2014-04-10 | 2014-06-30 |
| 248.01 | 2014-02-09 03:30:58 | 2014-03-18 18:02:21 | 2014-04-10 | 2014-06-30 |
| 178.01 | 2014-04-05 03:35:25 | 2014-03-21 17:10:12 | 2014-04-10 | 2014-06-30 |
| 184.01 | 2014-04-08 04:01:13 | 2015-03-20 16:38:02 | 2015-04-10 | 2015-06-30 |
| 320.01 | 2014-04-08 05:57:23 | 2015-03-17 20:49:19 | 2015-04-10 | 2015-06-30 |
| 230.02 | 2015-05-08 06:18:15 | 2016-03-20 16:41:08 | 2016-04-10 | 2016-06-06 |
| 325.01 | 2014-05-09 06:23:50 | 2015-03-17 20:42:04 | 2015-04-10 | 2015-06-30 |
+--------+---------------------+---------------------+----------------+------------+
Need to get next data:
+---------+---------+--------+-----------+---------+
| year | Created | Passed | To client | To prov |
+---------+---------+--------+-----------+---------+
| 2016-01 | 1901 | 1879 | 1873 | 1743 |
| 2016-02 | 2192 | 2169 | 2114 | 1912 |
| 2016-03 | 2693 | 2639 | 2539 | 2309 |
| 2016-04 | 2634 | 2574 | 2273 | 1976 |
| 2016-05 | 2593 | 2497 | 1109 | 949 |
| 2016-06 | 471 | 449 | 2 | 78 |
+---------+---------+--------+-----------+---------+
Where year like DATE_FORMAT(curdate(), '%Y-%m'), next column Count(assistfin.crt_date) as Created.
The problem is that crt_date can be like 2015%, but sent_to_client or dop_prov can be like 2016%.
How to make correct query?
Ok sorry this is so long and messy and also I couldnt do it using unions as I so arrogantly posted in the comments, also have to reference MySQL: Is it possible to 'fill' a SELECT with values without a table? that gave me the list of months. You could rewrite it so you left join all the tables to crt_date, but then it wont show a month when nothing was created, hence the generated months table. The original query had a limit 120 in the months, but I have replaced it with a datetime > '2014' for you to change with your earliest date.
Try this and see how quickly it runs for you.
select Months.yearmonth, created, passed, to_client, to_prov
from
(SELECT date_format(datetime,'%Y-%m') as yearmonth
FROM (
select (curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) MONTH) as datetime
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) AS t
where datetime > '2014' -- enter your earliest year here
ORDER BY datetime ASC) Months left join
(select date_format(crt_date,'%Y-%m') as yearmonth, count(no) as "created" from assistfin group by yearmonth) created on Months.yearmonth=created.yearmonth
left join
(select date_format(tobilling_date,'%Y-%m') as yearmonth, count(no) as "passed" from assistfin group by yearmonth) passed on Months.yearmonth=passed.yearmonth
left join
(select date_format(sent_to_client,'%Y-%m') as yearmonth, count(no) as "to_client" from assistfin group by yearmonth) to_client on Months.yearmonth=to_client.yearmonth
left join
(select date_format(dop_prov,'%Y-%m') as yearmonth, count(no) as "to_prov" from assistfin group by yearmonth) to_prov on Months.yearmonth=to_prov.yearmonth
where
group by yearmonth;
Use group by and date_forma in where
select date_format(crt_date, '%Y-%m') as year, count(sent_to_client ), count(dop_pprov)
from assistfin
where date_format(crt_date, '%Y-%m') = date_format(now(), '%Y-%m')
group by year
for the year you can
select date_format(crt_date, '%Y-%m') as year, count(sent_to_client ), count(dop_pprov)
from assistfin
where date_format(crt_date, '%Y') = date_format(now(), '%Y')
group by year
OR for A Range OF yearS you can
select date_format(crt_date, '%Y-%m') as year, count(sent_to_client ), count(dop_pprov)
from assistfin
where date_format(crt_date, '%Y')
BETWEEN(date_format(now(),'%Y')-2) and date_format(now(), '%Y')
group by year
Related
Given we have following table where the series number and the the date should increment
+----+--------+------------+
| id | series | date |
+----+--------+------------+
| 1 | 10 | 2020-08-13 |
| 2 | 9 | 2020-08-02 |
| 3 | 8 | 2020-06-23 |
| 4 | 7 | 2020-06-08 |
| 5 | 6 | 2020-05-20 |
| 6 | 5 | 2020-05-05 |
| 7 | 4 | 2020-05-01 |
+----+--------+------------+
Is there a way to check if there are records that do not follow this pattern ?
For example row 2 has bigger series number but it's date is before row 3
+----+--------+------------+
| id | series | date |
+----+--------+------------+
| 1 | 10 | 2020-08-13 |
| 2 | 9 | 2020-06-02 |
| 3 | 8 | 2020-07-23 |
| 4 | 7 | 2020-06-08 |
| 5 | 6 | 2020-05-20 |
| 6 | 5 | 2020-05-05 |
| 7 | 4 | 2020-05-01 |
+----+--------+------------+
You can use window functions:
select *
from (
select t.*, lead(date) over(order by series) lead_date
from mytable t
) t
where date > lead_date
Alternatively:
select *
from (
select t.*, lead(series) over(order by date) lead_series
from mytable t
) t
where series > lead_series
You can use lag():
select t.*
from (select t.*,
lag(id) over (order by series) as prev_id_series,
lag(id) over (order by date) as prev_id_date
from t
) t
where prev_id_series <> prev_id_date;
You can fetch problematic rows and their corresponding conflicting rows using SELF JOIN like this (assuming your table is called "series"):
SELECT s1.id AS row_id, s1.series AS row_series, s1.date AS row_date,
s2.id AS conflict_id, s2.series AS conflict_series, s2.date AS conflict_date
FROM series AS s1
JOIN series AS s2
ON s1.series > s2.series AND s1.date < s2.date;
I have three tables: tbl_job1 , tbl_job2 and tbl_users.
tbl_job1:
ID| DataComplited | Profit | UserID |
===================================
1 | 2017-01-01 | 100 | 1 |
2 | 2017-02-01 | 200 | 1 |
3 | 2017-03-01 | 150 | 1 |
4 | 2017-01-01 | 400 | 2 |
5 | 2017-01-01 | 120 | 1 |
6 | 2017-02-03 | 30 | 1 |
tbl_job2:
ID| DataComplited | Profit | UserID |
===================================
1 | 2017-02-01 | 50 | 1 |
2 | 2017-03-01 | 20 | 1 |
3 | 2017-02-03 | 20 | 1 |
4 | 2017-02-03 | 50 | 1 |
tbl_users:
ID| fullname |
==============
1 | Robert |
2 | Maria |
I want to see:
Fullname | Year | Month | Profit 1 | Profit 2 | Total |
==========================================================
Maria | 2017 |January | 400.00 | |400.00 |
Robert | 2017 |January | 220.00 | |220.00 |
| |February| 230.00 | 120.00 |350.00 |
| | March | 150.00 | 20.00 |170.00 |
But I get:
Fullname | Year | Month | Profit 1 | Profit 2 | Total |
==========================================================
Maria |2017 |January | 400.00 | |400.00 |
Robert |2017 |January | 220.00 | |220.00 |
| |February| 260.00 | 120.00 |380.00 |
| | March | 150.00 | 20.00 |170.00 |
Please see what Robert's got in February.
Sorry about my English, I'm Russian. But I think you can see everything on those tables. Actually I want to see sum from two jobs for every month.
I'm new on MySql, I tried this code:
SELECT
year(tbl_job1.DataComplited) AS `Year`,
DATE_FORMAT(tbl_job1.DataComplited, '%M') AS `Month`,
DATE_FORMAT(tbl_job1.DataComplited, '%m') AS Month_ord,
tbl_users.fullname,
SUM(tbl_job1.Profit) AS Profit_1
SUM(tbl_job2.Profit) AS Profit_2 ,
(SUM(tbl_job1.profit)) + (SUM(COALESCE(tbl_job2.profit, 0))) AS Total
FROM tbl_job1
LEFT OUTER JOIN tbl_job2 ON tbl_job1.DataComplited = tbl_job2.DataComplited
INNER JOIN tbl_users ON tbl_job1.UserID = tbl_users.ID
GROUP BY tbl_users.fullname,
month(tbl_job1.DataComplited),
DATE_FORMAT(`month`, '%m'),year
ORDER BY tbl_users.fullname,
year(tbl_job1.DataComplited),
DATE_FORMAT(tbl_job1.DataComplited, '%M')
Please help me.
thank you, I but I decided by myself.
SELECT
year(a.DataComplited) AS `Year`,
DATE_FORMAT(a.DataComplited, '%M') AS `Month`,
tbl_users.fullname,
SUM(a.Profit) AS Profit_1,
b.Profit AS Profit_2,
SUM(COALESCE(a.Profit, 0)) + COALESCE(b.Profit, 0) as Total
FROM tbl_job1 as a
INNER JOIN tbl_users ON a.UserID = tbl_users.ID
LEFT OUTER JOIN
(
SELECT
DATE_FORMAT(DataComplited, '%M') AS `Month`,
DataComplited,
SUM(COALESCE(tbl_job2.profit, 0)) AS Profit
FROM tbl_job2
GROUP BY month(DataComplited), DATE_FORMAT(`month`, '%m')
) AS b USING (DataComplited)
GROUP BY tbl_users.fullname, month(a.DataComplited), DATE_FORMAT(`month`, '%m'), year
ORDER BY tbl_users.fullname, year(a.DataComplited), DATE_FORMAT(a.DataComplited, '%m')
i have table
userID | date | time
===================
1 | 2015-02-08 | 06:32
1 | 2015-02-08 | 05:36
1 | 2015-02-08 | 17:43
1 | 2015-02-08 | 18:00
1 | 2015-02-09 | 06:36
1 | 2015-02-09 | 15:43
1 | 2015-02-09 | 19:00
1 | 2015-02-10 | 05:36
1 | 2015-02-10 | 17:43
1 | 2015-02-10 | 18:00
2 | 2015-02-08 | 06:32
2 | 2015-02-08 | 05:36
2 | 2015-02-08 | 17:43
2 | 2015-02-08 | 18:00
2 | 2015-02-09 | 06:36
2 | 2015-02-09 | 15:43
2 | 2015-02-09 | 19:00
2 | 2015-02-10 | 05:36
2 | 2015-02-10 | 17:43
2 | 2015-02-10 | 18:00
But i want the number of records returned to be exactly the same as the number of days of the current month and get min time for in and max time for the out. if the current month has 28 days and only had two records it should bring:
userID | date | in | out
========================
1 | 2015-02-01 | |
1 | 2015-02-02 | |
1 | 2015-02-03 | |
1 | 2015-02-04 | |
1 | 2015-02-05 | |
1 | 2015-02-06 | |
1 | 2015-02-07 | |
1 | 2015-02-08 | 06:32 | 18:00
1 | 2015-02-09 | 06:36 | 19:00
1 | 2015-02-10 | 05:36 | 18:00
1 | 2015-02-11 | |
1 | 2015-02-12 | |
1 | 2015-02-13 | |
1 | 2015-02-14 | |
1 | 2015-02-15 | |
1 | 2015-02-16 | |
1 | 2015-02-17 | |
1 | 2015-02-18 | |
1 | 2015-02-19 | |
1 | 2015-02-20 | |
1 | 2015-02-21 | |
1 | 2015-02-22 | |
1 | 2015-02-23 | |
1 | 2015-02-24 | |
1 | 2015-02-25 | |
1 | 2015-02-26 | |
1 | 2015-02-27 | |
1 | 2015-02-28 | |
How can i modify my query to achieve the above result?
this is my query:
$sql = "SELECT
colUserID,
colDate,
if(min(colJam) < '12:00:00',min(colJam), '') as in,
if(max(colJam) > '12:00:00',max(colJam), '') as out
FROM tb_kehadiran
WHERE colDate > DATE_ADD(MAKEDATE($tahun, 31),
INTERVAL($bulan-2) MONTH)
AND
colDate < DATE_ADD(MAKEDATE($tahun, 1),
INTERVAL($bulan) MONTH)
AND
colUserID = $user_id
GROUP BY colUserID,colDate";
I had to think about this one. But probably the simpliest answer so far:
WITH AllMonthDays as (
SELECT n = 1
UNION ALL
SELECT n + 1 FROM AllMonthDays WHERE n + 1 <= DAY(EOMONTH(GETDATE()))
)
SELECT
DISTINCT datefromparts(YEAR(GETDATE()), MONTH(GETDATE()), n) As dates
, MIN(d.time) as 'In'
, MAX(d.time) as 'Out'
FROM AllMonthDays as A
LEFT OUTER JOIN
table as d on
DAY(d.date) = A.n
GROUP BY n,(d.date);
--- Test and tried in this environment: ---
use Example;
CREATE TABLE demo (
ID int identity(1,1)
,date date
,time time
);
INSERT INTO demo (date, time) VALUES
('2015-12-08', '06:32'),
('2015-12-08', '05:36'),
('2015-12-08', '17:43'),
('2015-12-08', '18:00'),
('2015-12-09', '06:36'),
('2015-12-09', '15:43'),
('2015-12-09', '19:00'),
('2015-12-10', '05:36'),
('2015-12-10', '17:43'),
('2015-12-10', '18:00')
;
WITH AllMonthDays as (
SELECT n = 1
UNION ALL
SELECT n + 1 FROM AllMonthDays WHERE n + 1 <= DAY(EOMONTH(GETDATE()))
)
SELECT
DISTINCT datefromparts(YEAR(GETDATE()), MONTH(GETDATE()), n) As dates
, MIN(d.time) as 'In'
, MAX(d.time) as 'Out'
FROM AllMonthDays as A
LEFT OUTER JOIN
demo as d on
DAY(d.date) = A.n
GROUP BY n,(d.date);
DROP table demo;
The way I've approached this problem in the past is to have a date table that is pre-populated for some years in the future.
You could create such a table, possibly defining columns for year, month and date, with indexes on year and month.
You can then use this table with a JOIN on your data to ensure that all dates are present in your results.
You need three things:
A list of dates.
A left join
Aggregation
So:
select d.dte, min(t.time), max(t.time)
from (select date('2015-02-01') as dte union all
select date('2015-02-02') union all
. .
select date('2015-02-28')
) d left join
t
on d.dte = t.date
group by d.dte
order by d.dte;
Try this
set #is_first_date = 0;
set #temp_start_date = date('2015-02-01');
set #temp_end_date = date('2015-02-28');
select my_dates.date,your_table_name.user_id, MIN(your_table_name.time), MAX(your_table_name.time) from
( select if(#is_first_date , #temp_start_date := DATE_ADD(#temp_start_date, interval 1 day), #temp_start_date) as date,#is_first_date:=#is_first_date+1 as start_date from information_schema.COLUMNS
where #temp_start_date < #temp_end_date limit 0, 31
) my_dates left join your_table_name on
my_dates.date = your_table_name.date
group by my_dates.date
Try This query
SELECT `date`, MIN(`time`) as `IN`, MAX('time') AS `OUT`
FROM `table_name` WHERE month(current_date) = month(`date`)
GROUP BY `date`;
I am trying to show invoices for every single day, so for that purpose I used group by on created date and sum on subtotal. This is how I done it :
SELECT
`main_table`.*,
SUM(subtotal) AS `total_sales`
FROM
`sales_invoice` AS `main_table`
GROUP BY
DATE_FORMAT(created_at, "%m-%y")
Its working, but I also want to get the Invoice # from and Invoice # to for every date. Is it possible to do it with single query ?
EDIT :
Table Structure :
------------------------------------------------
| id | inoice_no | created_at | subtotal
| 1 | 34 | 2015-03-17 05:55:27 | 5
| 2 | 35 | 2015-03-17 12:35:00 | 7
| 3 | 36 | 2015-03-20 01:40:00 | 3
| 4 | 37 | 2015-03-20 07:05:13 | 6
| 5 | 38 | 2015-03-20 10:25:23 | 1
| 6 | 39 | 2015-03-24 12:00:00 | 6
------------------------------------------------
Output
---------------------------------------------------------------
| id | inoice_no | created_at | subtotal | total_sales
| 2 | 35 | 2015-03-17 12:35:00 | 7 | 12
| 5 | 38 | 2015-03-20 10:25:23 | 1 | 10
| 6 | 39 | 2015-03-24 12:00:00 | 6 | 6
-----------------------------------------------------------------
What I Expect
---------------------------------------------------------------
| id | inoice_no | created_at | subtotal | total_sales | in_from | in_to
| 2 | 35 | 2015-03-17 12:35:00 | 7 | 12 | 34 | 35
| 5 | 38 | 2015-03-20 10:25:23 | 1 | 10 | 36 | 38
| 6 | 39 | 2015-03-24 12:00:00 | 6 | 6 | 39 | 39
-----------------------------------------------------------------
If your invoice number is INTEGER then below query will give you the result what you want:
SELECT DATE_FORMAT(A.created_at, "%m-%y") AS InvoiceDate,
MIN(A.invoiveNo) AS FromInvoiceNo,
MAX(A.invoiveNo) AS ToInvoiceNo,
SUM(A.subtotal) AS total_sales
FROM sales_invoice AS A
GROUP BY InvoiceDate;
I guess salesid is primaryid in sales_invoice table.
select * from(
SELECT
`main_table`.*,
SUM(subtotal) AS `total_sales`
FROM
`sales_invoice` AS `main_table`
GROUP BY
DATE_FORMAT(created_at, "%m-%y")
order by main_table.salesid limit 1
union all
SELECT
`main_table`.*,
SUM(subtotal) AS `total_sales`
FROM
`sales_invoice` AS `main_table`
GROUP BY
DATE_FORMAT(created_at, "%m-%y")
order by main_table.salesid desc limit 1
)a
Is there anyway to count a given run of timestamps that are close to each other, but not necessarily in a fixed time frame?
Ie, not grouped by hour or minute, but rather grouped by how close the current row's timestamp is to the next row's timestamp. If the next row is within "x" seconds/minutes then add that row to the group, otherwise start a new grouping.
Given this data:
+----+---------+---------------------+
| id | item_id | event_date |
+----+---------+---------------------+
| 1 | 1 | 2013-05-17 11:59:59 |
| 2 | 1 | 2013-05-17 12:00:00 |
| 3 | 1 | 2013-05-17 12:00:02 |
| 4 | 1 | 2013-05-17 12:00:03 |
| 5 | 3 | 2013-05-17 14:05:00 |
| 6 | 3 | 2013-05-17 14:05:01 |
| 7 | 3 | 2013-05-17 15:30:00 |
| 8 | 3 | 2013-05-17 15:30:01 |
| 9 | 3 | 2013-05-17 15:30:02 |
| 10 | 1 | 2013-05-18 09:12:00 |
| 11 | 1 | 2013-05-18 09:13:30 |
| 12 | 1 | 2013-05-18 09:13:45 |
| 13 | 1 | 2013-05-18 09:14:00 |
| 14 | 2 | 2013-05-20 15:45:00 |
| 15 | 2 | 2013-05-20 15:45:03 |
| 16 | 2 | 2013-05-20 15:45:10 |
| 17 | 2 | 2013-05-23 07:36:00 |
| 18 | 2 | 2013-05-23 07:36:10 |
| 19 | 2 | 2013-05-23 07:36:12 |
| 20 | 2 | 2013-05-23 07:36:15 |
| 21 | 1 | 2013-05-24 11:55:00 |
| 22 | 1 | 2013-05-24 11:55:02 |
+----+---------+---------------------+
Desired Results:
+---------+-------+---------------------+
| item_id | total | last_date_in_group |
+---------+-------+---------------------+
| 1 | 4 | 2013-05-17 12:00:03 |
| 3 | 2 | 2013-05-17 14:05:01 |
| 3 | 3 | 2013-05-17 15:30:02 |
| 1 | 4 | 2013-05-18 09:14:00 |
| 2 | 3 | 2013-05-20 15:45:10 |
| 2 | 4 | 2013-05-23 07:36:15 |
| 1 | 2 | 2013-05-24 11:55:02 |
+---------+-------+---------------------+
This is a little complicated. To start, you need is time of the next event for each record. The following subquery adds in such a time (nexted), if it is within bounds:
select t.*,
(select event_date
from t t2
where t2.item_id = t.item_id and
t2.event_date > t.event_date and
<date comparison here>
order by event_date limit 1
) as nexted
from t
This uses a correlated subquery. The <date comparison here> is for whatever date comparison you want. When there is no record, the value will be NULL.
Now, with this information (nexted) there is a trick to get the grouping. For any record, it is the first event time afterwards where nexted is NULL. This will be the last event in the series. Unfortunately, this requires two levels of nested correlated subqueries (or joins with aggregations). The result looks a bit unwieldy:
select item_id, GROUPING, MIN(event_date) as start_date, MAX(event_date) as end_date,
COUNT(*) as num_dates
from (select t.*,
(select min(t2.event_date)
from (select t1.*,
(select event_date
from t t2
where t2.item_id = t1.item_id and
t2.event_date > t1.event_date and
<date comparison here>
order by event_date limit 1
) as nexted
from t1
) t2
where t2.nexted is null
) as grouping
from t
) s
group by item_id, grouping;
What about approaching it from finding each individual record's local associations, and then grouping on the max event date from each record's discoveries. This is based on a static differential time interval (5 minutes in my example)
SELECT item_id, MAX(total), MAX(last_date_in_group) AS last_date_in_group FROM (
SELECT t1.item_id, COUNT(*) AS total, COALESCE(GREATEST(t1.event_date, MAX(t2.event_date)), t1.event_date) AS last_date_in_group
FROM table_name t1
LEFT JOIN table_name t2 ON t2.event_date BETWEEN t1.event_date AND t1.event_date + INTERVAL 5 MINUTE
GROUP BY t1.id
) t
GROUP BY last_date_in_group