I have two tables (user and I_S) and the I_S table contains a column called score. I need to obtain the highest score and the corresponding user name from the tables.
I used a left join but I keep getting an error saying
Unknown column 'I_S.total_score' in 'field list'
This is the query I used.
SELECT MAX(interview_sessions.total_score)
FROM interview_sessions as sc
LEFT JOIN user as u on sc.user_id = u.user_id
SELECT DISTINCT users.name, I_S.score FROM users
LEFT JOIN I_S ON I_S.user_id = users.user_id WHERE score IN (SELECT MAX(score) FROM I_S)
All users with Max score.
And i think you should write sc.total_score instead interview_sessions.total_score in your query because you use alias
Try using this:
SELECT MAX(sc.total_score)
FROM interview_sessions as sc
LEFT JOIN user as u on sc.user_id = u.user_id
You need an inner query to first determine WHAT is the highest score. Form that, re-join to the interview sessions table on THAT max score. Then join to users to get the names. It is possible multiple people can have a same max score.
select
from
( SELECT MAX(i_s.total_score) as MaxScore
from interview_sessions i_s ) maxAll
JOIN interview_sessions i_s2
on maxAll.MaxScore = i_s2.total_score
JOIN User u
on i_s2.user_id = u.user_id
try this way
select b.*,a.totalscore from user b
inner join( select userid,max(total_score) as totalscore from I_S) a on a.userid=b.userid
Related
I have two tables: users and lessons.
Currently I select all the users using:
SELECT * FROM users WHERE user_type = 1;
Then use PHP to loop through them and count their number of lessons using
SELECT COUNT(*) FROM lessons WHERE student_id=users.user_id;
I would like to combine this into a single query and I'm pretty sure this is possible with a JOIN but it is beyond my basic SQL knowledge.
Do this all in one query. If you want a count per user:
select u.user_id, count(l.student_id)
from users u left join
lessons l
on u.user_id = l.student_id
where u.user_type = 1
group by u.user_id
You can use a join, or a correlated subquery:
select
u.*,
(select count(*) from lessons l where l.student_id = u.user_id) no_lessons
from users u
The upside of the subquery solution is that it does not require aggregation in the outer query. With an index on lessons(student_id), this should be an efficient option.
You can write the following query for this:
SELECT * FROM users u LEFT JOIN lessons l ON u.user_id=l.student_id WHERE u.user_type=1 GROUP BY u.user_id
This will join both the tables (users and lessons) based on the id of both tables and the GROUP BY clause will group all the records of same id as you just want the number of lessons per user.
I am trying to use column alias in the left join but I get sql error with uknown field.
select *, (select SenderId from messages where messageId = 5) as senderId from threads
Left join users where users.id = senderId
This query is quite simple but why is not it working or what is the best way to achieve this ?
I'll really appreciate any contribution.
Thanks
You can't use column aliases in ON or WHERE clauses, because column aliases are assigned to values in the result set, but ON and WHERE are used to create the result set. You need to use another JOIN.
SELECT t.*, m.senderId, u.*
FROM threads AS t
CROSS JOIN messages AS m
LEFT JOIN users AS u ON u.id = m.SenderId
WHERE m.messageId = 5
select t.*, mu.*
from threads as t
Left Join
(select SenderId,users. *
from messages, users
where messages.messageId
= users.id and messsageId = 5) as mu
You need to join threads and mu tables with some id
I am trying to count users that are NOT referenced in another table... Right now, I have something along the lines of this:
SELECT COUNT(DISTINCT u.id) FROM users u INNER JOIN orders o ON o.assigned!=u.id;
However, it's returning an invalid value. Any suggestions?
Thank you!
I would suggest using a LEFT JOIN between the two tables and filter the rows without a matching id in the orders table:
select count(u.id)
from users u
left join orders o
on o.assigned = u.id
where o.assigned is null
See SQL Fiddle with Demo
Use a left join and count the rows with no match:
SELECT COUNT(*)
FROM users u
LEFT JOIN orders o
ON o.assigned = u.id
WHERE o.assigned IS NULL
An alternative is to use a NOT IN check:
SELECT COUNT(*)
FROM users
WHERE id NOT IN (SELECT distinct(assigned) FROM orders)
However, in my experience the left join performs better (assuming appropriate indexes).
Simply use this query, assuming that the id is unique in users table:
select count(*) From Users as u where u.id not in (select assigned from orders)
an inner join explicitly looks for rows that match so that isn't the way to go if you are looking for non matched records
assuming that ORDERS.ASSIGNED is matched with USER.ID an outer join could return values from both and show when there aren't matches like so
select
u.id,
o.*
from users u
full outer join orders o
on o.assigned = u.id;
if you only want to know which USER.ID don't have an ORDERS record you could also INTERSECT or use NOT IN () eg
select u.id from users u where id not in (select o.assigned from orders.o);
SELECT COUNT(1) FROM users u
WHERE NOT EXISTS (SELECT * FROM orders o WHERE o.assigned=u.id);
Are you wanting a straight count (like you mentioned), or do you need values returned? This will give you the count; if you want other values, you should take one of the other approaches listed above.
The following query does what I want. It returns all the resuls in the users table and then if there is a match in the details tble, returns the relevant data
users
id|username
details
id|userid|firstname|lastname
$sql = "SELECT u.*, d.*
FROM `users` u
LEFT JOIN `details` d on
u.id = d.userid
ORDER BY $strorder";
However, when I try to join an additonal table where I want to do the same thing--return all the results of the users table and if there is a match in the third table, return the relevant data (total followers of this user)--it only returns one record.
3rd table
follow
id|followerid|followedid
$sql = "SELECT u.*, d.*, COUNT(f.id)
FROM `users` u
LEFT JOIN `details` d on
u.id = d.userid
LEFT JOIN `follow` f on
u.id = f.followedid
ORDER BY $strorder";
Can anyone see what I am doing wrong? Thanks in advance for any suggestions.
Many thanks.
Try to avoid * to select fields, it will be clearer to group your datas (even if mysql is quite permissive with groupings).
When you have an aggregate function (like COUNT, SUM), the other "non aggregated" requested fields should be in a GROUP BY clause.
Mysql don't force you to GROUP BY all the fields, but... I think it's quite a good habit to be "as ANSI as possible" (usefull when you use another DBMS)
SELECT u.id, u.username, d.firstname, d.lastname, count(*) as numberfollowers
FROM user u
LEFT JOIN details d on u.id = d.userid
LEFT JOIN follow f on u.id = f.followedid
GROUP BY u.id, u.username, d.firstname, d.lastname --or just GROUP BY u.id with Mysql
ORDER BY count(*) desc
COUNT being an aggregate function, when selected with other columns, requires you to group your results by those other columns in the select list.
You should rewrite your query with columns that you want to select from users and details and group by those columns.
I have a left join to a table and want to count columns from it, after grouping by a column of the parent table:
SELECT * , COUNT(list.id) AS listcount, COUNT(uploads.id) AS uploadcount
FROM members
LEFT JOIN lists ON members.id= list.mid
LEFT JOIN uploads ON members.id= uploads.mid
GROUP BY members.id
Assume that a user can have either lists or uploads based on the type of user. Then is above query good enough? If not why?
Or do I have to use this query?
SELECT * , l.listcount, u.uploadcount
FROM members
LEFT JOIN (select count(lists.id) as listscount,mid from lists group by mid) as l
on l.mid = m.id
LEFT JOIN (select count(uploads.id) as uploadscount
,mid from uploads group by mid) as u on u.mid = m.id
GROUP BY members.id
Or correlated subqueries?
SELECT *,
(select count(lists.id) as listscount from lists as l where l.mid = m.id
group by mid) as listcount
(select count(uploads.id) from uploads as u where u.mid = m.id
group by mid) as uploadscount
FROM members
GROUP BY members.id
And which is best solution?
The alias m for members is missing in query 2 and 3. Otherwise they should give the same numbers.
Query 2 (fixed) will perform fastest.
Query 1 is different in that it will give a higher number for uploads, if there are cases of multiple lists per member. After joining to lists, there will be multiple rows for a member too, which will increase the count for uploads. So query 1 is probably wrong.
Also, NULL values are not counted. The manual informs:
COUNT(expr)
Returns a count of the number of non-NULL values of expr in the rows
retrieved by a SELECT statement. The result is a BIGINT value.