I have two tables: the first is travellers_details and the second is
user_info.
traveller_details table has columns id, travel_mode, dep_from, arr_to, dep_date, user_id and status.
user_info table has columns user_id, first_name, last_name, email.
I want all records of both table join with user_id and I wrote following query but not correct:
$sql="SELECT * FROM `traveller_details` FULL OUTER JOIN `user_info` on
traveller_details.user_id=user_info.user_id where traveller_details.dep_from='".$this->from."' and
traveller_details.arr_to='".$this->to."' and traveller_details.dep_date='".$this->sending_date."' and
traveller_details.status='N'";
MySQL doesn't support full outer join, so your query definitely doesn't work. I suspect a left join is sufficient:
SELECT *
FROM `traveller_details` td LEFT OUTER JOIN
`user_info` ui
ON td.user_id = ui.user_id
WHERE td.dep_from = '".$this->from."' AND
td.arr_to = '".$this->to."' AND
td.dep_date = '".$this->sending_date."' AND
td.status = 'N'";
If all travelers have valid user info, then an INNER JOIN is sufficient.
Note that table aliases make the query easier to write and to read.
Related
Iam currently trying to left join a table on a left joined table as follows.
I have the tables:
accounts (id, vorname, nachname)
projektkurse (id, accounts_id, projektwochen_id)
projektkurs_einzel (id, projektkurse_id)
projektkurs_einzel_zeiten (id, date, shift, projektkurs_einzel_id)
Now I want to get every account and the amount times they have an entry inside of projektkurs_einzel_zeiten, which should also be unique. So having the same date and shift multiple times does not count as multiple entries. The result should also be limited by the column projektwochen_id from the table projektkurse. This column should match a certain value for example 8.
Some Accounts don't have any entries in projektkurse, projektkurs_einzel and projektkurs_einzel_zeiten, this is why my first thought was using LEFT JOIN like this:
SELECT accounts.id, accounts.vorname, accounts.nachname, COUNT(DISTINCT projektkurs_einzel_zeiten.date, projektkurs_einzel_zeiten.shift) AS T
FROM accounts
LEFT JOIN projektkurse on accounts.id = projektkurse.creator_id
LEFT JOIN projektkurs_einzel on projektkurse.id = projektkurs_einzel.projektkurs_id
LEFT JOIN projektkurs_einzel_zeiten ON projektkurs_einzel.id = projektkurs_einzel_zeiten.projektkurs_einzel_id
WHERE projektkurse.projektwochen_id = 8
GROUP BY accounts.id
This query does not achieve exactly what I want. It only returns accounts that have atleast one entry in projektkurse even if they have none in projektkurs_einzel and projektkurs_einzel_zeiten. The Count is obviously 0 for them but the accounts that have no entries in projektkurse are being ignored completly.
How can I also show the accounts that don't have entries in any other table with the Count 0 aswell?
I would recommend writing the query like this:
SELECT a.id, a.vorname, a.nachname,
COUNT(DISTINCT pez.date, pez.shift) AS T
FROM accounts a LEFT JOIN
projektkurse
ON a.id = pk.creator_id AND
pk.projektwochen_id = 8 LEFT JOIN
projektkurs_einzel pe
ON pk.id = pe.projektkurs_id LEFT JOIN
projektkurs_einzel_zeiten pez
ON pe.id = pez.projektkurs_einzel_id
GROUP BY a.id, a.vorname, a.nachname;
Notes:
Your problem is fixed by moving the WHERE condition to the ON clause. Your WHERE turns the outer join into an inner join, because NULL values do not match.
Table aliases make the query easier to write and to read.
It is a best practice to include all unaggregated columns in the GROUP BY. However, assuming that id is unique, your formulation is okay (due to something called "functional dependencies").
You should not use eft join table's column ins where condition this work as inner join
You should move the where condition for a left joined table in the corresponding ON clause
SELECT accounts.id, accounts.vorname, accounts.nachname, COUNT(DISTINCT projektkurs_einzel_zeiten.date, projektkurs_einzel_zeiten.shift) AS T
FROM accounts
LEFT JOIN projektkurse on accounts.id = projektkurse.creator_id
AND projektkurse.projektwochen_id = 8
LEFT JOIN projektkurs_einzel on projektkurse.id = projektkurs_einzel.projektkurs_id
LEFT JOIN projektkurs_einzel_zeiten ON projektkurs_einzel.id = projektkurs_einzel_zeiten.projektkurs_einzel_id
GROUP BY accounts.id
I have a products table where I include 3 columns, created_user_id, updated_user_id and in_charge_user_id, all of which are related to my user table, where I store the id and name of the users.
I want to build an efficient query to obtain the names of the corresponding user_id's.
The query that I build so far is the following:
SELECT products.*,
(SELECT name FROM user WHERE user_id = products.created_user_id) as created_user,
(SELECT name FROM user WHERE user_id = products.updated_user_id) as updated_user,
(SELECT name FROM user WHERE user_id = products.in_charge_user_id) as in_charge_user
FROM products
The problem with this query is that if I have 30,000 records, I am executing 3 more queries per row.
What would be a more efficient way of achieving this? I am using mysql.
For each type of user id (created, updated, in_charge) you would JOIN the users table once:
SELECT
products.*,
u1.username AS created_username,
u2.username AS updated_username,,
u3.username AS in_charge_username,
FROM products
JOIN user u1 ON products.created_user_id = u1.user_id
JOIN user u2 ON products.updated_user_id = u2.user_id
LEFT JOIN user u3 ON products.in_charge_user_id = u3.user_id
This is the best practice method to obtain the data.
It is similiar to your query with sub-selects but a more modern approach which I think the database can optimize and utilize better.
Important:
You need foreign key index on all the user_id fields in both tables!
Then the query will be very fast no matter how many rows are in the table. This requires an engine which supports foreign keys, like InnoDB.
LEFT JOIN or INNER JOIN ?
As the other answers suggest a LEFT JOIN, I would not do a left join.
If you have an user id in the products table, there MUST be a linked user_id in the user table, except for the in_charge_user which is only present some times. If not, the data would be semantically corrupt. The foreign keys assure that you always have a linked user_id and a user_id can only be deleted when there is no linked product left.
JOIN is equivalent to INNER JOIN.
You can use LEFT JOIN instead of subselects.
Your query should be like:
SELECT
P.*,
[CU].[name],
[UU].[name],
[CU].[name]
FROM products AS [P]
LEFT JOIN user AS [CU] ON [CU].[user_id] = [P].[created_user_id]
LEFT JOIN user AS [UU] ON [UU].[user_id] = [P].[updated_user_id]
LEFT JOIN user AS [CU] ON [CU].[user_id] = [P].[in_charge_user_id]
First, your query should be fine. You only need an index on user(user_id) or better yet user(user_id, name) for performance. I imagine that the first exists.
Second, you can write this using LEFT JOIN:
SELECT p.*, uc.name as created_user,
uu.name as updated_user, uin.name as in_charge_user
FROM products p LEFT JOIN
user uc
ON uc.user_id = p.created_user_id LEFT JOIN
user uu
ON uu.user_id = p.updated_user_id LEFT JOIN
user uin
ON uin.user_id = p.in_charge_user_id;
With one of the above indexes, the two methods should have very similar performance.
Also note the use of LEFT JOIN. This handles the case where one or more of the user ids is missing.
Try this below query
SELECT products.*, c.name as created_user,u.name as updated_user,i.name as in_charge_user
FROM products left join user c on(products.created_user_id=c.user_id ) left join user u on(products.updated_user_id=u.user_id ) left join user u on(products.in_charge_user_id=i.user_id )
Also as Gordon Linoff mentioned create index on user table will fetch your data faster.
I want to get numOfItem from table BUY using ticketTypeId and then using the BUY.userId to find in the table USER to get the gender. So I can get numOfItem from table BUY and gender from table USER. I don't know how to write this in one query. Any idea?
table structure:
TABLE BUY:
ticketTypeId
numOfItem
userId
TABLE USER:
gender
You need to join your tables on a common field, in this case user id
Select b.ticketTypeId, b.numOfItem, b.userId, u.gender
From buy b inner join user u on b.userid = u.userid
Where b.ticketTypeId = <val>
You want to include where to get only needed ticketTypeId
Generally speaking a join between two tables is something like:
select table1.*,table2.*
from
table1
join table2 on table1.key=table2.key
Add userId in the table user
join the tables with inner join in the select statement
select a.*,b.* from [user] a inner join [buy] b on a.userid = b.userid
You need to use a join. Here is an link
SELECT tb1.ticketId, tb1.numOfItem, tb1.userId, tb2.gender
FROM Table1 as tb1
JOIN Table2 as tb2
ON tb1.userId = tb2.userId
I am trying to count users that are NOT referenced in another table... Right now, I have something along the lines of this:
SELECT COUNT(DISTINCT u.id) FROM users u INNER JOIN orders o ON o.assigned!=u.id;
However, it's returning an invalid value. Any suggestions?
Thank you!
I would suggest using a LEFT JOIN between the two tables and filter the rows without a matching id in the orders table:
select count(u.id)
from users u
left join orders o
on o.assigned = u.id
where o.assigned is null
See SQL Fiddle with Demo
Use a left join and count the rows with no match:
SELECT COUNT(*)
FROM users u
LEFT JOIN orders o
ON o.assigned = u.id
WHERE o.assigned IS NULL
An alternative is to use a NOT IN check:
SELECT COUNT(*)
FROM users
WHERE id NOT IN (SELECT distinct(assigned) FROM orders)
However, in my experience the left join performs better (assuming appropriate indexes).
Simply use this query, assuming that the id is unique in users table:
select count(*) From Users as u where u.id not in (select assigned from orders)
an inner join explicitly looks for rows that match so that isn't the way to go if you are looking for non matched records
assuming that ORDERS.ASSIGNED is matched with USER.ID an outer join could return values from both and show when there aren't matches like so
select
u.id,
o.*
from users u
full outer join orders o
on o.assigned = u.id;
if you only want to know which USER.ID don't have an ORDERS record you could also INTERSECT or use NOT IN () eg
select u.id from users u where id not in (select o.assigned from orders.o);
SELECT COUNT(1) FROM users u
WHERE NOT EXISTS (SELECT * FROM orders o WHERE o.assigned=u.id);
Are you wanting a straight count (like you mentioned), or do you need values returned? This will give you the count; if you want other values, you should take one of the other approaches listed above.
I have two tables and they are as follows:
USERS
ORDERS
I want select all users who have at least 1 order or more in the ORDERS table. I know there is an inline query for this in MySQL, but right now I have to select all users and then make another query seeing if each user has an order - all this using a PHP loop.
What I am doing now is not ethically correct, so I basically just want to select all users who have been referenced in the ORDERS table in ONE MySQL query.
This is a query you should be using
select distinct u.* from users u
inner join orders o on o.user_id = u.id;
Note the distinct and u.*. This query will not select fields from orders and it will not select the same user twice (if one has more than one order).
Demo: http://sqlfiddle.com/#!2/6ebcc/3
You can use mysql join syntax. Assuming both of your tables has userid column, this is the example :
SELECT * FROM USERS a JOIN ORDERS b ON
a.UserId = b.UserId
This is a simple database operation, see here for the explanation join