I want to create a link on my error page to take user back to the previous link.
Suppose the current URL is http://example.com/site/product, and a user try to view
http://example.com/site/product?id=100 and a product with id =100 does not exit, the system should throw 404 error to the error page, now if i want to create a link to take the user back to http://example.com/site/product the previous URl how do I make this work. i can make this work by hardcoding this in my error views file, but i want it dynamically as i have many controller an action using the same view file.
I try this in my site conteoller
controller/site
public function actions()
{
$url = Url::remember();
return [
'error' => [
'class' => 'yii\web\ErrorAction',
],
$this->render('error',['url'=>$url]),
];
}
and try to get the value the in error view file like this
/views/site/error.php
<p>
<?= Html::a('go back', [$url)?>
</p>
but it has no vaule..
please any good idea on how to make this work, am also open to new solution
this is form Yii2 Guide http://www.yiiframework.com/doc-2.0/guide-helper-url.html#remember-urls
There are cases when you need to remember URL and afterwards use it
during processing of the one of sequential requests. It can be
achieved in the following way:
// Remember current URL Url::remember();
// Remember URL specified. See Url::to() for argument format.
Url::remember(['product/view', 'id' => 42]);
// Remember URL specified with a name given
Url::remember(['product/view', 'id' => 42], 'product');
In the next
request we can get URL remembered in the following way:
$url = Url::previous();
// or
$productUrl = Url::previous('product');
Related
I am using yii2-formwizard and I want to insert a checkbox as form input field for the field is_legal in a tabular step. So in fieldConfig array, reading the documentation, I inserted the following code:
'is_legal' => [
'options' => [
'type' => 'checkbox',
'template' => '{input}{beginLabel}{labelTitle}{endLabel}{error}{hint}',
],
'labelOptions' => ['label' => \Yii::t('app', 'Legal Representative')],
],
If I select the checkbox or not the value of the field is always 1 as shown on: .
However, when I add another instance of the model, in the preview step I have NA as value of the legal representative field :
Yes, you are correct about it. It incorrectly shows the value even if the check box is not checked i have updated the section and added a fix.
//check if single checkbox input
if (inputType.attr("type") == 'checkbox') {
return inputType.is(":checked") ? inputType.val() : '';
}
To get the latest code you need to repeat the steps for running composer using,
composer update
and clear the browser cache along with clearing the assets folder in the web directory.
Normally when i am working locally with extensions or if there is an update for an extension which includes javascript updates i add the following settings under the components array in my local config file that takes care of getting the latest files from, and the assets are force copied every time to the web/assets/ directory whenever you refresh the browser or the page reloads.
'components'=>[
'assetManager' => [
'forceCopy' => true,
],
]
Note: Dont leave it open on live site as it would make the page load slower.
I am trying to generate dynamic URL's using yii2 routing, but I didnt find any proper example for what I am looking for
I have a page which has list of users. If I click on any user name it gets redirected to particular user's profile page.
The URL for profile page is like
https://www.example.com/frontend/web/users/profile?id=1&name=xyz
I want to show this URL as https://www.example.com/xyz where xyz is users name.
I have seen examples of pretty URL's but couldnt find any specific example.
How to such dynamic URL's. Please help.
You cannot fully remove static link from link. You can leave profile and remove other. Then your link will be https://www.example.com/profile/xyz
First of all add to config:
'urlManager' => [
'showScriptName' => false,
'enablePrettyUrl' => true,
'rules' => [
'profile/<name>' => 'users/profile',
...
],
Change your action:
public function actionProfile($name) {
$user= User::findOne(['name'=>$name]);
I'm looking for 2 specific variables.
Wishlist - The var_message variable has some styling to it that im trying to edit.
Abandoned Carts - pulls on this extension URL : connector/email/basket/code/secret/quote_id/*****
And im unable to find the location of the file that is accessed by that URL or command.
Any assistance that can be provided would be greatly appreciated.
Also if someone could tell me how i might trace the locations of these things without "Just knowing" that would be grand too.
Kind Regards,
the correct variable name is message (not var_message)
variable message is populated in controller Mage_Wishlist_IndexController
inside method sendAction
here it is:
$emailModel = Mage::getModel('core/email_template');
$sharingCode = $wishlist->getSharingCode();
foreach ($emails as $email) {
$emailModel->sendTransactional(
Mage::getStoreConfig('wishlist/email/email_template'),
Mage::getStoreConfig('wishlist/email/email_identity'),
$email,
null,
array(
'customer' => $customer,
'salable' => $wishlist->isSalable() ? 'yes' : '',
'items' => $wishlistBlock,
'addAllLink' => Mage::getUrl('*/shared/allcart', array('code' => $sharingCode)),
'viewOnSiteLink' => Mage::getUrl('*/shared/index', array('code' => $sharingCode)),
'message' => $message
)
);
}
$wishlist->setShared(1);
$wishlist->save();
and the actual content of the message comes from a form input and gets fetched over here:
$message = nl2br(htmlspecialchars((string) $this->getRequest()->getPost('message')));
there is no actual styling or css assigned to it. In fact most of styles are defined inline in email templates
I'm using URL manager like the following:
'urlManager' => [
'enablePrettyUrl' => true,
'showScriptName' => false,
'rules' => [
'verses/view/<id:\d+>' => 'verses/view',
],
],
It works fine to make access using mysite.com/verses/view/158. The problem is, it is still possible to access the same content using non pretty URL i.e using plain get parameter such as mysite.com/verses/view?id=158. I need any way to restrict the access using the pretty URL.
I have tried the following couples of rules separately, but nothing I have gotten:
'verses/view<?id=>' => 'Error404',
'verses/view?id=<\d+>' => 'Error404',
What is the point of such restriction?
Anyway, one way to do it is something like this:
public function actionView($id)
{
if (strpos(\Yii::$app->request->getUrl(), '?') !== false) {
throw new \yii\web\BadRequestHttpException;
}
// ... the rest of action
}
No changes in UrlManager needed.
Try using UrlManager parameter enableStrictParsing = true.
What happens. UrlManager checks all rulls and they all do not match the request. Thus, by default it checks all default rules. Among default rules it finds the rule with ?id= and preforms routing to that one.
So, in order to avoid that route, you need to list all possible routes in the UrlManger rules and make enableStrictParsing = true. The routes not listed in the config rules parameter will be ignored.
In my app, I'm using session to store some user's data (e.g. name, role). I'm using default User class on common/models from yii2 and I'm getting the data I need by user id.The problem is that the data I stored in session are lost if user resume their previous session without entering password (using remember me option). To solve this, I tried to modify and put the codes for saving user's data inside validateAuthKey() method in User since it's called when yii2 checking for authkey to resume session. As in:
public function validateAuthKey($authKey)
{
$user = Member::findOne(['account_id' => Yii::$app->user->id]);
// Save on session
Yii::$app->session->set('name', $user->first_name . ' ' . $user->last_name);
Yii::$app->session->set('position', $user->position);
// .. other data
return true;
}
As you can see, I use the id of logged user to find Member. But by doing this, I got "Trying to get property of non-object" exception from Yii::$app->user->id. I can only get the id after the login process is completed. After prying around, I found that loginByCookie() from User in vendor\yiisoft\yii2\Web is used to log in. Is there any way to save user's data without tampering codes on vendor? Maybe some kind of event after loginByCookie() is executed.
Create your own User model extends \yii\web\User
namespace frontend\components;
class User extends \yii\web\User
{
protected function afterLogin($identity, $cookieBased, $duration)
{
...Do something here...
parent::afterLogin($identity, $cookieBased, $duration);
}
}
Modify the config (main.php).
'components' => [
'user' => [
'class' => 'frontend\components\User',
'identityClass' => 'common\models\User',
...
]
]
Put the below code in common/config/bootstrap.php
The EVENT_AFTER_LOGIN will be called even if the user is logged in by cookie.
use yii\web\User;
use yii\base\Event;
Event::on(User::className(), User::EVENT_AFTER_LOGIN, function() {
$user = Member::findOne(['account_id' => Yii::$app->user->id]);
// Save on session
Yii::$app->session->set('name', $user->first_name . ' ' . $user->last_name);
Yii::$app->session->set('position', $user->position);
});