moore neighbourhood code to find number of neighbour cells with 1s - function

Question

guys im given a task where i have to find the number of 1s around a cell in a grid.example from the example figure i should get 3 since there are 3 1s around the cell. so i did the code and i got it right but when i used a function to do the same code its giving me errors and i need your help.
def count_neighbours(((1, 0, 0, 1, 0),(0, 1, 0, 0, 0),(0, 0, 1, 0, 1),(1, 0, 0, 0, 0),(0, 0, 1, 0, 0),), 1, 2):
grid=count_neighbours[0]
row=count_neighbours[1]
col=count_neighbours[2]
length=len(grid)
s=0
d=0
for i in range(row-1,row+2):
for j in range(col-1,col+2):
if i>=0 and j>=0:
if i<=length-1 and j<=length-1:
if grid[i][j]==1:
s+=1
if grid[row][col]==1:
d+=1
total = s-d
return total
#error goes like this
def count_neighbours(((1, 0, 0, 1, 0),(0, 1, 0, 0, 0),(0, 0, 1, 0, 1),(1, 0, 0, 0, 0),(0, 0, 1, 0, 0),), 1, 2):
^
SyntaxError: invalid syntax

Answer 1

Please look into the basics of the function definition in python. You should not put the input values in the function definition.
I feel this is what you are looking for.
def count_neighbours(inputgrid):
grid=inputgrid[0]
row=inputgrid[1]
col=inputgrid[2]
length=len(grid)
s=0
d=0
for i in range(row-1,row+2):
for j in range(col-1,col+2):
if i>=0 and j>=0:
if i<=length-1 and j<=length-1:
if grid[i][j]==1:
s+=1
if grid[row][col]==1:
d+=1
total = s-d
print (total)
return total
count_neighbours((((1, 0, 0, 1, 0),(0, 1, 0, 0, 0),(0, 0, 1, 0, 1),(1, 0, 0, 0, 0),(0, 0, 1, 0, 0),), 1, 2))