I was working in a webapp (html / css) and I was asking myself if it's possible with css get what I've asked in the title.
I have this html:
<input type="text" class="custom-bg">
And this css:
.custom-bg {
background: url(icons.png) right -4579px no-repeat;
background-size: 39px 39px; //Size of the icon
}
My input is not always the same size, it may change if you resize the browser.
I want to put that icon (it's a down-arrow) in the right top corner, that's why I have right in the background property.
I want something like position: right 5% instead of a fixed position or value (number).
Is possible? (I mean the css-way, no js) It's an big webapp and there are some classes I can't touch.
Thanks
Baumann,
Absolutely that is possible, and I use this all of the time for input fields, especially with Search inputs. What you'll need to do is:
.custom-bg {
background: url(icons.png) no-repeat 95% 0px;
/*background-size: 39px 39px; //Size of the icon*/
}
As long as your icon is sized correctly in your file, you will not need the background size, and the 95% means that the icon will be placed to the far right of the input field, and the 0px is for your top to bottom spacing. You can adjust that percentage accordingly.
Related
So, I have this:
.cmon
{
background-repeat: repeat-x;
background-image: url("line2.png");
position:absolute;
bottom:0px;
}
What it should do, is put the image (line in this case) on the bottom of the page, from what I understand, and repeat it. It does put it on the bottom, but doesn't repeat, anybody knows what's my problem?
This is how it looks like when the code is on:
http://goolag.pw/temptest.html
Also, in the menu (top right corner) the image doesn't even show up, nor does is it on the bottom.
I will be more than happy if anybody knows whats the problem.
(sorry if links are not allowed here, there are no commercials on the web, it's really just to show what's the problem)
To position background images you should use the background-position property:
.cmon {
background-repeat: repeat-x;
background-image: url("line2.png");
background-position: bottom;
}
The background-position CSS property sets the initial position, relative to the background position layer defined by background-origin for each defined background image.
You'll need to ensure your element has some height and width, however, as background images are not content and do not affect the size of the element.
So first, your problem is not only about CSS but HTML too. You have to attach your attribute .cmon on another tag like <span>, <p>or even <div>.
<div class="cmon"></div>
Then for your CSS :
.cmon {
background-repeat: repeat-x;
background-image: url("line2.png");
position: absolute;
bottom: 0px;
left: 0px; right: 0px; // For having a full width bar
z-index: 999999; // Will be always visible, even when the menu is showed up
height: 4px; // attribute the height of your image
}
Hope this help you.
Ps : Don't forget to use HTML5 !
I've been dealing with a problem for a day now, and I seem not to be able to solve it. I've got four images I want to use as CSS background on the <body> tag. They are supposed to be aligned as the corners of the page.
According to multiple resources I should set the min-height on both the html and body element to 100% if I want the placement my CSS background to be relative to the entire content of my page (which extends beneath the viewport) and not just to the viewport. However, this is not working. The bottom two corner images seem to be stuck to the bottom of the viewport.
I'm using this for CSS:
html {
min-height: 100%;
height: auto;
margin: 0;
padding: 0;
}
body {
margin: 0;
padding: 0;
min-height: 100%;
height: auto;
background: url(../images/bgTopLeft.png) no-repeat left top,
url(../images/bgTopRight.png) no-repeat right top,
url(../images/bgBottomLeft.png) no-repeat left bottom,
url(../images/bgBottomRight.png) no-repeat right bottom;
}
My HTML shouldn't matter much here as I'm using the <body> tag, can't do much wrong there. The doctype is HTML5 in case anyone wants to know.
I've tried changing the setting of background-attachment to fixed, I tried the various settings of background-origin even though it doesn't seem to have to do anything with my current problem. I tried breaking up the multiple shorthand background into all the separate statements that are in there. I can't get it to work.
I'd rather not resort to sticking the bottom two corner images into a footer or a div at the bottom of my page that's just there for styling purposes. What I want, which is a <body> tag with four backgrounds positioned in the four corners of the entire page, should be possible, I just can't figure out what's going on here.
I've made a pen of what I think you're trying to achieve here:
Codepen example
I've used background-size to size the background images.
You may need to tweak this to match the size of your background images:
eg:
background-size: 40px 40px, 40px 40px, 40px 50px, 60px 60px;
depending on what size your images are.
I'm wondering if this is possible, the ability to set the background position of an image to the top left of the html document, not the top left of the element it's the background of.
Psuedo-code
body {
background-image: url(someurlhere);
background-position: top left;
}
element {
background-image: url(sameurlhere);
background-position: top left /*Relative to body not element*/;
}
If I need to provide anything else to this question let me know and I'll amend it, but I'm sure it's pretty straight forward.
Edit: I can't use absolute positioning, I'm loading dynamic content and I want a tiled image to fit the background of several elements to make the illusion of holes in the page.
Edit 2: Here are some pictures to better explain the problem.
Picture 1: Notice the repeated pattern in the header elements. http://i.imgur.com/3lWguRE.png
Picture 2:This variation is what I aim to achieve. http://i.imgur.com/WtOeCQ2.png
The first question would be why you are not just setting the background image on the body element.
But if that's not appropriate, you have the option to set a background image on an element to fixed, in which case it will be fixed to the top left of the browser window and won't scroll.
element {background: url(image.fig) repeat fixed;}
However, the background will only show on the element it's attached to, even though it starts at the top left corner of the screen. (This is handy for parallax effects.)
EDIT: As a side note, if you are using the longhand background properties, fixed is set with
background-attachment: fixed;
All you have to do is wrap your element in a div absolute, and position it as you wish.
Can you provide some more information on the context of the element? Does it have any positioning set? Where is it in the document? It's a little unclear to me what exactly you are trying to accomplish.
Would putting the background on the body work?
This would set the background at the top left, but I doubt this is actually what you are trying to accomplish:
<div class="test">
</div>
.test:before {
content: "";
position: absolute;
top: 0;
left: 0;
background: url(http://i1112.photobucket.com/albums/k497/animalsbeingdicks/abd-318.gif);
width: 352px;
height: 263px;
}
http://jsbin.com/imurah/1/
I use a table to show several images. I need to show the left half an image in the first td-element and the right half of it in the second td-element. This is because some of the images have double width as others. I thought i use a div and set this image as background image for the first two td-elements using a child-div. Now i am fiddling around to make it work using css.
Any suggestions?
Update: Working example: http://jsfiddle.net/BkAcu/2/
Use background-position: <horizontal> <vertical> where <horizontal> and <vertical> are background offsets, in conjunction with background-repeat: no-repeat.
Set the background-position to a negative value, to move the bg to the left.
See also: https://developer.mozilla.org/en/CSS/background-position
Example (assume your TDs to have a width of 100px, and the image to be 200px);
#td1, #td2 {
background: url("200.png") no-repeat;
}
#td2 {
background-position: -100px;
}
I want to display images in a 144px x 144px div element.
Images are always larger than 144px and so I want to zoom scale them. By that I mean that the smallest side will touch the edge of the div, cutting a bit from the other side - the opposite of letterbox.
How can I do this and have it work on older browsers like IE as well?
EDIT:
Changed the image, the first was wrong, sorry.
Resize the image so that inside the div there is no space without image
My first answer addressed intentionally blocking out the part of the image while intentionally keeping the space occupied. If you just want part of the image visible with no space or anything else taken up, the best option will be to use CSS Sprite techniques.
Here's an example:
HTML (copy and paste into your own file for a full test):
<html>
<head>
<style type="text/css">
.clippedImg {
background-image: url("http://www.grinderschool.com/images/top_main.jpg");
background-position: -75px -55px;
height: 100px;
width: 235px;
}
</style>
</head>
<body>
<div class='clippedImg'> </div>
</body>
</html>
CSS (this is really the key):
.clippedImg {
background-image: url("http://www.grinderschool.com/images/top_main.jpg");
background-position: -75px -55px;
}
You can adjust the position numbers to get exactly the portion and size of the image that you want.
Note also that if you want a black box around this, it's even easier than the other post I made. Just put a parent div around this one:
<div class='blackBox'>
<div class='clippedImg'> </div>
<div>
With a padding and width set to create the black-box effect you want:
.blackBox {
background-color: black;
padding: 0 20px;
width: 235px;
}
Set only the width of the image to 144px in CSS or in the attribute. The height will scale automatically. I'm fairly certain this works as low as IE 6. I'm not certain about anything older than that.
If I read your question right, you aren't trying to resize the image, but rather to actually cut off part of the image. If you just want to resize the image, then follow the other answers about that.
The simplest way I can think of to actually cut off the image this is to add <div class='blockOut'> </div> and then use CSS to place & size the div, make it's color match the background color of your page, and put it in front of the image. Example CSS:
.blockOut {
position: relative;
top: -100px;
left: 100px;
background-color: white;
z-index: 2; //this is the important part for putting this div in front of the other one
}
Edit: Note that since you added an example showing that you want all sides blacked out, this would require separate divs for blacking out the top, each side, and the bottom. Also, if you want part of the image to show through (as it does in your example) you can use CSS transparency options.
div{height:114px;width:114px;overflow:hidden;}
div img{position:relative;left:-100px /*or whatever you want. can change it with js*/;top:-100px;}
that is masking to only show a part of the img, as you say in the title. but in the description says you want to resize the img. decide yuorself
to do what you want with css, you should use max-height:144px;max-width:144px. but ie6 doesn't implements those simple properties, so you'll have to use js