I have a table (in mysql) like this:
TABLE1
Id Name Age
---------------
1 John 22
2 Mary 17
3 Peter 21
4 Agnes 34
5 Steve 14
6 Bart 26
7 Bob 32
8 Vince 18
...
What I am looking for is a SELECT statement, where I can get 4 records in a row. I mean, the result of the select statement would be:
Id1 Name1 Age1 Id2 Name2 Age2 Id3 Name3 Age3 Id4 Name4 Age4
-----------------------------------------------------------
1 John 22 2 Mary 17 3 Peter 21 4 Agnes 34
5 Steve 14 6 Bart 26 7 Bob 32 8 Vince 18
...
I guess it would be like a pivot...
Is this possible? If it is, then how can I achieve it?
I need to populate a report by showing 4 records on a row, so I would like to be able to do it from a datasource that returns this exact structure. So on first band/row there will be
rec1,rec2,rec3,rec4
then on second row:
rec5,rec6,rec7,rec8
and so on.
My first idea was to merge 4 queries that return every 5th record starting with 1,2,3,4 but I'm not exactly sure...
Can you help?
You can do this with arithmetic on the id and group by:
select (case when id % 4 = 1 then id end) as id1,
(case when id % 4 = 1 then name end) as name1,
(case when id % 4 = 1 then age end) as age1,
(case when id % 4 = 2 then id end) as id2,
(case when id % 4 = 2 then name end) as name2,
(case when id % 4 = 2 then age end) as age2,
(case when id % 4 = 3 then id end) as id3,
(case when id % 4 = 3 then name end) as name3,
(case when id % 4 = 3 then age end) as age3,
(case when id % 4 = 0 then id end) as id4,
(case when id % 4 = 0 then name end) as name4,
(case when id % 4 = 0 then age end) as age4
from t
group by floor((id - 1) / 4);
If the id doesn't increment without gaps, then you can generate one using:
from (select t.*, (#rn := #rn + 1) as seqnum
from t cross join
(select #rn := 0) params
order by id
) t
Related
I have 1 table called itemmovement : It has Item Id , Quantity In , Quantity Out , Invoice Id, Date. I need to make in one query to show how many pieces are sold and beside the sold column there will be the current on hand quantity .
itemmovement
Id itemid qtyin qtyout invid purchasereturnid date
1 1 10 2019-01-04
2 2 8 2019-01-06
3 2 2 1 2019-01-08
4 1 3 2 2019-01-12
5 2 1 2019-02-04
6 3 4 2019-03-04
7 1 1 3 2019-04-04
8 1 1 1 2019-04-14
9 3 1 2 2019-04-24
I need the query to show this result
Id itemid Sold Quantity OnHandQty
1 1 4 5
2 2 2 7
3 3 0 3
I'm Trying to use this query but not working
SELECT *
FROM
(SELECT itmv.itemid,
sum(itmv.qtyout)-sum(itmv.qtyin)
FROM itemmovement itmv
WHERE (itmv.systemdate BETWEEN '2019-01-01' AND '2019-06-01')
AND invid>0
GROUP BY itmv.itemid) AS result1,
(SELECT sum(itmv2.qtyin)-sum(itmv2.qtyout)
FROM itemmovement itmv2
WHERE itmv.itemid=itmv2.itemid
GROUP BY itmv2.itemid) AS result2
ORDER BY sum(itmv.qtyin)-sum(itmv.qtyout)
I'm getting :
Unknown column 'itmv.itemid' in 'where clause it for this syntax :
where itmv.itemid = itmv2.itemid
Here's your query.
select itemid
, sum(case when COALESCE(invid,0) > 0 then qtyout else 0 end) as Sold_Qantity
, sum(qtyin)-sum(qtyout) as OnHandQty
from itemmovement
group by itemid
I have a table in the following format
ID SOURCE_ID
1 1
2 1
3 1
4 2
5 3
6 3
7 4
8 4
9 4
10 4
11 4
12 1
13 1
14 3
15 3
16 3
17 3
18 2
19 2
I want to be able to select 5 records MAX for each unique source_id.
So I should end up having returned 5 rows for source_id = 1, 5 rows for souce_id = 2, and so on.
Any ideas? Thank you in advance.
E.g.:
SELECT id
, source_id
FROM
( SELECT id
, source_id
, CASE WHEN #prev = source_id THEN #i:=#i+1 ELSE #i:=1 END i
, #prev := source_id prev
FROM my_table
, (SELECT #prev:=null,#i:=0) vars
ORDER
BY source_id
, id
) x
WHERE i <=5
ORDER
BY id;
I am using Mysql and I want count distinct value and then make the distinct values as the column name.
I have a table Students like this
ID Names Age
1 Tim 12
2 James 14
3 White 13
4 John 13
5 Annie 11
6 Judy 13
I want to find how many people in each age. My expected result is:
11 12 13 14
1 1 3 1
I tried the query: "Select count(age), age from Students group by age;"
It gives out:
count(age) age
1 11
1 12
3 13
1 14
How can I take a "transpose" to the table?
If you are using MySQL you will need to know age in advance:
SELECT
SUM(CASE WHEN (age='11') THEN 1 ELSE 0 END) AS 11,
SUM(CASE WHEN (age='12') THEN 1 ELSE 0 END) AS 12,
SUM(CASE WHEN (age='13') THEN 1 ELSE 0 END) AS 13,
SUM(CASE WHEN (age='14') THEN 1 ELSE 0 END) AS 14
FROM
Students
So here's what my data table looks like:
TeamNum Round Points1 Points2
1 1 5 21
2 1 10 20
3 1 9 29
1 2 6 22
2 2 11 21
3 2 10 30
1 3 80 50
I also have a second table with this:
TeamNum TeamName
1 goteam1
2 goteam2
3 goteam4-1
I want SQL to take it and turn it into this:
Team Round1 Round2 Round3 TeamName
1 (points1+points2 of round1) (same but for r2) (same but for r3) goteam1
2 (points1+points2 of round1) (same but for r2) (same but for r3) goteam2
3 (points1+points2 of round1) (same but for r2) (same but for r3) goteam4-1
And a sample output from the tables above would be:
Team Round1 Round2 Round3 TeamName
1 26 28 130 goteam1
2 30 32 0 goteam2
3 38 40 0 goteam4-1
The actual data has a bunch of "points1" and "points2" columns, but there are only 3 rounds.
I am very new to SQL and this is all I have right now:
select
`data`.`round`,
`data`.`teamNumber`,
sum(`Points1`) + sum(`Points2`) as score
from `data` join `teams` ON `teams`.`teamNumber` = `data`.`teamNumber`
group by `data`.`teamNumber` , `round`
order by `data`.`teamNumber`, `data`.`round`
But it doesn't return anything at all. If I remove the join statement, it shows everything like I want, but doesn't consolidate Round1, 2, and 3 as columns, they are each separate rows. Can you guys help me out? Thanks!
Use conditional aggregation
SELECT t.teamnumber, t.teamname,
SUM(CASE WHEN d.round = 1 THEN d.points1 + d.points2 ELSE 0 END) round1,
SUM(CASE WHEN d.round = 2 THEN d.points1 + d.points2 ELSE 0 END) round2,
SUM(CASE WHEN d.round = 3 THEN d.points1 + d.points2 ELSE 0 END) round3
FROM data d JOIN teams t
ON d.teamnumber = t.teamnumber
GROUP BY t.teamnumber, t.teamname
Output:
| TEAMNUMBER | TEAMNAME | ROUND1 | ROUND2 | ROUND3 |
|------------|-----------|--------|--------|--------|
| 1 | goteam1 | 26 | 28 | 130 |
| 2 | goteam2 | 30 | 32 | 0 |
| 3 | goteam4-1 | 38 | 40 | 0 |
Here is SQLFiddle demo
No need to aggregate:
SELECT
t.teamnumber,
COALESCE(r1.points1 + r1.points2, 0) AS round1,
COALESCE(r2.points1 + r2.points2, 0) AS round2,
COALESCE(r3.points1 + r3.points2, 0) AS round3,
t.teamname
FROM teams t
LEFT JOIN data r1 ON r1.teamnumber = t.teamnumber AND r1.round = 1
LEFT JOIN data r2 ON r2.teamnumber = t.teamnumber AND r2.round = 2
LEFT JOIN data r3 ON r3.teamnumber = t.teamnumber AND r3.round = 3
Something like this:
select teams.teamNumber,
SUM(CASE WHEN Round=1 THEN `Points1`+`Points2` ELSE 0 END)as Round1,
SUM(CASE WHEN Round=2 THEN `Points1`+`Points2` ELSE 0 END)as Round2,
SUM(CASE WHEN Round=3 THEN `Points1`+`Points2` ELSE 0 END)as Round3,
teams.teamName
from `data` join `teams` ON `teams`.`teamNumber` = `data`.`teamNumber`
group by teamnumber , teamname
order by `data`.`teamNumber`, `data`.`round`
I'm a bit confuse how to name my question title.
Let say my MySQL database table like this. table_group
UserID UserGroup UserStatus
------------------------------
1 1 1
2 1 1
3 1 2
4 2 3
5 3 2
6 3 1
7 4 3
9 4 4
10 4 1
I want to group it by UserGroup and count the UserStatus.
Let me know what is the correct statement to get the result like this
UserGroup Status_1 Status_2 Status_3 Status_4
-------------------------------------------------
1 2 2 0 0
2 0 0 1 0
3 1 1 0 0
4 1 0 1 1
SELECT UserGroup, count(UserStatus = 1) as Status_1, count(UserStatus = 2) as Status_2,
count(UserStatus = 3) as Status_3, count(UserStatus = 4) as Status_4
FROM table_group GROUP BY UserGroup
You could use case to count rows that match a condition:
select UserGroup
, count(case when UserStatus = 1 then 1 end) as Status_1
, count(case when UserStatus = 2 then 1 end) as Status_2
, count(case when UserStatus = 3 then 1 end) as Status_3
, count(case when UserStatus = 4 then 1 end) as Status_4
from table_group
group by
UserGroup