Babel error: Class constructor Foo cannot be invoked without 'new' - ecmascript-6

I am using babel to transpile.
I have class BaseComponent which is extended by class Logger.
When I run new Logger() in the browser, I am getting this error
Class constructor BaseComponent cannot be invoked without 'new'
the code that throws this is:
var Logger = function (_BaseComponent) {
_inherits(Logger, _BaseComponent);
function Logger() {
_classCallCheck(this, Logger);
return _possibleConstructorReturn(this, Object.getPrototypeOf(Logger).call(this, "n")); //throws here
}

Due to the way ES6 classes work, you cannot extend a native class with a transpiled class. If your platform supports native classes, my recommendation would be, instead of using the preset es2015, use es2015-node5, assuming you're on Node 5. That will cause Babel to skip compiling of classes so that your code uses native classes, and native classes can extend other native classes.

Another solution is to include { exclude: ["transform-es2015-classes"] } in .babelrc
presets: [
["env", { exclude: ["transform-es2015-classes"] }]
]
UPDATE: In the latest version of "env" preset plugin names have changed (e.g. it's now "transform-classes"). Use the "debug" option to inspect which plugins are included.

Related

Typescript return HTML Template Element from Constructor typing not working

It is 'illegal' to use new when creating an instance of Template, where Template extends an HTMLTemplateElement.
To overcome this limitation, I get and return an HTMLTemplateElement using document.getElementById(id) from the Template constructor as below:
export class Template {
private htmlTemplateElement: HTMLTemplateElement;
constructor(id: string) {
this.htmlTemplateElement = document.getElementById(id) as HTMLTemplateElement;
return Object.assign(this.htmlTemplateElement, this)
}
public test = () => this.htmlTemplateElement.innerHTML
}
Providing an HTML Template Element exist in the DOM,
I can create a new instance of Template and use the extension method test() as illustrated below:
const template = new Template(id)
console.log(template.test())
console.log(template.innerHTML)
Both console.log() works just fine and prints the correct text to the console.
HOWEVER, the typescript compiler complains about template.innerHTML.
The error I get, saying innerHTML does not exist on type Template
Question: How can I add type information so I do not get a compiler error?
I have tried to use export class Template extends HTMLTemplateElement.
That does not work since it is illegal to create an instance using new.
I love typescript, but sometimes the type checking gets in my way.
Help me out here, please.
Although not ideal, I was able to keep the typescript compiler happy by implementing the following interface:
export interface ITemplate {
[key:string]: any;
test(): string;
}
and then using the interface:
export Template implements ITemplate {
...
}
Note:
Why did I not use customElements.define(<tag-name>,Template)?
I do not intend to create a new custom instance of HTMLTemplateElement, I just want to return an existing HTMLTemplateElement with additional utility extension methods.
Also, It might very well be possible that my approach is completely wrong.
However, that is a different topic than the question asked here.

Angular component with dynamic template created using ɵcompileComponent (Angular 9) is not working in production mode

I am creating a dynamic component in Angular 9. I have a <ul> tag in the html template, the sub-elements of which are dynamically loaded from the server (The server will return values like <li>One</li><li>Two</li><li (click)="onLinkClicked(3)">Three</li> using handlebar templates).
private createComponentFromRaw(template: string, containerRef: ElementRef) {
class DynamicComponent {
onLinkClicked(resource: any) {
console.log(resource);
}
}
ɵcompileComponent(DynamicComponent, { template, changeDetection: ChangeDetectionStrategy.OnPush });
ɵrenderComponent(DynamicComponent, {
host: containerRef.nativeElement,
injector: this.injector,
hostFeatures: [ɵLifecycleHooksFeature],
});
}
On calling this.createComponentFromRaw('<li>One</li>', this.ref.element); the component is rendered as expected when run as ng serve but throws the following error at runtime in production mode (ng build --prod):
ERROR Error: Angular JIT compilation failed: '#angular/compiler' not loaded!
- JIT compilation is discouraged for production use-cases! Consider AOT mode instead.
- Did you bootstrap using '#angular/platform-browser-dynamic' or '#angular/platform-server'?
- Alternatively provide the compiler with 'import "#angular/compiler";' before bootstrapping.
Looks like the only option currently available is to set buildOptimizer: false in the angular.json
This happens because the buildOptimizer incorrectly considers #angular/compiler as having no side-effects and removes it as part of the tree shaking

Gradle - using a function from within Ant

I have a Gradle script with few invocations of XJC to generate JAXB classes from XSD.
I thought I could parametrize these invocations and reuse the common code.
So I created a function:
ext.generateJaxbClasses = { HashMap params ->
project.ant {
...
And then I wanted to use it:
task genJaxb {
ext.generic = [
schema: "..."
]
doLast() {
ext.generateJaxbClasses(jaxbSetA)
ext.generateJaxbClasses(jaxbSetB)
}
But I get this error:
> No signature of method: org.gradle.internal.extensibility.DefaultExtraPropertiesExtension.generateJaxbClasses() is applicable for argument types: (LinkedHashMap) values: [[...]]
How can I use the function within a task definition?
Use project.ext.generateJaxbClasses(jaxbSetA)
Using ext inside the task resolves to searching for the property inside the task's extension container.
See ExtensionAware.
I would suggest using an actual free function inside the project rather than using extensions as it can lead to this kind of frustration.
def generateJaxbClasses(HashMap params) {
project.ant {...}
}

Custom error classes not extending correctly [duplicate]

I'm trying to throw a custom error with my "CustomError" class name printed in the console instead of "Error", with no success:
class CustomError extends Error {
constructor(message: string) {
super(`Lorem "${message}" ipsum dolor.`);
this.name = 'CustomError';
}
}
throw new CustomError('foo');
The output is Uncaught Error: Lorem "foo" ipsum dolor.
What I expect: Uncaught CustomError: Lorem "foo" ipsum dolor.
I wonder if that can be done using TS only (without messing with JS prototypes)?
Are you using typescript version 2.1, and transpiling to ES5? Check this section of the breaking changes page for possible issues and workaround: https://github.com/Microsoft/TypeScript-wiki/blob/master/Breaking-Changes.md#extending-built-ins-like-error-array-and-map-may-no-longer-work
The relevant bit:
As a recommendation, you can manually adjust the prototype immediately after any super(...) calls.
class FooError extends Error {
constructor(m: string) {
super(m);
// Set the prototype explicitly.
Object.setPrototypeOf(this, FooError.prototype);
}
sayHello() {
return "hello " + this.message;
}
}
However, any subclass of FooError will have to manually set the prototype as well. For runtimes that don't support Object.setPrototypeOf, you may instead be able to use __proto__.
Unfortunately, these workarounds will not work on Internet Explorer 10 and prior. One can manually copy methods from the prototype onto the instance itself (i.e. FooError.prototype onto this), but the prototype chain itself cannot be fixed.
The problem is that Javascript's built-in class Error breaks the prototype chain by switching the object to be constructed (i.e. this) to a new, different object, when you call super and that new object doesn't have the expected prototype chain, i.e. it's an instance of Error not of CustomError.
This problem can be elegantly solved using 'new.target', which is supported since Typescript 2.2, see here: https://www.typescriptlang.org/docs/handbook/release-notes/typescript-2-2.html
class CustomError extends Error {
constructor(message?: string) {
// 'Error' breaks prototype chain here
super(message);
// restore prototype chain
const actualProto = new.target.prototype;
if (Object.setPrototypeOf) { Object.setPrototypeOf(this, actualProto); }
else { this.__proto__ = actualProto; }
}
}
Using new.target has the advantage that you don't have to hardcode the prototype, like some other answers here proposed. That again has the advantage that classes inheriting from CustomError will automatically also get the correct prototype chain.
If you were to hardcode the prototype (e.g. Object.setPrototype(this, CustomError.prototype)), CustomError itself would have a working prototype chain, but any classes inheriting from CustomError would be broken, e.g. instances of a class VeryCustomError < CustomError would not be instanceof VeryCustomError as expected, but only instanceof CustomError.
See also: https://github.com/Microsoft/TypeScript/issues/13965#issuecomment-278570200
As of TypeScript 2.2 it can be done via new.target.prototype.
https://www.typescriptlang.org/docs/handbook/release-notes/typescript-2-2.html#example
class CustomError extends Error {
constructor(message?: string) {
super(message); // 'Error' breaks prototype chain here
this.name = 'CustomError';
Object.setPrototypeOf(this, new.target.prototype); // restore prototype chain
}
}
It works correctly in ES2015 (https://jsfiddle.net/x40n2gyr/). Most likely, the problem is that the TypeScript compiler is transpiling to ES5, and Error cannot be correctly subclassed using only ES5 features; it can only be correctly subclassed using ES2015 and above features (class or, more obscurely, Reflect.construct). This is because when you call Error as a function (rather than via new or, in ES2015, super or Reflect.construct), it ignores this and creates a new Error.
You'll probably have to live with the imperfect output until you can target ES2015 or higher...
I literally never post on SO, but my team is working on a TypeScript project, and we needed to create many custom error classes, while also targeting es5. It would have been incredibly tedious to do the suggested fix in every single error class. But we found that we were able to have a downstream effect on all subsequent error classes by creating a main custom error class, and having the rest of our errors extend that class. Inside of that main error class we did the following to have that downstream effect of updating the prototype:
class MainErrorClass extends Error {
constructor() {
super()
Object.setPrototypeOf(this, new.target.prototype)
}
}
class SomeNewError extends MainErrorClass {}
...
Using new.target.prototype was the key to getting all of the inheriting error classes to be updated without needing to update the constructor of each one.
Just hoping this saves someone else a headache in the future!
I ran into the same problem in my typescript project a few days ago. To make it work, I use the implementation from MDN using only vanilla js. So your error would look something like the following:
function CustomError(message) {
this.name = 'CustomError';
this.message = message || 'Default Message';
this.stack = (new Error()).stack;
}
CustomError.prototype = Object.create(Error.prototype);
CustomError.prototype.constructor = CustomError;
throw new CustomError('foo');
It doesn't seem to work in SO code snippet, but it does in the chrome console and in my typescript project:
I was having this problem in a nodejs server. what worked for me was to transpile down to es2017 in which these issues seems to be fixed.
Edit tsconfig to
"target": "es2017"
Try this...
class CustomError extends Error {
constructor(message: string) {
super(`Lorem "${message}" ipsum dolor.`)
}
get name() { return this.constructor.name }
}
throw new CustomError('foo')

Typescript: how to get function name as string without TS2339 error

I found the following example in the Function.name documentation
const o = {
foo(){}
};
o.foo.name; // "foo";
The problem in typescript (typed here):
const o: { foo: () => void } = {
foo: () => {
}
};
o.foo.name;
comes when I want to retrieve
o.foo.name, where I will get an error
TS2339 (property "name" does not exist)
How can I deal with it, keeping the object typing?
I want to avoid having to cast the property "foo" like (<any>o.foo).name
PS: The use case is to keep the typing for further refactoring. For instance the following is safe to be refactored:
spyOn(o, (<any>o.foo).name)
While this one is not
spyOn(o, "foo")
PS 2: It seems retrieving function name could be problematic on ts: Get name of function in typescript
The problem is that this code only works for newer versions of Javascript. If you change the target on the typescript compiler settings to es2015 the problem goes away. If you target es5 the definitions for that version do not include the name property because it might not work on older Javascript runtimes.
If you are ok with targeting es2015, that is ok, if not you should come up with a different solution that works for es5.
If you are targeting an environment that supports this property but you don't yet trust the es2015 implementation for all features, you could just add the the Function interface the missing property. At the top level in one of your files you can redefine the Function interface, and this will be merged into the default definition, adding the extra property:
interface Function {
/**
* Returns the name of the function. Function names are read-only and can not be changed.
*/
readonly name: string;
}
Post ES2015, this:
const o: { foo: () => void } = {
foo: () => { }
};
console.log(o.foo.name);
should work just fine.
Check it in the Typescript Playground, and observe the produced JavaScript. You will see the common sections with the foo example you mentioned.
Here is the console, nice and clean:
Pre-ES2015, this wouldn't work and I think you would have to cast it, if targeting post-ES2015 is not an option.