Lets say this is the table I am talking about
id pId fId
1 1 1
2 2 1
3 2 2
4 3 2
I need to get a list of pId's who have a match to ALL of the given indices in a list of fId's.
What I mean is ->
Consider the list of fId's to be:
(1,2)
Then the result should be
2
Because only pId 2 has a match to all given entries in the list of fId's (which would be 1 and 2).
I couldn't find any way to do it so far - any help is highly appreciated :-)
Aggregate on pid column and use a having clause.
select pid
from tablename
group by pid
having sum(case when fid in (1,2) then 1 else 0 end) >= 2
Related
Initially we have such a table
contact_id
group_id
1
1
2
1
2
3
3
1
3
3
3
2
1
2
After that I make a query to search for groups containing the values of contacts 1 and 3
SELECT `group_id` ,COUNT(DISTINCT(`contact_id`)) AS `variants`
FROM `TaskTeam_member`
WHERE `contact_id`='1' OR `contact_id`='3'
GROUP BY `group_id`
HAVING `variants`='2'
it turns out that such a table (correct)
contact_id
variants
1
2
2
2
And now I need to add in addition to searching for values 1 and 3 in the group to check the total number of elements in it (I need 2), that is, if presumably there are elements 1 and 3 in group 1, but the total number of elements is 3 and not 2 as in the example above, then this group should not be output
the result should be like this
contact_id
variants
2
2
help me complete my request!
If you want to check for other contact_ids you need to include all records, but only count the ones you want:
SELECT `group_id`
FROM `TaskTeam_member`
GROUP BY `group_id`
HAVING COUNT(DISTINCT contact_id)=2 AND COUNT(DISTINCT CASE contact_id WHEN 1 THEN 1 WHEN 3 THEN 3 END)=2
I have orders table like this:
OID CID ODATE
1 1 01/01/21
2 2 01/02/21
3 2 20/01/21
4. 3. 20/01/21
5. 4. 20/01/21
I want to see all the orders of cid 2 first then all the others
thanks ...
You may order using a CASE expression:
SELECT *
FROM yourTable
ORDER BY CASE CID WHEN 2 THEN 1 ELSE 2 END;
You may also add more sorting levels after the above CASE expression.
In MySQL, I am trying to sum values in a column given certain conditions. I have an example of some data below
Team Season Mth Stat
A 1 1 4
A 1 1 4
A 1 2 7
A 1 2 9
B 1 1 6
B 1 1 6
B 1 2 6
B 1 2 9
C 1 1 1
C 1 1 3
C 1 2 3
C 1 2 6
But I need the output to show up as
Team Season Mth Stat
A 1 1 8
A 1 2 16
B 1 1 12
B 1 2 15
C 1 1 4
C 1 2 9
So the Stat column is now the sum of the cells such that Match, Season, and Team are all the same. I have the code below. I see a lot of answers that use 'case' but that seems to be given logical operators that are not equal to each other. When I do it below, now it doesn't recognise the table where the columns are coming from. I do have a inner joins but the data itself is from one table. I get another error as well on the sum function because it requires one argument.
select
Team
,Season
,Match
--this is where I get lost-----------
sum(
select
Stat
From
table
Where
Mth=Mth
AND Season=Season
AND Team=Team
)
--end of getting lost----------------
FROM
table
Where
Season IN (1,2)
GROUP BY
Team
,Season
,Mth
Order BY
Team ASC
Edit:
It turns out I need to use GROUP BY as the comments suggest. So I am not summing within a table, but I sum the variable given the Group By parameters.
Unless I'm missing something, it's simply:
SELECT Team
,Season
,Match
,Sum(Stat)
FROM table
GROUP BY
Team
,Season
,Match
It's simple as this:
SELECT Team,
Season,
Match,
SUM(Stat)
FROM Table
WHERE Season IN (1,2)
GROUP BY Team,
Season,
Match
ORDER BY Team ASC
Please look at the SQL Fiddle example.
i have a table like
ID USER_ID type
1 1 2
2 1 1
3 3 3
4 3 1
5 6 2
6 6 3
and i want to get the sum of all user_id = 1 and user_id =3
and every type sum in user_id = 1 and user_id =3 ,it can be two sql
the result is
sum
4
type sum
1 2
2 1
3 1
The first function you needed to achieve the result is Count() not SUM() function
For first result
select count(*) as sum from user1 where user_id in(1,3)
For second result you need to select type also and it should be grouped
select type, count(*) as sum from user1 where user_id in(1,3)
group by type
Fiddle for second you can check the first one also there by taking the query
Next time post your effort. Guess you are naive to sql.
I have a table of data like this:
id user_id A B C
=====================
1 15 1 2 3
2 15 1 2 5
3 20 1 3 9
4 20 1 3 7
I need to remove duplicate user ids and keep the record that sorts lowest when sorting by A then B then C. So using the above table, I set up a temp query (qry_temp) that simply does the sort--first on user_id, then on A, then on B, then on C. It returns the following:
id user_id A B C
====================
1 15 1 2 3
2 15 1 2 5
4 20 1 3 7
3 20 1 3 9
Then I wrote a Totals Query based on qry_temp that just had user_id (Group By) and then id (First), and I assumed this would return the following:
user_id id
===========
15 1
20 4
But it doesn't seem to do that--instead it appears to be just returning the lowest id in a group of duplicate user ids (so I get 1 and 3 instead of 1 and 4). Shouldn't the Totals query use the order of the query it's based upon? Is there a property setting in the query that might impact this or another way to get what I need? If it helps, here is the SQL:
SELECT qry_temp.user_id, First(qry_temp.ID) AS FirstOfID
FROM qry_temp
GROUP BY qry_temp.user_id;
You need a different type of query, for example:
SELECT tmp.id,
tmp.user_id,
tmp.a,
tmp.b,
tmp.c
FROM tmp
WHERE (( ( tmp.id ) IN (SELECT TOP 1 id
FROM tmp t
WHERE t.user_id = tmp.user_id
ORDER BY t.a,
t.b,
t.c,
t.id) ));
Where tmp is the name of your table. First, Last, Min and Max are not dependent on a sort order. In relational databases, sort orders are quite ephemeral.