How to write arbitrary map to parque with spark - json

I will be parsing a bunch of json objects with spark and writing them out to parquet for searching and analysis later. Most of the json has a regular schema that maps directly to parquet, but there is one section where I have a data object that can have arbitrary fields and values with arbitrary data types.
Are there any thoughts on how to handle this? I can not put a Map[String, Any] in a dataframe.

Related

Json to Parquet with custom schema with Spark

What I'm trying to do is something similar to the Stackoverflow question here: basically converting .seq.gz JSON files to Parquet files with a proper schema defined.
I don't want to infer the schema, rather I would like to define my own, ideally having my Scala case classes so they can be reused as models by other jobs.
I'm not too sure whether I should deserialise my JSON into a case class and let toDS() to implicitly convert my data like below:
spark
.sequenceFile(input, classOf[IntWritable], classOf[Text])
.mapValues(
json => deserialize[MyClass](json.toString) // json to case class instance
)
.toDS()
.write.mode(SaveMode.Overwrite)
.parquet(outputFile)
...or rather use a Spark Data Frame schema instead, or even a Parquet schema. But I don't know how to do it though.
My objective is having full control over my models and possibly map JSON types (which is a poorer format) to Parquet types.
Thanks!

How structured streaming dynamically parses kafka's json data

I am trying to read data from Kafka using structured streaming. The data received from kafka is in json format.
My code is as follows:
in the code I use the from_json function to convert the json to a dataframe for further processing.
val **schema**: StructType = new StructType()
.add("time", LongType)
.add(id", LongType)
.add("properties",new StructType()
.add("$app_version", StringType)
.
.
)
val df: DataFrame = spark.readStream
.format("kafka")
.option("kafka.bootstrap.servers","...")
.option("subscribe","...")
.load()
.selectExpr("CAST(value AS STRING) as value")
.select(from_json(col("value"), **schema**))
My problem is that if the field is increased,
I can't stop the spark program to manually add these fields,
then how can I parse these fields dynamically, I tried schema_of_json(),
it can only take the first line to infer the field type and it not suitable for multi-level nested structures json data.
My problem is that if the field is increased, I can't stop the spark program to manually add these fields, then how can I parse these fields dynamically
It is not possible in Spark Structured Streaming (or even Spark SQL) out of the box. There are a couple of solutions though.
Changing Schema in Code and Resuming Streaming Query
You simply have to stop your streaming query, change the code to match the current schema, and resume it. It is possible in Spark Structured Streaming with data sources that support resuming from checkpoint. Kafka data source does support it.
User-Defined Function (UDF)
You could write a user-defined function (UDF) that would do this dynamic JSON parsing for you. That's also among the easiest options.
New Data Source (MicroBatchReader)
Another option is to create an extension to the built-in Kafka data source that would do the dynamic JSON parsing (similarly to Kafka deserializers). That requires a bit more development, but is certainly doable.

How do I read a Large JSON Array File in PySpark

Issue
I recently encountered a challenge in Azure Data Lake Analytics when I attempted to read in a Large UTF-8 JSON Array file and switched to HDInsight PySpark (v2.x, not 3) to process the file. The file is ~110G and has ~150m JSON Objects.
HDInsight PySpark does not appear to support Array of JSON file format for input, so I'm stuck. Also, I have "many" such files with different schemas in each containing hundred of columns each, so creating the schemas for those is not an option at this point.
Question
How do I use out-of-the-box functionality in PySpark 2 on HDInsight to enable these files to be read as JSON?
Thanks,
J
Things I tried
I used the approach at the bottom of this page:
from Databricks that supplied the below code snippet:
import json
df = sc.wholeTextFiles('/tmp/*.json').flatMap(lambda x: json.loads(x[1])).toDF()
display(df)
I tried the above, not understanding how "wholeTextFiles" works, and of course ran into OutOfMemory errors that killed my executors quickly.
I attempted loading to an RDD and other open methods, but PySpark appears to support only the JSONLines JSON file format, and I have the Array of JSON Objects due to ADLA's requirement for that file format.
I tried reading in as a text file, stripping Array characters, splitting on the JSON object boundaries and converting to JSON like the above, but that kept giving errors about being unable to convert unicode and/or str (ings).
I found a way through the above, and converted to a dataframe containing one column with Rows of strings that were the JSON Objects. However, I did not find a way to output only the JSON Strings from the data frame rows to an output file by themselves. The always came out as
{'dfColumnName':'{...json_string_as_value}'}
I also tried a map function that accepted the above rows, parsed as JSON, extracted the values (JSON I wanted), then parsed the values as JSON. This appeared to work, but when I would try to save, the RDD was type PipelineRDD and had no saveAsTextFile() method. I then tried the toJSON method, but kept getting errors about "found no valid JSON Object", which I did not understand admittedly, and of course other conversion errors.
I finally found a way forward. I learned that I could read json directly from an RDD, including a PipelineRDD. I found a way to remove the unicode byte order header, wrapping array square brackets, split the JSON Objects based on a fortunate delimiter, and have a distributed dataset for more efficient processing. The output dataframe now had columns named after the JSON elements, inferred the schema, and dynamically adapts for other file formats.
Here is the code - hope it helps!:
#...Spark considers arrays of Json objects to be an invalid format
# and unicode files are prefixed with a byteorder marker
#
thanksMoiraRDD = sc.textFile( '/a/valid/file/path', partitions ).map(
lambda x: x.encode('utf-8','ignore').strip(u",\r\n[]\ufeff")
)
df = sqlContext.read.json(thanksMoiraRDD)

Other data input format than flat json for crossfilter?

When using crossfilter (for example for dc.js), do I always need to transform my data to a flat JSON for input?
Flat JSON data when reading from AJAX requests tend to be a lot larger than it needs to be (in comparison to for example nested JSON, value to array or CSV data).
Is there an API available which can read in other types than flat json? Are there plans to add those?
I would like to avoid to let the client transform the data before using it.

how to convert nested json file into csv in scala

I want to convert my nested json into csv ,i used
df.write.format("com.databricks.spark.csv").option("header", "true").save("mydata.csv")
But it can use to normal json but not nested json. Anyway that I can convert my nested json to csv?help will be appreciated,Thanks!
When you ask Spark to convert a JSON structure to a CSV, Spark can only map the first level of the JSON.
This happens because of the simplicity of the CSV files. It is just asigning a value to a name. That is why {"name1":"value1", "name2":"value2"...} can be represented as a CSV with this structure:
name1,name2, ...
value1,value2,...
In your case, you are converting a JSON with several levels, so Spark exception is saying that it cannot figure out how to convert such a complex structure into a CSV.
If you try to add only a second level to your JSON, it will work, but be careful. It will remove the names of the second level to include only the values in an array.
You can have a look at this link to see the example for json datasets. It includes an example.
As I have no information about the nature of the data, I can't say much more about it. But if you need to write the information as a CSV you will need to simplify the structure of your data.
Read json file in spark and create dataframe.
val path = "examples/src/main/resources/people.json"
val people = sqlContext.read.json(path)
Save the dataframe using spark-csv
people.write
.format("com.databricks.spark.csv")
.option("header", "true")
.save("newcars.csv")
Source :
read json
save to csv