how to i loop this Marketplace_f, so when i loop it go to a to f?
this.clients.multiplayer.createJoinRoom("MarketPlace_f_v92",
"MarketPlace_f",
true,
{lobbyv:"MarketPlace_"+this.mpv},
{namehash:"3c0073212ba7bbf142cd3c5a01f518ac",
name:"Manuel Otto",
name:"Manuel Otto"},
this.handleJoin,
null);
I will take a wild guess that you want to generate strings from "MarketPlace_a" to "MarketPlace_f" :)
var startCode:int = 97; // ascii code for "a"
var endCode:int = 102; // ascii code for "f"
for (var i:int = startCode; i < endCode + 1; i++)
{
// if you use AS2: var letter:String = chr(i);
var letter:String = String.fromCharCode(i);
var myString:String = "MarketPlace_" + letter;
trace(myString);
}
Related
Seeking a way to merge arrays by index like so:
var a1:Array = ["a", "b", "c"];
var a2:Array = ["1", "2", "3"];
var a3:Array = result: ["a", 1, "b", 2, "c", 3]
I've tried concat, push, splice... not getting close. Thanks.
function arrayMerge(arr1:Array, arr2:Array):Array {
var o:Array = new Array();
for (var i:int=0; i<Math.max(arr1.length, arr2.length); i++) {
if (i<arr1.length) o.push(arr1[i]);
if (i<arr2.length) o.push(arr2[i]);
}
return o;
}
Thanks Payam for answer and non-judgement. Here's how I applied your work:
var arr1:Array = ["question1", "question2", "question3"];
var arr2:Array = ["answer1", "answer2", "answer3"];
var o:Array = new Array();
for (var i:int=0; i<Math.max(arr1.length, arr2.length); i++) {
if (i<arr1.length) o.push(arr1[i]);
if (i<arr2.length) o.push(arr2[i]);
}
trace(o); //(question1,answer1,question2,answer2,question3,question3)
#AndyH :
payamsbr is right, but you may work with Vectors or Arrays
Perhaps tl; dr; but this is the principle.
If You want to understand something try those possibilities.
If you don't, just copy and paste some shorter code ;)
var v1:Vector.<String> = new <String>["a", "b", "c"];
var v2:Vector.<uint> = new <uint>[1, 2, 3]; // why do you use String here and not uint?
// if you want to convert a uint to a String, use myUint.toString();
function convertVectorToArray(v1:Vector.<String>,v2:Vector.<uint>):Array{
var mergedArray:Array = new Array();
if (v1.length != v2.length){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same lenfgth!"));
}else{
for(var i:uint = 0; i <v1.length ; i++){
mergedArray.push(v1[i]);
mergedArray.push(v2[i]);
}
}
return(mergedArray);
}
function mergeVectors(v1:Vector.<String>,v2:Vector.<uint>):Vector.<Object>{
var mergedVector:Vector.<Object> = new Vector.<Object>();
if (v1.length != v2.length){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}
for(var i:uint = 0; i <v1.length ; i++){
mergedVector.push(v1[i] as String);
mergedVector.push(v2[i] as uint);
}
return(mergedVector);
}
var mergedArray:Array = (convertVectorToArray(v1,v2));
var mergedVector:Vector.<Object> = (mergeVectors(v1,v2));
function listArray(arr:Array):String{
var str: String="";
if ((v1.length*2) != (v1.length + v2.length)){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}else{
for (var i:uint = 0; i < arr.length ; i++){
str+="typeof(arr[" + i + "]) = " + (typeof(arr[i]) as String).toUpperCase() + ", value = " + arr[i] + "\n";
}
}
return str;
}
function listVector(vect:Vector.<Object>):String{
var str: String = "";
if ((v1.length*2) != (v1.length + v2.length)){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}else{
for (var i:uint = 0; i < vect.length ; i++){
str+="typeof(vect[" + i + "]) = " + (typeof(vect[i]) as String).toUpperCase() + ", value = " + vect[i] + "\n";
}
}
return str;
}
trace(listArray(mergedArray));
trace(listVector(mergedVector));
You may add a sort() method if You need it (you didn't told about it)
And Always throw an Error if the 2 Arrays or Vectors don't have the same length!
Throwing an Error is the best way to understand if something goes wrong...
This will avoid You a lot of time if You need to debug Your code!!!
As You can see the output is the same, but if the Vector Class is used correctly, this is more efficient than an Array.
Output :
Since there's a Vector Class, I don't understand a lot of people who chose Arrays instead...
Of course Vector. is a nonsense, but I posted it anyway so You can figure You out the Vector Class.
Output is the same :
typeof(arr[0]) = STRING, value = a
typeof(arr[1]) = NUMBER, value = 1
typeof(arr[2]) = STRING, value = b
typeof(arr[3]) = NUMBER, value = 2
typeof(arr[4]) = STRING, value = c
typeof(arr[5]) = NUMBER, value = 3
typeof(vect[0]) = STRING, value = a
typeof(vect[1]) = NUMBER, value = 1
typeof(vect[2]) = STRING, value = b
typeof(vect[3]) = NUMBER, value = 2
typeof(vect[4]) = STRING, value = c
typeof(vect[5]) = NUMBER, value = 3
I forgot this easiest way if you really want an Array...
Quick done!
var ar1:Array = [1,2,3];
var ar2:Array = ["a","b","c"];
function merge(...arrays):Array {
var result:Array = [];
for(var i:int=0;i<arrays.length;i++){
result = result.concat(arrays[i]);
}
return result;
}
trace(merge(ar1, ar2));
// outputs : 1,2,3,a,b,c
Another possibility :
function populateObject(v1:Vector.<String>, v2:Vector.<uint>):Object{
var obj = new Object();
if ((v1.length*2) != (v1.length + v2.length)){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}else{
for (var i:uint = 0; i < v1.length; i++){
obj[v2[i]] = v1[i];
}
}
return obj;
}
var o:Object = populateObject(v1,v2);
function listObject(someObj:Object):void{
var myObj:Object = someObj;
for (var i:String in someObj){
trace(someObj[i] + ": " + i);
}
}
listObject(o);
output =
a: 1
b: 2
c: 3
I think that You have a lot of possibilities to use here even it's my longer answer ;)
If You try those possibilities and understand them, this will certainty help You to think to find the best way to deal with Your issue.
But You may also copy and paste some shorter code.
I just wanted to show You that there's more than one answer.
If you understand this, You will be able to go further with coding.
Have fun ;)
Sincerely.
Nicolas
Best regards.
Nicolas.
How to Save positions for 3 objects in Array to make random position between each other by AS3?
import flash.geom.Point;
var arry:Point = new Point();
arry[0] = arry[78,200];
arry[1] = arry[217,200];
arry[2] = arry[356,200];
//object called b1
b1.x = arry[0][0];
b1.y = arry[0][1];
//object called b2
b2.x = arry[1][0];
b2.y = arry[1][1];
//object called b3
b3.x = arry[2][0];
b3.y = arry[2][1];
//make objects swap positions between each other
var rand:Number = (Math.random()*arry.length);
//output to see random position [[78,200],[217,200],[356,200]]
trace(arry);
to get random with tween like this... https://www.youtube.com/watch?v=8m_m64plQ6E
At compile time you should get this Error I suppose : "ReferenceError: Error #1069"
Here is a way to store the positions (like in the link you provided from youtube) :
import flash.geom.Point;
var squareWidth:uint = 40;
var squareHeight:uint = 40;
var marginX:uint = 100;
var marginY:uint = 75;
var spacer:uint = 10;
var positions:Vector.<Point > = new Vector.<Point > (9);
function setPositions(v:Vector.<Point>):void {
var count:uint = 0;
var posx:uint;
var posy:uint;
for (var i = 0; i < 3; i ++)
{
for (var j = 0; j < 3; j ++)
{
posx = (j * squareWidth) + (spacer * j) + marginX;
posy = (i * squareHeight) + (spacer * i) + marginY;
v[count] = new Point(posx,posy);
count++;
}
}
}
setPositions(positions);
trace(positions);
// output :
// (x=100, y=75),(x=150, y=75),(x=200, y=75),(x=100, y=125),(x=150, y=125),(x=200, y=125),(x=100, y=175),(x=150, y=175),(x=200, y=175)
So here you have nine Points to place the clips like in the video.
You just have to add a function to swap the nine boxes stored in another Vector.
In your case.
For 3 positions do the following if I understand your question.
import flash.geom.Point;
var positions:Vector.<Point> = new Vector.<Point>(3);
var p1:Point = new Point(78,200);
var p2:Point = new Point(217,200);
var p3:Point = new Point(356,200);
positions[0] = p1;
positions[1] = p2;
positions[2] = p3;
trace(positions);
// output : (x=78, y=200),(x=217, y=200),(x=356, y=200)
So, you're still unclear!
Your issue is to find a random position?
This may help you if this is the problem you're facing :
import flash.geom.Point;
var positions:Vector.<Point > = new Vector.<Point > (3);
var numbers:Vector.<uint> = new Vector.<uint>();
var numbersAllowed:uint = 3;
var rndNmbrs:Vector.<uint> = new Vector.<uint>(3);;
var p1:Point = new Point(78,200);
var p2:Point = new Point(217,200);
var p3:Point = new Point(356,200);
positions[0] = p1;
positions[1] = p2;
positions[2] = p3;
trace(positions);
function populateRndNmbrs(n:uint):void {
for (var i:uint = 0; i < n; i++)
{
numbers[i] = i;
}
}
populateRndNmbrs(numbersAllowed);
function populateRandomNumbers(n:uint):void
{
var rnd:uint;
for (var i:uint = 0; i < n; i++)
{
rnd = numbers[Math.floor(Math.random() * numbers.length)];
for (var j:uint = 0; j < numbers.length; j++)
{
if (rnd == numbers[j])
{
numbers.splice(j,1);
}
}
rndNmbrs[i] = rnd;
}
}
populateRandomNumbers(numbersAllowed);
trace("rndNmbrs = " + rndNmbrs);
for (var i:uint = 0; i < numbersAllowed; i++)
{
trace("b"+ (i+1) + ".x = " + positions[rndNmbrs[i]].x);
trace("b"+ (i+1) + ".y = " + positions[rndNmbrs[i]].y);
// In place of trace, you should place the boxes at those random positions.;
}
//output:
//(x=78, y=200),(x=217, y=200),(x=356, y=200)
//rndNmbrs = 2,0,1
//b1.x = 356
//b1.y = 200
//b2.x = 78
//b2.y = 200
//b3.x = 217
//b3.y = 200
Is that what you want? Or do you want to know how to create a motion effect?
I'm not sure about what you really need...
This will help you to place all the boxes in a random position.
You may do this like here bellow, and add a function to check if the random positions are not the same.
With only 3 MovieClips, you will often have the same random positions as long they're stored in the "positions Vector"
var squares:Vector.<MovieClip> = new Vector.<MovieClip>(3);
function populateMCs(target:DisplayObjectContainer,n:uint):void{
for (var i:uint = 0; i < n; i++){
squares[i] = target["b"+(i+1)];
}
}
function swapMCs():void{
for (var i:uint=0; i<squares.length; i++){
squares[i].x = positions[rndNmbrs[i]].x;
squares[i].y = positions[rndNmbrs[i]].y;
}
}
populateMCs(this,numbersAllowed);
swapMCs();
I give you a last example to get a motion effect in AS3.
I'm not a translator AS2 -> AS3 and a video is not the best way to show your code :(
This will make your boxes move smoothly, but not the way you want.
Now, you have to learn AS3 and try to make the job by yourself.
Then, if you have another issue, just ask clearly what you want.
var friction:Number = 0.15;
setDestination(squares[0],squares[0].x,350,friction);
setDestination(squares[1],squares[1].x,350,friction);
setDestination(squares[2],squares[2].x,350,friction);
squares[0].addEventListener(Event.ENTER_FRAME,moveClip);
squares[1].addEventListener(Event.ENTER_FRAME,moveClip);
squares[2].addEventListener(Event.ENTER_FRAME,moveClip);
function setDestination(mc:MovieClip,x:uint,y:uint,friction:Number):void{
mc.destinx = x;
mc.destiny = y;
mc.f = friction;
}
function moveClip(e:Event):void{
var mc:MovieClip = e.target as MovieClip;
trace(mc.name)
mc.speedx = (mc.destinx - mc.x);
mc.speedy = (mc.destiny - mc.y);
mc.x += mc.speedx*mc.f;
mc.y += mc.speedy*mc.f;
if((Math.floor(mc.speedx)<1) && (Math.floor(mc.speedy)<1)){
mc.removeEventListener(Event.ENTER_FRAME,moveClip);
trace("STOP MOVE FOR " + mc.name);
}
}
Is there? Like Let's say I need 5 variables in ActionScript 3.0 and would like to name them as follows:
var myVar_1 = "things";
var myVar_2 = "things";
var myVar_3 = "things";
var myVar_4 = "things";
var myVar_5 = "things";
But instead of having to type them 1 by 1, would it work in a loop? I can't seem to make it work and would really love some help/advice on this matter.
Yes, you can create a dynamic property name using [ ] array access:
var variables:Object = {};
for(var i:int = 0; i < 5; i++){
variables["myVar" + i] = "value " + i;
}
trace(variables.myVar3); // "value 3"
The variables object in this case could be replaced by any dynamic object, including MovieClips.
However, in most cases to store data by index it usually makes more sense to use an array. Example:
var variables:Array = [];
for(var i:int = 0; i < 5; i++){
variables.push("value " + i);
}
trace(variables[3]); // "value 3"
You should use Vector.<String>, Array, Object or Dictionary for that:
var variables:Vector.<String> = new <String>[];
for(var i:int = 0; i<5; i++)
{
variables[i] = "things";
}
I am trying to create multiple Numbers with for loop.
var sasutu1x : Number = Number(sasutu1.text);
var sasutu2x : Number = Number(sasutu2.text);
var sasutu3x : Number = Number(sasutu3.text);
var sasutu4x : Number = Number(sasutu4.text);
var sasutu5x : Number = Number(sasutu5.text);
var sasutu6x : Number = Number(sasutu6.text);
My Solution :
var i:int;
for (i = 0; i < 7; i++)
{
var this["sasutu" i + "x"] : Number = Number(["sasutu" + i].text);
}
Thanks for you help.
You can use a Vector, or if you want to get a reference to that number by name later, you can also use a Dictionary.
var i:int;
var sasutuDict:Dictionary = new Dictionary(true);
for (i = 0; i < 7; i++)
{
sasutuDict["sasutu" i + "x"] = Number(["sasutu" + i].text);
}
One advantage of a dictionary, is that you can even do something like this:
for (i = 0; i < 7; i++)
{
var sasutuTexField:TextField = this["sasutu" + i];
sasutuDict[sasutuTexField] = Number(sasutuTexField.text);
}
Meaning you can have the key of the dictionary be the text field itself.
A better solution would be to use a Vector instead.
var vec:Vector.<int> = new Vector.<int>();
for (var i:int = 0; i < 7; i++)
{
vec.push(Number(["sasutu"+i].text));
}
I've been working on a project for a while but got stuck where I have a text file that contains a set of numbers in this format:
1-2-3-4
1-2-3-4
1-2-3-4
1-2-3-4
So I must read the numbers from the file and put them in an array according to the column so at the end I have
column1:Array (1,1,1,1)
column2:Array (2,2,2,2)
..... and so on. I can't figure how to do this.
What I managed to do was read all the file and have all the numbers in 1 array but just that.
Here's the code
var myTextLoader:URLLoader = new URLLoader;
var txtArray:Array;
myTextLoader.load(new URLRequest(inputFile.text));
myTextLoader.addEventListener(Event.COMPLETE,onLoaded);
function onLoaded(e:Event):void
{
txtArray = e.target.data.split(/\-|\n/g);
}
before split \n \r to array (reading with a loop)
and the same with... -
a loop in loop to get a multidimensional array
in mind the result is a "table"
finally to get a result do this.
variable[file][column]
a[2][3] ----> 4
;)
Try splitting it into two parts, first by line, then by element:
function onLoaded(e:Event):void
{
preArray:Array = e.target.data.split(/\n/g);
txtArray = new Array();
for(var i:int = 0; i < preArray.length; i++) {
txtArray.push(preArray[i].split(/\-/g));
}
}
This will give you a 2D array, which you'd access like this:
textArray[0][0]; // result: 1
textArray[2][3];
Et cetera.
Thanks to Llanis who gave me the idea. This is my final code. Sorry i didn't tag the language it never ocurred to me i'm new.
myTextLoader.load(new URLRequest(inputWX.text));
myTextLoader.addEventListener(Event.COMPLETE,onLoaded);
function onLoaded(e:Event):void
{
txtArray = e.target.data.split(/\-|\n/g);
var wArray:Array = new Array(txtArray.length/4);
var xArray:Array = new Array(txtArray.length/4);
var yArray:Array = new Array(txtArray.length/4);
var zArray:Array = new Array(txtArray.length/4);
var a:int = 0;
var b:int = 0;
var c:int = 0;
var d:int = 0;
var columna:int = 1;
for(var arrayIndex:int = 0; arrayIndex <= txtArray.length-1;arrayIndex++)
{
switch(columna){
case 1: wArray[a] = txtArray[arrayIndex]; a+=1;
break;
case 2: xArray[b] = txtArray[arrayIndex]; b+=1;
break;
case 3: yArray[c] = txtArray[arrayIndex]; c+=1;
break;
case 4: zArray[d] = txtArray[arrayIndex]; d+=1;
break;
}
if(columna == 4)
columna = 1;
else columna++;
}
}