Determining menu items to be shown depending on who logs in - yii2

I am developing a health information system. Its my first project in Yii2. However, i am having trouble at some point. I want menu items to be shown on the navbar to depend on who logs in. For example, if a doctor logs in, i only want menu items associated with him to show, the same case for nurses, pharmacists and so on..I think this could be implemented in the following segment of code in main.php file in layouts, though i don't know how. Please help.
$menuItems = [
['label' => 'Home', 'url' => ['/site/index']],
];
if (Yii::$app->user->isGuest) {
$menuItems[] = ['label' => 'Login', 'url' => ['/site/login']];
} else {
$menuItems[] = '<li>'
. Html::beginForm(['/site/logout'], 'post')
. Html::submitButton(
'Logout (' . Yii::$app->user->identity->username . ')',
['class' => 'btn btn-link']
)
. Html::endForm()
. '</li>';
}

You need to read about RBAC, http://www.yiiframework.com/doc-2.0/guide-security-authorization.html#rbac
Create a role for each type of user and filter the menu off that.
$menuItems = [];
if (Yii::$app->user->can('doctor')) {
$menuItems = [['label' => 'Patients', 'url' => ...]];
} else if (Yii::$app->user->can('nurse')) {
$menuItems = [['label' => 'Medicines', 'url' => ...]];
}

Related

Don't create field in database

I hava code like below. It creates a field in database and show in another places. I would like to block create a database field if message field is not exit. Rest fields are taken from system. What is wrong in my code.
$delivery->comments_buro()->create([
'name' => auth()->user()->firstname,
'user_id' => auth()->user()->id,
'message' => $request['repair_report_buro'],
'icon' => 'fa fa-commenting-o',
'style' => $position->style,
]);
Thanks for help.
You need Laravel Validations for that. Please read this: https://laravel.com/docs/5.8/validation
For example:
//controller
public function index(Request $request)
{
$validator = Validator::make($request->all(), [
'message' => 'required|string',
]);
if ($validator->fails()) {
//do validation error handling here
}
// create new row in database.
}
I have a right code. It works with it. I close this question. The right code is:
if(isset($request['repair_report_buro']) && !empty($request['repair_report_buro'])){
$delivery->comments_buro()->create([
'name' => auth()->user()->firstname,
'user_id' => auth()->user()->id,
'message' => $request['repair_report_buro'],
'icon' => 'fa fa-commenting-o',
'style' => $position->style,
]);
}

How to make active item of SideNav in another style?

I want the items in my SideNav by Kartik in the yii2 app to change the color when it is active(was clicked and open).
Sorry, I am pretty new for PHP and Yii and the question might be seen obvious but I really stack here.
I have already tried to use the "active" option that is explained in the documentation but it doesn't work. It doesn't show any error but is not working. I have a file adminMenu.php where the SideNav is written. and the panel.php view file where I showing it.
Also, I tried to add echo
$this->render('adminMenu'['currentPage'=>'admin/personal']);
but it shows error and thus I comment it for now.
adminMenu.php:
class adminMenu extends Widget{
public function init(){
$curentpage = Yii::$app->controller->id ;
parent::init();
ob_start();
echo SideNav::widget([
'type' => SideNav::TYPE_PRIMARY,
'headingOptions' => ['class'=>'head-style'],
'items' => [
['label' => 'Personal',
'url' => ['/admin/personal'],
'active' => ($curentpage == 'admin/personal')],
['label' => 'Clients',
'url' => ['/admin/clients'],
'active' => ($curentpage == 'admin/clients')],
...
]);
panel.php:
if(\Yii::$app->user->can('Admin')){
echo adminMenu::widget();
//echo $this->render('adminMenu'['currentPage'=>'admin/personal']);
}
i think that you mistake is in this line
$curentpage = Yii::$app->controller->id;
Yii::$app->controller->id only return the name of your controller , in this casi will be "admin" then you compare "admin" equals "controller/action" ('admin/personal') this never will be equals .
To do this , you can do a concat the actual controller and the actual action like this :
$curentpage = Yii::$app->controller->id.'/'.Yii::$app->controller->action->id;
and the comparation will be success and the "active" class add to you sidebar

Yii2 change breadcrumb url

There are two user types in my admin application. If an admin is logged in, there should be a param in each url like this:
Home>>Property>> view property
Current url : www.example.com/property/index
Desired Url : www.example.com/property/index?agentid=5
How can I achieve this?
This param value will be dynamic and only for admin.
In the top of your view file, (I consider view.php) You can use User::can() function to check for some admin/other permissions, and look at this example code to add param to link:
if (Yii::$app->user->can('admin')) {
$this->params['breadcrumbs'][] = ['label' => 'Property', 'url' => ['index', 'agentid' => 5]];
} else {
$this->params['breadcrumbs'][] = ['label' => 'Property', 'url' => ['index']];
}
$this->params['breadcrumbs'][] = $this->title;
It adds agentid=5 param if user has admin permission, and do not otherwise

Customize prestashop web service

I want to customize Prestashop web service for my own usage but I don't know how and I can't find any tutorial. I have a mobile application that want to retrieve data from website but the default web service is useless.
For example I want the list of categories (in a language) with they're pictures but It seems I should call two different service to retrieve categories and images separately.
Assume I want to have a JSON array of categories that a category is a JSON object that have these fields {id,title,imageUrl} but It seems I should get {id,title} with a method and after that I can get images on by one by another method!
I couldn't find any guide for extending or customizing web service in the documentation.
I'm a bit late but:
Prestashop version requier : > 1.6
If you want to customize a web service and return specific fields with a JSON format output. You need to do it this way:
First
In override :
Create a class : myClassForWs that extends myClassCore
Override WebserviceRequest in webservice/WebserviceRequest.php
In webservice/WebserviceRequest.php : Add myClassForWs to
ressources:
public static function getResources()
{
$resources = parent::getResources();
$resources['myClassForWs'] = array('description' => 'The class','class' => 'myClassForWs');
ksort($resources);
return $resources;
}
}
In myClassForWs : redefine $webserviceParameters and $definition with the fields you need:
protected $definition = array(
'table' => 'category',
'primary' => 'id_category',
'multilang' => true,
'multilang_shop' => true,
'fields' => array(
'name' =>array('type' => self::TYPE_STRING, 'lang' => true, 'validate' => 'isCatalogName', 'required' => true, 'size' => 128),
'link_rewrite' =>array('type' => self::TYPE_STRING, 'lang' => true, 'validate' => 'isLinkRewrite', 'required' => true, 'size' => 128),
'description' =>array('type' => self::TYPE_HTML, 'lang' => true, 'validate' => 'isCleanHtml'),
),
);
protected $webserviceParameters = array(
'objectsNodeName' =>'categories',
'hidden_fields'=>array('nleft', 'nright', 'groupBox'),
'fields' => array(
'level_depth' => array('setter' => false),
),
'associations' => array(
'images' => array(
'resource' => 'image',
'fields' => array('id' => array())
),
),
);
Then
Go in your admin tab :
in performance : clear cache
in advanced settings > Web service: active a api Key and set myClassForWs for this key
Finally
Access to your web service with url :
my.prestashop/api/myClassForWs/{id_class}?output_format=**JSON**
And it returns your datas
I hope it helps.

html to pdf converter in yii2 with pagination in table

view:
<p>
<?= Html::a('Download This page', ['report'], ['class' => 'btn btn-danger']) ?>
</p>
controller:
public function actionReport()
{
// setup kartik\mpdf\Pdf component
$pdf = new Pdf([
'content' => $content,
'options' => ['title' => 'Krajee Report Title'],
'methods' => [
'SetHeader' => ['Krajee Report Header'],
'SetFooter' => ['{PAGENO}'],
]
]);
return $pdf->render();
}
This function works perfectly but my html table has pagination . so i am confused how to deal with table that has pagination.
You should disable the pagination. it all depends on how you define your data provider (read more about data providers here http://www.yiiframework.com/doc-2.0/guide-output-data-providers.html). Probably you should do something like this
************* = new ActiveDataProvider([
'pagination' => false,
..............
]);
I think you can also call it like
$dataProvider->pagination =false;
Just in case you need to disable it in a specific case.