I have searched all over and cannot seem to find a definitive answer for this issue! I have a simple chat here grouped on the 5 categories below detailing the Sums of their SqFt.
I want to add a Total Column to the graph ~(Total = 11M sqft). Can this only be done in SQL? It is a bit puzzling for me to do this because the query already sums the sqft for each row (as a nested query). I would need to Sum(sum(sqft)) in order to produce what I want, however, I dont believe this will work on the group level.
Sample Data set:
ID| Type| Sqft|
12| OF| 500
14| IN| 1294
99| OF| 12042
24| ME| 92043
15| IN| 13945
16| OW| 2650
Can this be done in the report builder?
Thanks!
You can add a Total row in your query by using GROUPING SETS operator. Once the total is in the dataset it is trivial to show the column in the chart.
Based on the data sample you posted you can use a similar query to the below:
SELECT
CASE
WHEN GROUPING_ID(Type) = 1 THEN 'TOTAL'
ELSE Type
END [Type],
SUM(Sqft) Sqft,
GROUPING_ID(Type) [Grouping]
FROM your_table
GROUP BY GROUPING SETS ((Type), ())
Check this Live Demo
If you are confused by the above query you can simply use the union operator to add a row to the end of your current dataset.
SELECT
ID,
[Type],
Sqft
FROM your_table
UNION ALL
SELECT
NULL,
'Total',
SUM(Sqft)
FROM your_table
Now just create your chart using the produced dataset.
Let me know if this helps.
Related
I have a table named Company which has categorized by several sector_id
SELECT sector_id,count(sector_id) FROM Company group by sector_id
I could get the company numbers like this
sector_id count(sector_id)
1 10
2 15
3 22
Then, I would like to get the sum of count(sector_id) 10 + 15 + 22
Is it possible to do this by sql only? or I need to make some code with php??
Just remove the group by:
SELECT count(*)
FROM Company ;
EDIT:
It occurs to me that you want a summary row as well as the original data. If so, you can use rollup or grouping sets in most databases. Something like this:
SELECT sector_id, count(sector_id)
FROM Company
GROUP BY sector_id WITH ROLLUP;
Yes, it is possible to calculate sum using sql by using SUM() method
Syntax :
SELECT SUM(column_name)
FROM Table_Name;
In your case it will be like this :
SELECT SUM(sector_id)
FROM Company ;
Hope it helps.
SQL Question
I am currently trying to get the average of a certain subset of a column based on the shared value of another column. Here's some example data:
Score Player
5 1
9 1
7 1
8 2
3 2
6 2
So how can I get the average of Player 1's scores separately from Player 2's? My first thought is to try something like:
SELECT AVG(score) FROM table WHERE DISTINCT player
But, of course, distinct only works in the select portion of the query. Any attempt I've made to use a subquery results in an error saying:
the subquery returns more than one row.
Any assistance anyone could give would be greatly appreciated.
Sounds like you're looking for GROUP BY:
SELECT Player, AVG(Score)
FROM my_table
GROUP BY Player;
Try this below query. I hope you are looking for this solution.
LIVE DEMO
SELECT
Player,
AVG(Score) AS Avarage
FROM
table_name
GROUP BY
Player
Output:
I have a matrix set up with a Row Group called "company", a Column Group called "Year" and a value field that is a sum of charges through the year called revenue. The column Group will end up having 2 columns in it that are provided through user input. The end results is a matrix that will look something like this:
Year 1 | Year 2
Company: $500 $250
Company2: $750 $250
What I would like to do is add a column to the matrix that calculates the change from year 1 to year 2. Is there a way to do this within the matrix such as adding a new column with an expression that compares the 2 entries in the row or will I need to manipulate the SQL code to create a column that does this within the code? To that end here is a view of the code for the dataset if that is the way I need to go:
SELECT
company.cmp_id
,company.Company
,ChargeDetails.[Bill To ID]
,ChargeDetails.[Delivery Year]
,ChargeDetails.Revenue
FROM
ChargeDetails
LEFT OUTER JOIN company
ON ChargeDetails.[Bill To ID] = company.cmp_id
WHERE
ChargeDetails.[Delivery Year] = #DeliveryYear
OR
ChargeDetails.[Delivery Year] = #ComparisonYear2
ORDER BY ChargeDetails.[Delivery Year] DESC,ChargeDetails.Revenue DESC;`
Try to add a column outside the Year group in header type Change or what you want to put, in the below cell use this expression:
=Sum(iif(Max(Fields!DeliveryYear.Value)=Fields!DeliveryYear.Value,Fields!Revenue.Value,0))-
Sum(iif(Min(Fields!DeliveryYear.Value)=Fields!DeliveryYear.Value,Fields!Revenue.Value,0))
Note I am substracting the min year (1) revenue sum to the max
year (2) revenue sum.
In your example it will produce:
+-----------+--------+--------+--------+
| Company | Year 1 | Year 2 | Change |
+-----------+--------+--------+--------+
| Company A | 500 | 250 | -250 |
+-----------+--------+--------+--------+
You can define change in many ways maybe in percentage or any other measure, this is only an example, learn what the above expression is doing in order to calculate the measure you need.
EDIT 1:
Add the matrix with this data arrangement.
The matrix looks like this one in preview:
Be sure you added the Change column outside the DeliveryYear group as shown in above image. Also check the fields names correspond to yours in the expression.
EDIT 2:
If Revenue has null values you can try this:
Try replace the null values at query level using T-SQL ISNULL() Function, change your query in this part as follows
,ISNULL(ChargeDetails.Revenue,0)
However if DeliveryYear has null values you may want to ignore that records, so try to exclude it in the where clause.
Let me know if you need further help.
I ended up using the following as the expression in the change column.
=sum(iif(Fields!Delivery_Year.Value=Parameters!DeliveryYear.Value,1,0)*Fields!Revenue.Value) - sum(iif(Fields!Delivery_Year.Value=Parameters!ComparisonYear2.Value,1,0)* Fields!Revenue.Value)
I think it will be easiest to start with the table I have and the result I am aiming for.
Name | Date
A | 03/01/2012
A | 03/01/2012
B | 02/01/2012
A | 02/01/2012
B | 02/01/2012
A | 02/01/2012
B | 01/01/2012
B | 01/01/2012
A | 01/01/2012
I want the result of my query to be:
Name | 01/01/2012 | 02/01/2012 | 03/01/2012
A | 1 | 2 | 2
B | 2 | 2 | 0
So basically I want to count the number of rows that have the same date, but for each individual name. So a simple group by of dates won't do because it would merge the names together. And then I want to output a table that shows the counts for each individual date using php.
I've seen answers suggest something like this:
SELECT
NAME,
SUM(CASE WHEN GRADE = 1 THEN 1 ELSE 0 END) AS GRADE1,
SUM(CASE WHEN GRADE = 2 THEN 1 ELSE 0 END) AS GRADE2,
SUM(CASE WHEN GRADE = 3 THEN 1 ELSE 0 END) AS GRADE3
FROM Rodzaj
GROUP BY NAME
so I imagine there would be a way for me to tweak that but I was wondering if there is another way, or is that the most efficient?
I was perhaps thinking if the while loop were to output just one specific name and date each time along with the count, so the first result would be A,01/01/2012,1 then the next A,02/01/2012,2 - A,03/01/2012,3 - B,01/01/2012,2 etc. then perhaps that would be doable through a different technique but not sure if something like that is possible and if it would be efficient.
So I'm basically looking to see if anyone has any ideas that are a bit outside the box for this and how they would compare.
I hope I explained everything well enough and thanks in advance for any help.
You have to include two columns in your GROUP BY:
SELECT name, COUNT(*) AS count
FROM your_table
GROUP BY name, date
This will get the counts of each name -> date combination in row-format. Since you also wanted to include a 0 count if the name didn't have any rows on a certain date, you can use:
SELECT a.name,
b.date,
COUNT(c.name) AS date_count
FROM (SELECT DISTINCT name FROM your_table) a
CROSS JOIN (SELECT DISTINCT date FROM your_table) b
LEFT JOIN your_table c ON a.name = c.name AND
b.date = c.date
GROUP BY a.name,
b.date
SQLFiddle Demo
You're asking for a "pivot". Basically, it is what it is. The real problem with a pivot is that the column names must adapt to the data, which is impossible to do with SQL alone.
Here's how you do it:
SELECT
Name,
SUM(`Date` = '01/01/2012') AS `01/01/2012`,
SUM(`Date` = '02/01/2012') AS `02/01/2012`,
SUM(`Date` = '03/01/2012') AS `03/01/2012`
FROM mytable
GROUP BY Name
Note the cool way you can SUM() a condition in mysql, becasue in mysql true is 1 and false is 0, so summing a condition is equivalent to counting the number of times it's true.
It is not more efficient to use an inner group by first.
Just in case anyone is interested in what was the best method:
Zane's second suggestion was the slowest, I loaded in a third of the data I did for the other two and it took quite a while. Perhaps on smaller tables it would be more efficient, and although I am not working with a huge table roughly 28,000 rows was enough to create significant lag, with the between clause dropping the result to about 4000 rows.
Bohemian's answer gave me the least amount to code, I threw in a loop to create all the case statements and it worked with relative ease. The benefit of this method was the simplicity, besides creating the loop for the cases, the results come in without the need for any php tricks, just simple foreach to get all the columns. Recommended for those not confident with php.
However, I found Zane's first suggestion the quickest performing and despite the need for extra php coding it seems I will be sticking with this method. The disadvantage of this method is that it only gives the dates that actually have data, so creating a table with all the dates becomes a bit more complicated. What I did was create a variable that keeps track of what date it is supposed to be compared to the table column which is reset on each table row, when the result of the query is equal to that date it echoes the value otherwise it does a while loop echoing table cells with 0 until the dates do match. It also had to do a check to see if the 'Name' value is still the same and if not it would switch to the next row after filling in any missing cells with 0 to the end of that row. If anyone is interested in seeing the code you can message me.
Results of the two methods over 3 months of data (a column for each day so roughly 90 case statements) ~ 12,000 rows out of 28,000:Bohemian's Pivot - ~0.158s (highest seen ~0.36s)Zane's Double Group by - ~0.086s (highest seen ~0.15s)
Evening folks,
I have a complex MySQL COUNT query I am trying to perform and am looking for the best way to do it.
In our system, we have References. Each Reference can have many (or no) Income Sources, each of which can be validated or not (status). We have a Reference table and an Income table - each row in the Income table points back to Reference with reference_id
On our 'Awaiting' page (the screen that shows each Income that is yet to be validated), we show it grouped by Reference. So you may, for example, see Mr John Smith has 3 Income Sources.
We want it to show something like "2 of 3 Validated" beside each row
My problem is writing the query that figures this out!
What I have been trying to do is this, using a combination of PHP and MySQL to bridge the gap where SQL (or my knowledge) falls short:
First, select a COUNT of the number of incomes associated with each reference:
SELECT `reference_id`, COUNT(status) AS status_count
FROM (`income`)
WHERE `income`.`status` = 0
GROUP BY `reference_id`
Next, having used PHP to generate a WHERE IN clause, proceed to COUNT the number of confirmed references from these:
SELECT `reference_id`, COUNT(status) AS status_count
FROM (`income`)
WHERE `reference_id` IN ('8469', '78969', '126613', ..... etc
AND status = 1
GROUP BY `reference_id`
However this doesn't work. It returns 0 rows.
Any way to achieve what I'm after?
Thanks!
In MySQL, you can SUM() on a boolean expression to get a count of the rows where that expression is true. You can do this because MySQL treats true as the integer 1 and false as the integer 0.
SELECT `reference_id`,
SUM(`status` = 1) AS `validated_count`,
COUNT(*) AS `total_count`
FROM `income`
GROUP BY `reference_id`