I have a column in my MySql database which stores a date as a string "dd/mm/yyyy" is there a way for me to have this in an update query where I can check if the date in the table is overdue compared to now().
I've had a look at the CONVERT function but can't figure out how to use it for my case.
STR_TO_DATE() converts the str string into a date value based on the fmt format string. The STR_TO_DATE() function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE() function returns NULL.
SELECT STR_TO_DATE('21/5/2013','%d/%m/%Y');
With time :-
SELECT STR_TO_DATE('01/01/2013 1130','%d/%m/%Y %h%i') ;
compare with now()
Where now()=STR_TO_DATE('01/01/2013 1130','%d/%m/%Y %h%i') ;
Try this:
SELECT ... FROM ... WHERE STR_TO_DATE(col, '%d/%m/%Y') > NOW()
Related
I have a string column which acts as a date and I want to select it as a DATE.
Is it possible?
My sample data format would be:
month/day/year -> 12/31/2011
As was told at MySQL Using a string column with date text as a date field, you can do
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAY
You can handle all kinds of date/time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter of STR_TO_DATE().
STR_TO_DATE('12/31/2011', '%m/%d/%Y')
Here's another two examples.
To output the day, month, and year, you can use:
select STR_TO_DATE('14/02/2015', '%d/%m/%Y');
Which produces:
2015-02-14
To also output the time, you can use:
select STR_TO_DATE('14/02/2017 23:38:12', '%d/%m/%Y %T');
Which produces:
2017-02-14 23:38:12
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
use the above page to refer more Functions in MySQL
SELECT STR_TO_DATE(StringColumn, '%d-%b-%y')
FROM table
say for example use the below query to get output
SELECT STR_TO_DATE('23-feb-14', '%d-%b-%y') FROM table
For String format use the below link
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The following illustrates the syntax of the STR_TO_DATE() function:
STR_TO_DATE(str,fmt);
The STR_TO_DATE() converts the str string into a date value based on the fmt format string. The STR_TO_DATE() function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE() function returns NULL.
The following statement converts a string into a DATE value.
SELECT STR_TO_DATE('21,5,2013','%d,%m,%Y');
Based on the format string ‘%d, %m, %Y’, the STR_TO_DATE() function scans the ‘21,5,2013’ input string.
First, it attempts to find a match for the %d format specifier, which
is a day of the month (01…31), in the input string. Because the
number 21 matches with the %d specifier, the function takes 21 as the
day value.
Second, because the comma (,) literal character in the format string
matches with the comma in the input string, the function continues to
check the second format specifier %m , which is a month (01…12), and
finds that the number 5 matches with the %m format specifier. It
takes the number 5 as the month value.
Third, after matching the second comma (,), the STR_TO_DATE()
function keeps finding a match for the third format specifier %Y ,
which is four-digit year e.g., 2012,2013, etc., and it takes the
number 2013 as the year value.
The STR_TO_DATE() function ignores extra characters at the end of the input string when it parses the input string based on the format string. See the following example:
SELECT STR_TO_DATE('21,5,2013 extra characters','%d,%m,%Y');
More Details : Reference
So I'm trying to insert dates into a table and the date is in this format:
8/3/2021
However I want to add a leading 0 before the month and day so the date shows 08/03/2021. Also I want to add it as a string concatenated with another string so test123-08/03/2021
If you really store date in that format then you may try this:
SELECT
DATE_FORMAT(STR_TO_DATE(date_col_string,'%d/%m/%Y'),'%d/%m/%Y') as 'zero-padded',
CONCAT(string_val,'-',DATE_FORMAT(STR_TO_DATE(date_col_string,'%d/%m/%Y'),'%d/%m/%Y')) as 'concatenated'
FROM mytable;
Use STR_TO_DATE() function to change the date value to standard MySQL date format of YYYY-MM-DD then use DATE_FORMAT() function to display the date value as per your desired output. The second operation is adding CONCAT() function on the converted date with your selected string. I'm assuming that your date value is d/m/y, because as #Stu mentioned in the comment, since you're not storing as MySQL standard date format, that means 8/3/2021 can be either d/m/y or m/d/y. With a standard date format value, the query would be shorter:
SELECT
DATE_FORMAT(date_col,'%d/%m/%Y') as 'zero-padded',
CONCAT(string_val,'-',DATE_FORMAT(date_col,'%d/%m/%Y')) as 'concatenated'
FROM mytable;
Demo fiddle
You should be inserting your source dates into a proper date or datetime column. Then, to view your dates in the format you want, use the DATE_FORMAT() function with the appropriate format mask:
SELECT DATE_FORMAT(date_col, '%d/%m/%Y') AS date_out
FROM yourTable;
I have a string column which acts as a date and I want to select it as a DATE.
Is it possible?
My sample data format would be:
month/day/year -> 12/31/2011
As was told at MySQL Using a string column with date text as a date field, you can do
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAY
You can handle all kinds of date/time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter of STR_TO_DATE().
STR_TO_DATE('12/31/2011', '%m/%d/%Y')
Here's another two examples.
To output the day, month, and year, you can use:
select STR_TO_DATE('14/02/2015', '%d/%m/%Y');
Which produces:
2015-02-14
To also output the time, you can use:
select STR_TO_DATE('14/02/2017 23:38:12', '%d/%m/%Y %T');
Which produces:
2017-02-14 23:38:12
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
use the above page to refer more Functions in MySQL
SELECT STR_TO_DATE(StringColumn, '%d-%b-%y')
FROM table
say for example use the below query to get output
SELECT STR_TO_DATE('23-feb-14', '%d-%b-%y') FROM table
For String format use the below link
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The following illustrates the syntax of the STR_TO_DATE() function:
STR_TO_DATE(str,fmt);
The STR_TO_DATE() converts the str string into a date value based on the fmt format string. The STR_TO_DATE() function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE() function returns NULL.
The following statement converts a string into a DATE value.
SELECT STR_TO_DATE('21,5,2013','%d,%m,%Y');
Based on the format string ‘%d, %m, %Y’, the STR_TO_DATE() function scans the ‘21,5,2013’ input string.
First, it attempts to find a match for the %d format specifier, which
is a day of the month (01…31), in the input string. Because the
number 21 matches with the %d specifier, the function takes 21 as the
day value.
Second, because the comma (,) literal character in the format string
matches with the comma in the input string, the function continues to
check the second format specifier %m , which is a month (01…12), and
finds that the number 5 matches with the %m format specifier. It
takes the number 5 as the month value.
Third, after matching the second comma (,), the STR_TO_DATE()
function keeps finding a match for the third format specifier %Y ,
which is four-digit year e.g., 2012,2013, etc., and it takes the
number 2013 as the year value.
The STR_TO_DATE() function ignores extra characters at the end of the input string when it parses the input string based on the format string. See the following example:
SELECT STR_TO_DATE('21,5,2013 extra characters','%d,%m,%Y');
More Details : Reference
The default date format in my SQL is : '2019-05-06'
and its fine but when i insert date to my table i want this format 2019-5-6 not the above format
It means month and day must be start 1 to 30 not 01 to 31.Is there any way to change default format in my sql?
You seem to be looking for the MySQL STR_TO_DATE function :
It takes a string str and a format string format. STR_TO_DATE() returns a DATETIME value if the format string contains both date and time parts, or a DATE or TIME value if the string contains only date or time parts.
So if the date coming out of your application is like '2019-5-6', to convert it to a MySQL date you need :
STR_TO_DATE('2019-5-6', '%Y-%c-%e')
In an INSERT statement :
INSERT INTO mytable VALUES(1, STR_TO_DATE('2019-5-6', '%Y-%c-%e'));
Tip :
%Y : Year as a numeric, 4-digit value
%c : numeric month name (0 to 12)
%e: day of the month as a numeric value (0 to 31)
The default way to store a date in a MySQL database is by using DATE. The proper format of a DATE is: YYYY-MM-DD. If you try to enter a date in a format other than the Year-Month-Day format, it might work but it won't be storing the dates as you expect.
In order to run a MySQL Insert command and add the current date into your table you can use MySQL's built-in function CURDATE() in your query.
An example of how to Insert a Date in MySQL using CURDATE
$query_auto = "INSERT INTO tablename (col_name, col_date) VALUE ('DATE: Auto CURDATE()', CURDATE() )";
Also, you can run a query to set the date manually
An example of how to Insert a Date in MySQL manually
$query_manual = "INSERT INTO tablename (col_name, col_date) VALUES ('DATE: Manual Date', '2008-7-04')";
It is recommended to do the date formatting when doing a query, like so:
SELECT DATE_FORMAT(BirthDate, "%W %M %e %Y") FROM Employees;
You can find more examples of formatting the date here:
https://www.w3schools.com/sql/func_mysql_date_format.asp
I have a string column which acts as a date and I want to select it as a DATE.
Is it possible?
My sample data format would be:
month/day/year -> 12/31/2011
As was told at MySQL Using a string column with date text as a date field, you can do
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAY
You can handle all kinds of date/time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter of STR_TO_DATE().
STR_TO_DATE('12/31/2011', '%m/%d/%Y')
Here's another two examples.
To output the day, month, and year, you can use:
select STR_TO_DATE('14/02/2015', '%d/%m/%Y');
Which produces:
2015-02-14
To also output the time, you can use:
select STR_TO_DATE('14/02/2017 23:38:12', '%d/%m/%Y %T');
Which produces:
2017-02-14 23:38:12
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
use the above page to refer more Functions in MySQL
SELECT STR_TO_DATE(StringColumn, '%d-%b-%y')
FROM table
say for example use the below query to get output
SELECT STR_TO_DATE('23-feb-14', '%d-%b-%y') FROM table
For String format use the below link
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The following illustrates the syntax of the STR_TO_DATE() function:
STR_TO_DATE(str,fmt);
The STR_TO_DATE() converts the str string into a date value based on the fmt format string. The STR_TO_DATE() function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE() function returns NULL.
The following statement converts a string into a DATE value.
SELECT STR_TO_DATE('21,5,2013','%d,%m,%Y');
Based on the format string ‘%d, %m, %Y’, the STR_TO_DATE() function scans the ‘21,5,2013’ input string.
First, it attempts to find a match for the %d format specifier, which
is a day of the month (01…31), in the input string. Because the
number 21 matches with the %d specifier, the function takes 21 as the
day value.
Second, because the comma (,) literal character in the format string
matches with the comma in the input string, the function continues to
check the second format specifier %m , which is a month (01…12), and
finds that the number 5 matches with the %m format specifier. It
takes the number 5 as the month value.
Third, after matching the second comma (,), the STR_TO_DATE()
function keeps finding a match for the third format specifier %Y ,
which is four-digit year e.g., 2012,2013, etc., and it takes the
number 2013 as the year value.
The STR_TO_DATE() function ignores extra characters at the end of the input string when it parses the input string based on the format string. See the following example:
SELECT STR_TO_DATE('21,5,2013 extra characters','%d,%m,%Y');
More Details : Reference